Percentages

Percentages

Q. 1. The difference between 78% of a number and 59% of the same number is 323. What is 62% of that number?(a) 1071    (b) 1173    (c) 1037     (d) 1159     (e) None of theseAns: (e) None of theseExplanation:The difference in percentage = 78% - 59% = 19%i.e. 19% of a number = 323therefore,  62% of the number = 323 × 62/19 = 1054.Ans.Q. 2. 88% of a number is 35640. What is 65% of that number?(a) 25920   (b) 26500   (c) 26325    (d) 26730     (e) None of theseAns: (c) 26325Explanation:88% of a number = 35640Therefore, 65% of that number = 35640 × 65/88 = 26325. Ans.Q. 3. Tanya obtained 95% marks in Physics, Chemistry and Maths together and she obtained 225 marks in Social Science, English and Hindi together. If the maximum marks one can obtain in each of the subjects is 100, what is Tanya’s overall percentage in all the six subjects together?(a) 80  (b)75  (c) 90   (d) 95  (e) None of theseAns: (e) None of theseExplanation:Maximum marks in each subject = 100So, his total marks in Physics, Chemistry and Maths = 95% of 300 = 285Total marks obtained in Social Science, English and Hindi = 225 out of 300Therefore, total marks in 6 subjects = 285 + 225 = 510So, the required percentage = 510 × 100/600 = 85%. Ans.Q. 4. 40% of 60% of 3/5th  of a number is 504. What is 25% of 2/5th of that number?(a) 180   (b) 175    (c) 360     (d) 350    (e) None of theseAns: (d) 350Explanation:Let ‘x’ be the number.Then, 40/100 × 60/100 × 3/5 × x = 504144x = 504 × 1000Therefore, x = 504 × 1000/144 = 3500Then, 25/100 × 2/5 × 3500 = 350. Ans.Q. 5. In a test consisting of 80 questions carrying one mark each, Arpita answers 65% of the first 40 questions correctly. What percent of the other 40 questions does she need to answer correctly to score 75% on the entire test?(a) 60   (b) 80    (c) 75    (d) 40    (e) None of theseAns: (e) None of theseExplanation:Total marks  for 80 questions = 80

75% of 80 = 6065% of 40 = 26Required marks for other 40 questions = 60 – 26 = 34  out of 40Therefore, the required percentage = 34 × 100/40 = 85%. Ans.Q. 6. A sum of Rs.2236 is divided among A, B and C such that A receives 25% more than C and C receives 25% less than B, what is A’s share in the amount?(a) Rs. 460   (b) Rs. 890  (c) Rs. 780   (d) Rs.1280   (e) None of theseAns: (c) Rs.780Explanation:C = 75 B/100 = 3 B/4  and  so, A = 125 × 3 B/100 × 4 = 15 B/16Then, 15 B/16 + 3 B/4 + B = 2236i.e. 43 B/16 = 2236   and   B = 2236 × 16/43 = 832Therefore, A’s amount = 15 × 832/16 =Rs.780.Ans.Q. 7. (7.9% of 134) – (3.4% of 79) = ?(a) 8.1   (b) 7.8   (c) 8.6    (d) 7.3    (e) None of theseAns: (e) None of theseExplanation:7.9 ×134/100 – 3.4 × 79/100 = 10.586 – 2.686 = 7.9. Ans.Q. 8. In a class of 65 students and 4 teachers, each student got sweets that are 20% of the total number of students and each teacher got sweets that are 40% of the total number of students. How many sweets were there?(a) 845   (b) 897    (c) 949   (d) 104    (e) None of theseAns: (c) 949Explanation:No. of  sweets each student get = 20% of 65 = 13No. of sweets each teacher get = 40% of 65 = 26No. of sweets distributed to 65 students =  13 × 65 = 845No. of sweets distributed to 4 teachers = 4 × 26 = 104Therefore, the total no. of sweets there = 845 + 104 = 949. Ans.Q. 9. What is 35% of 42 % of 6/7th of 500?(a) 36    (b) 44   (c) 52    (d) 60    (e) None of theseAns:  (e) None of theseExplanation:35/100 × 42/100 × 6/7 × 500 = 63. Ans.Q. 10. 88.25% of 450 = ?% of 530(a) 70    (b) 68    (c) 75    (d) 80    (e) 65Ans: (c) 75Explanation:88.25 × 450/100 = ? × 530/100i.e. 88.25 × 450  = ? × 530:. ? = 88.25 × 450/530 = 75.15 = 75 approximately. Ans.Q. 11. ?% of 450 + 46% of 285 = 257.1(a) 34    (b) 32    (c) 21   (d)   28    (e) None of theseAns: (d) 28Explanation:? × 450/100 + 46 × 285/100 = 257.1

? × 450  + 46 × 285/100 = 257.1? × 450 + 46 × 285 = 25710? × 450 = 25710 – 13110 = 12600? = 12600/450 = 28 Ans.Q. 12. 75% of 280 – 24% of 45 = ?(a) 194.5   (b) 195  (c) 199.2    (d) 198   (e) None of theseAns: (c) 199.2Explanation:75% of 280 = 280 × ¾ = 21024% of 45 = 25% of 45 – 1% of 45                 = 25/4  -   .45 = 11.25 - .45 = 10.80Therefore, ? = 210 – 10.80 =199.2. Ans.Q. 13. 5040 ÷ ( ?% of 840) = 8(a) 45   (b) 60    (c) 75      (d) 50   (e) None of theseAns: (c) 75Explanation:5040 ÷ ? × 840/100 =85040 × 100 /? × 840 = 8? = 5040 × 100/8 × 840 =75. Ans.Q. 14. The 18% of a number is 59.04. what is 25% of that number?(a) 76   (b) 82   (c) 68    (d) 91   (e) None of theseAns: (b) 82Explanation:18% = 59.041% = 59.04/1825% of the number = 59.04 × 25/18 = 82. Ans.Q. 15. Three –fifth of a number is 168. What is 12% of that number?(a) 35.4   (b) 34.2   (c) 36.4   (d) 33.6   (e) None of theseAns: (d) 33.6Explanation:3/5th of  the number = 168So, the number = 168 × 5/3 = 28012% of 280 = (10% + 2%) of 280 = 28 + 5.6 = 33.6.Ans.Q.16. 38% of 341 = ?(a) 120.68    (b) 129.58   (c) 135.78    (d) 136.28   (e) None of theseAns: (b) 129.58Explanation:38% of 341 = (3 × 10% + 8%) of 341                   = 3 × 34.1 + 8 × 3.41                              (where 1% = 3.41)                  = 102.3 + 27.28 =129.58.Ans.Q. 17. Out of 820 employees in an organization 20% of the employees got promoted to a higher grade. How many employees did not get promoted?(a) 680   (b) 668   (c) 656    (d) 674    (e) None of theseAns: (c) 656Explanation:The no. of employees did not get promoted  = 80% of 820

                                                                      = 8 × 10% of 820  = 8 × 82 = 656.Ans.Q. 18. 96% of a number is 19584. What is 56% of that number?(a) 11016  (b)11222   (c) 11628    (d) 10812     (e) None of theseAns: (e) None of theseExplanation:Because 96% = 195841% = 19584/96Then 56% of that number = 19584 × 56/96 = 11424.Ans.Q. 19. 16% of 380 × 5 = ?(a) 276    (b)284    (c) 304      (d) 312    (e)None of theseAns: (c)304Explanation:16% of 380 = (10% + 5% + 1%) of 380                   = 38 + 19 + 3.8 = 60.816% of 380 × 5 = 60.8 × 5 = 304.Ans.Q.20. 4550 ÷ 25% of ? = 130(a) 145   (b) 140   (c) 125   (d) 160   (e) None of theseAns: (b) 140Explanation:4550 ÷ 25 ?/100 =1304550 × 100/25? =130? = 4550 × 100/25 × 130 = 140. Ans.Q.21. (550% of 250) ÷ 275 = ?(a)15  (b)1.5   (c)0.5   (d) 25    (e) None of theseAns: (e) None of theseExplanation:550% of 250 = (5 × 100% + 50%) of 250                     = 1250 + 125 = 13751375/275 = 5. Ans.Q. 22. 155 of 45% of a  number is 105.3. What is 24% of that number?(a) 385.5   (b)374.4  (c) 390  (d)375   (e) None of theseAns: (b) 374.4Explanation:15/100 × 45/100 × x = 105.3Then, x = 105.3 × 100 × 100/ 15 × 45 = 156024% of 1560 = (20% + 4%) of 1560                     = 312 + 62.4 = 374.4. Ans.Q. 23. 135% of 480 + ?% of 320 = 728(a) 25   (b) 28   (c) 125   (d) 115  (e) None of theseAns: (a) 25Explanation:135% of 480 = (100% + 3× 10% + 5%) of 480                     = 480 + 144 + 24 = 648?/100 ×320 = 728 – 648  ? = 80 × 100/320 = 25.Ans.Q. 24. 64% of a number is 2592. What is 88% of that number?

(a) 3458  (b) 3202   (c) 3826   (d) 3564    (e) None of theseAns: (d) 3564Explanation:64% = 2592So, 1% = 2592/6488% of the same number = 2592 × 88/64  = 3564.Ans.Q. 25. The difference between 54% of a number and 26% of the same number is 22526. Whaat is 66% of that number?(a) 53097  (b) 48372  (c) 51218  (d) 49124   (e) None of theseAns: (a) 53097Explanation:The difference in percentage i.e. 54% - 26% = 28%Given that 28% = 225261% = 22526/2866% of the same number = 22526 × 66/28 = 53097.Ans.Q. 26. 30% of 15.6 + ? = 40% of 30What is the value of question mark in the above equation?

(a)    6.32    (b) 7.32   (c) 8.32   (d) 5.32   (e) None of theseAns: (b) 7.32Explanation:30% of 15.6 = 3 × 1.56 = 4.6840% of 30 = 4 × 3 =12Given that 4.68 + ? = 12Therefore, ? = 12 – 4.68= 7.32. Ans.Q. 27. The difference between 90% of a number and 83% of the same number is 175. What is 99% of that number?(a) 2420   (b) 2475  (c) 2500  (d) 1750   (e) None of theseAns: (b)  2475Explanation:The difference in percentage = 90% - 83% = 7%Given that 7% = 175So, 1% = 175/7  99% of the same number = 175 × 99/7 = 2475.Ans.Q. 28. 45% of 90 = ?% of 81(a) 405   (b) 500    (c) 50    (d) 28.5    (e)None of theseAns: (c) 50Explanation:45% of 90 = (50% - 5%) of 90                 = 45 – 4.5 = 40.50i.e. 40.5 = ?/100 × 81? = 40.5 × 100/81   = 50.Ans.Q. 29. 15% of 15 = ?(a) 2.25   (b) 22.5    (c) 0.15     (d) 0.25   (e) None of theseAns: (a) 2.25Explanation:15% of 15 = (10% + 5%) of 15

                 = 1.5 + .75 = 2.25. Ans.Q. 30. The value of  7/10 of 3/17 of 30% of 425 is equal to(a) 13.5  (b) 24.25   (c) 15.75   (d) 16    (e) None of theseAns: (c) 15.75Explanation:30% of 425 =  3 × 10% of 425 = 127.57/10 × 3/17 × 127.5 = 63/4 = 15.75.Ans.+Q. 31. 36% of 182 + 177% of 36 = ?(a) 125    (b) 130    (c) 135    (d) 140    (e) 170Ans: (b) 130Explanation:36% of 182 = ( 3 × 10% + 5% + 1) of 182                   = 3 × 18.2 + 9.1 + 1.82 =  54.6 + 9.1 + 1.82 = 65.52177% of 36 = (100% + 75% + 2%) of 36 = 36 + 27 + .72 = 63.72Therefore, the required sum = 65.52 + 63.72 = 129.24 = 130 approximately. Ans.Q. 32. Because of decrease of available manpower a toy factory reduced its monthly output by 20%. What should be the percent increase of manpower to bring the production up to normal?(a) 16 2/3   (b) 24    (c) 20   (d) 25   (e) None of theseAns: (d) 25%Explanation:The reduced out put = 80%Therefore, the increase in manpower required in percentage = 20 × 100/80 = 25%. Ans.Q. 33. Vaishali spent Rs.31897 on the air-conditioner for her home, Rs.38789 on buying plasma television and the remaining 23% of the total amount she had as cash with her. What was the total amount?(a) Rs.74625   (b) Rs.86750   (c) Rs.91800   (d) Cannot be determined   (e) None of theseAns: (c) Rs.91800Explanation:The total amount she  spent = Rs.31897 + Rs.38789 = Rs.70686Percentage of amount she spent = 100 – 23 =  77 %  i.e. 77% = 70686Therefore, the total amount = 70686 × 100/77 = Rs.91800.  Ans.Q. 34. 40% of 250 = 50% of ?(a) 200   (b) 100  (c) 150    (d) 400   (e) None of theseAns: (a) 200Explanation:40% of 250 = (50% - 10% 0 of 250 = 125 – 25 = 100Given that, 100 = 50 ?/100? = 10000/50 = 200. AnsQ. 35. In an examination it is required to get 40% of the aggregate marks to pass. A student gets 265 marks and is declared fail by 55 marks. What is the maximum aggregate marks a student can get?(a) 800  (b) 750   (c) 650    (d) Cannot be determined   (e) None of theseAns: (a) 800Explanation:

265 + 55 = 320 = 40% of the aggregate marksTherefore, the aggregate marks = 320 × 100/40 = 800. Ans.Q. 36. The difference between 75% of a number and 20% of the same number is 378.4.  What is 40% of that number?(a) 275.2    (b) 274   (c) 267.2    (d) 266    (e) None of theseAns: (a) 275.2Explanation:The difference in percentage i.e. 75% - 20% = 55%   55% of a number = 378.4Therefore, 1% of the number = 378.4/55And 40% of the same number = 378.4 × 40/55 = 275.2. Ans.Q. 37. The difference between 56% of a number and 39% of the same number is 425. What is 63% of that number?(a) 1525  (b) 1650   (c) 1700  (d) 1575   (e) None of theseAns: (d) 1575Explanation:The difference in percentage i.e. 56% - 39% = 17%17% of the number = 425Therefore, 1% = 425/17 = 25So, 63 % of the number = 25 × 63 = 1575. Ans.Q. 38. 60 per cent of first number is 40 per cent of the second number. What is the respective ratio of the first number to the second number?(a) 2 : 3   (b) 21 : 31   (c) 7 : 10   (d) cannot be determined  (e) None of theseAns: (a) 2 : 3Explanation:Let the numbers be ‘a’ and ‘b’60a/100 = 40b/10060a  = 40bThen, a : b = 40 : 60                  = 2 : 3. Ans.Q. 39. 82% of 850 – (?)² = 16²(a) 30    (b) 27   (c) 24   (d) 21     (e) None of theseAns: (d) 21Explanation:82% of 850 = (8 × 10% + 2%) of 850                  = 680 + 17 = 697i.e. 697 – 256 = ?² 441 = 21² = 21.Ans.Q. 40. 40% of 15% of 3/4th of a number is 153. What is the number?(a) 3400    (b) 3650   (c) 3600    (d) 3200   (e) None of theseAns: (a) 3400Explanation:Let ‘x’ be the numberThen, 40/100 × 15/100 × ¾ × x = 153

So, x = 153 × 100  × 100 × 4/40 × 15 × 3 = 3400.Ans.Q. 41. 185% of 400 + 35% of 240 = ?% of 1648(a) 85   (b) 75   (c) 125   (d) 50    (e) None of theseAns: (d) 50Explanation:185% of 400 = (100% + 8 × 10% + 5%) of 400                     = 400 + 320 + 20 = 74035% of 240 = (3 × 10% + 5%) of 240 = 72 + 12 = 84740 + 84 = 824   Given that, 824 = ?/100 × 1648? = 824 × 100/1648 = 50. Ans.Q. 42. 15% of ?  = 94.5(a) 14.175   (b) 1410   (c) 630   (d) 141   (e) None of theseAns: (c) 630Explanation:15 ?/100 = 94.5? = 94.5 × 100/15 = 630. Ans.Q. 43. 63% of a number is 2583. What is 45% of that number?(a) 1845   (b) 1763   (c) 2255   (d) 1927   (e) None of theseAns: (a) 1845Explanation:63% = 2583Then, 1% = 2583/6345% = 2583 × 45/63 = 1845. Ans.Q. 44. What is 240 per cent of 700?(a) 1650    (b) 1780    (c) 1560     (d) 1710     (e) None of theseAns: (e)   None of theseExplanation:240% = 2 × 100% + 4 × 10% 240% of 700 = 2 × 700 + 4 × 70 = 1680 Ans.Q. 45. What is 30% of 25% of 3/5th of 9800? (a) 433   (b) 453   (c) 441    (d) 391   (e) None of theseAns: (c) 441Explanation:30/100 × 25/100 × 3/5 × 9800 = 441.Ans.Q. 46. Sameera wove a sweater buying wool for Rs.375. She sold it for Rs.300. Calculate her loss per cent.(a) 35%    (b) 25%   (c) 20%    (d) 15%   (e) None of theseAns: (c) 20%Explanation:Percentage loss/gain = Actual loss/ gain × 100/ CostActual loss = 375 – 300 = Rs.75So, Percentage loss = 75 ×100/375 = 20%. Ans.Q. 47. ? ÷ 6 = 30% of 860

(a) 1548   (b) 1624    (c) 17208   (d) 1428     (e) None of theseAns: (a) 1548Explanation:?/6 = 30 × 860/100? = 30 × 860 × 6/100 = 1548. Ans.Q. 48. Ramu gave 35% of the  amount he had to Shakeel. Shakeel in turn gave two-thirds of what he received from Ramu to Joseph. After spending Rs.150 on lunch out of the amount he got from Shakeel, Joseph now has Rs.550 left with him. How much amount did Ramu have?(a) Rs.2800   (b) Rs.2000  (c) Rs.3000   (d) Can’t be determined  (e) none of theseAns: (c) Rs.3000Explanation:The amount given by Shakeel to Joseph = 150 + 550 = Rs.700This is 2/3rd of the amount given to Shakeel by Ramu and let the amount got by Shakeel = ‘x’i.e. 2/3 × x = 700Therefore, the amout given to Shakeel by Ramu , x = 700 × 3/2 = Rs.1050Rs. 1050 is 35% of amount Ramu hadSo, the Total amount Ramu had = 1050 × 100/35 = Rs.3000.Ans.Q.49. What is the 30% of 40% of 2/5th of 2500?(a)500   (b) 400   (c) 360   (d) 120   (e) None of theseAns: (d) 120Explanation:30/100 × 40/100 × 2/5 ×  2500 = 120.Ans.Q. 50. Two numbers are less than the third number by 50% and 54% respectively. By how much per cent is the second number less than the first number?(a) 13   (b) 10   (c) 12   (d) Cannot be determined   (e) None of theseAns: (e) None of theseExplanation:Let the third number be ‘100’Then the first number = 100 – 50 = 50The second number = 100 – 54 = 46The difference between the first and the second number = 50 – 46 = 4Therefore, the required percentage = 4 × 100/50 =8. Ans.Q. 51. If the numerator of a fraction is increased by 200% and the denominator is increased by 300%, the resultant fraction is 15/26. What was the original fraction?(a) 8/11   (b) 10/11    (c) 9/13    (d) 10/13   (e) None of theseAns: (d) 10/13Explanation:Let x/y be the original fractionThen, x + 2x/100 / y + 3y/100 = 15/26i.e. x + 2x/y + 3y = 15/163x/4y = 15/26x/y = 15 × 4/26 × 3 = 10/13. Ans.Q. 52. One – fifth of a number is 81. What will 68% of that number be?(a) 195.2    (b) 275.4   (c) 225.6    (d) 165.8     (e) None of these

Ans: (b) 275.4Explanation:Let ‘x’ be the numberThen, x/5 = 81   So, x = 81 × 5 = 40568% = 50% + 10 % + 8 × 1%68% of 405 = 202.5 + 40.5 + 32.4 = 275.4 Ans.Q. 53. In an examination, 1100 boys and 900 girls appeared. 50% of the boys and 40% of the girls passed. The percentage of failed candidates is(a) 45.0   (b) 45.5   (c) 54.5    (d) 59.2    (e) None of theseAns: (c) 54.5Explanation:No. of failed boys = 550No. of failed girls = 540Therefore, total number of failed candidates = 1090So, the required percentage = 1090 × 100/2000 = 54.5 Ans.Q. 54. 56% of a number is less than its 72% by 56. What is 70% of that number?(a) 300   (b) 235    (c) 240   (d) 350   (e) None of theseAns: (e) None of theseExplanation:i.e. 72 – 56 = 16 % of the number = 561% of the number = 56/16Then, 70% of the number = 56 × 70/16 = 245. Ans.Q. 55. Five – sixth of a number is 720. What will 45% of that number be?(a) 346.6    (b) 388.8    (c) 392.2     (d) 344.4      (e) None of theseAns: (b) 388.8Explanation:Let ‘x’ be the numberThen, 5x/6 = 720So, x = 720 × 6/5 = 86445% = 50% - 5%45% of 864 = 432 – 43.2 = 388.8.Ans.Q. 56.  In an examination it is required to get 380 of the aggregate marks to pass. A student gets 32% marks and is declared failed by 76 marks. What are the maximum aggregate marks a student can get?(a) 945   (b) 975   (c) 950    (d) Cannot be determined   (e) None of theseAns: (c) 950Explanation:32% of the total marks = 380 – 76 = 304Therefore, 1% of the total marks = 304/32So, the total marks a student can get = 304 × 100/32 =950. Ans.Q. 57. One – seventh of a number is 51. What will be 64% of that number?(a) 248.12  (b) 228.48    (c) 238.24     (d) 198.36    (e) None of theseAns: (b) 228.48

Explanation:Let ‘x’ be the numberThen, x = 51 × 7 = 35764% = 50% + 10% + 1% × 4So, 64% of 357 = 178.5 + 35.7 + 14.28 = 228.48 Ans.Q. 58. The difference between 56% of a number and 41% of the same number is 660. What is 8% of that number?(a) 321    (b) 336   (c) 345     (d) 358      (e) None of theseAns: (e) None of theseExplanation:56 – 41 = 15% of the number = 660Therefore, 1% of the same number = 660/15And so, 8%  of the number = 660 × 8/15 = 352.Ans.Q. 59. A cricketer has batted in 105 innings. He has scored 17 centuries, crossed the 50- run mark 28 times and crossed the 25-run mark 39 times. The no. of times he has scored below 25 is what percentage of the number of times he scored between 25 and 49 ( both 25 and 49 included)?(a) 450%   (b) 600%    (c) 500% (d) cannot be determined   (e) None of theseAns: (b) 600%Explanation:The no. of times he crossed above 25-run mark = 39So, the no. of times he crossed below the 25 – run mark = 105 – 39 = 66 timesThe no. of times he crossed above 50 – run mark = 28Therefore, the no. of times he crossed in between 25-run mark and 50-run mark = 39-28 = 11Therefore the required percentage = 66 × 100/11 = 600%. Ans.Q. 60. 25% of 50% of a number is 385. What is the number?(a) 3050    (b) 3100   (c) 3004    (d) 3080     (e) None of theseAns: (d) 3080Explanation:25% = ¼;     50% = ½,  and let the number be ‘x’i.e. ¼ × ½ × x = 385Therefore, x = 385 × 4 × 2 = 3080. Ans.Q. 61. Samir secured 580 marks out of a total of 750 in an examination. What is Samir’s approximate percentage in the exam?(a) 81    (b) 77    (c) 71   (d) 75    (e) 84Ans: (b) 77Explanation:Required percentage = 580 × 100/750 = 77.3% = 77 approximately. Ans.Q. 62. What is 160% of 480?(a) 768    (b) 684   (c) 786     (d) 864     (e) None of theseAns: (a) 768Explanation:160% = 100% + 50% + 10%160% of 480 = 480 = 240 + 48 = 768. Ans.

Q. 63. 15% of the total number of students in a college play football. How many students do not play football, if the total number of students in the college is 6500?(a) 975    (b) 5525  (c) 910    (d) 5590    (e) None of theseAns: (b) 5525Explanation:15% = 10% + 5%15 % of 6500 = 650 + 325  = 975Therefore, the no. of students who do not play  football = 6500 – 975 = 5525.Ans.Q. 64. 75% of a number is equal to four – fifths of another number. What is the ratio between the first number and the second number?(a) 5 : 3   (b) 15 : 16   (c) 3 : 5   (d) 16 : 15  (e) None of theseAns: (d) 16 : 15Explanation:Let the two numbers be ‘x’ and ‘y’Then, 75x/100 = 4y/55 × 75x = 4 × 100yx/y = 400/375 = 16 : 15. Ans.Q. 65. Sunil scored 54 percent marks in a test. Ravi scored 450 marks in the same test which is 300 less than Sonu. Sunil’s score is 60 more than Sonu. If Ram scored 900 marks in the test, what is Ram’s percentage?(a) 80    (b) 65    (c) 75    (d) 60   (e) None of theseAns: (d) 60Explanation:Sonu’s score = 450 + 300 = 750Sunil’s score = 54% of the total = 750 + 60 =810Then, the maximum marks = 810 × 100/54 = 1500Therefore, the required percentage = 900/1500 × 100 = 60%. Ans.Q. 66. In a school there are 800 students out of whom 45 percent are girls. Monthly fee of each boy is Rs.600 and monthly fee of each girl is 30 percent less than each boy. What is the total monthly fee of girls and boys together?(a) Rs.425400   (b) Rs.414600    (c) Rs.419600   (d) Rs.423400   (e) None of theseAns: (e) None of theseExplanation:No. of boys = 55% of 800 = 440No. of girls = 800 – 440 = 360Total monthly fee of boys = 440 × 600 = 264000Total monthly fee of girls = 360 × 70% of 600 = 360 × 420 = 151200Therefore, the total monthly fee of boys and girls = 264000 + 151200 = Rs.415200.Ans.Q. 67. While selling a watch, a shopkeeper gives a discount of 15%. If he gives a discount of 20%, he earns Rs.51 less as profit. What is the original price of the watch?(a) Rs.920    (b) Rs.985    (c) Rs.1125    (d) Rs.1020   (e) None of theseAns: (d) Rs.1020Explanation:The difference in percentage, i.e. 20% - 15% = 5% = Rs.51

That is, Rs.51 is 5% of the original price of the watchTherefore, the original price of the watch =  51 ×100/5 = Rs.1020.Ans.Q. 68. Five-ninth of a number is equal to twenty five per cent of second number. Second number is equal to one-fourth of third number. The value of third number is 2960. What is 30% of first number?(a) 88.8   (b) 99.9    (c) 66.6    (d) cannot be determined   (e) None of theseAns: (b) 99.9Explanation:Let a, b, and c be the three numbersThen, b = c/45a/9 = 25c/4/100,     i.e. 5a/9 = 25c/4005a × 400 = 9 × 25c2000a = 225c             ( given, c = 2960)Therefore, a = 225 × 2960/2000   = 333   So, 30% of a = 3 × 10% of a                     = 3 × 33.3 = 99.9.Ans.Q. 69. What is 28% of 36% of 5/7th of 5000?(a) 480   (b) 375    (c) 360   (d) 420    (e) None of theseAns: (c) 360Explanation:28/100 × 36/100 × 5/7 × 5000 = 360. Ans.Q. 70. In a class of 50 students and 5 teachers, each student got sweets that are 12% of the total number of students and each teacher got sweets that are 20% of the total number of students. How many sweets were there?(a) 345   (b) 365   (c) 330   (d) 350    (e) None of theseAns: (d) 350Explanation:50 × 12 × 50/100 + 5 × 20 × 50/100  = 300 + 50 = 350.Ans.Q. 71. If the numerator of a fraction is increased by 500% and the denominator is increased by 300%, the resultant fraction is 1 1/17. What was the original fraction?(a) 12/17   (b) 13/17    (c) 3/7   (d) 4/11   (e) None of theseAns: (a) 12/17Explanation:Let x/y be the original fractionThen, x + 5x/y + 3y = 18/17          (i.e. 500% of x = 5x, & 300% of y = 3y)That is, 6x /4y = 18/17    i.e. 102x = 72yThen, x/y = 72/102 = 24/34 = 12/17. Ans.Q. 72. One-fifth of a number is 62. What will 73% of that number be?(a) 198.7   (b) 212.5    (c) 226.3     (d) 234.8     (e) None of theseAns: (c) 226.3Explanation:Let ‘x’ be the numberThen, x/5 = 62So, x = 62 × 5 = 310

73% = 50% + 2 × 10% + 3 × 1%So, 73% of 310 = 155 + 62 + 9.3 = 226.3. Ans.Q. 73. In a class of 240 students, each student got sweets that are 15% of the total number of students. How many sweets were there?(a) 3000   (b) 3125    (c) 8640    (d) Cannot be determined   (e) None of theseAns: (c) 8640Explanation:Each student gets 15% of 240 sweets,  i.e. = 36 nos.Therefore, the total number of sweets = 240 × 36 = 8640. Ans.Q. 74. 12% of 840 × 0.25% of 148 = ?(a) 37.296    (b) 101.17      (c) 68.432     (d) 97.046     (e) None of theseAns: (b) 101.17Explanation:12% of 840 = 100.8.25%  of 148 = .37Required sum = 100.8 + .37 = 101.17.Ans.Q. 75. The total number of students in the school are 4800, out of which 60% are girls. What is the total number of boys in this school?(a) 1920   (b) 1934    (c) 1980    (d) 1910   (d) None of theseAns: (a) 1920Explanation:The number of boys in the school = 100 – 60 = 40% of 4800                                                                        = 4 × 10% of 4800                                                                       = 4 × 480 = 1920.Ans.Q. 76. The difference between 55% of a number and 25% of the same number is 11.10. What is 75% of that number?(a) 27.75    (b) 37    (c) 21.25    (d) 45   (e) None of theseAns: (a) 27.75Explanation:The difference in percentage, i.e. 55 -25 = 30%30% of the number = 11.10Therefore, 75% of that number = 11.10 × 75/30 = 111/4 = 27.75. Ans.Q. 77. In an election between two candidates, one got 52% of the total valid votes. 25% of the total votes were invalid. The total number of votes were 8400. How many valid votes did the other person get?(a) 3276    (b) 3196   (c) 3024    (d) Cannot be determined   (e) None of theseAns: (c) 3024Explanation:Number of valid votes = 75% of 8400 = 8400 × ¾ = 6300Percentage of valid votes got by other person = 48%Therefore, the required number  of valid votes = 48% of 6300 = 4 × 10% + 5% + 3 × 1% of 6300                                                                                                    = 4 × 630 + 315 + 3 × 63                                                                                                    = 2520 + 315 + 189                                                                                                   = 3024.Ans.

Q. 78. Two-fifth of a number is 182. What will 48% of that number be?(a) 236.6    (b) 218.4    (c) 209.3     (d) 200.2    (e) None of theseAns: (b) 218.4Explanation:Let the number be ‘x’Then, 2x/5 = 182Then, x = 182 × 5/2 = 91 × 5 = 45548% =50% - 2% Therefore, 48% of 455 = 227.5 – 9.1 = 218.4. Ans.Q. 79. In a school there are 250 students out of whom 12 per cent are girls. Each girl’s monthly fee is Rs.450/- and each boy’s monthly fee is 24 percent more than a girl. What is the total monthly fee of girls and boys together?(a) Rs.136620/-   (b) Rs.136260/-    (c) Rs.132660/-   (d) Rs.132460/-     (e)None of theseAns: (b) 136260/-Explanation:No. of girls = 12% of 250 = 30No. of boys = 250 – 30 = 220Total fee of 30 girls = 30 × 450 = Rs.13500/-Fee for each boy = 450 + 24% of 450                            = 450 + 108 = Rs.558Total fee of 220 boys = 220 × 558 = Rs. 122760Therefore, total monthly fee of boys and girls in the school = 122760 + 13500 =Rs.136260/-. Ans.Q. 80. Ravi scored 225 marks in a test and failed by 15 marks. If the passing percentage of passing the test is 25 per cent. What are the maximum marks of the test?(a) 860    (b) 840    (c) 920    (d) 960     (e) None of theseAns: (d) 960Explanation:25% of the maximum marks = 225 + 15 = 240Therefore, maximum marks = 240 × 4 = 960. Ans.Q. 81. If the height of a triangle is decreased by 40% and its base is increased by 40% and its base is increased by 40%, what will be the effect on its area?(a) No change    (b) 16% increase    (c) 8% decrease    (d) 16% decrease   (e) None of  theseAns: (d) 16% decreaseExplanation:Let the base = 100 and height = 100Then the area of the triangle = ½ × base × a height                                              = 100 × 100/2 = 5000Now, the height is decreased to 60 and  the base is increased  to 140Then, the area = 60× 140/2 =4200The difference = 5000- 4200 = 800 decreasePercentage effect on its area = 800 × 100/5000 = 16% decrease. Ans.

Q. 82. An HR Company employs 4800 people, out of which 45 per cent are males and 60 per cent of the males are either 25 years or older. How many males are employed in HR Company who are younger than 25 years?(a) 2640   (b) 2160   (c) 1296    (d) 864      (e) None of theseAns: (d) 864Explanation:No. of males = 45% = 50% - 5%                     = 2400 – 240 = 2160The no. of employees who are younger than 25 years = 40% of 2160                                                                                     = 4 × 10% of 2160                                                                                    = 4 × 216 = 864. Ans.Q. 83. Six-eleventh of a number is equal to twenty two per cent of second number. Second number is equal to the one-fourth of third number. The value of the third number is 2400. What is the 45% of first number?(a) 109.8   (b) 111.7     (c) 117.6     (d) 123.4     (e) None of theseAns: (e) None of theseExplanation:The third number = 2400So, the second number = 2400/4 = 60022% of 600 = 132This 132 = 6/11 of first numberTherefore, the  first no. = 132 × 11/6 = 24245% of 242 = 50% - 5% of 242                   = 121 – 12.1 = 108.9.Ans.Q. 84. Two – third of the first number is equal to the cube of the second number. If the second number is equal to twelve per cent of 50. What is the sum of the first and the second numbers?(a) 330   (b) 360    (c) 390    (d) 372   (e) None of theseAns: (a) 330Explanation:Second number = 12% of 50 = 62/3 × First number =  6³ = 216First number = 216 × 3/2 = 324Then, the sum of first and the second number = 324 + 6 = 330. Ans.Q. 85. What is the value of twenty four percent of four-ninth of five times square of twenty seven?(a) 388.8    (b) 376.8    (c) 378.6     (d) 346.6   (e) None of theseAns: (a) 388.8Explanation:24/100 × 4/9 × 5 × 27²24/100 × 4/9 ×5 × 27 × 27 = 388.8.Ans.Q. 86. 14% of 80 + ?% of 90 = 31.9(a) 16    (b) 23    (c) 18   (d) 26    (e) None of theseAns: (b) 23Explanation:

14% of 80 = 11.2?% of 90 = 31.9 – 11.2 = 20.7i.e.  ?/100 × 90 = 20.7? = 20.7 × 100/90 = 207/9 = 23%. Ans.Q. 87. What is the value of thirty eight per cent of seven-twelfth of twice the cube of fifteen?(a) 1496.25    (b) 1478.50   (c) 1649.25     (d) 1748.50     (e) None of theseAns: (a) 1496.25Explanation:38/100 × 7/12 × 2 × 3375 = 1496.25. Ans.Q. 88. Previously the price of an article was Rs.460/- and now it has been increased to Rs.550/-. What was the approximate per cent increase in the price of that article?(a) 80   (b) 8     (c) 40    (d) 60    (e) 20Ans: (e) 20Explanation:The difference = Rs.90.Therefore the percentage increase = 90 × 100/460 = 20 approximately. Ans.Q. 89. Two numbers are greater than the third number by 40% and 48% respectively. By what per cent is the second number greater than the first number?(a) 42.17%   (b) 57.14%   (c) 82.5%   (d) 69%    (e) 5.71%Ans: (e) 5.71%Explanation:Let the third number = 100Then, the second no. = 148 and the first number = 140The difference 148 – 140 = 8So, the required percentage = 8 /140 × 100 = 5.71%. Ans.Q. 90.  In an examination Sunil secured 480 marks out of 1200 marks and failed by 96 marks. What is the minimum passing percentage?(a) 46   (b) 45    (c) 42   (d) 38   (e) None of theseAns: (e) None of theseExplanation:Required marks for pass = 480 + 96 = 576Therefore, the minimum passing percentage = 576 × 100/1200 = 48%. Ans.Q. 91. Raman scored 456 marks in an exam and Seeta got 54 percent marks in the same exam which is 24 marks less than Raman. If the minimum passing marks in the exam is 34 per cent, then how much more marks did Raman score than the minimum passing marks?(a) 184   (b) 196   (c) 190   (d) 180    (e) None of theseAns: (a) 184Explanation:54% of the maximum marks = 456 -24 = 432Therefore, the maximum marks = 432 × 100 /54 = 800Then, the minimum passing marks = 34 % of 800 = 272The mark Raman scored above the passing marks = 456 -272 = 184. Ans.Q. 92. If a number is added to seven-ninth of thirty five percent of 900, the value so obtained is 325. What is the number?

(a) 60   (b) 120   (c) 90    (d) 180   (e) None of theseAns: (e) None of theseExplanation:Let ‘x’ be the number7/9 × .35 × 900 + x = 325Therefore, x = 325 – 245 = 80. Ans.Q. 93. A man sold a wristwatch for Rs.2400/- at a loss of twenty five percent. At what rate should he have sold the wristwatch to earn a profit of twenty five per cent?(a) Rs.3600   (b) Rs. 4000   (c) Rs.3500   (d) Rs.3800    (e) None of theseAns: (b) Rs.4000Explanation:Rs.2400 is 75% of the cost price of the wrist watchTherefore, the cost price = 2400 × 100/75 = Rs. 3200To get a profit of 25%, it should be sold at Rs.3200 + 25% of 3200         So, the required  selling price = Rs. 3200 + 800 = Rs.4000. Ans.Q. 94. Jasmine scored 52 marks in Science, 36 marks in Hindi, 47 marks in English and 73 marks in Sanskrit. The total marks of all the subjects together is 400. What is the overall percentage of marks she got?(a) 56    (b) 48   (c)45   (d) 52   (e) None of theseAns: (d) 52Explanation:The total marks scored by Jasmine in four subjects out of 400 = 208Therefore, the required percentage = 208/400 × 100 = 52%. Ans.Q.95. 35% of a number is 182. What is 130% of that number?(a) 676    (b) 667    (c) 673   (d) 663     (e) None of theseAns: (a) 676Explanation:1% of the number = 182/35Therefore, 130% of the same number = 182 × 130/35 = 26 × 26 = 676. Ans.Q. 96. One-third of a number is 96. What will 67% of that number be?(a) 192.96   (b) 181.44    (c) 169.92   (d) 204.48   (e) None of theseAns: (a) 192.96Explanation:Let the number =xThen, x = 3 × 96 = 28867% = 50% + 10% + 5 % + 2 × 1%Therefore, 67% of 288 = 144 + 28.8 + 14.4 + 5.76 = 192.96.Ans.Q. 97. There are 360 students in a class out of which 35% are day scholars. How many day scholars are there in the class?(a) 128   (b) 122   (c) 124   (d) 126   (e) None of theseAns: (d) 126Explanation:The no. of day scholars = 35% of 360               = (3 × 10% + 5% ) of 360 = 3× 36 + 18 = 108 + 18

                                                                            = 126. Ans.Q. 98. In an examination it is required to get 55% of the aggregate marks to pass. A student got 340 and was declared failed by 5% marks. What are the maximum aggregate marks a student can get?(a) 650   (b) 660   (c) 680    (d) Cannot be determined  (e) None of theseAns: (c) 680Explanation:i.e. 50% of the aggregate marks = 340So, the aggregate marks = 340  × 2 = 680. Ans.Q. 99. The sum of 35% of a number and 12% of the same number is 3055. What is the 72% of that number?(a) 4685   (b) 4680   (c) 4675    (d) 4670    (e) None of theseAns: (b) 4680Explanation:Let the number be ‘x’Then, 35x/100 + 12x/100 = 3055i.e. 35x + 12x/100 =3055     47x = 305500So, x = 305500/47 = 650072 % = 50% + 2 × 10% + 2× 1%Therefore, 72% of 6500 = 3250 + 1300 + 130 = 4680. Ans.Q. 100. In an examination it is required to get 65% of the aggregate marks to pass. A student gets 522 marks and is declared failed by 7% marks. What are the maximum aggregate marks a student can get?(a) 850  (b) 780   (c) 900  (d) Cannot be determined  (e) None of theseAns: (c) 900Explanation:That is, 65 – 7 =58% of the maximum marks = 522So, 1% of the aggregate marks = 522/58Therefore, the aggregate marks = 522 × 100/58  = 900. Ans.