2012 Jun Enunciado
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Transcript of 2012 Jun Enunciado
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7/25/2019 2012 Jun Enunciado
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x(t) =
k=
xkej 2
T
kt
x(t) = a0
2 +
k=1
akcos
2
T kt
+
k=1
bksin
2
T kt
ak bk
x0 = a02
xk= 1
2(ak jbk) xk =
1
2(ak+ jbk)
T = 2
x(t) =
8
2
sin t
1
9sin 3t +
1
25sin 5t
1
49sin 7t +
t
x(t)
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7/25/2019 2012 Jun Enunciado
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x(t) ak= 0 xk {xk} = 0 xk= xk
ak bk xk
x1(t) x1(t)
x2(t)
x3(t) x2(t)
x[n] N = 4
ak =1
2
|k| k= 1, 0, 1 2
y[n] x[n]
h1[n] =
sin(
4n)
n
2cos(
2n)
y[n] ej
2n
w[n] h2[n]
nx ny nw nz
][2
nh][1
nh
nj
e 2
z[n] h2[n] z[n]2z[n 1] + 2z[n 2] =w[n] w[n 1]
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a
x[n] y[n]
h1[n] = anu[n 1]
nx n][1 nh
h1[n]
nx n+
1
h1[n] h2[0] = 1 h2[1] =2a h2[n] = 0 n 2 n
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h(t) =
1 |t|< T10 |t| T1
x(t) =
n=
A(t n)
T1 A
y(t) = 1
Ha(j)
!"#$%&'()#
!"#+#,"-.('/&%0"
!"#$%&'()#
.('/&%0"-!"#+#,"
1(2,&3 4
5467 467
1(2,&3 8
597 97
1(2,&3 :
44
;
;3?0@
x(t) X(j)
H(ej) xp(t) x(t)
xd[n]
xa(t)
xa(t)