For Edexcel

GCSE Mathematics

Foundation Tier

Paper 1A (Non-Calculator)Marking Guide

Method marks (M) are awarded for knowing and using a correct method.

Accuracy marks (A) are awarded for correct answers, having used a correct method.

(B) marks are independent of method marks.

(C) marks are for communication.

Written by Shaun ArmstrongOnly to be copied for use in the purchaser's school or college

2012 EFA Paper 1 marks Page 1 Churchill Maths Limited

Foundation Tier Paper 1A Marking Guide

1 (a) Busrah B1

(b) 6 B1

(c) Abraham B1

(d) Dabir B1 Total 4

2 (a) forty thousand three hundred B1

(b) 610 205 B1

(c) (i) = 8 + 6 = 14 B1

(ii) = 3 + 14 = 17 B1 Total 4

3 (a) 34 B1

(b) 0.3 B1

(c) 22 B1

(d) = 36300 100% = 363 % = 12% M1 A1 Total 5

4 (a) 26 g B1

(b) 9.2 cm B1

(c) 92 mm B1 Total 3

5 (a) (i) 62 B1

(ii) alternate angles B1

(b) (i) 180 105 = 75180 (62 + 75) = 180 137 = 43 B1

(ii) e.g. angles on a straight line total 180 andangles in a triangle total 180 B1 Total 4

2012 EFA Paper 1 marks Page 2 Churchill Maths Limited

0.5 10

0.5 10

0.5 10

6 (a) B1

(b) B1

(c) B1

(d) e.g. the letter D being picked B1 Total 4

7 (a) 60 C (from graph) B1

(b) 176 F (from graph) B1

(c) 32 F (from graph) B1 Total 3

8 (a) paid out 20.00 B1

(b) 5.00, 25.00, 48.00, 60.50, 124.50 B2

(c) 3rd to 4th, 14th to 25th M12 + 12 = 14 days A1 Total 5

9 38 of 80 = 30, 15 of 80 = 16 M1

no. of novels = 80 (30 + 16) = 80 46 = 34 M1 A1 Total 3

10 car = 10 mins + 3 hrs 20 mins = 210 mins M1train = 20 mins + 2 hrs 35 mins = 175 minsratio is 210 : 175 M1

= 42 : 35= 6 : 5 A1 Total 3

11 (a) I B1

(b) F B1

(c) G B1 Total 3

*12 (a) e.g. it is a leading question C1

[ valid reason expressed clearly ]

(b) e.g. no option to answer 0 C1groups overlap (4 is in 2nd and 3rd choices) C1 Total 3

[ valid criticisms expressed clearly ]

2012 EFA Paper 1 marks Page 3 Churchill Maths Limited

Buy FreeR C

W BW C

S CS B

R B

13 (a) equilateral B1

(b) rhombus B1

(c) obtuse B1

(d) angle AEC = 180 60 = 120 M1opposite angles of rhombus are equal, angle ABC = 120 A1 Total 5

14 e.g. twenty 5p coins = 153 coins left, worth 88p M1 A1if all 53 are 1p coins, value = 53pneed extra 35p so 35 of them must be 2p coins M1 A1 Total 4

15 M1 A1

Total 2

16 (a) B2

(b) 16 B1 Total 3

17 (a)B2

(b)B2

Total 4

2012 EFA Paper 1 marks Page 4 Churchill Maths Limited

18 (a) B2x 1 0 1 2y 4 1 2 5

(b) B2

(c) y = 3x 3 B1 Total 5

19 (a) 230 B1

(b) 3300 B1

* (c) 1500 costs 280 M150% more = 1.5 280 = 420420 buys 4400 leaflets M1e.g. yes, as 4400 is nearly 3 times 1500 C1 Total 5

[ consistent conclusion following valid method ]

*20 e.g. if the card is 310 mm thick,

total thickness = 45 310 = 13510 = 13.5 mm M1 A1

14 mm is more than this so card must be thick enough C1 Total 3

[ valid method involving calculation, clear determination of whether card is thick enough ]

21 1 0.88 = 0.12 M1p = 0.12 4 = 0.03 M1 A1 Total 3

2012 EFA Paper 1 marks Page 5 Churchill Maths Limited

1

2

4

3

5

y

1 2 x1

4

2

3

1O

22 e.g. each pattern has 3 more dots than previous one M1to get from pattern 1 to 50 we add 49 lots of 3 M14 dots in pattern 1number of dots in pattern 50 = 4 + 49 3 = 151 M1 A1 Total 4

23 (a) = 5 7 = 35 M1 A1

(b) T5

= n m M1

n = T5 + m [ or n = T 5 m

5 ] A1 Total 4

24 sides of missing triangle are 4 m and 5 m B1area = 6 8 12 4 5 M1 = 48 10 = 38 m2 A1cost = 50 38 = 3800 2 = 1900 M1 A1 Total 5

25 bought for 30 15 = 450 B1sold for 16 25 + 12 20 + 16.50 + 9.20 M1

= 400 + 240 + 25.70= 665.70 A1

profit = 665.70 450 = 215.70 M1 A1 Total 5

26 (a) (b)

M1 A1

M1 A1

Total 4

TOTAL FOR PAPER: 100 MARKS

2012 EFA Paper 1 marks Page 6 Churchill Maths Limited

1

2

4

3

5y

1 2 43 5 6 7 8 x6 5 34 2 1

5

4

2

3

1O

A

C

B