2012 Jun Enunciado

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    x(t) =

    k=

    xkej 2

    T

    kt

    x(t) = a0

    2 +

    k=1

    akcos

    2

    T kt

    +

    k=1

    bksin

    2

    T kt

    ak bk

    x0 = a02

    xk= 1

    2(ak jbk) xk =

    1

    2(ak+ jbk)

    T = 2

    x(t) =

    8

    2

    sin t

    1

    9sin 3t +

    1

    25sin 5t

    1

    49sin 7t +

    t

    x(t)

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    x(t) ak= 0 xk {xk} = 0 xk= xk

    ak bk xk

    x1(t) x1(t)

    x2(t)

    x3(t) x2(t)

    x[n] N = 4

    ak =1

    2

    |k| k= 1, 0, 1 2

    y[n] x[n]

    h1[n] =

    sin(

    4n)

    n

    2cos(

    2n)

    y[n] ej

    2n

    w[n] h2[n]

    nx ny nw nz

    ][2

    nh][1

    nh

    nj

    e 2

    z[n] h2[n] z[n]2z[n 1] + 2z[n 2] =w[n] w[n 1]

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    a

    x[n] y[n]

    h1[n] = anu[n 1]

    nx n][1 nh

    h1[n]

    nx n+

    1

    h1[n] h2[0] = 1 h2[1] =2a h2[n] = 0 n 2 n

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    h(t) =

    1 |t|< T10 |t| T1

    x(t) =

    n=

    A(t n)

    T1 A

    y(t) = 1

    Ha(j)

    !"#$%&'()#

    !"#+#,"-.('/&%0"

    !"#$%&'()#

    .('/&%0"-!"#+#,"

    1(2,&3 4

    5467 467

    1(2,&3 8

    597 97

    1(2,&3 :

    44

    ;

    ;3?0@

    x(t) X(j)

    H(ej) xp(t) x(t)

    xd[n]

    xa(t)

    xa(t)