6.3 Factoring Trinomials II Ax 2 + bx + c. Factoring Trinomials Review X 2 + 6x + 5 X 2 + 6x + 5 (x...
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Transcript of 6.3 Factoring Trinomials II Ax 2 + bx + c. Factoring Trinomials Review X 2 + 6x + 5 X 2 + 6x + 5 (x...
6.3 Factoring 6.3 Factoring Trinomials IITrinomials II
AxAx22 + bx + c + bx + c
Factoring Trinomials Factoring Trinomials ReviewReview
XX22 + 6x + 5 + 6x + 5 (x )(x )(x )(x )
Find factors of 5 that add to 6: Find factors of 5 that add to 6:
1*6 = 61*6 = 6 1+6 = 71+6 = 7
2*3 = 6 2*3 = 6 2+3 = 52+3 = 5 (x + 2)(x + 3)(x + 2)(x + 3)
Factoring Trinomials Factoring Trinomials where a ≠ 1 where a ≠ 1
Follow these steps:Follow these steps:
1. Find two numbers that multiply to ac 1. Find two numbers that multiply to ac and add to b for axand add to b for ax22 + bx + c + bx + c
2. Replace bx with the sum of the 2 2. Replace bx with the sum of the 2 factors found in step 1. factors found in step 1.
ie: axie: ax22 + bx + c becomes ax + bx + c becomes ax22 + mx + nx + c, + mx + nx + c, where m and n are the factors found in where m and n are the factors found in step 1.step 1.
3. Use grouping to factor this expression 3. Use grouping to factor this expression into 2 binomialsinto 2 binomials
2x2x2 2 + 5x + 2 + 5x + 2
Step 1: ac = 2*2 = 4Step 1: ac = 2*2 = 4 1*4 = 41*4 = 4 1+4 = 51+4 = 5 2*2 = 42*2 = 4 2+2 = 42+2 = 4 m = 1 and n = 4m = 1 and n = 4
Step 2: Rewrite our trinomial by expanding Step 2: Rewrite our trinomial by expanding bxbx
2x2x22 + 1x + 4x + 2 + 1x + 4x + 2Step 3: Group and FactorStep 3: Group and Factor
(2x(2x2 2 + 1x) + (4x + 2)+ 1x) + (4x + 2) x(2x + 1) + 2( 2x + 1)x(2x + 1) + 2( 2x + 1) (2x + 1) (x + 2)(2x + 1) (x + 2)
2x2x2 2 + 5x + 2 + 5x + 2
Questions for thought: Questions for thought:
1.1. Does it matter which order the new Does it matter which order the new factors are entered into the polynomial?factors are entered into the polynomial?
2.2. Do the parenthesis still need to be the Do the parenthesis still need to be the same?same?
3.3. Will signs continue to matter when Will signs continue to matter when finding m and n?finding m and n?
4.4. Does it matter how we group the terms Does it matter how we group the terms for factoring?for factoring?
3z3z22 + z – 2 + z – 2
Step 1: ac = 3*-2 = -6Step 1: ac = 3*-2 = -6 -1*6 = -6-1*6 = -6 -1+6 = 5-1+6 = 5 1* -6 = -6 1* -6 = -6 1+-6 1+-6
= -5= -5 -2*3 = -6-2*3 = -6 -2+3 = 1-2+3 = 1 2* -3 = -6 2* -3 = -6 2+-3 2+-3 = -1= -1
m = -2 and n = 3m = -2 and n = 3Step 2: Rewrite our trinomial by expanding bxStep 2: Rewrite our trinomial by expanding bx
3z3z22 + 3z – 2z – 2 + 3z – 2z – 2 Step 3: Group and FactorStep 3: Group and Factor
(3z(3z2 2 + 3z) + (-2z - 2)+ 3z) + (-2z - 2) 3z(z + 1) - 2( z + 1)3z(z + 1) - 2( z + 1) (z + 1) (3z - 2)(z + 1) (3z - 2)
3z3z22 + z – 2 + z – 2
Step 1: ac = 3*2 = 6Step 1: ac = 3*2 = 6 -1*6 = -6-1*6 = -6 -1+7 = 6-1+7 = 6 1* -6 = -6 1* -6 = -6 1+-7 1+-7
= -6= -6 -2*3 = -6-2*3 = -6 -2+3 = 1-2+3 = 1 2* -3 = -6 2* -3 = -6 2+-3 2+-3 = -1= -1
m = -2 and n = 3m = -2 and n = 3Step 2: Rewrite our trinomial by expanding bxStep 2: Rewrite our trinomial by expanding bx
3z3z22 + 3z – 2z+ 3z – 2z – 2 – 2
Notice that I changed the order of m and n Notice that I changed the order of m and n between step 1 and step 2. Why do you between step 1 and step 2. Why do you think I did this? Do you have to change think I did this? Do you have to change the order to get the correct answer?the order to get the correct answer?
3z3z22 + z – 2 + z – 2
What are the 3 steps for solving this What are the 3 steps for solving this quadratic equation?quadratic equation? Step 1: Multiply a*c. Find the factors Step 1: Multiply a*c. Find the factors
that multiply to that multiply to acac and add to and add to bb Step 2: Expand bx to equal mx + nxStep 2: Expand bx to equal mx + nx Step 3: Group and FactorStep 3: Group and Factor
4x4x33 – 22x – 22x22 + 30x + 30x
Step 0: Factor out the GCF: 2xStep 0: Factor out the GCF: 2x
2x(2x2x(2x22 – 11x + 15) – 11x + 15) Step 1: a*c = 30Step 1: a*c = 30
-1*-30 = 30-1*-30 = 30 -1+-30 = -31-1+-30 = -31
-2*-15 = 30-2*-15 = 30 -2+-15 = -17-2+-15 = -17
-3*-10-3*-10 = 30= 30 -3+-10 = -13-3+-10 = -13
-5*-6 = 30-5*-6 = 30 -5+-6 = -11-5+-6 = -11
4x4x33 – 22x – 22x22 + 30x + 30x
Step 0: Factor out the GCF: 2xStep 0: Factor out the GCF: 2x
2x(2x2x(2x22 – 11x + 15) – 11x + 15) Step 1: a*c = 30Step 1: a*c = 30
-1*-30 = 30-1*-30 = 30 -1+-30 = -31-1+-30 = -31
-2*-15 = 30-2*-15 = 30 -2+-15 = -17-2+-15 = -17
-3*-10-3*-10 = 30= 30 -3+-10 = -13-3+-10 = -13
-5*-6 = 30-5*-6 = 30 -5+-6 = -11-5+-6 = -11
4x4x33 – 22x – 22x22 + 30x + 30x
Step 2: Expand bx to equal mx + nxStep 2: Expand bx to equal mx + nx-11x = -5x + -6x-11x = -5x + -6x
2x(2x2x(2x22 – 5x – 6x + 15) – 5x – 6x + 15) Step 3: Group and FactorStep 3: Group and Factor
2x((2x2x((2x22 – 5x )(– 6x + 15)) – 5x )(– 6x + 15))
2x(x(2x – 5) -3(2x – 5)) 2x(x(2x – 5) -3(2x – 5))
2x(2x – 5) (x – 3) 2x(2x – 5) (x – 3)
4x4x33 – 22x – 22x22 + 30x + 30x
Step 2: Expand bx to equal mx + nxStep 2: Expand bx to equal mx + nx-11x = -5x + -6x-11x = -5x + -6x
2x(2x2x(2x22 – 5x – 6x + 15) – 5x – 6x + 15) Step 3: Group and FactorStep 3: Group and Factor
2x((2x2x((2x22 – 5x )(– 6x + 15)) – 5x )(– 6x + 15))
2x(x(2x – 5) -3(2x – 5)) 2x(x(2x – 5) -3(2x – 5))
Note: The Parenthesis are the SameNote: The Parenthesis are the Same
2x(2x – 5) (x – 3) 2x(2x – 5) (x – 3)
PracticePractice
1. 3x1. 3x22 + 5x + 2 + 5x + 2
2. 6x2. 6x22 + 7x – 3 + 7x – 3
3. 6 + 4y3. 6 + 4y22 – 11y – 11y
PracticePractice
1. 3x1. 3x22 + 5x + 2 + 5x + 2
(3x + 2)(x + 1)(3x + 2)(x + 1)
2. 6x2. 6x22 + 7x – 3 + 7x – 3
(3x – 1)(2x + 3)(3x – 1)(2x + 3)
3. 6 + 4y3. 6 + 4y22 – 11y – 11y
(4y – 3)(y – 2)(4y – 3)(y – 2)
ReviewReview
What is Step 0? When do you need What is Step 0? When do you need to include this step?to include this step?
When will your factors both be When will your factors both be negative?negative?
When will you have one negative and When will you have one negative and one positive factor?one positive factor?
How do you check your answers?How do you check your answers?
??? Questions ?????? Questions ???
6.4 Special Types 6.4 Special Types of Factoringof Factoring
1. Differnce of Squares1. Differnce of Squares
2. Perfect Square Trinomials2. Perfect Square Trinomials
(Sum and Difference of Cubes is not (Sum and Difference of Cubes is not included)included)
Difference of SquaresDifference of Squares
Think back to Chapter 5. What Think back to Chapter 5. What happened when we multiplied a sum happened when we multiplied a sum and difference?and difference?
(a – b)(a + b) = a(a – b)(a + b) = a22 – b – b22
So, the reverse is also true.So, the reverse is also true.
aa22 – b – b22 = (a – b)(a + b) = (a – b)(a + b)
xx22 – 25 – 25
Notice that we do not have a Notice that we do not have a bxbx term. term. This means that we only have the F This means that we only have the F and L in foil; therefore, none of the and L in foil; therefore, none of the procedures from 6.1, 6.2, or 6.3 will procedures from 6.1, 6.2, or 6.3 will work.work.
We need to use aWe need to use a22 – b – b22 = (a – b)(a + b) = (a – b)(a + b)
where a = x and b = 5where a = x and b = 5 XX22 – 25 = (x – 5)(x + 5) – 25 = (x – 5)(x + 5)
xx22 – 36 – 36
We need to use aWe need to use a22 – b – b22 = (a – b)(a + = (a – b)(a + b)b)
where a = x and b = 6where a = x and b = 6 XX22 – 36 = (x – 6)(x + 6) – 36 = (x – 6)(x + 6)
PracticePractice 4x4x22 – 9 – 9
100 – 16t100 – 16t2 2
49y49y22 – 64z – 64z22
PracticePractice 4x4x22 – 9 – 9
a = 2x, b = 3a = 2x, b = 3
(2x – 3) (2x + 3)(2x – 3) (2x + 3) 100 – 16t100 – 16t2 2
a = 10, b = 4ta = 10, b = 4t
(10 – 4t) (10 + 4t)(10 – 4t) (10 + 4t) 49y49y22 – 64z – 64z22
a = 7y, b = 8za = 7y, b = 8z
(7y – 8z) (7y + 8z)(7y – 8z) (7y + 8z)
Perfect Square Perfect Square TrinomialsTrinomials
Think back to Chapter 5. What Think back to Chapter 5. What happened when we squared a happened when we squared a binomial?binomial?
(a + b)(a + b)22 = a = a22 + 2ab + b + 2ab + b22
(a – b)(a – b)22 = a = a22 – 2ab + b – 2ab + b22
So, the reverse is also true.So, the reverse is also true.
aa22 + 2ab + b + 2ab + b22 = (a + b) = (a + b)22
aa22 – 2ab + b – 2ab + b22 = (a – b) = (a – b)22
xx22 + 10x + 25 + 10x + 25
This can be worked 2 different waysThis can be worked 2 different ways The first way is the simplest, but The first way is the simplest, but
depends on whether you recognize the depends on whether you recognize the equation as a perfect square trinomial.equation as a perfect square trinomial.
aa22 + 2ab + b + 2ab + b22 = (a + b) = (a + b)22
Where a = x and b = 5Where a = x and b = 5
xx22 + 10x + 25 = (x + 5) + 10x + 25 = (x + 5)22
xx22 + 10x + 25 + 10x + 25
This can be worked 2 different waysThis can be worked 2 different ways The second way is to use the method we The second way is to use the method we
learned in 6.2learned in 6.2
xx22 + 10x + 25 + 10x + 25
5*5 = 25 and 5+5 = 105*5 = 25 and 5+5 = 10
(x + 5) (x + 5) or (x + 5)(x + 5) (x + 5) or (x + 5)22
4x4x22 - 4x + 1 - 4x + 1
This can be worked 2 different waysThis can be worked 2 different ways The first way is the simplest, but The first way is the simplest, but
depends on whether you recognize the depends on whether you recognize the equation as a perfect square trinomial.equation as a perfect square trinomial.
aa22 + 2ab + b + 2ab + b22 = (a + b) = (a + b)22
Where a = 2x and b = 1Where a = 2x and b = 1
4x4x22 - 4x + 1 = (2x – 1) - 4x + 1 = (2x – 1)22
4x4x22 - 4x + 1 - 4x + 1
This time we need to use the 6.3 This time we need to use the 6.3 methodmethod
4*1 = 44*1 = 4
-2 * -2 = 4 and -2 + -2 = -4 -2 * -2 = 4 and -2 + -2 = -4
(4x(4x22 – 2x) ( – 2x + 1) – 2x) ( – 2x + 1)
2x(2x – 1) – 1(2x – 1) 2x(2x – 1) – 1(2x – 1)
(2x – 1) (2x – 1) or (2x – 1)(2x – 1) (2x – 1) or (2x – 1)22
PracticePractice xx22 – 4xy + 4y – 4xy + 4y22
9a9a22 – 60a + 100 – 60a + 100
25y25y22 + 20yz + 4z + 20yz + 4z22
PracticePractice xx22 – 4xy + 4y – 4xy + 4y22
a = x, b = 2ya = x, b = 2y
(x – 2y)(x – 2y)22
9a9a22 – 60a + 100 – 60a + 100
a = 3a, b = 10a = 3a, b = 10
(3a – 10) (3a – 10) 25y25y22 + 20yz + 4z + 20yz + 4z22
a = 5y, b = 2za = 5y, b = 2z
(5y + 2z)(5y + 2z)
ReviewReview
What methods can you use to factor What methods can you use to factor a Difference of Squares?a Difference of Squares?
What methods can you use to factor What methods can you use to factor a Perfect Square Trinomial?a Perfect Square Trinomial?
What clues should you look for to What clues should you look for to identify a Difference of Squares?identify a Difference of Squares?
What clues should you look for to What clues should you look for to identify a Perfect Square Trinomial?identify a Perfect Square Trinomial?
??? Questions ?????? Questions ???