5.4 – Use Medians and Altitudes
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5.4 – Use Medians and Altitudes
description
5.4 – Use Medians and Altitudes. Line from the vertex of a triangle to the midpoint of the opposite side. Line from the vertex of a triangle perpendicular to the opposite side. - PowerPoint PPT Presentation
Transcript of 5.4 – Use Medians and Altitudes
5.4 – Use Medians and Altitudes
Median
Altitude
Line from the vertex of a triangle to the midpoint of the opposite side
Line from the vertex of a triangle perpendicular to the opposite side
Construct a triangle with the given sides. Then construct the median for each side of the triangle. What do you notice?
A B
A C
B C
A B
C
A B
C
Special Segment
Definition
Median
Line from the vertex to midpoint of opposite side
Concurrency Property Definition
Centroid 2/3 the distance from each vertex and 1/3 distance from the midpoint
Construct a triangle with the given sides. Then construct the perpendicular bisector for each side of the triangle. What do you notice?
A B
A C
B C
A B
C
A B
C
Special Segment Definition
Altitude
Line from vertex to the opposite side
Concurrency Property Definition
orthocenter
If obtuse – outside of triangle
If right – at vertex of right angle
If acute – inside of triangle
Perpendicular Bisector
Circumcenter
Angle Bisector
Incenter
Median Centroid
Altitude Orthocenter
P
A
M
A
C
I
C
O
6
In PQR, S is the centroid, PQ = RQ, UQ = 5, TR = 3, and SU = 2. Find the measure.
Find TP.
3
In PQR, S is the centroid, PQ = RQ, UQ = 5, TR = 3, and SU = 2. Find the measure.
Find SV.3
2
In PQR, S is the centroid, PQ = RQ, UQ = 5, TR = 3, and SU = 2. Find the measure.
Find RU.3
24 + 2 = 6 4
In PQR, S is the centroid, PQ = RQ, UQ = 5, TR = 3, and SU = 2. Find the measure.
Find ST.3
24
3
In PQR, S is the centroid, PQ = RQ, UQ = 5, TR = 3, and SU = 2. Find the measure.
Find VQ.3
24
3
5
In ABC, G is the centroid, AE = 12, DC = 15. Find the measure.
Find GE and AG.
A C
B
F
D E
G12
GE = 4
AG = 8
In ABC, G is the centroid, AE = 12, DC = 15. Find the measure.
Find GC and DG.
A C
B
F
D E
G12
GC = 10
DG = 5
15
Point L is the centroid for NOM. Use the given information to find the value of x.
OL = 5x – 1 and LQ = 4x – 5
5x – 1 = 2(4x – 5)
5x – 1 = 8x – 10
–1 = 3x – 109 = 3x3 = x
5x – 1
4x – 5
Point L is the centroid for NOM. Use the given information to find the value of x.
LP = 2x + 4 and NP = 9x + 6
3(2x + 4) = 9x + 6
6x + 12 = 9x + 6
12 = 3x + 66 = 3x2 = x
2x + 4
9x + 6
