6035 Functions Defined by the Definite Integral AB Calculus.

16
6035 Functions Defined by the Definite Integral AB Calculus

Transcript of 6035 Functions Defined by the Definite Integral AB Calculus.

Page 1: 6035 Functions Defined by the Definite Integral AB Calculus.

6035 Functions Defined by the Definite Integral

AB Calculus

Page 2: 6035 Functions Defined by the Definite Integral AB Calculus.

Accumulation Functions

Given

Then A (x) is the Accumulation function. The points on A(x) reflects the amount under the curve f (t).

2

bA x f t dt

Net Area: Net Distance Net Money:

BIG PICTURE:

Page 3: 6035 Functions Defined by the Definite Integral AB Calculus.

Functions Defined by the Definite Integral

f (t)

2( ) 1f t t

2

0

( ) ( 1)x

A x t dt Also can work with negative accumulation.

A (-1) =

A (-2) =

Page 4: 6035 Functions Defined by the Definite Integral AB Calculus.

Functions Defined by the Definite Integral

f (t)

2( ) 1f t t 2

0

( ) ( 1)x

A x t dt A (0) =

A (1) =

A (2) =

A(3) =

TI-89 Graph then F-5 Math #7

TI-83 2nd Calc #7

x

y

x

y

x

y

0

12

4

3

14

3

x

y

Page 5: 6035 Functions Defined by the Definite Integral AB Calculus.

Functions Defined by the Definite Integral

f (t)2( ) 1f t t 2

0

( ) ( 1)x

A x t dt Also can work with negative accumulation.

A (-1) =

A (-2) =

x

y

x

y

x

y

4

3

14

3

Page 6: 6035 Functions Defined by the Definite Integral AB Calculus.

Functions Defined by the Definite Integralf (t) A (x)

2( ) 1f t t

2

0

( ) ( 1)x

A x t dt

A (x) points indicate the quantity of accumulation under f (t).

x

y

Page 7: 6035 Functions Defined by the Definite Integral AB Calculus.

Verify: Write the equation A(x)

2

0

( ) ( 1)x

A x t dt

A (0) = , A (1) = , A (2) = ,

A(3) = , A (-1)= , A (-2) =

=

3

( ) 03

xA x x

=

Page 8: 6035 Functions Defined by the Definite Integral AB Calculus.

Writing the Equations: Initial Values = Particular Solutions

2

0

( ) ( 1)x

A x t dt

2

2

( ) ( 1)x

A x t dt

2

1

( ) ( 1)x

A x t dt

What do -2, 0, and 1 represent?

REM: The Antiderivative finds…

Page 9: 6035 Functions Defined by the Definite Integral AB Calculus.

Writing the Equations: Initial Values = Particular Solutions

Example:3

3

( 4 )x

t t dt

2

cos 2

x

t dt

20 (3 1)

x tdt

t

Page 10: 6035 Functions Defined by the Definite Integral AB Calculus.

Initial Value Problems : 1st Fundamental Theorem

Think: I have $200.00 and deposit $20.00 a week for 4 weeks.

My brother has $350.00 and deposits $20.00 a week for 4 weeks.

( ) ( ) ( )

( ) ( ) ( )

( ) ( ) ( )

b

a

b

a

b

a

f t dt F b F a

F b F a f t dt

F b F a f t dt

Words:

or

Page 11: 6035 Functions Defined by the Definite Integral AB Calculus.

Initial Value Problems (concept)

If A (0) = 4 , Find A (7)

b

0

A(x)= f(t)dtIf

7

0

7

0

7

0

A(7) - A(0) = f(t)dt

(7) A(0) + f(t)dt

(7) 4 + f(t)dt

A

A

7

0

f(t)dt

7

0

f(t)dt4 +

4

Page 12: 6035 Functions Defined by the Definite Integral AB Calculus.

Initial Value Problems

If A (5) = 6 , Find A (8)

82

5

A(x)= (t +1)dtIf

Page 13: 6035 Functions Defined by the Definite Integral AB Calculus.

Accumulation Functions

Suppose f (1) = 10. Find f (3)

Suppose f (0) = 0. Find f (1), f (2), f (3)

The graph the derivative, f / ,is given.

Page 14: 6035 Functions Defined by the Definite Integral AB Calculus.

Accumulation Functions

The graph of a function, f , is shown.

a. Evaluate

b. Determine the average value

of the function on the

interval [ 1 , 7 ].

c. If F( 1) = -2 find F ( 7).

7

1( )f x dx

d. Determine the answers to parts a, b and c if the graph is translated two units up.

Page 15: 6035 Functions Defined by the Definite Integral AB Calculus.

AP type

Page 16: 6035 Functions Defined by the Definite Integral AB Calculus.

Last Update:

• 01/30/10

• Get Text problems