A Pentagonal Tiling of the Euclidean Plane · A Pentagonal Tiling of the Euclidean Plane We’ve...

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A Pentagonal Tiling of the Euclidean Plane We’ ve chosen one of the tile families from the Wikipedia article on pentagonal tilings (shown below) and we aim to see, using Mathematica, how this tiles the plane. In this tile we have: a = b, d = c+e angle(A) = angle(C) = angle(D) =120° We arbitrarily set the point “B” at the origin: pointB = 80, 0<; p1 = Graphics@8PointSize@LargeD, Red, Point@pointBD<, Axes TrueD -1.0 -0.5 0.5 1.0 -1.0 -0.5 0.5 1.0 We arbitrarily place the point “A” on the horizontal axis at (-2,0) and join point “A" and point”B” with a line:

Transcript of A Pentagonal Tiling of the Euclidean Plane · A Pentagonal Tiling of the Euclidean Plane We’ve...

  • A Pentagonal Tiling of the Euclidean Plane

    We’ve chosen one of the tile families from the Wikipedia article on pentagonal tilings (shown below) and

    we aim to see, using Mathematica, how this tiles the plane.

    In this tile we have:

    a = b, d = c+e

    angle(A) = angle(C) = angle(D) =120°

    We arbitrarily set the point “B” at the origin:

    pointB = 80, 0

  • pointA = 8-2, 0

  • pointE = 8-3, Sqrt@3D

  • -3.0 -2.5 -2.0 -1.5 -1.0 -0.5

    0.5

    1.0

    1.5

    2.0

    Having located the coordinates of the vertices of the pentagon we can use Mathematica’s Polygon

    function to draw a filled polygon with these vertices:

    vertexlist = 8pointA, pointB, pointC, pointD, pointE

  • vertexlist2 = [email protected]@@kDD, 8k, 1, Length@vertexlistD, 90, -2 3 =>F

    We draw the new pentagon, in a different color, along with the basic pentagon:

    a2 = Graphics@8Yellow, pentagon2

  • a2 = Graphics@8Yellow,Polygon@Table@vertexlist2@@kDD + 8-3, Sqrt@3D

  • a3 = Graphics@8Red, Polygon@Table@vertexlist3@@kDD + 8-3, -Sqrt@3D