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HASHMITE UNIVERSITY Building Materials Laboratory 

Lab Number: 5Experiment name: Tensile strength of 

steel

Name: Deiaa al-majalee

ID Number: 433150Date: 15/12/2005

Section: 1

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Introduction:

 The steel is very famous building material because it can carry tension

stress in structure which cant concert carry it, although this materialvery good in tension and compression.Ductility of steel is another advantage which is can expansion andshrinkage in suitable state compare to its stress (tension, compressionstrength) the test was obtained by using UTM which is a strong andmodifying machine. 

 Abstract:

 This experiment to determine the tension strength of steel rod specimenusing UTM (Universal tensile machine) which give us stress straindiagram which can determine elastic and plastic strip and ultimate andyielding stress on it as the result the steel is good in the tension andductility is good.

• Measure tension strength of steel rod specimen.

• Knowing to the stress strain diagram and determine the following

parameter: ultimate stress plastic and elastic limit and yielding stress

•

Determine the strain of specimen.

Methodology:

• Specimen : L=360 mm d=25.5mm W=842.2g

 

Procedure test:

1. Determine the length of specimen.2. Determine the diameter of specimen.3. Weight the specimen using electronic balance.4. Put the specimen in the correct place in machine.5.Measure the length specimen between the supports.6. Start the test from computer which connects to the machine and

waiting until the failure occurs in the specimen.7. Take the stress strain diagram from the computer and other data.

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III

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Load Vs Deflection

048

1216202428323640

44485256606468

727680848892

0 3 6 9 12 15 18 21 24 27 30 33 36 39 42 45 48 51 54 57 60 63 66 69

Deflection (mm)

 

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stress strain diagram

0

20

40

60

80

100

120

140

160

180

0 0.02 0.04 0.06 0.08 0.1 0.12 0.14 0.16 0.18 0.2

strain

ultimate stress = 169.5 Nmm2

plastic

elastic zone

E=∆σ/∆Є

yeil d stress=90 N/mm2

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Sample of calculation:

•Strain = ∆L/L

Final length = 360mm + 64 mm = 424mm (elongated)For the second point= 0.34mm/360mm=0.000972.

•Stress = load/ area

Area initial = (22/7*.25*25.52) =5.11 mm2

Area final =Stress for the second point= 4000N/5.11 mm2= 7.83 N/mm2.

• From graph the Ultimate stress = 169.5 N/mm2.

• From graph Yield stress = 90 N/mm2.

• The modulus of elasticity = E=∆σ/∆Є E= (23.49 – 7.289 )/(0.002778-0.000972)= 8970.653 N/mm2

•

Ductility = (initial diameter – final diameter) /initial diameter= (360-464)/360*100%= 17.8%

Discussion and conclusion:Concrete is very weak in tension so we must use the steel to improvethe properties of concrete in tension strength.Steel improve the ductility of concrete the so when the concreteelongated the steel resist the crakes.Every concrete beam or slap expectant tension force we must add steel

bar in this concrete other wise the concrete failure.

VI