A new Approach for Magnetic Curves in Riemannian Manifolds 3 D Zehra Bozkurt 1 * , Ismail Gök 2 * ,...

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    in curvature to achieve aesthetic curves [17]. Then, Ling Xu and David Mould proposed tocontinuously change the charge on a simulated particle so that it can trace out a complex curve

    with continuously varying curvature. They showed some examples of abstract figures created by

    this method and also show how some stylized representational forms, including fire, hair, and trees,can be drawn with magnetic curves [18].

    In this paper, we give a new variational approach to studies the magnetic flow asociated with theKilling magnetic field in a D3 Riemannian space ).,( 3 gM And then, we investigate the

    trajectories of the magnetic fields called as N-magnetic and B-magnetic curves. Moreover, weobtain some solitions of the Lorentz force eqution and give some examples of these curves withdraw their pictures by using Mathematica.

    2. PreliminariesLet M be a )2( n dimensional oriented Riemannian manifold. The Lorentz force of a magnetic

    field F on M is defined to be a skew symetric operator given by

    (2) ),()),(( YXFYXg for all ).(, MYX

    The magnetic trajectories of F are curves on M which satisfy theLorentz equation

    (3) ).(

    The mixed productof the vector fields )(,, MZYX is defined by

    (4) ).,,(),( ZYXdvZYXg g

    LetV

    be a Killing vector field onM

    and gVV dvF

    be the corresponding Killing magneticfield, where is denoted the inner product. Then theLorentz forceof the

    VF is

    (5) .)( XVX

    Consequently, theLorentz force equationmay be written as

    (6) . V

    A unit speed curve is a magnetic trajectoryof a magnetic field V if and only if V can be

    written along as

    (7) )()()()( sBssTsV where the function )(s associated with each magnetic curve will be called its quasislope

    measured with respect to the magnetic field V (see for details [3]).

    Proposition 2.1. [3]Let 3: MI R be a curve in a 3D oriented Riemannian Manifold

    ),( 3 gM and V be a vector field along the curve . One can take a variation of in the

    direction of V, say, a map

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    3),(: MI which satisfies ),()0,( ss ).(),( sVtss

    In this setting, we have the

    following functions,

    1. the speed function ,),(),( tstsvs

    2. the curvature function ),( ts of ),(st

    3. the torsion function ),( ts

    of ).(s

    t

    The variations of those functions at ,0t

    ),,),((),(

    ),(),),((?

    1),()()10(

    ),,),((),(2),(),()()9(

    ,),(),()()8(

    2

    0

    2

    0

    0

    BNTVRgTVg

    BVBTTVRVgtst

    V

    NTTVRgTVgNVgtst

    V

    vTVgtst

    vvV

    T

    T

    s

    T

    t

    TT

    t

    T

    t

    where R is curvature tensor of .3

    M

    Proposition 2.2. [3]Let )(sV be the restriction to )(s of a Killing vector field ,say, V of3

    M ; then.0)()()( VVvV

    Proposition 2.3.[12] Let be a unit speed space curve with 0)( s . Then is a slant helix

    if and only if

    )()(

    2/3

    22

    2

    ss

    is a constant function.

    3.New Kind of Magnetic Curves in 3D OrientedRiemannian Manifolds

    3.1. N-Magnetic Curves. In this section, we defined a new kind of magnetic curve called N-

    magnetic curve in oriented 3D Manifolds, .,3 gM Moreover, we obtain some characterizationsand examples of the curve.

    Definition 3.1.Let 3: MI R be a curve in D3 oriented Riemannian space ),( 3 gM

    and F be a magnetic field on .M We call the curve is a N-magnetic curve if the normal

    vector field of the curve satisfy the Lorentz force equation, that is,

    (12) .)( NVNN

    Proposition3.1.Let be a unit speed N-magnetic curve in D3 oriented Riemannian space

    ),( 3 gM with the Frenet apparatus ,,,, BNT . Then we have the Serret-Frenet formulae:

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    (12) .

    00

    0

    00

    B

    N

    T

    B

    N

    T

    T

    T

    T

    And then the Lorentz force in the Frenet frame written as

    (13) .

    0

    0

    0

    )(

    )(

    )(

    1

    1

    B

    N

    T

    B

    N

    T

    where1 is a certain function.

    Proof. Let be a unit speed N-magnetic curve in D3 oriented Riemannian space ),( 3 gM

    with the Frenet apparatus ,,,, BNT . Since },,,{)( BNTspanT we have

    BNTT )(

    and thus

    1)),((

    )(),()),(()),((

    0)),((

    BTg

    BTgTNgTNgNTg

    TTg

    Therefore we can write

    BNT 1)(

    Similarly, we can easily calculate that

    .)(

    )(

    1 NTB

    BTN

    These complete the proof.

    Proposition 3.2. Let be a unit speed N-magnetic trajectory of a magnetic field V if and

    only if V can be written along the curve as

    (14) .1

    BNTV

    Proof. Let be a unit speed N-magnetic trajectory of a magnetic field .V Using the Proposition

    3.1 and Eq. (5), we can easily see that

    .1 BNTV This completes the proof.

    Theorem 3.3.(Main result) Let V be a Killing vector field on a simply connected space form

    .),(3 gCM Then, the unit speed N-magnetic trajectories of VgCM ,),(3 are curves withcurvature and torsion satisfying

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    (15)

    11

    2

    11 ,01

    C

    where C is curvature of the Riemannian space 3M and1 satisfy

    .1

    BNTV

    Proof. Let Vbe a magnetic field in a Riemannian 3D manifold. Then V satisfy Eq. (14).

    Differentiating Eq. (14) with respect to s , we have

    (16) ,)'()( 111 BNTVT

    By differentiating of Eq. (24) with respect to s and using the Serret-Frenet formulas, we get

    (17) .)'())'(( 111112

    BNTVT

    Proposition 2.2 implies that ,0)( vV so from Eq. (a) and Eq. (24), we get

    (18) 01 then, if Eq. (24) and Eq. (25) are considered with 0)( V in Proposition 2.2, we obtain

    .0),),(()'( 11

    NTTVRg

    In particular, if 3M has constant curvature ,C then 0),(),),(( NVCgNTTVRg and so,

    (19) .0)'( 11

    Similarly, if we combine Eq. (24) and Eq. (25) wih 0)( V in Proposition 2.2, we have

    .0),),((),),(()'(' 12

    11 BTTVRBNTVRg

    Hence, if 3M has constant curvature ,C then CBVCgBTTVRg ),(),),(( and

    0),),(( BNTVRg give us

    (20) .0)'(' 12

    11

    C

    Finally, considering Eq. (26) and Eq. (27) with Eq. (28), this implies

    .,01

    11

    2

    11

    C

    This completes the proof.

    Corollary 3.4. Considering1 is a non-zero constant function, we can easily see that the N-

    magnetic curve is a curve in the Euclidean 3 space.

    Proof. Using the similar method of the above proof, it is obvious.

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    Corollary 3.5. Let be a unit speed N-magnetic curve in D3 oriented Riemannian manifold

    gCM ),(3 . If the function1 non-zero constant, then the curve is a slant helix. Moreover,

    the axis of the slant helix is the the vector field .V

    Proof. We assume that is a N-magnetic curve in Euclidean 3-space with non-zero constant

    function 1 , then from Eq. (15), we get

    (21)1

    '

    which implies that

    constant22 Also, Eq. (17) carry out the following equation with the different point of view, we get

    constant' 221

    or

    .122

    2

    where1 and

    22 are constant functions. By the Proposition 2.3 we obtain that is a

    slant helix in Euclidean 3-space. These complete the proof.

    Example 3.1.We consider a N-magnetic curve in Euclidean 3 space is defined by

    15

    )3cos(4),

    64

    2sin

    64

    9sin(

    5

    8),

    64

    2cos

    64

    9cos(

    5

    8)(

    sssss

    s

    The picture of the N-magnetic curve is rendered in Figure 1. The curve has the following

    curvature and torsion given by

    ss

    ss

    3sin4)(

    3cos4)(

    and using the corollary 3.5 we can easily see that .11 So is a N-magnetic curve. The

    picture of the curve is rendered in Figure 1.

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    )1(curvemagnetic-N1.Figure 1

    Corollary 3.6.Let be a N-magnetic curve in Euclidean 3-space with1 is zero, then

    is a circular helix. Moreover, the axis of the circular helix is the vector field .V

    Proof.It is obvious from Eq. (15).

    Example 3.2.We consider a N-magnetic curve in Euclidean 3 space is defined by

    .2

    ,2

    sin,2

    cos)(

    ssss

    The curve has the following curvature and torsion given by

    2

    1)(

    21)(

    s

    s

    and using the corollary 3.5 we can easily see that .01 So is a N-magnetic curve.The

    picture of the curve is rendered in Figure 1.

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    )0(curvemagnetic-N2.Figure 1

    3.2. B-Magnetic Curves. In this section, we defined a new kind of magnetic curve called

    B-magnetic curve in oriented 3D Manifolds, .,3 gM Moreover, we obtain somecharacterizations and examples of the curve.

    Definition 3.2.Let 3: MI R be a curve in D3 oriented Riemannian space ),( 3 gM

    and F be a magnetic field on .M We call the curve is a B-magnetic curve if the binormal

    vector field of the curve satisfy the Lorentz force equation, that is,

    (22) .)( BVBB

    Proposition 3.7.Let be a unit speed B-magnetic curve in D3 oriented Riemannian space

    ),( 3 gM with the Frenet apparatus ,,,, BNT . Then we have the Serret-Frenet formulae:

    (23) .

    00

    0

    00

    B

    N

    T

    B

    N

    T

    T

    T

    T

    And then the Lorentz force in the Frenet frame written as

    (24) .

    00

    0

    00

    )(

    )(

    )(

    2

    2

    B

    N

    T

    B

    N

    T

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    where2

    is a certain function.

    Proof. Let be a unit speed N-magnetic curve in D3 oriented Riemannian space ),( 3 gM

    with the Frenet apparatus ,,,, BNT . Since },,,{)( BNTspanT we have

    BNTT )( and thus,

    .0),(),()),(()),((

    ,)),((

    ,0)),((

    2

    TNgTBgTBgBTg

    NTg

    TTg

    Therefore we can write

    NT 2)(

    Similarly, we can easily calculate that

    .)(

    )( 2

    NB

    BTN

    These complete the proof.

    Proposition 3.8.Let be a unit speed B-magnetic trajectory of a magnetic field V if and only

    if V can be written along the curve as

    (25) .2BTV

    Proof. Let be a unit speed B-magnetic trajectory of a magnetic field .V Using the

    Proposition 3.7 and Eq. (5), we can easily see that

    .2BTV

    This completes the proof.

    Theorem 3.9.(main resul t) Let V be a Killing vector field on a simply connected space form

    .),(3 gCM Then, the unit speed B-magnetic trajectories of VgCM ,),(3 are curves withcurvature and torsion satisfying

    (26) .,0'''2)( 22 constCa

    where C is curvature of the Riemannian space 3M and2

    satisfy

    (27) .2BTV

    or

    .)2

    ( BaTV

    Proof. Let V be a magnetic field in a Riemannian 3D manifold. Then V satisfy Eq. (21).

    Differentiating Eq. (21), we have

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    (28) BNTVT

    22)(

    by differentiating of Eq. (29) with respect to s , we get

    (29) BNTVT

    )()2'()( 222

    22

    2

    2

    2

    Proposition Pro 4 implies that ,0)( vV so from Eq. (a) and Eq. (29), we get

    (30) 0

    then, if Eq. (29) and Eq. (30) are considered with 0)( V in Proposition 2.2, we obtain

    .0),),((2' 2 NTTVRg

    In particular, if 3M has constant curvature ,C then 0),(),),(( NVCgNTTVRg and so

    (31) .02'2

    Similarly, if we combine Eq. (29) and Eq. (30) wih 0)(

    V in Proposition 2.2, we have

    .0),),((),),((222

    2

    2

    2 BTTVRgBTTVRg

    Hence, if 3M has constant curvature ,C then CBVCgBTTVRg ),(),),(( and

    0),),(( BNTVRg gives

    (32) .0222

    2

    2

    2

    C

    Finally, considering Eq. (31)and Eq. (32) with Eq. (33), this implies

    (33) .0'''2)( 22 Ca

    Using Eq. (34), we obtain following second-order nonlinear ordinary differential equation

    constants.and);()(,0)(2))(()()()(22 CstysCyasysytysy

    Now, we consider the above differential equation in Euclidean 3 space ,E3 in 3 sphere3S

    and in hyperbolic 3 space ,H3 respectively.

    In D3 Euclidean space :E3

    3,0),()(,0)1)((9)()()(2

    Cssysysysysy

    plots of sample indilidual solutions of this equation as:

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    sample solution family:

    space.Euclidean3Dincurvemagnetic-Bof)(curvaturetheofesTrajectori. t3Figure

    In D3 sphere :S3

    3,1),()(,0)(2)1)((9)()()( 2 Cssysysysysysy

    plots of sample indilidual solutions of this equation as:

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    sample solution family:

    sphere.3Dincurvemagnetic-Bof)(curvaturetheofesTrajectori. t4Figure

    In D3 hyperbolic space :H3

    3,1),?()(,0)(2)1)((9)()()( 2 Cssysysysysysy

    plots of sample indilidual solutions of this equation as:

    sample solution family:

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    space.Hyperbolic3Dincurvemagnetic-Bof)(curvaturetheofesTrajectori. t5Figure

    Corollary 3.10. Let be a B-magnetic curve in a Euclidean 3-space with2

    constant,

    then is a general helix. Moreover, the axis of the helix is the vector field .V

    Proof.

    It is obvious from Eq. (23) and Eq. (21).

    Corollary 3.11.The tangent indicatrix of the N-magnetic curve is a magnetic curve or B-magneticcurve in Euclidean 3-space.

    Proof. In [14], we know that the tangent indicatrix of the slant helix is a general helix . So the proofis obvious from Corollary 3.5 and corollary 3.10.

    Corollary 3.12.The binormal indicatrix of the N-magnetic curve is a circle.

    Proof.In [14], we know that the binormal indicatrix of the slant helix is a circle . So the proof is

    obvious from Corollary 3.5 and corollary 3.10.

    Corollary 3.13.The normal indicatrix of the N-magnetic curve is a magnetic curve or B-magneticcurve in Euclidean 3-space.

    Proof.In [14], we know that the normal indicatrix of the slant helix is a general helix . So the proofis obvious from Corollary 3.5 and corollary 3.10.

    Example 3.3.We consider a N-magnetic curve in Euclidean 3 space is defined by

    .15

    )3cos(4),

    64

    2sin

    64

    9sin(

    5

    8),

    64

    2cos

    64

    9cos(

    5

    8)(

    sssss

    s

    and the tangent indicatrix (see for details in [14]) of the curve is a general helix calculatedas

    ).3sin5

    4,9cos

    320

    722cos

    5

    4),9sin

    320

    722sin

    5

    4(

    )(

    1)( sssss

    s

    s

    The picture of the N-magnetic curve and its tangent indicatrix is rendered in Figure

    6.

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    ly.respective,indicatrixtangentitsandcurvemagnetic-N6.Figure

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