4-8 Augmented Matrices & Systems. Objectives Solving Systems Using Cramer’s Rule Solving Systems...
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Transcript of 4-8 Augmented Matrices & Systems. Objectives Solving Systems Using Cramer’s Rule Solving Systems...
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4-8 Augmented Matrices & Systems
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Objectives
Solving Systems Using Cramer’s Rule
Solving Systems Using Augmented Matrices
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Vocabulary
Cramer’s Rule
ax + by = mcx + dy = n dc
baD
dn
bmDx
nc
maDy
SystemUse the x- and y-coefficients.
Replace the x-coefficients with the constants
Replace the y-coefficients with the constants
D
Dx x
D
Dy yThen, &
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Use Cramer’s rule to solve the system .
Evaluate three determinants. Then find x and y.
7x – 4y = 153x + 6y = 8
D = = 547 –43 6
Dx = = 12215 –4 8 6
Dy = = 117 153 8
x = = Dx
D6127
1154
Dy
Dy = =
The solution of the system is , .6127
1154
Using Cramer’s Rule
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Find the y-coordinate of the solution of the
system .–2x + 8y + 2z = –3–6x + 2z = 1–7x – 5y + z = 2
D = = –24 Evaluate the determinant.–2 8 2–6 0 2–7 –5 1
Dy = = 20 Replace the y-coefficients with theconstants and evaluate again.
–2 –3 2–6 1 2–7 2 1
y = = – = – Find y.2024
Dy
D56
The y-coordinate of the solution is – .56
Using Cramer’s Rule with
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Vocabulary
An augmented matrix contains the coefficients and the constants from a system of equations. Each row represents an equation.
-6x + 2y = 10 4x = -20
2004
1026
System of Equations
Augmented Matrix
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Write an augmented matrix to represent the
system –7x + 4y = –3 x + 8y = 9
System of equations –7x + 4y = –3 x + 8y = 9
x-coefficients y-coefficients constants
Augmented matrix –7 4 –3 1 8 9
Draw a vertical bar to separate the coefficients from constants.
Writing an Augmented Matrix
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Write a system of equations for the augmented
matrix .9 –7 –12 5 –6
Augmented matrix 9 –7 –1 2 5 –6
x-coefficients y-coefficients constants
System of equations 9x – 7y = –12x + 5y = –6
Writing a System From an Augmented Matrix
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Vocabulary
Row Operations
To solve a system of equations using an augmented matrix, you can use one or more of the following row operations.
•Switch any two rows•Multiply a row by a constant•Add one row to another•Combine one or more of these steps
The goal is to get the matrix to the left of the line into the identity matrix. The values to the right of the line will be your solutions.
y
x
10
01 Number here will be x-value
Number here will be y-value
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Use an augmented matrix to solve the system
x – 3y = –174x + 2y = 2
1 –3 –174 2 2
Write an augmented matrix.
Multiply Row 1 by –4 and add it to Row 2.Write the new augmented matrix.
1 –3 –17
0 14 70
–4(1 –3 –17) 4 2 2 0 14 70
1141 –3 –17
0 1 5
Multiply Row 2 by .
Write the new augmented matrix.
(0 14 70) 0 1 5
114
Using an Augmented Matrix
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(continued)
1141 –3 –17
0 1 5 (0 14 70) 0 1 5
1 0 –20 1 5
1 –3 –173(0 1 5) 1 0 –2
Multiply Row 2 by 3 and add it to Row 1.Write the final augmented matrix.
The solution to the system is (–2, 5).
Check: x – 3y = –17 4x + 2y = 2 Use the original equations. (–2) – 3(5) –17 4(–2) + 2(5) 2 Substitute. –2 – 15 –17 –8 + 10 2 Multiply. –17 = –17 2 = 2
Continued
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Use the rref feature on a graphing calculator to solve the
system 4x + 3y + z = –1–2x – 2y + 7z = –10. 3x + y + 5z = 2
Step 1: Enter theaugmented matrixas matrix A.
Step 2: Use the rref featureof your graphingcalculator.
The solution is (7, –9, –2).
Using a Graphing Calculator
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(continued)
Partial Check: 4x + 3y + z = –1 Use the original equation.
4(7) + 3(–9) + (–2) –1 Substitute.
28 – 27 – 2 –1 Multiply.
–1 = –1 Simplify.
Continued
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Homework
4-8 pg 220 # 2-20 even