2011 May TZ1 HL Paper3_questions
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M11/5/MATHL/HP3/ENG/TZ0/SE
MATHEMATICSHIGHER LEVELPAPER 3 – SERIES AND DIFFERENTIAL EQUATIONS
Monday 9 May 2011 (morning)
INSTRUCTIONS TO CANDIDATES
y�Do not open this examination paper until instructed to do so.y�Answer all the questions.y�Unless otherwise stated in the question, all numerical answers must be given exactly or correct
to three significant figures.
2211-7208 3 pages
1 hour
© International Baccalaureate Organization 2011
22117208
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M11/5/MATHL/HP3/ENG/TZ0/SE
2211-7208
– 2 –
Please start each question on a new page. Full marks are not necessarily awarded for a correct answer with no working. Answers must be supported by working and/or explanations. In particular, solutions found IURP�D�JUDSKLF�GLVSOD\�FDOFXODWRU�VKRXOG�EH�VXSSRUWHG�E\�VXLWDEOH�ZRUNLQJ��H�J��LI�JUDSKV�DUH�XVHG�WR�¿QG� a solution, you should sketch these as part of your answer. Where an answer is incorrect, some marks may be given for a correct method, provided this is shown by written working. You are therefore advised to show all working.
1. [Maximum mark: 10]
� �D�� )LQG�WKH�¿UVW�WKUHH�WHUPV�RI�WKH�0DFODXULQ�VHULHV�IRU� ln ( )1+ ex. [6 marks]
� �E�� +HQFH��RU�RWKHUZLVH��GHWHUPLQH�WKH�YDOXH�RI� lim ln ( ) lnx
x xx→
+ − −0 22 1 4e
. [4 marks]
2. [Maximum mark: 8]
� &RQVLGHU�WKH�GLIIHUHQWLDO�HTXDWLRQ� ddyx
x y= +2 2 �ZKHUH� y =1�ZKHQ� x = 0 .
� �D�� 8VH� (XOHU¶V� PHWKRG� ZLWK� VWHS� OHQJWK� ���� WR� ¿QG� DQ� DSSUR[LPDWH� YDOXH� RI� �y ZKHQ� x = 0.4 . [7 marks]
� �E�� :ULWH�GRZQ��JLYLQJ�D�UHDVRQ��ZKHWKHU�\RXU�DSSUR[LPDWH�YDOXH�IRU��y��LV�JUHDWHU�WKDQ�RU�OHVV�WKDQ�WKH�DFWXDO�YDOXH�RI��y . [1 mark]
3. [Maximum mark: 11]
� 6ROYH�WKH�GLIIHUHQWLDO�HTXDWLRQ
x yx
y xy x2 2 23 2dd
= + +
� JLYHQ�WKDW� y = −1�ZKHQ� x =1 ���*LYH�\RXU�DQVZHU�LQ�WKH�IRUP� y f x= ( ) .
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M11/5/MATHL/HP3/ENG/TZ0/SE
2211-7208
– 3 –
4. [Maximum mark: 15]
� 7KH�LQWHJUDO� In �LV�GH¿QHG�E\ I x xnx
n
n= −+
∫ e dπ
π( )| sin |
1��IRU� n∈` .
� �D�� 6KRZ�WKDW� I0121= + −( )e π
. [6 marks]
� �E�� %\�OHWWLQJ� y x n= − π ��VKRZ�WKDW� I Inn= −e π
0 . [4 marks]
� �F�� +HQFH�GHWHUPLQH�WKH�H[DFW�YDOXH�RI� e d−∞
∫ x x x0
| sin | . [5 marks]
5. [Maximum mark: 16]
� 7KH�H[SRQHQWLDO�VHULHV�LV�JLYHQ�E\� exn
n
xn
==
∞
∑ !0.
� �D�� )LQG�WKH�VHW�RI�YDOXHV�RI��x��IRU�ZKLFK�WKH�VHULHV�LV�FRQYHUJHQW� [4 marks]
� �E�� �L�� 6KRZ��E\�FRPSDULVRQ�ZLWK�DQ�DSSURSULDWH�JHRPHWULF�VHULHV��WKDW�
ex xx
− <−
1 22
��IRU�0 2< <x .
� � �LL�� +HQFH�VKRZ�WKDW� e < +−
⎛⎝⎜
⎞⎠⎟
2 12 1
nn
n
��IRU� n∈ +] . [6 marks]
� �F�� �L�� :ULWH�GRZQ� WKH�¿UVW� WKUHH� WHUPV�RI� WKH�0DFODXULQ� VHULHV� IRU� 1− −e x and
H[SODLQ�ZK\�\RX�DUH�DEOH�WR�VWDWH�WKDW
12
2
− > −−e x x x ��IRU�0 2< <x .
� � �LL�� 'HGXFH�WKDW� e >− +
⎛⎝⎜
⎞⎠⎟
22 2 1
2
2n
n n
n
��IRU� n∈ +] . [4 marks]
� �G�� /HWWLQJ� n =1000��XVH�WKH�UHVXOWV�LQ�SDUWV��E��DQG��F��WR�FDOFXODWH�WKH�YDOXH�RI�H�FRUUHFW�WR�DV�PDQ\�GHFLPDO�SODFHV�DV�SRVVLEOH� [2 marks]