5-Change of Station
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Transcript of 5-Change of Station
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Homework Questions
5.3
5.5 5.6
5.8
5.9
5.13
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Change of Station
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Change of Station
R
M1
M2
Guide in center
Our initial position
Our station
assignment
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Change of Station - determineyour required course and speed for a
maneuver
e
mDRM
SRM
Reference shipscourse and speedManeuvering ships
course and speed
rm
er = guideem = your ship
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Change of station problems
utilize both the relative plot andspeed triangle to solve for the
following: Required course and speed to take station
Course to station is given
Stationing speed is given Desired time of arrival at new station is
given
Passing no closer than a specified distance
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Basic Moboard techniques for
Change of Station problems Guide in center
Determine DRM line -between old and new station
Plot er vector and rmvector, solve for em usingvariables given in problems
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Sample Change of Station problem
The guide is on course 050 T, speed 14 kts.
The guide now bears 140 T, range 7,000yds. Take station bearing 211 T, range
7,000 yds from the guide.
FIND: (A) DRM and MRM
(B) CPA bearing and range
(C) Your course to station at 20 kts.
(D) Your course to station at 15 kts.
(E) Your speed if you steer course 120 T
(F) Minimum speed to complete maneuver
(G) Your course at minimum speed
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Find: (A) DRM and MRM Plot our initial position M1 and our
assigned station position M2 Measure the distance between M1 and M2
to find the MRM
Shift the relative movement line from M1 -M2 to the center and read the DRM
Shift the M1-M2 line to the tip of the er
vector and extend the line from the r inthe direction of relative motion
Answer: DRM - 175.5 T, MRM - 11,400 ds
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Find: (B) CPA bearing and range
CPA Bearing = DRM +/- 90 degrees in the
direction of the relative movement line of therelative plot
REMEMBER BEARING IS READ FROM
OWN SHIP TO CONTACT plot line and label point of intersection with
relative movement line M3
CPA range = distance bwtn center of plot to M3
Answer = CPA bearing - 085.5 T, range 4,050 yds
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Find: (C) Your course to station
at 20 kts
You know the length of the em vector is our
ships speed - given
Measure 20 kts on dividers and swing from centerof plot e. Where it crosses rm line indicates
position of m to find the em vector
Read off the course in the direction of e to m
= our course to station Answer = Course -141 T
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Find: (D) Your course to station
at 15 kts
You know the length of the em vector is our
ships speed - given
Measure 15 kts on dividers and swing from centerof plot e. Where it crosses rm line indicates
position of m to find the em vector
Read off the course in the direction of e to m
= our course to station Answer = Course -125 T
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Find: (E) Your speed if you steer
course 120 T
You know our course - direction em vector isdrawn
Draw line from e along course 120. Where it
crosses rm line indicates position of m to findthe em vector
Measure the length of the em vector to give usour speed
Answer = Speed 13.8 kts
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Find: (F) Minimum speed to
complete maneuver
Minimum speed - slowest possible speed atwhich you can complete maneuver
represented as the SHORTEST VALUE
THE em VECTOR CAN BE DRAWN
Draw shortest line from e to the rm vector
Where it crosses rm line indicates position ofm to find the em vector
Measure the length of the em vector to giveus our speed
Answer = Speed = 11.4 kts
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Find: (G) Your course at
minimum speed Read the direction of the em vector to give us
our course
Answer = Course = 085.5 T
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Sample Time problem
The guide is on course 050 T, speed 14 kts.
The guide now bears 140 T, range 7,000yds. Take station bearing 211 T, range
7,000 yds from the guide. CO desires you to
be on station in 20 minutesFIND: (A) Course to station
(B) Speed to station
Fi d (A) C t t ti d (B)
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Find: (A) Course to station and (B)
Speed to station
Plot our initial position M1 and ourassigned station position M2
Measure the distance between M1 and M2
to find the MRM Shift the M1-M2 line to the tip of the er
vector and extend the line from the r in
the direction of relative motion Solve for SRM using required time (20
minutes) and MRM (11,500 yds) - 17.5 kts
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Draw length of rm vector 17.5 kts and
read course and speed to station as em
vector
Answer: Course - 125.5 T, Speed - 15 kts
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Passing no closer than...
10
NM
5NM
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Passing no closer than
Desire to maintain minimum passingdistance between all maneuvering
ships
each CO is different as per COsStanding Orders
3-2-1 rule for maneuvering in
formation with aircraft carriersdo not pass closer than 3,000 yards
ahead, 2,000 yards abeam, or 1,000 yards
astern of a carrier
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Homework
Do Problems 6.2, 6.6, 6.12, 7.2, 7.7,
16.4
Read Chapter 12 (Intercept)