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Compression Members
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Introduction
ResistanceofCrossSectionsSectionsnotpronetolocalbuckling
Sectionspronetolocalbuckling
BucklingResistanceofMembersSectionsnotpronetolocalbuckling
Sectionspronetolocalbuckling
ReductionFactorforBucklingResistance
Elastic
Critical
Force
&
Buckling
LengthNonDimensionalSlendernessforFlexuralBucklingBucklingCurveofPerfectColumnBucklingCurvesofImperfectColumnsSelectionofBucklingCurveandImperfectionFactor
DesignProcedure
ExamplesExampleCM1(UCwithintermediaterestraintundercompression)ExampleCM2(CHSundercompression)
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Introduction
Compression members are structural components that are subject toaxial compression loads only.
These generally refer to compressed pin-ended struts found in trusses,lattice girders or bracing members.
Most real columns are subjected to significant bending moments inaddition to the axial loads, due to the eccentricities of axial load and the
presence of transverse forces. They are referred to as beam-columnsand are covered in a separate chapter.
Compression members must be checked for resistance of cross-sections buckling resistance of members
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Resistance of Cross-Section
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Class 1, 2 and 3 cross-sections are
unaffected by local buckling.Design resistance of cross-sectionNc,Rdequals the plastic resistanceNpl,Rd.
Resistance of Cross-Sections
SectionsNOTPRONEtolocalbuckling
Class 4 sections suffers from local buckling
which prevents the attainment of squash load.Design resistance of cross-sectionNc,Rdlimited to local buckling resistance.
SectionsPRONEtolocalbuckling
EN 1993-1-1 Clause 6.2.4 (1)
The design value of the compression forceNEdat each cross-section shall satisfy:
EN 1993-1-1 Clause 6.2.4 (2)
IfClass4sectionisunsymmetrical,ithastobedesignedasbeamcolumn duetotheadditionalmoment arisingfromeccentricityofthe
centroidalaxis.
M0 = 1.00
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Buckling Resistance of Member
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Elastic Buckling of ColumnsEuler Buckling Load
Ncr=L
Buckling stress
I =i2 A
i = radius of gyration
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f
fy
Failureby
Crosssectionyielding
Failurebyelasticbuckling
Euler elastic buckling
BucklingCurveofPerfectColumn
1
where is the column slenderness.
Whenfcr=fy, = 1
is the radius of gyration.
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f/fy
FactorsInfluencetheBucklingofColumns
/1
=0
Euler buckling curve
1. Effective length of Column
2. Residual Stresses
3. Member initial out-of-straightness
4. Types of cross section
5. Local buckling of component plate
Practical Region
Inelastic buckling
Elastic buckling
Imperfect
columns
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= L / 1000
Initial out of straightness
+260 N/mm
-125 N/mm
+55 N/mm
Rolled Section
C
T
C C
C C
T
2
2
2
CC
T
CC
T
C
T
TWeb Distribution
Welded section
Factors that affect overall buckling of columns
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Design buckling resistanceNb,Rdshould betaken as:
Buckling Resistance of Members
SectionsNOTPRONEtolocalbuckling
Design buckling resistanceNb,Rdshould betaken as:
SectionsPRONEtolocalbuckling
EN 1993-1-1 Clause 6.3.1.1 (1)
The design value of the compression forceNEdshall be checked against the designbuckling resistance:
EN 1993-1-1 Clause 6.3.1.1 (2)
IfClass4sectionisunsymmetrical,ithastobedesignedasbeamcolumn.
HolesforfastenersatthecolumnendsneedNOT
tobe
taken
into
account
in
determining A and Aeff.
M1 = 1.00
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ReductionFactor forBucklingResistanceEN 1993-1-1 Clause 6.3.1.2
where
imperfection factor (refer to Table 6.1 & 6.2)
non-dimensional slenderness
For ,orfor , thebucklingresistancecheck
canbe
ignored
and
only
cross
sectional
checks
apply.
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Buckling lengthLcr = effective length in BS5950
No guidance given in EC3
NCCI
Use same factors as BS5950 Applied to system length, L
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ElasticCriticalForce&BucklingLength
I Second moment of area which is determined based on thegross cross sectional properties for all classes of cross-sections.
Lcr Buckling length in the buckling plane considered.
Nominal buckling lengthsLcr for compression membersNonswaymode Swaymode
where
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NonDimensionalSlendernessforFlexuralBuckling
ForClass 1, 2 and 3 cross-sections,
ForClass 4 cross-sections,
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f/fy
BucklingCurvesofImperfectColumns
=0.13=0.21=0.34
=0.49=0.76
=0
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Euler buckling curve
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Buckling curve a0 a b c d
Imperfection factor 0.13 0.21 0.34 0.49 0.76
Table 6.2: Selection of buckl ing curve for a cross-section Table 6.1: Imperfection factors for buckl ing curves
SelectionofBucklingCurveandImperfectionFactor
Imperfectionscanbeattributedtothefollowing:
initialoutofstraightness
eccentricityof
applied
loads
materialvariations
residualstresses
Typical residual stress profile in a hot-rolled I-section
Residual compressive stress
Residual tensile stress
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Design Procedure
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For each axis of buckling, determine
buckling lengthLcr Limiting slenderness
1 non-dimensional slenderness
appropriate strut curve (a0, a, b, c or d) from Table 6.2
imperfection factorfrom Table 6.1
buckling reduction factor
Design Procedure
Check ifNb,Rd>NEd. Else, repeat steps.
Use the smaller value ofto determine buckling resistanceNb,Rd.
Determine design axial forceNEd.
Select a trial section such thatNEdM0 /A
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Examples
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Example CM-1: Universal column with intermediate restraint under compression
Determine the maximum compression load that can be taken by a 5m column using203x203x60UC in S275 steel. Both ends of the column are pin supported about both y-y and
z-z axes. A lateral restraint, that is aligned to the y-y axis, is provided at mid-height.
N
N
2.5m
2.5m
AA
Section AA
z z
y
y
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Yield Strength
tw = 9.4mm, tf= 14.2mm.
Maximum thickness = 14.2mm < 16mm (EN 10025-2)
For S275 steel,fy = 275N/mm2
Section Classification = (235/fy)
0.5 = 0.92
Classification of flange
Flange is Class 1 (Plastic).
Classification of web
Web is Class 1 (Plastic).
Section is Class 1 (PLASTIC).
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Resistance of CrossSection
Flexural Buckl ing abouty-y axis
Use buckling curveb = 0.34
Buckling curve a0 a b c d
Imperfection factor 0.13 0.21 0.34 0.49 0.76
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Flexural Buckl ing aboutz-z axis
Use buckling curvec = 0.49
Buckling curve a0 a b c d
Imperfection factor 0.13 0.21 0.34 0.49 0.76
Buckl ing Resistance of Member
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Minor axis buckling (z-axis) control!
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27/9/00
.25
Lcr,y = 5m
Nby,Rd = 1710kN
Page C-13203x203x60UC in
S275 steel
Lcr,z = 2.5m
Nbz,Rd = 1710kN
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Example CM-2: Circular hollow section under compression
A circular hollow section (CHS) member is to be used in a 4m long column which is pinned atboth ends. The design axial compression,NEd, is 2400kN. Assess the suitability of a hot-rolled
244.5x10 CHS in grade 355 steel for this application.
Yield Strength
t= 10.0mm < 16mm (EN 10025-2)
For S355 steel,fy = 355N/mm2
Section Classification
= (235/fy)0.5 = 0.814
d/t= 244.5/10.0 = 24.5 502 = 33.1
Section is Class 1.
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Resistance of CrossSection
Buckling Resistance of Member
Use buckling curvea = 0.21
The chosen cross-section, 244.5x10 CHS, in grade S355 steel is not acceptable.
Try 244.5x12.5 CHS, in grade S355
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Page D-15
hot-hrolled 244.5x10
CHS in grade 355
Le =4m
Nbz,Rd = 2300kN
2400kN
adequate
NEd, is 2400kN
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Typical effective length
factor for use in
column design
=KL
K
L
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Effective length factor for continuous columns based on
stability analysis
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Pi t d f
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Pin-connected space frame
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Adequate Bracing duringConstruction
Sequence of erection
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2
3
6
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Cantilever Structure
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Cantilever trusses
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2
3
6
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Lateral bracing for
cantilever trusses
1
1
2
3
6
4
5
Purlin
Cantilever trussFly bracing
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