3-3 Parallel Lines and Transversals. Section 3.2.
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Transcript of 3-3 Parallel Lines and Transversals. Section 3.2.
![Page 1: 3-3 Parallel Lines and Transversals. Section 3.2.](https://reader033.fdocuments.in/reader033/viewer/2022061608/5697c0211a28abf838cd2ab5/html5/thumbnails/1.jpg)
3-3 Parallel Lines and
Transversals
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Section3.2
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PROPERTIES OF PARALLEL LINES
POSTULATE
POSTULATE 15 Corresponding Angles Postulate
1
2
1 2
If two parallel lines are cut by a transversal, then the pairs of corresponding angles are congruent.
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PROPERTIES OF PARALLEL LINES
THEOREMS ABOUT PARALLEL LINES
THEOREM 3.4 Alternate Interior Angles
3
4
3 4
If two parallel lines are cut by a transversal, then the pairs of alternate interior angles are congruent.
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PROPERTIES OF PARALLEL LINES
THEOREMS ABOUT PARALLEL LINES
THEOREM 3.5 Consecutive Interior Angles
5
6
m 5 + m 6 = 180°
If two parallel lines are cut by a transversal, then the pairs of consecutive interior angles are supplementary.
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PROPERTIES OF PARALLEL LINES
THEOREMS ABOUT PARALLEL LINES
THEOREM 3.6 Alternate Exterior Angles
7
8
7 8
If two parallel lines are cut by a transversal, then the pairs of alternate exterior angles are congruent.
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PROPERTIES OF PARALLEL LINES
THEOREMS ABOUT PARALLEL LINES
THEOREM 3.7 Perpendicular Transversal
j k
If a transversal is perpendicular to one of two parallellines, then it is perpendicular to the other.
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Proving the Alternate Interior Angles Theorem
Prove the Alternate Interior Angles Theorem.
SOLUTION
GIVEN p || q
p || q Given
Statements Reasons
1
2
3
4
PROVE 1 2
1 3 Corresponding Angles Postulate
3 2 Def first -Vertical Angles Theorem
1 2 Transitive property of Congruence
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Using Properties of Parallel Lines
SOLUTION
Given that m 5 = 65°, find each measure. Tellwhich postulate or theoremyou use.
Linear Pair Postulatem 7 = 180° – m 5 = 115°
Alternate Exterior Angles Theoremm 9 = m 7 = 115°
Corresponding Angles Postulatem 8 = m 5 = 65°
m 6 = m 5 = 65° Vertical Angles Theorem
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Using Properties of Parallel Lines
Use properties ofparallel lines to findthe value of x.
SOLUTION
Corresponding Angles Postulatem 4 = 125°
Linear Pair Postulatem 4 + (x + 15)° = 180°
Substitute.125° + (x + 15)° = 180°
PROPERTIES OF SPECIAL PAIRS OF ANGLES
Subtract.x = 40°