4.4 TRIGONOMETRIC FUNCTIONS OF ANY ANGLE MATERIAL/4_4 TRIF...• Evaluate trigonometric functions of...
Transcript of 4.4 TRIGONOMETRIC FUNCTIONS OF ANY ANGLE MATERIAL/4_4 TRIF...• Evaluate trigonometric functions of...
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4.4 TRIGONOMETRIC FUNCTIONS OF ANY ANGLE
Copyright © Cengage Learning. All rights reserved.
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• Evaluate trigonometric functions of any angle.
• Find reference angles.
• Evaluate trigonometric functions of real
numbers.
What You Should Learn
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Introduction
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Introduction
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Example 1 – Evaluating Trigonometric Functions
Let (–3, 4) be a point on the terminal side of . Find the
sine, cosine, and tangent of .
Solution:
x = –3, y = 4,
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Example 1 – Solution
cont’d
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Introduction
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Reference Angles
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Reference Angles
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Reference Angles
The reference angles for in Quadrants II, III, and IV.
′ = – (radians)
′ = 180 – (degrees) ′ = – (radians)
′ = – 180 (degrees) ′ = 2 – (radians)
′ = 360 – (degrees)
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Example 4 – Finding Reference Angles
Find the reference angle ′.
a. = 300
b. = 2.3
c. = –135
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Example 4(a) – Solution
Because 300 lies in Quadrant IV, the angle it makes
with the x-axis is
′ = 360 – 300
= 60.
Degrees
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Example 4(b) – Solution
Because 2.3 lies between /2 1.5708 and 3.1416,
it follows that it is in Quadrant II and its reference angle is
′ = – 2.3
0.8416.
Radians
cont’d
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Example 4(c) – Solution
First, determine that –135 is coterminal with 225, which
lies in Quadrant III. So, the reference angle is
′ = 225 – 180
= 45.
Degrees
cont’d
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Trigonometric Functions of Real Numbers
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Trigonometric Functions of Real Numbers
By definition, you know that
sin = and tan = .
For the right triangle with acute angle ′ and sides of
lengths | x | and | y |, you have
sin ′ = =
and
tan ′ = = .
opp = | y |, adj = | x |
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Trigonometric Functions of Real Numbers
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Example 5 – Using Reference Angles
Evaluate each trigonometric function.
a. cos
b. tan(–210)
c. csc
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Example 5(a) – Solution
Because = 4 / 3 lies in Quadrant III, the reference angle
is
as shown in Figure 4.44.
Moreover, the cosine is negative in
Quadrant III, so
cont’d
Figure 4.44
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Example 5(b) – Solution
Because –210 + 360 = 150, it follows that –210 is
coterminal with the second-quadrant angle 150.
So, the reference angle is ′ = 180 – 150 = 30, as shown
in Figure 4.45.
cont’d
Figure 4.45
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Example 5(b) – Solution
Finally, because the tangent is negative in Quadrant II, you
have
tan(–210) = (–) tan 30
= .
cont’d
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Example 5(c) – Solution
Because (11 / 4) – 2 = 3 / 4, it follows that 11 / 4 is
coterminal with the second-quadrant angle 3 / 4.
So, the reference angle is ′ = – (3 / 4) = / 4, as shown
in Figure 4.46.
cont’d
Figure 4.46
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Example 5(c) – Solution
Because the cosecant is positive in Quadrant II, you have
cont’d