9-9 Notes

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Section 9-9 Advanced Factoring Techniques

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Advanced Factoring Techniques

Transcript of 9-9 Notes

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Section 9-9Advanced Factoring Techniques

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Warm-upFactor.

1. 2x3 + 3x2 + x 2. 2x3 + 2x2 + x2 + x

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Warm-upFactor.

1. 2x3 + 3x2 + x 2. 2x3 + 2x2 + x2 + x

x(2x2 + 3x + 1)

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Warm-upFactor.

1. 2x3 + 3x2 + x 2. 2x3 + 2x2 + x2 + x

x(2x2 + 3x + 1)

x(2x + 1)( x + 1)

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Warm-upFactor.

1. 2x3 + 3x2 + x 2. 2x3 + 2x2 + x2 + x

x(2x2 + 3x + 1)

x(2x + 1)( x + 1)

(2x3 + 2x2 ) + ( x2 + x )

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Warm-upFactor.

1. 2x3 + 3x2 + x 2. 2x3 + 2x2 + x2 + x

x(2x2 + 3x + 1)

x(2x + 1)( x + 1)

(2x3 + 2x2 ) + ( x2 + x )

2x2 ( x + 1) + x( x + 1)

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Warm-upFactor.

1. 2x3 + 3x2 + x 2. 2x3 + 2x2 + x2 + x

x(2x2 + 3x + 1)

x(2x + 1)( x + 1)

(2x3 + 2x2 ) + ( x2 + x )

2x2 ( x + 1) + x( x + 1)

(2x2 + x )( x + 1)

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Warm-upFactor.

1. 2x3 + 3x2 + x 2. 2x3 + 2x2 + x2 + x

x(2x2 + 3x + 1)

x(2x + 1)( x + 1)

(2x3 + 2x2 ) + ( x2 + x )

2x2 ( x + 1) + x( x + 1)

(2x2 + x )( x + 1)

x(2x + 1)( x + 1)

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Factoring by Grouping

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Factoring by Grouping

Grouping terms with common factors, then factoring out the GCF and applying distribution

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Factoring by Grouping

Grouping terms with common factors, then factoring out the GCF and applying distribution

...you know, like we do with factoring quadratics

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Example 1Factor

6a2b + 2ac + 3ab2 + bc

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Example 1Factor

6a2b + 2ac + 3ab2 + bc

(6a2b + 2ac) + (3ab2 + bc)

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Example 1Factor

6a2b + 2ac + 3ab2 + bc

(6a2b + 2ac) + (3ab2 + bc)

2a(3ab + c) + b(3ab + c)

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Example 1Factor

6a2b + 2ac + 3ab2 + bc

(6a2b + 2ac) + (3ab2 + bc)

2a(3ab + c) + b(3ab + c)

(3ab + c)(2a + b)

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Example 2Factor

4x2 + 4x − 15

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Example 2Factor

4x2 + 4x − 15

4x2 + 10x − 6x − 15

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Example 2Factor

4x2 + 4x − 15

(4x2 + 10x ) + (−6x − 15) 4x2 + 10x − 6x − 15

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Example 2Factor

4x2 + 4x − 15

2x(2x + 5) − 3(2x − 5) (4x2 + 10x ) + (−6x − 15)

4x2 + 10x − 6x − 15

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Example 2Factor

4x2 + 4x − 15

2x(2x + 5) − 3(2x − 5) (4x2 + 10x ) + (−6x − 15)

4x2 + 10x − 6x − 15

(2x − 3)(2x + 5)

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Factoring by Grouping and Graphing

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Factoring by Grouping and Graphing

Factoring into linear factors and graphing to see possible solutions

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Example 3Describe the set of ordered pairs (x, y) satisfying

x3 + 3x2 − yx − 3 y = 0

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Example 3Describe the set of ordered pairs (x, y) satisfying

x3 + 3x2 − yx − 3 y = 0

( x3 + 3x2 ) + (− yx − 3 y) = 0

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Example 3Describe the set of ordered pairs (x, y) satisfying

x3 + 3x2 − yx − 3 y = 0

( x3 + 3x2 ) + (− yx − 3 y) = 0

x2 ( x + 3) − y( x + 3) = 0

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Example 3Describe the set of ordered pairs (x, y) satisfying

x3 + 3x2 − yx − 3 y = 0

( x3 + 3x2 ) + (− yx − 3 y) = 0

x2 ( x + 3) − y( x + 3) = 0

( x2 − y)( x + 3) = 0

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Example 3Describe the set of ordered pairs (x, y) satisfying

x3 + 3x2 − yx − 3 y = 0

( x3 + 3x2 ) + (− yx − 3 y) = 0

x2 ( x + 3) − y( x + 3) = 0

( x2 − y)( x + 3) = 0

x2 − y = 0

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Example 3Describe the set of ordered pairs (x, y) satisfying

x3 + 3x2 − yx − 3 y = 0

( x3 + 3x2 ) + (− yx − 3 y) = 0

x2 ( x + 3) − y( x + 3) = 0

( x2 − y)( x + 3) = 0

x2 − y = 0 x + 3 = 0

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Example 3Describe the set of ordered pairs (x, y) satisfying

x3 + 3x2 − yx − 3 y = 0

( x3 + 3x2 ) + (− yx − 3 y) = 0

x2 ( x + 3) − y( x + 3) = 0

( x2 − y)( x + 3) = 0

x2 − y = 0 x + 3 = 0

y = x2

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Example 3Describe the set of ordered pairs (x, y) satisfying

x3 + 3x2 − yx − 3 y = 0

( x3 + 3x2 ) + (− yx − 3 y) = 0

x2 ( x + 3) − y( x + 3) = 0

( x2 − y)( x + 3) = 0

x2 − y = 0 x + 3 = 0

y = x2 x = 3

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Example 3Describe the set of ordered pairs (x, y) satisfying

x3 + 3x2 − yx − 3 y = 0

( x3 + 3x2 ) + (− yx − 3 y) = 0

x2 ( x + 3) − y( x + 3) = 0

( x2 − y)( x + 3) = 0

x2 − y = 0 x + 3 = 0

y = x2 x = 3

The union of the sets of ordered pairs satisfying y = x2 and x = 3.

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Homework

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Homework

p. 610 #1-17