6 th Grade Math Homework Ch. 7-5 Page 346 #6-14 #28-36 (Spiral Review)

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6 th Grade Math Homework Ch. 7-5 Page 346 #6-14 & #28-36 (Spiral Review)

description

7-5 Triangles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day

Transcript of 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14 #28-36 (Spiral Review)

Page 1: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

6th Grade Math HomeworkCh. 7-5

Page 346#6-14 & #28-36

(Spiral Review)

Page 2: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Ch 7 Learning Goal: PLANE GEOMETRY• Learn to describe the figures by using the terms of geometry (7-1)• Learn to name, measure, classify, estimate and draw angles (7-2)• Learn to understand relationship of angles (7-3)• Learn to classify the different types of lines (7-4)• Learn to classify triangles and solve problems involving angle and side

measures of triangles (7-5)• Learn to identify, classify, and compare quadrilaterals (7-6)• Learn to identify regular and not regular polygons and to find the angle

measures of regular polygons (7-7)• Learn to recognize, describe, and extend geometric patterns (7-8)• Learn to identify congruent figures and to use congruence to solve

problems (7-9)• Learn to use translations, reflections, and rotations to transform geometric

shapes (7-10)• Learn to identify line symmetry (7-11)• Learn to identify tessellations and shapes that can tessellate (7-12)

Page 3: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

7-5 Triangles

Course 1

Warm UpWarm Up

Lesson PresentationLesson PresentationProblem of the DayProblem of the Day

Page 4: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Warm Up1. What are two angles whose sum is

90°?2. What are two angles whose sum is

180°?3. A part of a line between two points is called a _________.4. Two lines that intersect at 90° are

______________.

complementary angles

supplementary angles

segment

Course 1

7-5 Triangles

perpendicular

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Problem of the DayFind the total number of shaded triangles in each figure.

3 6 10

Course 1

7-5 Triangles

Page 6: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Today’s Learning Goal AssignmentLearn to classify triangles and solve problems involving angle and side measures of triangles. Course 1

7-5 Triangles

Page 7: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Vocabularyacute triangleobtuse triangleright trianglescalene triangleisosceles triangleequilateral triangle

Insert Lesson Title Here

Course 1

7-5 Triangles

Page 8: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Course 1

7-5 Triangles

A triangle is a closed figure with three line segments and three angles. Triangles can be classified by the measures of their angles. An acute triangle has only acute angles. An obtuse triangle has one obtuse angle. A right triangle has one right angle.

Acute triangle Obtuse triangle Right triangle

Page 9: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Course 1

7-5 Triangles

To decide whether a triangle is acute, obtuse, or right, you need to know the measures of its angles.

The sum of the measures of the angles in any triangle is 180°. You can see this if you tear the corners from a triangle and arrange them around a point on a line.

By knowing the sum of the measures of the angles in a triangle, you can find unknown angle measures.

Page 10: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Course 1

7-5 TrianglesAdditional Example 1: Application

D

E

F

To classify the triangle, find the measure of D on the trophy.

So the measure of D is 90°. Because DEF has one right angle, the trophy is a right triangle.

Subtract the sum of the known angle measures from 180°

m D = 180° – (38° + 52°)m D = 180° – 90°m D = 90°

Sara designed this triangular trophy. The measure of E is 38°, and the measure of F is 52°. Classify the triangle.

Page 11: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Course 1

7-5 TrianglesTry This: Example 1

D

E

F

To classify the triangle, find the measure of D on the trophy.

So the measure of D is 136°. Because DEF has one obtuse angle, the trophy is an obtuse triangle.

Subtract the sum of the known angle measures from 180°

m D = 180° – (22° + 22°)m D = 180° – 44°m D = 136°

Sara designed this triangular trophy. The measure of E is 22°, and the measure of F is 22°. Classify the triangle.

Page 12: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Course 1

7-5 Triangles

You can use what you know about vertical, adjacent, complementary, and supplementary angles to find the measures of missing angles.

Page 13: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Course 1

7-5 TrianglesAdditional Example 2A: Using Properties of Angles

to Label TrianglesUse the diagram to find the measure of each indicated angle.

QTR and STR are supplementary angles, so the sum of m QTR and m STR is 180°.m QTR = 180° – 68°

= 112°

P

S R

Q

T

68°

55°

A. QTR

Page 14: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Course 1

7-5 TrianglesTry This: Example 2A

Use the diagram to find the measure of each indicated angle.

MNO and PNO are supplementary angles, so the sum of m MNO and m PNO is 180°.

m MNO = 180° – 44° = 136°

L

P O

M

N44°

60°

A. MNO

Page 15: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Course 1

7-5 TrianglesAdditional Example 2B: Using Properties of Angles

to Label Triangles

QRT and SRT are complementary angles, so the sum of m QRT and m SRT is 90°.m SRT = 180° – (68° + 55°) = 180° – 123°

= 57°m QRT = 90° – 57°

= 33°

P

S R

Q

T

68°

55°

B. QRT

Page 16: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Course 1

7-5 TrianglesTry This: Example 2B

MON and PON are complementary angles, so the sum of m MON and m PON is 90°.

m PON = 180° – (44° + 60°) = 180° – 104°

= 76°m MON = 90° – 76°

= 14°

L

P O

M

N44°

60°

B. MON

Page 17: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Course 1

7-5 Triangles

Triangles can be classified by the lengths of their sides. A scalene triangle has no congruent sides. An isosceles triangle has at least two congruent sides. An equilateral triangle has three congruent sides.

Page 18: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Course 1

7-5 TrianglesAdditional Example 3: Classifying Triangles by

Lengths of SidesClassify the triangle. The sum of the lengths of the sides is 19.5 in.

c = 6.5

6.5 in.

N L c

M

c + (6.5 + 6.5) = 19.5 c + 13 = 19.5

c + 13 – 13 = 19.5 – 13

6.5 in.

Side c is 6.5 inches long. Because LMN has three congruent sides, it is equilateral.

Page 19: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Course 1

7-5 TrianglesTry This: Example 3

Classify the triangle. The sum of the lengths of the sides is 21.6 in.

d = 7.2

7.2 in.

C A d

B

d + (7.2 + 7.2) = 21.6 d + 14.4 = 21.6 d + 14.4 – 14.4 = 21.6 – 14.4

7.2 in.

Side d is 7.2 inches long. Because ABC has three congruent sides, it is equilateral.

Page 20: 6 th Grade Math Homework Ch. 7-5 Page 346 #6-14  #28-36 (Spiral Review)

Lesson QuizIf the angles can form a triangle, classify the triangle as acute, obtuse, or right.

1. 37°, 53°, 90° 2. 65°, 110°, 25°

3. 61°, 78°, 41° 4. 115°, 25°, 40°

The lengths of three sides of a triangle are given. Classify the triangle.

5. 12, 16, 25 6. 10, 10, 15

not a triangleright

Insert Lesson Title Here

acute obtuse

Course 1

7-5 Triangles

scalene isosceles