5 Wave Properties of Particles

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    Wave Properties of Particles

    Serway/Jewett chapters 38.5; 40.4 40.7

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    Photons and Waves Revisited

    Some experiments are best explained bythe photon model

    Some are best explained by the wavemodel

    We must accept both models and admit thatthe true nature of light is not describable interms of any single classical model

    The particle and wave models complementone another

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    Dual Nature of EM radiation

    To explain all experiments with EM radiation(light), one mustassume that light can bedescribed both as wave (Interference, Diffraction)andparticles (Photoelectric Effect, Frank-Hertz

    Experiment, x-ray production, x-ray scatteringfrom electron) To observe wave properties must make

    observations using devices with dimensions

    comparable to the wavelength. For instance, wave properties of X-rays were observed

    in diffraction from arrays of atoms in solids spaced by afew Angstroms

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    Louis de Broglie

    1892 1987

    French physicist

    Originally studied

    history

    Was awarded theNobel Prize in 1929

    for his prediction ofthe wave nature ofelectrons

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    De Broglies Hypothesis

    Louis de Broglie postulated that the dualnature of the light must be expanded toALL matter

    In other words, all material particles possess

    wave-like properties, characterized by thewavelength,B, related to the momentump ofthe particle in the same way as for light

    p

    hB de Broglie

    wavelength of the

    particle

    Plancks Constant

    Momentum of the

    particle

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    Wave Properties of Particles

    Louis de Broglie postulated that because photons haveboth wave and particle characteristics, so too all forms ofmatter have both properties

    For photons:

    De Broglie hypothesized that particles of well definedmomentum also have a wavelength, as given above, thede Broglie wavelength

    p

    hOr

    hchcEp

    hE

    ,

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    Frequency of a Particle

    In an analogy with photons, de Brogliepostulated that a particle would also have afrequency associated with it

    These equations present the dual nature of

    matter Particle nature, pand E

    Wave nature, and (and k)

    fhhfEhEf 2

    2

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    Photons and Waves Revisited

    Some experiments are best explained bythe photon model

    Some are best explained by the wave

    model

    We must accept both models and admitthat the true nature of light is not

    describable in terms of any single classicalmodel

    Also, the particle model and the wave

    model of light complement each other

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    Complementarity

    The principle of complementarity statesthat the wave and particle models of eithermatter or radiation complement each other

    Neither model can be used exclusively todescribe matter or radiation adequately

    No measurements can simultaneouslyreveal the particle and the wave propertiesof matter

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    The Principle of Complementarity

    and the Bohr Atom

    How can we understand electron orbits inhydrogen atom from wave nature of the electron?

    Remember: An electron can take only certainorbits: those for which the angular momentum, L,takes on discrete values

    How does this relate to the electrons de

    Broglies wavelength?

    nmvrL

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    The Principle of Complementarity

    Only those orbits are allowed,which can fit an integer(discrete) number of the electrons

    de Broglies wavelength Thus, one can replace 3rdBohrs

    postulate with the postulatedemanding that the allowed orbitsfit an integer number of theelectrons de Broglies wavelength

    This is analogous to the standingwave condition for modes inmusical instruments

    B

    BB

    B

    B

    nr

    nh

    nr

    hmv

    mv

    h

    p

    h

    nmvrL

    2

    2

    Bnr 2

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    De Broglies Hypothesis predictsthat one should see diffractionand interference of matter waves

    For example we should observeElectron diffractionAtom or molecule diffraction

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    Estimates for De Broglie wavelength

    Bullet:

    m = 0.1 kg; v = 1000 m/s B ~ 6.6310-36 m

    Electron at 4.9 V potential: m = 9.1110-31 kg; E~4.9 eV B ~ 5.510-10 m = 5.5

    Nitrogen Molecule at Room Temperature: m ~ 4.210-26 kg; E = (3/2)kBT0.0375 eV B~2.810-11 m = 0.28

    Rubidium (87) atom at 50 nK:

    B ~ 1.210-6

    m = 1.2 mm = 1200

    mE

    h

    mv

    h

    p

    hB

    2

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    Diffraction of X-Rays by Crystals

    X-rays are electromagnetic waves of relatively shortwavelength ( = 10-8 to 10-12 m = 100 0.01 )

    Max von Laue suggested that the regular array ofatoms in a crystal (spacing in order of several

    Angstroms) could act as a three-dimensionaldiffraction grating for x-rays

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    X-ray Diffraction Pattern

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    X-Ray Diffraction

    This is a two-dimensionaldescription of thereflection (diffraction) ofthe x-ray beams

    The condition forconstructive interference is

    where n = 1, 2, 3

    nd sin2 This condition is

    known as Braggs law

    This can also be usedto calculate the spacing

    between atomic planes

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    Davisson-Germer Experiment

    If particles have a wave nature, then underappropriate conditions, they should exhibitdiffraction

    Davisson and Germer measured thewavelength of electrons

    This provided experimental confirmation ofthe matter waves proposed by de Broglie

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    Davisson and Germer Experiment Electrons were directedonto nickel crystals Accelerating voltage is

    used to control electronenergy: E = |e|V The scattering angle

    and intensity (electron

    current) are detected is the scattering angle

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    Davisson and Germer Experiment If electrons are just particles, we expect a smooth

    monotonic dependence of scattered intensity onangle and voltage because only elastic collisions areinvolved

    Diffraction pattern similar to X-rays would beobserved if electrons behave as waves

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    Davisson and Germer Experiment

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    Davisson and Germer Experiment

    Observations:

    Intensity was strongerfor certain angles forspecific accelerating

    voltages (i.e. for specificelectron energies) Electrons were reflected

    in almost the same way

    that X-rays ofcomparable wavelength

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    Davisson and Germer Experiment

    Observations: Current vs accelerating

    voltage has a maximum,i.e. the highest numberof electrons is scatteredin a specific direction

    This cant be explainedby particle-like nature of

    electrons

    electronsscattered on crystalsbehave as waves

    For ~ 50

    the maximum is at ~54V

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    Davisson and Germer Experiment

    For X-ray Diffraction on Nickel

    5065

    A65.1;A91.0

    sin2

    o

    ray-X

    o

    111

    d

    d

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    Davisson and Germer Experiment

    (Problem 40.38) Assuming the wave nature

    of electrons we can use de Brogliesapproach to calculate wavelengths of amatter wave corresponding to electrons inthis experiment

    V= 54 V E = 54 eV = 8.6410-18J

    A67.1J106.8kg101.92

    sec-J1063.6

    2,2,

    2

    1831

    34

    2

    B

    BmE

    hmEp

    m

    pE

    This is in excellent agreement with wavelengths of

    X-rays diffracted from Nickel!

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    In previous experiments many electrons

    were diffracted Will one get the same result for a single

    electron?

    Such experiment was performed in 1949 Intensity of the electron beam was so low that

    only one electron at a time collided withmetal

    Still diffraction pattern, and not diffusescattering, was observed, confirming that

    Thus individual electrons behave as waves

    Single Electron Diffraction

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    Two-slit Interference

    Thomas YoungThe intensity is obtained bysquaring the wave,I1 ~ , I2 ~ ,I12 = = ,where < > is average over time of

    the oscillating wave.h1h2 ~ cos(2p/) and reflects theinterference between wavesreaching the point from the twoslits.When the waves arriving fromslits 1 and 2 are in phase, p = n,and cos(2p/) = 1.For = , I12 = 4I1.When the waves from slits 1 and 2are out of phase, = n + /2, and

    cos(2/) = -1 and I12 = 0.

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    Electron Diffraction, Set-Up

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    Electron Diffraction, Experiment

    Parallel beams of mono-energeticelectrons that are incident on a double slit

    The slit widths are small compared to the

    electron wavelength An electron detector is positioned far from

    the slits at a distance much greater than

    the slit separation

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    Electron Diffraction, cont.

    If the detector collectselectrons for a longenough time, a typicalwave interference

    pattern is produced This is distinct evidence

    that electrons areinterfering, a wave-likebehavior

    The interference patternbecomes clearer as thenumber of electronsreaching the screen

    increases

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    Active Figure 40.22

    Use the active figureto observe thedevelopment of the

    interference pattern Observe the

    destruction of thepattern when you

    keep track of whichslit an electron goesthrough PLAY

    ACTIVE FIGURE

    http://../Active_Figures/active_figures/AF_4022.htmlhttp://../Active_Figures/active_figures/AF_4022.htmlhttp://../Active_Figures/active_figures/AF_4022.html
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    Electron Diffraction, Equations

    A maximum occurs when This is the same equation that was used for

    light

    This shows the dual nature of the electron The electrons are detected as particles at a

    localized spot at some instant of time

    The probability of arrival at that spot isdetermined by calculating the amplitudesquared of the sum of all waves arriving at apoint

    sind m

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    Electron Diffraction Explained

    An electron interacts with both slitssimultaneously

    If an attempt is made to determineexperimentally through which slit the electrongoes, the act of measuring destroys theinterference pattern It is impossible to determine which slit the

    electron goes through

    In effect, the electron goes through both slits The wave components of the electron are

    present at both slits at the same time

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    Neutrons He atoms

    C60

    molecules

    Other experiments showed wave nature forneutrons, and even big molecules, which

    are much heavier than electrons!!

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    Example of Electron Diffraction Electrons from a hot filament are incident upon a crystal at an angle = 30

    from the normal (the line drawn perpendicular) to the crystal surface. Anelectron detector is place at an angle = 30 from the normal. Atomiclayers parallel to the sample surface are spaced by d = 1.3 A.

    Through what voltage V must the electron be accelerated for a maximum inthe electron signal on the detector?

    Will the electrons scatter at other angle?

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    Addition of Two Waves

    )2

    sin()2

    cos(2)sin()sin(),(

    tkxAtkxAtkxAtxy

    tkxAtkxAtkxAtxy cossin2)sin()sin(),(

    Two sine waves traveling in the same direction:

    Constructive and Destructive Interference

    Two sine waves traveling in opposite directions create a standing wave

    Two sine waves with different frequencies: Beats

    ]2

    (

    2

    (sin[])2/()2/cos[(2

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    (

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    )21)21

    )21)21)21)21

    2211

    txkk

    txkA

    txkk

    txkk

    A

    txkAtxkAtxy

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    Beat Notes and Group Velocity, vg

    This represents a beat note with the amplitude of the beat moving at speed

    dk

    d

    v

    vkv

    g

    g

    :wavesofondistributicontinuousofionsuperpositFor

    /)2//()2/(

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    sin[])2/()2/cos[(2),(

    )21)21

    tx

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    Beats and Pulses

    Two tuning forks are struck simultaneously. The vibrate at 512 and 768 Hz.(a) What is the frequency of the separation between peaks in the beat envelope?(b) What is the velocity of the beat envelope?

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    Beats and Pulses

    Two tuning forks are struck simultaneously. The vibrate at 512 and 768 Hz.(a) What is the separation between peaks in the beat envelope?(b) What is the velocity of the beat envelope?

    (a)

    The rapidly oscillating wave is multiplied by a more slowly varying envelopewith wave vector

    ]2

    (

    2

    (sin[])2/()2/cos[(2),(

    )21)21tx

    kktxkAtxy

    phasebeat

    beat

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    phasephase

    phasephase

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    vvsothofwavelengtindependenissoundofspeedceresultExpected

    kvb

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    mkkk

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    mphsmsoundofspeedtheisv

    ffkv

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    sin

    344)35.903.14/()512768(2)2//()2/()(

    70.233.2/2/2:tan

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    1

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    Construction Particles From Waves Particles are localized in space

    Waves are extended in space. It is possible to build localized entities from a

    superposition of number of waves with differentvalues of k-vector. For a continuum of waves, thesuperposition is an integral over a continuum ofwaves with different k-vectors. The wave then has a non-zero amplitude only within a

    limited region of space

    Such wave is called wave packet

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    Wave Picture of Particle

    Consider a wave packet made up of waves with adistribution of wave vectors k,A(k), at time t. Asnapshot, of the wave in space along the x-direction is obtained by summing over waves

    with the full distribution of k-vectors. For acontinuum this is an integral. The spatial distribution at a time t given by:

    0

    )cos()(),( dktkxkAtx

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    Wave Picture of Particle

    1. A(k)is spiked at a given k0, and

    zero elsewhere only one wave with k = k0 ( = 0)

    contributes; thus one knowsmomentum exactly, and thewavefunction is a traveling wave

    particle is delocalized2. A(k)is the same for all k No distinctions for momentums, so

    particles position is well defined -the wavefunction is a spike,representing a very localized

    particle3. A(k)is shaped as a bell-curve

    Gives a wave packet partiallylocalized particle

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    Wave Picture of Particle

    The greater the range of wave numbers (andtherefore s) in the mix, the narrower thewidth of the wave packet and the morelocalized the particle

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    Group Velocity for Particles and Waves

    The group velocity in term of particle parameters is

    Consider a free non-relativistic particle. The total,energy for this particle is, E= Ek = p2/2m

    dpdE

    pd

    Ed

    dk

    dvg

    particle

    particle

    g

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    Group Velocity

    The group speed of wave packet is identical to the

    speed of the corresponding particle,

    Is this true for photon, for which u = c? For photon total energy E =pc

    cpcdpd

    dpdEvg

    dp

    dEvu gparticle

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    Group Velocity in Optical Fiber

    A pulse of light is launched in an optical fiber. The amplitude A(k) of the pulsesis peaked in the telecommunications band at the wavelength in air, = 1,500nm.The optical fiber is dispersive, with n = 1.50 + 102/, near = 1,500nm, where isexpressed in nm. What is the group velocity?

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    Group Velocity in Optical Fiber

    A pulse of light is launched in an optical fiber. The amplitude A(k) of the pulsesis peaked in the telecommunications band at the wavelength in air, = 1,500nm.The optical fiber is dispersive, with n = 1.50 + 102/, near = 1,500nm, where isexpressed in nm. What is the group velocity?

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