6.002x CIRCUITS AND ELECTRONICS · 2013. 1. 15. · 3 Review v O =V S −i D R L ( )2 v I 1 2 K −...
Transcript of 6.002x CIRCUITS AND ELECTRONICS · 2013. 1. 15. · 3 Review v O =V S −i D R L ( )2 v I 1 2 K −...
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6.002x CIRCUITS AND ELECTRONICS
MOSFET SCS Model MOSFET Amplifier
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n Superposition with dependent sources. One approach: - leave all dependent sources in; - solve for one independent source at a time - [section 3.5.1 of the text]
+ –
+
– aʹ′v
bʹ′)(vfi =
n Dependent source in a circuit
Review
a b
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Review
LDSO RiVv −=
( )2I 1v2K
−
for vI ≥ 1V
= 0 otherwise + –
( )2ID 1v2Ki −=VCCS
Vs
RL
vO
vI
Next, quick review of amp. Reading: Chapter 7.3–7.7
iD
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The i-v relation for a current source
i
v
Hold the thought
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Key device Needed
+ –
VCCS
Vs
vO
vI
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Key device Needed
Let’s look at our old friend, the MOSFET …
B
C
VCCS
i = f(v)
+ –
VCCS
Vs
vO
vI
A
vD + –
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Our old friend, the MOSFET First, we sort of lied. The on-state behavior of the MOSFET is quite a bit more complex than either the ideal switch or the resistor model would have you believe.
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Let’s Look at the MOSFET Behavior Graphically
D
S
G
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Graphically Demo
SR MODEL
iDS
vDS
S MODEL
iDS
vDS
+ – +
– vGS
iDS vDS
D
SG
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Graphically Demo
vDS
iDS
+ – +
– vGS
iDS vDS
D
SG
TGS Vv ≥
TGS Vv <
TGS Vv ≥
S MODEL SR MODEL
TGS Vv <
iDS iDS
vDS vDS
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TGS Vv ≥
TGSDS Vvv −≥
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Graphically
TGS Vv ≥
TGS Vv <
TGS Vv ≥
1GSvSaturation region
Trio
de r
egio
n
S MODEL SR MODEL
TGS Vv <
TGS Vv <
2GSv
3GSv
. . .
TGSDS Vvv −=
Cutoff region
vDS
iDS iDS iDS
vDS vDS
+ – +
– vGS
iDS vDS
D
SG
Notice that MOSFET behaves like a current source
when TGSDS Vvv −≥
TGSDS Vvv −<
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MOSFET SCS Model When and the MOSFET is in its saturation region, and the switch current source (SCS) model of the MOSFET is more accurate than the S or SR model
TGSDS Vvv −≥ TGS Vv ≥
D
G
S
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When to use which model
S MODEL SR MODEL SCS MODEL
for fun! for digital designs for analog designs
When to use each model in 6.002?
TGS Vv ≥
TGS Vv <
TGS Vv ≥
Saturation region
Trio
de r
egio
n
TGS Vv <
TGS Vv <
. . .
TGSDS Vvv −=iDS iDS iDS
vDS vDS vDS
vGS3
vGS2
vGS1
TGS Vv ≥
TGSDS Vvv −≥
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TGSDS Vvv −≥TGSDS Vvv −<
use SCS model use SR model
Note: alternatively (in more advanced courses)
In More Advanced Courses…
or, use SU (Switch Unified) Model (Section 7.8 of A&L)
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Back to Amplifier
To ensure the MOSFET operates as a VCCS, we must operate it in its saturation region only. To do so, we promise to adhere to the
“saturation discipline”
A
VS
vO vI
vI vO AMP
( )212
−= ID vKi
VS
RL
vI
vO
iD
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MOSFET Amplifier
“Saturation discipline”
In other words, we will operate the amp circuit such that:
in saturation region
( )22 TIDS VvKi −=
VS
D
RL
G
S
vI
vO
TGSDS Vvv −≥
TGS Vv ≥
1GSvSaturation region
Trio
de r
egio
n
TGS Vv <
2GSv
3GSv
. . .
TGSDS Vvv −=
Cutoff region
vDS
iDS
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MOSFET Amplifier
“Saturation discipline”
In other words, we will operate the amp circuit such that
in saturation region
( )22 TIDS VvKi −=
VS
D
RL
G
S
vI
vO
TGSDS Vvv −≥
TGS Vv ≥
1GSvSaturation region
Trio
de r
egio
n
TGS Vv <
2GSv
3GSv
. . .
TGSDS Vvv −=
Cutoff region
vDS
iDS
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Let’s analyze the circuit
in saturation region
( )22 TIDS VvKi −=
VS
D
RL
G
S
vI
vO
First, replace the MOSFET with its SCS model
Two methods: 1. Analytical 2. Graphical
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Let’s analyze the circuit
1 Analytical method:
(vO = vDS in our example) Find
for TIO Vvv −≥
IGS vv =+
– + – S
A
( )22 TIDS VvKi −=
VS
D
vO
RL
G
vI
vO vs vI
vO vs vI
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: B From
2 Graphical method From A ( )2
2 TIDS VvKi −=: Saturation region
Trio
de
regi
on
TGS Vv <
. . .
TGSDS Vvv −=
iDS
vDS
vGS3
vGS2
iDS
vDS 0
2
2 ODS vKi =
LDSSO RiVv −=
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Constraints and must be met A B
A
2
2 ODS vKi ≤
iDS
vO VS
= vGS vI
: B
A ( ) ,2
2TIDS VvKi −=: 2
2 ODS vKi ≤for
vO vS vI Remember, superimpose “loadline due to rest of circuit (B)” over device relation (A)
2 Graphical method
L
O
L
SDS R
vRVi −=
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Constraints and must be met A B
L
S
RV
A
2
2 ODS vKi ≤
iDS
vO VS
= vGS vI
: B A ( ) ,
22
TIDS VvKi −=: 2
2 ODS vKi ≤for
vO vS vI 2 Graphical method
L
O
L
SDS R
vRVi −=
B
Then, given VI, we can find VO, IDS
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Large Signal Analysis of Amplifier (under “saturation discipline”)
vO versus vI 1
2 Valid input operating range and valid output operating range (to guarantee saturation region operation)
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Large Signal Analysis 1 vO versus vI
Demo
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A Curious Aside
( ) LTIS RVvKV 2
2−−
gets into triode region
TIO Vvv −=
Cutoff region
VS
vO
VT
vI
VS
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2 What are the valid operating ranges under the saturation discipline?
Large Signal Analysis
Our Constraints
Iv
iDS
vO
VS
D
RL
G
S
vI
vO
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2 What are the valid operating ranges under the saturation discipline?
Large Signal Analysis
TIO
TI
VvvVv
−≥
≥
2
2 ODS vKi ≤
Our Constraints
Z 2
2 ODS vKi ≤
L
S
RV
L
O
L
SDS R
vRVi −=
Iv( )2
2 TIDS VvKi −=
iDS
VS
vO vI=VT vO=VS and iDS=0
VS
D
RL
G
S
vI
vO
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2 What are the valid operating ranges under the saturation discipline?
Large Signal Analysis
2
2 ODS vKi ≤
L
S
RV
L
O
L
SDS R
vRVi −=
( )22 TIDS VvKi −=
iDS
VS
vO vI=VT vO=VS and iDS=0
Iv
L
SLO KR
VKRv 211 ++−=
TIO
TI
VvvVv
−≥
≥
2
2 ODS vKi ≤
Our Constraints
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Corresponding output range:
Valid input range:
2 Valid operating ranges under the saturation discipline?
Large Signal Analysis Summary 1 vO versus vI
We will look at another way of obtaining (2) shortly
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Another Way of Obtaining (2) Valid Op Range
V5
V1
Vs
vI
vO
VT
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TVV1 V2~
V1~
~ 5V VS
vO
vI
Another Way of Obtaining (2) Valid Op Range
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( )L
TISO RVvKVv
2
2−−=
TVV1 V2~
V1~
~ 5V VS
vO
Another Way of Obtaining (2) Valid Op Range
TIO Vvv −=
IO vv =
TIO Vvv −>
TIO Vvv −<
TIO Vvv −=