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    CRYSTAL STRUCTURE AND

    CRYSTAL GEOMETRY

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    !pace lattice and unit cell

    "Physical structure of solid materials depend on the arrangement

    of atoms, ions or molecules and the bonding forces between

    them.

    " If the arrangements in a pattern that itself crystal structure(crystalline solid or crystalline materials) most metals,

    alloys

    and some ceramic.

    " Atomic arrangement can be described in network space

    lattice

    " Each space lattice can be described by specifying ite atom

    position in a repeating unit cell.

    "he si!e and shape of unit cell can be described by " lattice

    #ectors (a, b, c) and intera$ial angels , and are the latticeconstantof the unit cell.

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    Figure 3.1

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    Crystal systems and #ra$ais %attices

    " %nly se#en different types of unit cell create all point lattices" &ra#ais showed that ' standard unit cell to describe all

    possible lattice network.

    " basic types of unit cells simple, body-centred, face-centred

    and base-centred.

    "he si!e and shape of unit cell can be described by " lattice#ectors (a, b, c) and intera$ial angels , and are the latticeconstantof the unit cell.

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    Figure 3.2

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    Metallic crystal structures

    " *+ elemental metal crystallise when solidified" " form of packed crystal structure are

    - &ody-centred cubic, face-centred cubic and he$agonal

    closed packed

    " nit cell are #ery small, e.g &// iron has a 0 +.123 nm.

    if unit cells of pure irons are line up side by side in ' mm,there will be ".2 $ '+4 unit cell ('mm /+.123 $'+-4 mm)

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    Figure 3.3

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    #ody-centred cu&ic '#CC( structure

    " he central atom is surrounded by 2 nearest neighbours 2coordination number" Each unit cells has the e5ui#alent of two atoms per-unit

    cell.

    " 6elationship between the lattice constant, a and atomic radius,

    6

    ry e.g. ".' pg "

    "

    Ra=

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    Figure 3.4

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    Figure 3.5

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    )tomic pac*ing actor ')P+(

    cellunitofvol

    cellunitinatomsofvolAPF

    .

    .=

    ry e.g. ".1 pg

    C G C

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    +ace-centred cu&ic '+CC( structure

    " Each atom is surrounded by '1 nearest neighbours '1coordination number

    " Each unit cells has the e5ui#alent of four atoms per-unit

    cell.

    " 6elationship between the lattice constant, a and atomic radius,

    6

    1

    Ra=

    ry AP7 for 7// (+.3)

    C i ht Th M G Hill C i I P i i i d d ti di l

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    Figure 3.6

    C i ht Th M G Hill C i I P i i i d d ti di l

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    Figure 3.7

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    Heaganol closed-pac*ed 'HCP( structure" Each atom is surrounded by '1 nearest neighbours '1

    coordination number

    " Each unit cells has the e5ui#alent of 4 atoms per-unit

    cell (2 $ 8 9 1 (4 $ ':4) 0 4) .

    ry e.g ".", pg

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    Figure 3.8

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    Figure 3.9

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    Atomic Positions in cubic unit cells

    "o locate the atom position in unit cells, $,y,! a$es are

    used

    7or e.g. the position of atom in in &// are as shown in

    7igure ".'+.

    ry with 7//;

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    Figure 3.10

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    Figure 3.11

    ry e.g. "., ". and ".4

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    py g p , q p p y

    ++'?,

    =

    indices of a family or form

    ?+''>

    ?'++>

    ++'

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    py g p , q p p y

    Example 3.4

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    py g p q p p y

    Example 3.5

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    Example 3.6

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    =iller Indices for crystallographic planes in unit cubic cells

    " =iller indices is used to identify crystal planes in a cubic

    crystal structure.

    "he procedures to obtain miller indices for cubic crystal plane

    - /hoose the plane that does not pass through the origin at

    (+,+,+).

    -

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    Figure 3.13

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    Figure 3.14

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    Example 3.7

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    Interplanar spacing

    " he direction indices of a direction perpendicular to the

    crystal plane as the same as the miller indices of that plane

    (applied only for cubic system).

    7or e.g. >'++? direction is perpendicular to the ('++) crystal

    plane.

    " Interplanar spacing (dhkl) is the distance between two closestparallel planes with the same miller indices

    111

    lkh

    ad lkh

    ++

    =

    ry /u has an 7// crystal structure and a unit cell with the a0 +."4'nm.

    Chat is the interplanar spacing d11+D (pg 3)

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    Figure 3.15

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    Figure 3.16

    /P unit cell are

    identified using indices,

    (hkil) which based on

    /oordinate system with a$es, a', a1, a"and c

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    Folume, planar and linear density of unit cell

    sing hard sphere atomic model

    " #0 (mass:unit cell)/(#olume:unit cell)

    " p 0 (e5ui#. no. of atoms whose center are intersected by selected area)/

    (selected area)

    " l 0 (no. of atomic diameter intersected by selected length of linein the direction of interest)/(selected length of line)

    ry E$ample page '+, '-"

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    Figure 3.17

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    Figure 3.23

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    Crystal structure analysis

    Analysis of crystal structure can be obtained using $-rays

    diffraction techni5ues ($-ray diffractometer).&y referring to 7igure ".12,

    n0 =P 9 P@ (n 0 ',1,",G.%rder of the diffraction)

    &oth =P and P@ e5ual to dhklsin ,

    n = 2 dhklsin (Braggs law)

    Hi#es the relationship between the $-ray radiation and

    interplanar spacings dhkl of the crystal plane. In most case thefirst order of diffraction is used (n0'), &raggBs law become

    = 2 dhklsin

    Tr e. . 10 no.4

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    Figure 3.28

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    Figure 3.29

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    Polymorphism or allotropy

    ame element can e$ist in more than one crystallineform. 7or e.g. iron e$ist in both &// and 7// crystal

    structures o#er a temperature range from room

    temperature to its melting point.

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    LEARNING OUTCOMES: At the end of this chapter youshould e ale to:

    J Identify what signify the crystalline material

    J E$plain space lattice and identify some important crystal system todescribe certain elements

    J Identify main crystal systems for metallic crystal structures

    J /alculate the lattice constant (a) and atomic packing factor (AP7)for different type of crystal systems

    J