5-Crack Tip Stress Fields
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Transcript of 5-Crack Tip Stress Fields
1/22/2014
1
5. Crack Tip Stress Analysis
ME559Introduction to Fracture Mechanics
p y
Prof. M. Ramulu
© M. Ramulu 1
Outline
• Plane Problem &Airy’s Stress Functions
• Modes of Fracture
• Crack Tip Stress & Displacement fields
– Westergaard
M kh li h ili– Muskhelishvili
– Williams
• Stress Intensity Factor, K
• Relation between G & K
• Summary
© M. Ramulu 2
Crack Tip Stress Analysis• Fracture mechanics is based on the assumption that all
engineering materials contain cracks from which failure starts.
• Require knowledge of the redistribution of stress caused by the cracks in conjunction with crack growth condition.
L di f k d b d i ll i d b• Loading of a cracked body is usually accompanied by inelastic deformation & other nonlinear effects near the crack tip, except ideally brittle materials. Assume these effects are small compared to crack size. Therefore linear theory is more than adequate to address stress distribution in the crack body.
© M. Ramulu 3
Crack Tip Stress Analysis: Stress Function Approach
• A “Valid” stress function is one that satisfies both the equilibrium and the compatibility conditions.
• The “Airy Stress Function” automatically satisfies these conditions.
• To satisfy a real problem, the boundary conditions must match the problem.
© M. Ramulu 4
Crack Tip Stress Analysis: Stress Function Approach
• Plane problem
• Plane stress :
x = x (x,y), y = y(x,y), xy = (x,y) z = xz = yz= 0Triaxial strains.Triaxial strains.
• Plane strain :
u = u(x,y), v = v(x,y), w = 0
z = xz = yz= 0; z= (x+y)
Triaxial stresses.
© M. Ramulu 5
Crack Tip Stress Analysis: Stress Function Approach
• Linear elasticity field equation
• 1) Equilibrium equations for plane problem.
2) Strain‐displacement relations.
© M. Ramulu 6
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Crack Tip Stress Analysis: Stress Function
• 3) Stress‐strain relations (Hooks’ law).
4) Compatibility equations.
Combining the above lead to the compatibility equations :
© M. Ramulu 7
Crack Tip Stress Analysis: Airy’s Stress Function
• For a 2‐D elastic problem there exists a function (x,y) from which the stresses can be derived.
• The equilibrium and compatibility equations are q p y qautomatically satisfied if x,y has the biharmonic property
• The function is called the Airy stress function
© M. Ramulu 8
Crack Tip Stress Analysis: Airy’s Stress Function
• Airy’s stress function, (or U)
• Where 1,2,3 are harmonic functions.
• Airy’s stress function, or U;
– satisfied 22 = 0 (Biharmonic equation).
– This implies that the equilibrium and compatibility equations are automatically satisfied.
© M. Ramulu 9
Crack Tip Stress Analysis: Airy’s Stress Function
• In polar Coordinate;
© M. Ramulu 10
2D‐Crack Problems
• Stress Functions:
–Westergaard (1939)
–Williams (1952, 1957)
Muskhelishvili (1953)–Muskhelishvili (1953)
They all used Airy’s stress function.
© M. Ramulu 11
Crack Tip Stress Analysis: Westergaard’s Stress Function
• Westergaard stress function Z(z) expressed in complex variable form.
Z( ) i d i d i i th k ti t• Z(z) is used in deriving the crack tip stresses
• The Westergaard stress function is related to Airy stress function as follows
© M. Ramulu 12
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Crack Tip Stress Analysis: Westergaard’s Stress Function
© M. Ramulu 13
Crack Tip Stress Analysis: Westergaard’s Stress Function
© M. Ramulu 14
Crack Tip Stress Analysis: Westergaard’s Stress Function
Stresses in terms of the Z(z) are
© M. Ramulu 15
Using these stresses and a polar coordinate system at the crack tip, the elastic stresses at the crack tip can be derived.
Crack Tip Stress Analysis: Basic Modes of Fracture
The three Modes of loading cracks are:
• Mode I: Opening
• Mode II: In-Plane Shear
Mode III: O t of Plane Shear
© M. Ramulu 16
• Mode III: Out-of-Plane Shear
Opening Mode is the predominant mode of fracture in real engineering problems
In-plane Mode is also called sliding mode
Out-of-plane Mode is also called tearing mode
Crack Tip Stress Analysis:CRACK TRIP STRESS AND DISPLACEMENT FIELDS
z
py
o
rx
z
py
o
rx
z
py
o
rx
© M. Ramulu 17
Crack Tip Stress Analysis:Mode I crack problem
y
r
© M. Ramulu 18
x2a
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Crack Tip Stress Analysis:Mode I crack problem
xx
yy
xy
iy
© M. Ramulu 19
xx
x
aa
rZ = x +iy
rei
Crack Tip Stress Analysis:Mode I crack problem
© M. Ramulu 20
Crack Tip Stress Analysis:Mode I crack problem
-
© M. Ramulu 21
Crack Tip Stress Analysis:Mode I crack problem
© M. Ramulu 22
Crack Tip Stress Analysis:Mode I crack problem
© M. Ramulu 23
Crack Tip Stress Analysis: Mode I crack problem (stress Intensity Factor , KI)
Mode I stress intensity factor, KI
• Stress analysis of a component containing crack(s) reduces to determination of KI at the tip of the crack(s).
• KI has units of psi (in)0.5 or MPa (m)0.5.
C i f K i (i )0 5 1 0989* MP ( )0 5
© M. Ramulu 24
Conversion factor: Ksi (in)0.5 = 1.0989* MPa (m)0.5
• The difference between one cracked component and another lies in the magnitude of the stress field parameter KI. Higher K indicates higher stress field.
• In essence, KI serves as a scale factor to define the magnitude of the crack tip stress field.
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Crack Tip Stress Analysis:Mode I Crack Tip Elastic Stress Distribution
KI characterizes the magnitude (intensity) of the stresses in the vicinity of an ideally sharp crack tip in linear-elastic and isotropic material.
© M. Ramulu 25
KI is a measure for the stress singularity at the crack tip.
These equations are based on the theory of linear elasticity.
They describe the stress field near the crack tip.
Crack Tip Stress Analysis:Mode I crack problem
strain plane and stress plane
for different is and modulusshear is
2cos21
2sin
22
2sin21
2cos
22
2
2
Where
rKv
rKu
I
I
© M. Ramulu 26
Crack Tip Stress Analysis:Mode I crack problem
© M. Ramulu 27
Crack Tip Stress Analysis:Mode II crack problem
iy
XY
r
© M. Ramulu 28
x2a
Crack Tip Stress Analysis:Mode II crack problem
© M. Ramulu 29
Crack Tip Stress Analysis:Mode III crack problem
© M. Ramulu 30
2a
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Crack Tip Stress Analysis:Mode III crack problem
© M. Ramulu 31
Crack Tip Stress Analysis:Mode III crack problem
© M. Ramulu 32
Muskhelishvili’s stress function (1953)
• Suitable for solving boundary‐value problem.
• Utilize conformal‐mapping technique.
• Muskhelishvili’s stress function consists of two analytic functions (z) and X(z) which are selected to Airy’s stress function (x,y), throughfunction (x,y), through
© M. Ramulu 33
Muskhelishvili’s stress function (1953)
© M. Ramulu 34
Williams (1952, 1957)Using semi-inverse method Williams assumed an Airy stress function in polar coordinates of the form
Where the value(s) of are to be determined
y
© M. Ramulu 35
as part of the solution.
With this choice of stress function, the stresses can be expressed in polar coordinates
A Wedge of apex angle 2 with traction-free flanks.
Crack Tip Stress Analysis: Airy’s Stress Function
• Stresses in polar Coordinate;
© M. Ramulu 36
01111
2
2
22
2
2
2
22
2224
rrrrrrrr
Biharmonic Equation is :
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Williams (1952, 1957)Boundary Conditions:
Substituting the assumed airy stress function into
y
© M. Ramulu 37
the biharmonic equation ( ) yields:
Result in an ordinary differential equation and the general solution for f()
4
Williams (1952, 1957)The constants C1, C2, C3, and C4 are to be determined from the boundary conditions on the faces of the wedge. Using the boundary conditions in f() and its derivative :
© M. Ramulu 38
Williams (1952, 1957)The resulting equations, in matrix form
© M. Ramulu 39
Therefore,
The resulting eigenequation for the crack problem
Williams (1952, 1957)Let =n/2 and = in matrix form yields
© M. Ramulu 40
Williams (1952, 1957)General solution in terms of stress function for the Wedge shaped or single-ended crack with traction-free faces is:
© M. Ramulu 41
Williams (1952, 1957)Crack tip near-field equations
© M. Ramulu 42
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Displacement Equation mode I and mode II
© M. Ramulu 43
Substituting rr, r,, r in Hooks law for strains and integrity them to obtain displacements
Displacement Equation mode I and mode II
Mode I
© M. Ramulu 44
Displacement Equation mode I and mode II
Mode II
© M. Ramulu 45
Crack tip elastic stress fields
Linear Elastic Fracture Mechanics (LEFM)
• Fracture Modes • William’s Mode I and II Infinite Plate
solution• Mode III solution• Truncation of Williams solution to 2‐terms• Introduction of T‐stressIntroduction of T stress
∑2
21
2 12 2
12
12
3
2 12 2
12
12
3
12 2
12
12
3
∞1
∑2
21
2 12 2
12
12
3
2 12 2
12
12
3
12 2
12
12
3
∞1
22 1 2
1
21
∞
1,3,5,…
2 1 21
sin2
1
∞
2,4,..
1
12
21
232
21
232
2 232
12
400
1
12
22
232
2 232
21
232
22
000
4 2
Theoretical Results
Crack‐tip Stress fields T=0 T=+0.5 T=‐0.5
(a) Cartesian stresses in Cartesian and Polar coordinates
30 ° 60 ° 90 ° 120 ° 150 ° 180 °�
0.5
1.0
�ij 2�r
K1
�xy
�y
�x
�T�, 0.��0.4 �0.2 0.2 0.4 0.6 0.8 1.0
�1.0
�0.5
0.5
1.0
1.0
�ij 2�r
K11.0
(a) Cartesian stresses in Cartesian and Polar coordinates
30 ° 60 ° 90 ° 120 ° 150 ° 180 °�
0.5
1.0
�ij 2�r
K1
�xy
�y
�x
�T�, 0.5��0.4 �0.2 0.2 0.4 0.6 0.8 1.0
�1.0
�0.5
0.5
1.0
�ij 2�r
K11.0
(a) Cartesian stresses in Cartesian and Polar coordinates
30 ° 60 ° 90 ° 120 ° 150 ° 180 °�
0.5
1.0
�ij 2�r
K1
�xy
�y
�x
�T�, �0.5��0.2 0.2 0.4 0.6 0.8 1.0
�1.0
�0.5
0.5
1.0
�ij 2�r
K11.0
(b) Polar Stresses in Cartesian and Polar coordinates
(c) Principal stresses in Cartesian and Polar coordinates
30 ° 60 ° 90 ° 120 ° 150 ° 180 °�
0.2
0.4
0.6
0.8
�r�
���
�rr
�T�, 0.��0.4 �0.2 0.2 0.4 0.6 0.8 1.0
�1.0
�0.5
0.5
30 ° 60 ° 90 ° 120 ° 150 ° 180 °�
0.2
0.4
0.6
0.8
1.0
1.2
�ij 2�r
K1
�3
�2
�1
�T�, 0.��0.5 0.5 1.0
�1.0
�0.5
0.5
1.0
(b) Polar Stresses in Cartesian and Polar coordinates
(c) Principal stresses in Cartesian and Polar coordinates
30 ° 60 ° 90 ° 120 ° 150 ° 180 °�
0.2
0.4
0.6
0.8
1.0
�r�
���
�rr
�T�, 0.5��0.5 0.5 1.0
�1.0
�0.5
0.5
30 ° 60 ° 90 ° 120 ° 150 ° 180 °�
0.2
0.4
0.6
0.8
1.0
1.2
�ij 2�r
K1
�3
�2
�1
�T�, 0.5��0.5 0.5 1.0
�1.0
�0.5
0.5
1.0
(b) Polar Stresses in Cartesian and Polar coordinates
(c) Principal stresses in Cartesian and Polar coordinates
30 ° 60 ° 90 ° 120 ° 150 ° 180 °�
0.2
0.4
0.6
0.8
1.0
�r�
���
�rr
�T�, �0.5��0.4 �0.2 0.2 0.4 0.6 0.8 1.0
�1.0
�0.5
0.5
30 ° 60 ° 90 ° 120 ° 150 ° 180 °�
0.2
0.4
0.6
0.8
1.0
1.2
�ij 2�r
K1
�3
�2
�1
�T�, �0.5��0.5 0.5 1.0
�1.0
�0.5
0.5
1.0
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Crack under Mode III action by torsion
A i l C
y
yz
y
x
yz
© M. Ramulu 49
Antiplane stress Components
Free
Free
x
r
z rz
y
z
Mode III – closely related to Torsion problem
equation harmonic has 02uzz
© M. Ramulu 50
)(ulet
0
0
.conditions
boundary under sloved be shouldIt
wzz
z
gr
uzz
z
Mode III – closely related to Torsion problem
© M. Ramulu 51
Mode III – closely selected to Torsion problem
© M. Ramulu 52
Mode III – closely selected to Torsion problem
© M. Ramulu 53
Stresses along the extended crack line and displacements along the crack sides will be of particular importance. We first rename the coefficients C11, C21, and D1 as follows:
© M. Ramulu 54
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22
1)(u :0xFor
2)0( :0xFor
:0 yII, Mode
yx
xK
ku
x
K
IIr
IIr
© M. Ramulu 55
2
2)( w:0xFor
2)0( :0xFor
:0 yIII, Mode
yz
xKu
x
K
IIIz
IIIz
Crack Tip Stress Analysis: Stress Intensity as a Similitude Parameter
Two cracked bodies of different size and shape, but of the same material with cracks of different size, the crack tip stress field is given by:
Ki characterizes the magnitude (intensity) of the stresses in the vicinity of an ideally sharp crack tip in linear-elastic and isotropic
iji
ij fr
K
2
© M. Ramulu 56
vicinity of an ideally sharp crack tip in linear-elastic and isotropic material. If the stress intensities for the two cases are equal, there is exact similitude ( ie.,two cracks respond in the same manner). Because of the similutude argument, any cracked body of this material will cause fracture at the same value of the stress intensity.
Restrictions:- Same thickness (plane stress or plane strain)
- No plastic deformation or negligible plastic deformation (Condition of the crack tip)
Relation Between Strain Energy Release Rate and Stress Intensity Factor
GUaa
lim
0
U F x V x x V x dxy yy
2
12
a a
2V
a
yy VG 02
lim 180
yy
a
0
K
2 r
K
2 xV
r
K I
2 2 21 2
22
sin cos
© M. Ramulu 57
a-x
Closure stress
yy
Closure Stress
Displacement
aaG
00 2
lim
Relation between G & K
Vr
K I
2 21
Va a a x
KI 2
12
at
2 2
G
a a a
a
a x
xdx
a
a
lim
0
0
1
4
K KI I
18
KI2
© M. Ramulu 58
GE
K I2
E
v
E Plane stress
E Plane strain
1 2
where
cossin2 and ; sinLet 2 adxax
Relation between G & K
rK
Where V is the crack opening displacement
COD
r
a x
K
E
I
2
1
4 2 2
© M. Ramulu 59
Relation between G & K
GEI
I2K
G II2K
Mode-I:
Mode-II: GEII
II
GIIIIII2K
2
E
v
E Plane stress
E Plane strain
1 2
© M. Ramulu 60
Mode II:
Mode-III:
Where
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Relation between G & K
K K K + KI II IIITotal
K K K + KI IA IB ICTotal Same mode of deformation
G G G GTotal
+ I II III
© M. Ramulu 61
However,
Summary
• Crack tip stress analysis using stress function approach was introduced.
– Airy’s stress function
• Westergaard
• Williams• Williams
• Muskhelishvili
• Crack tip stress state is characterized by a single parameter called stress intensity factor, K. Equal K guarantees similitude.
• Relation exists between energy release rate and the stress intensity factors for all modes of deformation
© M. Ramulu 62