4-2 Warm Up

19
Determine the slope of the line that passes through each pair of points: (3, 5) and (7, 12) (-2, 4) and (5, 4) (-3, 6) and (2, -6) (7, - 2) and (7, 13) Determine the value of n so that the slope of the line through (n, 4) and (1, n) is . 2 1 4 7 m 0 m 5 12 m undefine 3 n

description

4-2 Warm Up. Determine the slope of the line that passes through each pair of points: (3, 5) and (7, 12) (-2, 4) and (5, 4) (-3, 6) and (2, -6) (7, -2) and (7, 13). - PowerPoint PPT Presentation

Transcript of 4-2 Warm Up

Page 1: 4-2 Warm Up

Determine the slope of the line that passes through each pair of points:

(3, 5) and (7, 12) (-2, 4) and (5, 4)

(-3, 6) and (2, -6) (7, -2) and (7, 13)

Determine the value of n so that the slope of the

line through (n, 4) and (1, n) is . 21

47

m 0m

512

m undefined

3n

Page 2: 4-2 Warm Up

Algebra 1 Glencoe McGraw-Hill JoAnn Evans

Math 8H

4-2

Slope and

Direct Variation

Page 3: 4-2 Warm Up

A direct variation equation is a special type of linear equation.

Every direct variation equation will graph as a line that passes through the origin. (0,

0)

x

y

Page 4: 4-2 Warm Up

The two quantities will be represented as y and x.

Written in ratio form the ratio of y to x is .

What ratio did we study in the previous lesson? SLOPE!

In direct variation equations, the slope has a different name. It is known as the “constant of

variation”.

When two quantities have a constant ratio, they are said to have a direct variation.

xy

Page 5: 4-2 Warm Up

Slope is the ratio of the change in y to the change in

x.change in y

m (SLOPE)change in x

A direct variation equation is: kxy

In a direct variation equation k is called the constant of variation. On

the graph of a direct variation equation k is the slope of the line.

Page 6: 4-2 Warm Up

Solve the direct variation equation for y.

kxy

kxy

)x()x(

kxy

A direct variation equation represents a constant rate of change.

“k” is the constant of variation

Page 7: 4-2 Warm Up

This is a graph of the direct variation

equation y = 3x.

The constant of variation is 3.

What is the slope of the line?

12

12

xxyy

313

0103

(1, 3)

(0, 0)

The slope of the line is the same

as the constant of variation.

Page 8: 4-2 Warm Up

This is a graph of the

direct variation equation

y = x.

What is the constant of

variation?

What is the slope of the line?

12

12

xxyy

41

0401

(4, 1)

(0, 0)

The slope of the line is the same

as the constant of variation.

41

41

Page 9: 4-2 Warm Up

Remember: every direct variation equation will graph as a line that passes through

the origin.

x

y

Page 10: 4-2 Warm Up

Graph y = 5x

x

y

• 1. Write the slope as a ratio.

15

5

2. Plot a point at (0, 0).

3. Walk the slope. A

slope

of tells you to go

UP 5, OVER 1.

15

4. Plot the point. Connect the two

points with a line.

Page 11: 4-2 Warm Up

Graph y = x

1. The slope is already a ratio. Assign the negative to the numerator.2. Plot a point at (0, 0).

3. Walk the slope. A

slope

of tells you to go

DOWN 3, OVER 4.

43

4. Plot the point. Connect the two

points with a line.

x

y

••

43

Page 12: 4-2 Warm Up

Graph y = x

x

y

••

52

Graph y = -x

x

y

••

What is the slope?

It’s -1. Written as a

ratio, that’s . 11

Page 13: 4-2 Warm Up

Y varies directly as x. Write a direct variation equation that relates x and y.

kxy

Use this information towrite the direct variation

equation.

( 27) k( 3) 3 3

If y = -27 when x = -3, find x when y = 108.

Using the equation, answer the question.

y 9x108 9x

9 9

12 x

x equals 12 when y = 108.

k9

kxy x9y

Page 14: 4-2 Warm Up

Y varies directly as x. Write a direct variation equation that relates x and y.

kxy

Use this information towrite the direct variation

equation.

( 15) k(5) 5 5 k3

kxy x3y

If y = -15 when x = 5, find x when y = -87.

Using the equation, answer the question.

y 3x87 3x

3 3 x29

x equals 29 when y = -87.

Page 15: 4-2 Warm Up

Y varies directly as x. Write a direct variation equation that relates x and y.

kxy

Use this information towrite the direct variation

equation.

(7.5) k(.5) .5 .5

15 k

kxy y 15x

If y = 7.5 when x = 0.5, find y when x = -0.3.

Using the equation, answer the question.

y 15x

y 15 .3 y 4.5

y equals -4.5 when x = -.3.

Page 16: 4-2 Warm Up

Y varies directly as x. Write a direct variation equation that relates x and y.

kxy

Use this information towrite the direct variation

equation.

(12) k(18) 18 18

2k

3

kxy 2

y x3

If y = 12 when x = 18, find x when y = -16.

Using the equation, answer the question.

2y x

3

216 x

3

24 x

x equals 24when y = -16.

Page 17: 4-2 Warm Up

The cost of bananas varies directly with their weight. If 3 pounds of bananas cost $2.04, find the cost of 4

pounds.

c kw

2.04 k 3 3 3

.68 k

c .68w

If c = $2.04 when w = 3, find c when w = 4.

c .68w

c .68 4

c 2.72

The cost is $2.72 for 4 lb. of bananas.

Write a direct variation equation that relates the cost, c, to the weight, w. Use the equation to answer the question.

Page 18: 4-2 Warm Up

d = rt is a direct variation equation! Distance (d) varies directly as time (t).The rate (r) is the constant of variation.

A hot air balloon’s distance of ascent varies directly as the time. The balloon ascended 372

feet in six minutes. Write a direct variation equation that relates the distance, d, to the time,

t.d = rt

(372) = r(6)

62 = r The balloon’s ascent rate is 62 feet per minute.d = 62t is the direct variation

equation.

Page 19: 4-2 Warm Up

Use the direct variation equation to find how long will it take for the balloon to rise 1209 feet.

d = 62t (1209) = 62t

19.5 = t

The balloon should ascend 1209 feet in 19.5 minutes.