9-ProjCobMadParte5.pdf

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    g) Dimensionamento compresso: (NBR 7190 requisito 7.3.2)

    ndice de esbeltez (0 e Lim):2kgf/cm105000E =

    29,87

    5138

    105000

    38

    E0

    2

    C

    2

    0 =

    =

    =

    56,1381240 LimLim =

    2C kgf/cm51=

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    Banzo Superior (Barra 57):

    N = 9816,27 kgf Lfl = 136,0 cm b = 7,5 cm (adotado) 2 perfis

    cm17,2i12

    5,7

    12

    bi mnmn ===

    )OK(82,6217,2

    136iL Limmn

    fl

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    =

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    Banzo Inferior (Barra 24):

    N = 1021,34 kgf Lfl = 133,3 cm b = 7,5 cm (adotado) 2 perfis

    cm17,2i12

    5,7

    12

    bi mnmn ===

    )OK(57,6117,2 3,133iLLim

    mnfl

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    =

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    Montante (Barra 23): N = 3676,86 kgf Lfl = 20,0 cm b = 3,8 cm (adotado) 1 perfil

    cm10,1i12

    8,3

    12

    bi mnmn ===

    )OK(23,1810,1 0,20iLLim

    mn

    fl

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    =

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    Montante (Barra 45): N = 1371,45 kgf Lfl = 46,7 cm b = 3,8 cm (adotado) 1 perfil

    cm10,1i12

    8,3

    12

    bi mnmn ===

    )OK(57,4210,1

    7,46

    i

    LLim

    mnfl

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    =

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    Montante (Barra 67): N = 526,10 kgf Lfl = 73,3 cm b = 3,8 cm (adotado) 1 perfil

    cm10,1i12

    8,3

    12

    bi mnmn ===

    )OK(82,6610,1

    3,73

    i

    LLim

    mnfl

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    =

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    Diagonal (Barra 78): N = 28,33 kgf Lfl = 152,2 cm b = 5 cm (adotado) 2 perfis

    cm44,1i12

    5

    12

    bi mnmn ===

    )OK(45,10544,1

    2,152

    i

    LLim

    mnfl

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    20

    Cfl0

    3

    2

    =>

    2fl

    2

    fl kgf/cm30,2329,87

    512

    =

    =

    ,

    2mn

    flmn cm61,0A

    30,232

    33,28

    2

    NA

    =

    =

    Concluso: 2 perfis (2 x 2) A = 25,00 cm2

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    Diagonal (Barra 910): N = 734,70 kgf Lfl = 166,7 cm b = 5 cm (adotado) 2 perfis

    cm44,1i12

    5

    12

    bi mnmn ===

    )OK(49,11544,1

    7,166

    i

    LLim

    mnfl

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    20

    Cfl0

    3

    2

    =>

    2fl

    2

    fl kgf/cm42,1929,87

    512

    =

    =

    ,

    2mn

    flmn cm91,18A

    42,192

    70,734

    2

    NA

    =

    =

    Concluso: 2 perfis (2 x 2) A = 25,00 cm2

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    Diagonal (Barra 1112): N = 1182,08 kgf Lfl = 183,9 cm b = 5 cm (adotado) 2 perfis

    cm44,1i12

    5

    12

    bi mnmn ===

    )OK(41,12744,1

    9,183

    i

    LLim

    mnfl

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    20

    Cfl0

    3

    2

    =>

    2fl

    2

    fl kgf/cm96,1529,87

    512

    =

    =

    ,

    2mn

    flmn cm03,37A

    96,152

    08,1182

    2

    NA

    =

    =

    Concluso: 2 perfis (2 x 3) A = 37,50 cm2

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    Diagonal (Barra 1314): N = 1533,99 kgf Lfl = 203,2 cm b = 7,5 cm (adotado) 2 perfis

    cm17,2i12

    5,7

    12

    bi mnmn ===

    )OK(85,9317,2

    2,203

    i

    LLim

    mnfl

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    20

    Cfl0

    3

    2

    =>

    2fl

    2

    fl kgf/cm41,2929,87

    512

    =

    =

    ,

    2mn

    flmn cm08,26A

    41,292

    09,1533

    2

    NA

    =

    =

    Concluso: 2 perfis (3 x 3) A = 56,25 cm2

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    h) Dimensionamento trao: (NBR 7190 requisito 7.3.1)

    2TfT kgf/cm87==

    N = 1041,57 kgf 2 perfis

    2mn

    Tmn cm99,5A

    872

    57,1041

    2

    NA

    =

    =

    Concluso: 2 perfis (3 x 7) A = 131,25 cm2

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    Banzo Inferior (Barra 68): N = 9625,64 kgf 2 perfis

    mnTmn cm32,55A872

    ,

    2A ==

    Concluso: 2 perfis (3 x 3) A = 56,25 cm2

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    Montante (Barra 89): N = 13,65 kgf 1 perfil

    mnTmn cm16,0A87

    ,

    A ==

    Concluso: 1 perfil (1 x 1) A = 9,50 cm2

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    Montante (Barra 1011): N = 440,82 kgf 1 perfil

    mnTmn cm07,5A87

    ,

    A ==

    Concluso: 1 perfil (1 x 1) A = 9,50 cm2

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    Montante (Barra 1213): N = 814,14 kgf 1 perfil

    mnTmn cm36,9A87

    ,

    A ==

    Concluso: 1 perfil (1 x 1) A = 9,50 cm2

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    Montante (Barra 1415):

    N = 2315,08 kgf 1 perfil

    mnTmn cm61,26A87

    ,

    A ==

    Concluso: 1 perfil (1 x 3) A = 28,50 cm2

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    Diagonal (Barra 56):

    N = 1592,55 kgf 2 perfis

    mnTmn cm15,9A872

    ,

    2A

    =

    =

    Concluso: 2 perfis (1 x 1) A = 9,50 cm2

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    i) Resumo das dimenses:

    Observao: NBR 7190 Item 10.2.1

    Amn = 50 cm2 ; emn = 5 cm

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    2

    Observao: NBR 7190 Item 10.2.1

    Amn = 18 cm2 ; emn = 2,5 cm

    2

    2

    2