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Transcript of 2110Crystal_Oct2015
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CRYSTAL STRUCTURE AND
CRYSTAL GEOMETRY
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!pace lattice and unit cell
"Physical structure of solid materials depend on the arrangement
of atoms, ions or molecules and the bonding forces between
them.
" If the arrangements in a pattern that itself crystal structure(crystalline solid or crystalline materials) most metals,
alloys
and some ceramic.
" Atomic arrangement can be described in network space
lattice
" Each space lattice can be described by specifying ite atom
position in a repeating unit cell.
"he si!e and shape of unit cell can be described by " lattice
#ectors (a, b, c) and intera$ial angels , and are the latticeconstantof the unit cell.
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Figure 3.1
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Crystal systems and #ra$ais %attices
" %nly se#en different types of unit cell create all point lattices" &ra#ais showed that ' standard unit cell to describe all
possible lattice network.
" basic types of unit cells simple, body-centred, face-centred
and base-centred.
"he si!e and shape of unit cell can be described by " lattice#ectors (a, b, c) and intera$ial angels , and are the latticeconstantof the unit cell.
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Figure 3.2
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Metallic crystal structures
" *+ elemental metal crystallise when solidified" " form of packed crystal structure are
- &ody-centred cubic, face-centred cubic and he$agonal
closed packed
" nit cell are #ery small, e.g &// iron has a 0 +.123 nm.
if unit cells of pure irons are line up side by side in ' mm,there will be ".2 $ '+4 unit cell ('mm /+.123 $'+-4 mm)
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Figure 3.3
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#ody-centred cu&ic '#CC( structure
" he central atom is surrounded by 2 nearest neighbours 2coordination number" Each unit cells has the e5ui#alent of two atoms per-unit
cell.
" 6elationship between the lattice constant, a and atomic radius,
6
ry e.g. ".' pg "
"
Ra=
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Figure 3.4
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Figure 3.5
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)tomic pac*ing actor ')P+(
cellunitofvol
cellunitinatomsofvolAPF
.
.=
ry e.g. ".1 pg
C G C
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+ace-centred cu&ic '+CC( structure
" Each atom is surrounded by '1 nearest neighbours '1coordination number
" Each unit cells has the e5ui#alent of four atoms per-unit
cell.
" 6elationship between the lattice constant, a and atomic radius,
6
1
Ra=
ry AP7 for 7// (+.3)
C i ht Th M G Hill C i I P i i i d d ti di l
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Figure 3.6
C i ht Th M G Hill C i I P i i i d d ti di l
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Figure 3.7
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Heaganol closed-pac*ed 'HCP( structure" Each atom is surrounded by '1 nearest neighbours '1
coordination number
" Each unit cells has the e5ui#alent of 4 atoms per-unit
cell (2 $ 8 9 1 (4 $ ':4) 0 4) .
ry e.g ".", pg
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Figure 3.8
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Figure 3.9
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Atomic Positions in cubic unit cells
"o locate the atom position in unit cells, $,y,! a$es are
used
7or e.g. the position of atom in in &// are as shown in
7igure ".'+.
ry with 7//;
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Figure 3.10
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Figure 3.11
ry e.g. "., ". and ".4
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py g p , q p p y
++'?,
=
indices of a family or form
?+''>
?'++>
++'
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py g p , q p p y
Example 3.4
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py g p q p p y
Example 3.5
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Example 3.6
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=iller Indices for crystallographic planes in unit cubic cells
" =iller indices is used to identify crystal planes in a cubic
crystal structure.
"he procedures to obtain miller indices for cubic crystal plane
- /hoose the plane that does not pass through the origin at
(+,+,+).
-
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Figure 3.13
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Figure 3.14
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Example 3.7
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Interplanar spacing
" he direction indices of a direction perpendicular to the
crystal plane as the same as the miller indices of that plane
(applied only for cubic system).
7or e.g. >'++? direction is perpendicular to the ('++) crystal
plane.
" Interplanar spacing (dhkl) is the distance between two closestparallel planes with the same miller indices
111
lkh
ad lkh
++
=
ry /u has an 7// crystal structure and a unit cell with the a0 +."4'nm.
Chat is the interplanar spacing d11+D (pg 3)
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Figure 3.15
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Figure 3.16
/P unit cell are
identified using indices,
(hkil) which based on
/oordinate system with a$es, a', a1, a"and c
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Folume, planar and linear density of unit cell
sing hard sphere atomic model
" #0 (mass:unit cell)/(#olume:unit cell)
" p 0 (e5ui#. no. of atoms whose center are intersected by selected area)/
(selected area)
" l 0 (no. of atomic diameter intersected by selected length of linein the direction of interest)/(selected length of line)
ry E$ample page '+, '-"
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Figure 3.17
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Figure 3.23
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Crystal structure analysis
Analysis of crystal structure can be obtained using $-rays
diffraction techni5ues ($-ray diffractometer).&y referring to 7igure ".12,
n0 =P 9 P@ (n 0 ',1,",G.%rder of the diffraction)
&oth =P and P@ e5ual to dhklsin ,
n = 2 dhklsin (Braggs law)
Hi#es the relationship between the $-ray radiation and
interplanar spacings dhkl of the crystal plane. In most case thefirst order of diffraction is used (n0'), &raggBs law become
= 2 dhklsin
Tr e. . 10 no.4
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Figure 3.28
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Figure 3.29
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Polymorphism or allotropy
ame element can e$ist in more than one crystallineform. 7or e.g. iron e$ist in both &// and 7// crystal
structures o#er a temperature range from room
temperature to its melting point.
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LEARNING OUTCOMES: At the end of this chapter youshould e ale to:
J Identify what signify the crystalline material
J E$plain space lattice and identify some important crystal system todescribe certain elements
J Identify main crystal systems for metallic crystal structures
J /alculate the lattice constant (a) and atomic packing factor (AP7)for different type of crystal systems
J