2x + y = 13 x = 3y 4

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11419 Solving Systems by Elimination.notebook 1 November 04, 2019 11/4/19 Algebra 1 Warmup: Solve the following system by using substitution. Objectives Solving Systems by Elimination 2x + y = 13 x = 3y 4

Transcript of 2x + y = 13 x = 3y 4

11-4-19 Solving Systems by Elimination.notebook1
November 04, 2019
11/4/19   Algebra 1 Warm­up:  Solve the following system by using substitution.  
Objectives ­ Solving Systems by Elimination
2x + y = 13 x = 3y ­ 4
11­4­19 Solving Systems by Elimination.notebook
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Solving Systems by Elimination x + 2y = 7 3x ­ 2y = ­3
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Solving by elimination
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11­4­19 Solving Systems by Elimination.notebook
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11­4­19 Solving Systems by Elimination.notebook
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2018­2019 Algebra 1 Johnston Workbook.pdf
Section 4 Workbook Answer Key.pdf
Name: ___________________________
Algebra 1: Solve Systems by Graphing Quiz
1. Solve the following systems by graphing. Express your final answer as a coordinate.
Answer: ( , ) Answer: ( , )
Algebra 1: Solve Systems by Graphing Quiz
1. Solve the following systems by graphing. Express your final answer as a coordinate.
Answer: ( , ) Answer: ( , )
SMART Notebook
SMART Notebook
SMART Notebook
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Name: _____________________________________blogs.ccsd.edu/arenholz-7a/files/2017/11/Polynomials... · Web view... 2x + 1 _____ 3) 4 + 3y – 8y 3 _____4) x 2 + 6x + 5 _____ 5) x 3

Name: _____________________________________blogs.ccsd.edu/arenholz-7a/files/2017/11/Polynomials... · Web view... 2x + 1 _____ 3) 4 + 3y – 8y 3 _____4) x 2 + 6x + 5 _____ 5) x 3

€¦  · Web view2017. 12. 30. · 1st difference =2 and a=2 . y=mx+b y=ax+b Let’s ... 2x+3y+2z=3 . Eliminate the z: 2x+y-z=-5 2 2x+y-z=-5 →4x+2y-2z=-10 . 4x-2y+z=10 2x+3y+2z=3

€¦  · Web view2017. 12. 30. · 1st difference =2 and a=2 . y=mx+b y=ax+b Let’s ... 2x+3y+2z=3 . Eliminate the z: 2x+y-z=-5 2 2x+y-z=-5 →4x+2y-2z=-10 . 4x-2y+z=10 2x+3y+2z=3

Tuesday September 23, 2014 Warm-up: Put the … Solve the system using the substitution method 2x + 5y = -5 (1) x + 3y = 3 (2) Solution: Step 1. Solve (2) for x x + 3y = 3 (2) x =

Tuesday September 23, 2014 Warm-up: Put the … Solve the system using the substitution method 2x + 5y = -5 (1) x + 3y = 3 (2) Solution: Step 1. Solve (2) for x x + 3y = 3 (2) x =

2x 3y = 4 4x + 5y = 8...2x 2y = 8 2x + 2y = 4 4x + 3y = 16 2x 3y = 8 2x 3y = 4 4x + 5y = 8 5x 3y = 16 4x + 5y = 2 2.6B Systems Elimination.notebook October 18, 2018 practice due tomorrow~

2x 3y = 4 4x + 5y = 8...2x 2y = 8 2x + 2y = 4 4x + 3y = 16 2x 3y = 8 2x 3y = 4 4x + 5y = 8 5x 3y = 16 4x + 5y = 2 2.6B Systems Elimination.notebook October 18, 2018 practice due tomorrow~

Entry Task Solve for y 1) 2x + -3y < 12 2) x > ½ y - 7.

Entry Task Solve for y 1) 2x + -3y < 12 2) x > ½ y - 7.

SOLUTIONS TO PRACTICE QUESTIONS FOR THE FINAL EXAM · 18. slope of line ⇒ m = − 1 3 slope of line perpendicular ⇒ m =3 D (3 19. 2x−3y= 7 −3y = −2x+ 7 y= 2 3 x− 7 3 slope

SOLUTIONS TO PRACTICE QUESTIONS FOR THE FINAL EXAM · 18. slope of line ⇒ m = − 1 3 slope of line perpendicular ⇒ m =3 D (3 19. 2x−3y= 7 −3y = −2x+ 7 y= 2 3 x− 7 3 slope

Graph 2x-3y -8 Graph -2x-5y>15.

Graph 2x-3y -8 Graph -2x-5y>15.

Simultaneous Equations - Salford Solve the following simultaneous equations and select the correct result: 3x+3y = 0 2x+3y = 1 (a) x = 0, y = 0 (b) x = −1, y = 1 (c) x = 0, y = 1

Simultaneous Equations - Salford Solve the following simultaneous equations and select the correct result: 3x+3y = 0 2x+3y = 1 (a) x = 0, y = 0 (b) x = −1, y = 1 (c) x = 0, y = 1

C1 Edexcel Solution Bank Chapter 3 - PMT · Solve these simultaneous equations by elimination: 2x − y = 6 4x + 3y = 22 Solution: 63x − y = 18 4x + 3y = 22 Add: 10x = 40 x = 4

C1 Edexcel Solution Bank Chapter 3 - PMT · Solve these simultaneous equations by elimination: 2x − y = 6 4x + 3y = 22 Solution: 63x − y = 18 4x + 3y = 22 Add: 10x = 40 x = 4

Solve for “y” for each: 1.) 2x + y = 92.) -x = y + 3 3.) 2y – 4 = 3x4.) 2 = y – ⅓x 5.) 7x – y = -86.) 3y – 1 = -3x y = -2x + 9 y = ⅓x + 2 y = -x - 3 y.

Solve for “y” for each: 1.) 2x + y = 92.) -x = y + 3 3.) 2y – 4 = 3x4.) 2 = y – ⅓x 5.) 7x – y = -86.) 3y – 1 = -3x y = -2x + 9 y = ⅓x + 2 y = -x - 3 y.

y = 4 + 2x · 2020. 6. 16. · -5x - 3y = -23 y = -39 + 5x-4x + 5y = 20 y = 4 + 2x 7x - 2y = -66 x = -4 + 3y-2x - 5y = -56 y = 16 - 2x Solve each system of equations using substitution.

y = 4 + 2x · 2020. 6. 16. · -5x - 3y = -23 y = -39 + 5x-4x + 5y = 20 y = 4 + 2x 7x - 2y = -66 x = -4 + 3y-2x - 5y = -56 y = 16 - 2x Solve each system of equations using substitution.

S.4 Mathematics x + y –7 = 0 2x – 3y +6=0 x y 0 (3, 4) Put (3,4) into x +y –7 =0 LHS = 3+4 – 7 Put (3,4) into 2x –3y +6 =0 LHS = (2)3 – 3(4) + 6 = 0.

S.4 Mathematics x + y –7 = 0 2x – 3y +6=0 x y 0 (3, 4) Put (3,4) into x +y –7 =0 LHS = 3+4 – 7 Put (3,4) into 2x –3y +6 =0 LHS = (2)3 – 3(4) + 6 = 0.

Warmups Graph: 1. x – 3y = 6 2. y = -2x + 4 3. y – 3 = 1(x + 2) 4. y = -2 5. x = 4.

Warmups Graph: 1. x – 3y = 6 2. y = -2x + 4 3. y – 3 = 1(x + 2) 4. y = -2 5. x = 4.

Simultaneous equations SAMPLE · ... then x+y =4+3=7, and 2x+3y = 2(4)+3(3) = 17. ... 7x+3y = ¡5 f ½ 3x¡4y = ¡2 2x+3y = ¡10 ... 4x+3y = ¡11 ¡4x¡2y =6 e ½ 2x¡5y =14 4x+5y

Simultaneous equations SAMPLE · ... then x+y =4+3=7, and 2x+3y = 2(4)+3(3) = 17. ... 7x+3y = ¡5 f ½ 3x¡4y = ¡2 2x+3y = ¡10 ... 4x+3y = ¡11 ¡4x¡2y =6 e ½ 2x¡5y =14 4x+5y

Lesson 6 III. Basic Algebra. A. Simplifying Algebraic Expressions Combining like terms Ex1) Ex2) 3x – 2(x + 3y) – 4y Multiplying Binomials Ex1) (x – 3)(2x.

Lesson 6 III. Basic Algebra. A. Simplifying Algebraic Expressions Combining like terms Ex1) Ex2) 3x – 2(x + 3y) – 4y Multiplying Binomials Ex1) (x – 3)(2x.

Algebraic Expressions 2x + 3y - 7

Algebraic Expressions 2x + 3y - 7

Factor out the common binomial factor.sevillaj.weebly.com/.../p.5_factoring_polynomials_notes.pdfFactoring Polynomials x 21x! x (2x+3y)(x+y) 1 Step 2 Find two Last terms whose product

Factor out the common binomial factor.sevillaj.weebly.com/.../p.5_factoring_polynomials_notes.pdfFactoring Polynomials x 21x! x (2x+3y)(x+y) 1 Step 2 Find two Last terms whose product

 · Exercise 5.3 2x + 3y = sin x Differentiating both sides with respect to x, we get — sin x dx dx dx dy cosx — 2 dx 2x + = sin y dy dx cos x Question 2: 2x + = sin y Answer

 · Exercise 5.3 2x + 3y = sin x Differentiating both sides with respect to x, we get — sin x dx dx dx dy cosx — 2 dx 2x + = sin y dy dx cos x Question 2: 2x + = sin y Answer

Operations with Complex Numbers. Aim: Add, subtract, multiply and/or divide complex numbers in order to simplify. Simplify: 1. 2x + 3y – x + y = x + 4y.

Operations with Complex Numbers. Aim: Add, subtract, multiply and/or divide complex numbers in order to simplify. Simplify: 1. 2x + 3y – x + y = x + 4y.

Class X - NCERT Maths EXERCISE NO: 3...x 3y 6 (2) Therefore, the algebraic representation is For x – 7y = − 42, x = − 42 + 7y The solution table is For x – 3y = 6 x = 6 + 3y

Class X - NCERT Maths EXERCISE NO: 3...x 3y 6 (2) Therefore, the algebraic representation is For x – 7y = − 42, x = − 42 + 7y The solution table is For x – 3y = 6 x = 6 + 3y