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Transcript of 2010_01_12_3DBeam_CDT6
A preliminary design tool for composite A preliminary design tool for composite structures : 3D structures : 3D Beam II, v 5.51Beam II, v 5.51
CDT 6, Jan 15, 2010
Sung K. Ha, Mustafa Ghulam, Lei Xu & Stephen Tsai
Stanford Composite Design TeamStanford University
1
y
3D Beam II
MS Excel based User-friendly finite element analysis program
for beam or frame type structures
Structure with large slenderness ratio Structure with large slenderness ratio (long compared to cross-section)
Three dimensional grid, frame structures Tapered / Untapered beam structure Arbitrary ply drop off
A bit l d (3 f / 3 t ) t l ti Arbitrary loads (3 forces / 3 moments) at any location Multiply connected frames Modal analysis Modal analysis
An accurate, yet easy-to-use tool !!
2
Beam modeling of 3D structures
Beam analysis3D geometry- Fast
Si l- Slow
Complicated[A]n,[B]n,[D]n
- Simple- Complicated
[A]k,[B]k,[D]k
[A]2,[B]2,[D]2
[A]1,[B]1,[D]1
3
FEM formulation for a composite beam
1 1 3 2 2 3( , , )u x y z d x x
1) Displacement 3 3,d
At each node (6 dof)
2 2 3 1( , , )u x y z d x
3 3 2 1( , , )u x y z d x d
2 2,d Laminates
11 1 1
13
22
3 u d x x 22 2 2 0 u 33 3 3 0 u
2) strain-displacement
'n3 n1' ''
n3' n2''
1 1,d
11 1 11
31
21x x x, 22 2 2, 33 3 3,
12 1 2 2 1 3
2
13
1
1
12
12
( ), ,u u d
xx
x
n1n2=n2'
n3'
n1
n2'n1'=n1''
n3'' n2
13 1 3 3 1 2
3
12
1
1
12
12
( ), ,u u d
xx
x
23 2 3 3 2 1 112
12
0 ( ), ,u u
1 1 1 1
2 1 2 2 1 2 2
3 1 2 2 1 2 3
0d C S Dd S S C C S Dd S C S C C D
2 2
1 11 1 3 2 2 3
5 13 5 2 122
x xx
4
6 12 6 3 12 x
FEM formulation for a composite beam
1
5
11 15 16
15 55 56
1
5
1
5
Local
C C CC C C C
3) Constitutive equation (stress-strain) 4) F.E. formulation
d d dT
1
MD'
5
6
15 55 56
16 56 66
5
6
5
6
local local local
Local
localC C C
1 11 16 15 2 15 3 16 3 11 2 11
1
6
C C C x C x C x C x C
d d d
1 5 6 5
6
MD
d N d N iih
a ai ih
aa ai
a
, , ,
1
2
1
2
1 2 3( )
5
6
15 56 55 2 55 3 56 3 15 2 15
16 66 56 2 56 3 66 3 16 2 16
5
1
2
3
C C C x C x C x C x CC C C x C x C x C x C
D'
k B DB B DBe T Txdx jd
e
( ) ( ) 12
11 16 15 11 12 131 1
66 56 21 22 232 6
A G G B B BFG G B B BF
G B B BF
Resultants Loads vs strains
k B DB B DBx
dx jde
( ) ( )
1155 31 32 333 5
11 12 131 1
22 232 2
333 3
.
G B B BFD D DM
sym D DMDM
2
1
1
1( )
e
e
xe
xN dx N jd
f f f
2 1( )
exe N dx N jd m m mM
e e e e ed d m +k f MD+KD F
1 1( )
exN dx N jd
m m m
F
3F
3M
2F 2M
11 2 3. .,e g A dx dx 11= CLaminates
5
d dm +k f MD+KD F1F
1M
FEM formulation for a composite beam
3 3,d 3Q
3M
2 2,d
Laminates
1N2Q 2M
1 1,d 1
1M1x
5) strain-displacement
6) Constitutive equation (macro strain macro stress) MMF •Failure
SMM+
F b F i( )1 2 6
7) Failure criterion : Quadratic Tsai-Wu criterion
(macro strain macro stress) MMF •Fatigue Life
a F b F iij i j i i , ( , , )1 2 6
aR bR2 1 0 R
0 : safe0 : fail
kR
1 0 : fail0 : safe
Strength ratio
6
0 : fail
Coordinate Transformation for 3D Post-processingn
Plies
X3x3
t
(If = 0°, the reference X2-axis is parallel to the global X-Y plane.)
Z
L#n1
n2n
Bricksx2
Laminates n
bxs
TxI
J
J
X2
X1
X3
X3X1
t s nX2
b
,G Ix
I J
X1 Y
I
I
X2
X3X2
X2
X3
X1
t s n(1,0,0)s
h t
,g Ix Global coordinates (X-Y-Z)
X
J
S
,2B T bx x t xZ
, ,G I T g I x Tx x Reference coordinates (X1-X2-X3)
Local coordinates (x1-x2-x3)YX
, ,G g
T: a transformation matrix from (s, n,t) to (S,X2,X3)
local node#
1 46 7
85
n
tlocal node#
7
3D Beam v5.4x; worksheet : PostProcess-I 32 s
Coordinate systems and Layup direction
ZY
Structure
X₂X₃
Element
Ply
Fiber direction
X X₁ , ply angle
X1
, p y g
Cross Section
X
Plies
Bricks
X3
x2
x3
LaminatesLayup Sequence
Global coordinates (X-Y-Z)
X2
n2nt n3
y p qDirection, t
( )
Reference coordinates (X1-X2-X3)
L#n1
8
Local coordinates (x1-x2-x3)
Program Flow : 3D Beam II
Main Analysis ModulesInput Output
Step 1 : Section & Material• Cross Section
• Material property
• Displacement & Rotation
• Global Strains & Curvatures
Step 2 : Global Geometry
Material property
• Nodes (Global coordinates)
• Global Loadings & Moments
• In-Plane Strains
Step 3 : Loads
•Elements (node connectivity)
• Boundary conditions
• In-Plane Loads
• Strength Ratios
• Mode shape & NaturalStep 3 : Loadsy
• Global ForcesMode shape & Natural
Frequency
Step 4 : Solve
Graphical Post Processor:3D contour Plot tool
9
3D contour Plot tool,HUSAP
Version updated3D BEAM “M i ” h
Version 5.xx
3D BEAM “Main” sheet
Import and export input files(*.3db)
Modal analysis
Version 5.xx
Modal analysis (up to 10 mode)
10
Step 1 : Specification of Plies, Laminates and Sections3D BEAM “S i DB” h
[A]n,[B]n,[D]n3D BEAM “Section DB” sheet
(4)
[A] [B] [D]
[ ]n,[ ]n,[ ]n
[A]k,[B]k,[D]k
[A]2,[B]2,[D]2
pliesbricks
X3x3
Laminates
[A]1,[B]1,[D]1
bricks
X2
x2
(2 (3)
brick nodesMaterial DB sheet
• SI unit
Laminate nodes
)
(1)p8
Ply group number(2)
L2 L3
p1
p
…
(4)
(2)
•English unit
L1
L2
(3) (x2,x3)
11
Laminates in a rectangular thin-wall cross section
2
x3[03/45/-45/902]s
(2 , 1)(-2 , 1)
x3
a1a2 a1a2
Direction of ply sequencea1a2
n
t
1
x22" 3 x2
x1 t
2
4"
4
(-2 , -1) (2 , -1)
x1
Laminate #1
x1
Laminate #1
Laminate #2 a1a2
Laminate #3
Laminate #4
12
Base Line Option :0
Step 2 : Global Geometry (nodes and elements)3D BEAM “Gl b l h ”3D BEAM “Global geometry sheet”
[A]n,[B]n,[D]n
[A]k,[B]k,[D]k
[A]2,[B]2,[D]2
13
[A]1,[B]1,[D]1
Varying Sections
Z
21 3 4 Element #
X
1 2 32 Group #Section (group) #
[A]2[B]2[D]2
1 2 43 521 3 4
[A]1[B]1[D]1 [A]3[B]3[D]3
N d #
1 2 32
element #Section (group) #
1 2 43 5 Node #
14
Step 3 : Loads3D BEAM “L d h ”
Displacements & Rotations
3D BEAM “Loads sheet”
Displacements & Rotations
U3
Y
Z
X U
U2
X U1
Forces & Moments
[A]n,[B]n,[D]n
Forces & Moments
Z
F3
M3
M2
[A]k,[B]k,[D]k
[A]2,[B]2,[D]2
Y
X F1 M1
F2
15
[A]1,[B]1,[D]1 Global coordinates (X-Y-Z)
Step 4 : Results3D BEAM “R l h ”
Displacements & Rotations
Displacement chart Global resultant stress
3D BEAM “Results sheet”
Displacements & Rotations
U3
Y
Z
X U
U2
X U1
Forces & Moments
In plane load Strength ratio
Forces & Moments
Z
F3
M3
M2
Y
X F1 M1
F2
16
Global coordinates (X-Y-Z)
Step 4 : Results
Deflection along the X‐axis0.02
Cross‐sectionY 1kN
‐0.005
0
0.005
0 0.1 0.2 0.3 0.4 0.5 0.6
U₁
0.005
0.01
0.015
z_b
0.03m
0.5m
X
0 025
‐0.02
‐0.015
‐0.01U₁
U₂
U₃
‐0.015
‐0.01
‐0.005
0
‐0.02 ‐0.015 ‐0.01 ‐0.005 0 0.005 0.01 0.015 0.02
zT
zB
Cross-section:20 segments (laminates)
‐0.03
‐0.025
‐0.02
At each section, in-plan loads, strains and strength ratios
20 segments (laminates)
0 2
0.4
0.6
0.8
In Plane stress at Element # 1
N1
N2
N6 0.002
0.004
0.006
In Plane strain at Element # 1
e1
e2
e60.40.60.81
1.21
23
4
517
18
1920
Failure Index (1/R)
‐0.6
‐0.4
‐0.2
0
0.2
0 5 10 15 20 25
‐0.004
‐0.002
0
0 5 10 15 20 25
e6
00.2
6
7
8
913
14
15
16
‐0.8Laminate #
‐0.006
Laminate #
910
1112
13
Laminat #
Step 5 : 3D contour plotHUSAPHUSAP
18
Verification of 3D Beam – Comparison with analytic solution
Z 100 NCross-Section
X3 (x3)
7 cm.
X X2 (x2)
11 m
Comparison of three point bending results
0.0150.02
0.025with [010/9010]s
-0.0050
0.0050.01
0 0.2 0.4 0.6 0.8 1x) &
w'(x
)
0 025-0.02
-0.015-0.01
0 0.2 0.4 0.6 0.8 1
w(x
3D BEAM:w(x)
Analytic:w(x)
3D BEAM:w'(x)
A l ti '( )
19
-0.025X [m]
Analytic:w'(x)
Verification of 3D Beam –Case 2: Hollow Composite Beam with Circular Cross-section
Deformation under simple loadingVertical100 N Torsion
100 N · m
L 1 m
D = 0.1 m
[0/±45/90]S
L = 1 m
1
1.2
aqus
res
ult
Deflection
0 4
0.6
0.8
norm
aliz
ed b
y A
ba
3D Beam IIAbaqus
0
0.2
0.4
Def
orm
atio
n n
20
0Deflection Rotational Angle Rotational Angle
Verification of 3D Beam –Case 2: Hollow Composite Beam with Circular Cross-section
Natural frequencies & mode shapes
L 1
D = 0.1 m Mode 1
L = 1 m
[0/±45/90]S
M d 2
1400
1600
1800
Mode 2
800
1000
1200
1400
l Fre
quen
cy (H
z)
3D Beam IIAbaqus
Mode 3
200
400
600
Nat
ural
Abaqus
21
0Mode 1 Mode 2 Mode 3 Mode 4
Mode 4
Case 5: Hollow Composite Beam with Rectangular Cross-section
1.60E‐04
Load Case 1 : Max. Displacement
Results Results
Load Case 2 : Max. Rotation
0 00 002.00E‐054.00E‐056.00E‐058.00E‐051.00E‐041.20E‐041.40E‐0460 0
Dispalcemen
t (m)
Load Case 1 Load Case 2L = 1 m
1.00E‐042.00E‐043.00E‐044.00E‐045.00E‐046.00E‐047.00E‐048.00E‐04
Rotatio
n (radians)
0.00E+00
Abaqus (Shell Element) Abaqus (Beam Element) 3D Beam II5.50
H = 0.1m
100 N 100 N · m
H = 0.1m
0.00E+00
Abaqus (Shell Element) Abaqus (Beam Element)
3D Beam II5.50
W = 0.1m
Laminate Layup : [08/±458/908]SMaterial : AS/H3501
W = 0.1m
AbaqusAbaqus(Beam Element)(Beam Element)
AbaqusAbaqus(Shell Element)(Shell Element)
3D Beam II5.503D Beam II5.50
Load Case 1Load Case 1
Load Case 2Load Case 2
Case 5: Hollow Composite Beam with Rectangular Cross-sectionResults : Natural Frequencies & Mode shapesResults : Natural Frequencies & Mode shapes
AbaqusAbaqus(Shell Element)(Shell Element)
AbaqusAbaqus(Beam Element)(Beam Element)
3D Beam II5.503D Beam II5.50
Laminate Layup : [08/±458/908]S
L = 1 mMode 1Mode 1
130.45 120.32 132.64
1200
1400
1600
1800
z)
Abaqus (Shell Element)
Abaqus (Beam Element)
3DBeam II5 50
Material : AS/H3501
Mode Mode 22705.49 972.93 743
0
200
400
600
800
1000
1200
1stMode 2ndMode 3rdMode 4thMode
Freq
uency (Hz 3D Beam II5.50
ModeMode 33 792 25 791 77 923 591st Mode 2nd Mode 3rd Mode 4th Mode Mode Mode 33 792.25 791.77 923.59
Mode Mode 441539.5 1648.8 1481.6
Case 6 :Ellipse Composite Circular Beam
8.00E‐03
Load Case 1 : Max. DisplacementD = 0.1 m
Results Results
2 50E 02
Load Case 2 : Max. Rotation
0 00 001.00E‐032.00E‐033.00E‐034.00E‐035.00E‐036.00E‐037.00E‐038 00 03
Dispalcemen
t (m)
Load Case 1 Load Case 2100 N 100 N · m
L = 1 m
0 00E 00
5.00E‐03
1.00E‐02
1.50E‐02
2.00E‐02
2.50E‐02
Rotatio
n (radians)
0.00E+00
Abaqus (Shell Element) Abaqus (Beam Element) 3D Beam II5.50
100 N
5 cm
100 N · m
5 cm
0.00E+00
Abaqus (Shell Element) Abaqus (Beam Element)
3D Beam II5.50
Laminate Layup : [0/±45/90]SMaterial : AS/H3501
10 cm 10 cm
AbaqusAbaqus(Beam Element)(Beam Element)
AbaqusAbaqus(Shell Element)(Shell Element)
3D Beam II5.503D Beam II5.50
Load Case 1Load Case 1
Load Case 2Load Case 2
Case 6 :Ellipse Composite Circular BeamResults : Natural Frequencies & Mode shapesResults : Natural Frequencies & Mode shapes
D = 0.1 m
AbaqusAbaqus(Shell Element)(Shell Element)
AbaqusAbaqus(Beam Element)(Beam Element)
3D Beam II5.503D Beam II5.50
Laminate Layup : [0/±45/90]S
L = 1 m
Mode 1Mode 1
61.46 61.61 61.93
700
Material : AS/H3501
Mode Mode 22103.88 101.95 104.93
200
300
400
500
600
Frequency (H
z)
Abaqus (Shell Element)
Abaqus (Beam Element)
3D Beam II5.50
ModeMode 33 366 15 379 43 371 56
0
100
1st Mode 2nd Mode 3rd Mode 4th Mode
Mode Mode 33 366.15 379.43 371.56
Mode Mode 44613.01 610.32 620.27
Verification of 3D Beam – Case 1: Composite plate
Deformation under simple loading
10 N Torsion
L = 1 m W = 7 cm
10 N · m
L 1 m
[08/±458/908]S
1
1.2
aqus
res
ult
Deflection
0 4
0.6
0.8
norm
aliz
ed b
y A
ba
3D Beam IIAbaqus
0
0.2
0.4
Def
orm
atio
n n
Rotational
26
0Deflection Rotational Angle
Rotational Angle
Verification of 3D Beam – Case 1: Composite plate
Natural frequencies & mode shapes
Mode 1
L 1 mW = 7 cm
L = 1 m
[08/±458/908]S
Mode 2
140
160
180
Mode 380
100
120
140
l Fre
quen
cy (H
z)
3D Beam IIAbaqus
20
40
60
Nat
ural
Abaqus
27
Mode 40Mode 1 Mode 2 Mode 3 Mode 4
Verification of 3D Beam – Case4: Composite Pi-Joint Deformation under simple loading
100 N
L = 1 m[08/±458/908]S
Torsion100 N · m
W = 7 cm
H = 3.5 cm
Deflection
1
1.2
1.4
aqus
res
ult
0.6
0.8
1
norm
aliz
ed b
y A
ba
3D Beam IIAbaqus
0
0.2
0.4
Def
orm
atio
n n
28
Rotational Angle
0Deflection Rotational Angle
Verification of 3D Beam – Case4: Composite Pi-Joint Natural frequencies & mode shapes
L = 1 m[08/±458/908]S
Mode 1
W = 7 cm
H = 3.5 cm
[08/±458/908]S
Mode 2
200
250
z)
Mode 3100
150
ral F
requ
ency
(Hz
3D Beam IIAbaqus
0
50
Nat
ur
29
Mode 40
Mode 1 Mode 2 Mode 3 Mode 4
Parametric Study-Easy to change the layup angles.
Pli
3D BEAM “Section DB” sheet
Laminates
Plies
Change ply angle for 3 cases
θ
C (1) 30°
•[0/±θ/90]s
Case (1) 30°
Case (2) 45°
Case (3) 60°
30
( )
Results: a clamped beam with circular cross-section
Displacement U3Z
Y
XZ
X
Case (2) : θ = 45° ; Deflection= -0.018 m
Case (1) : θ = 30° ; Deflection= -0.014 m
°Case (3) : θ = 60° ; Deflection= -0.020 m
31
Results: a clamped beam with circular cross-sectionR lt t th tA cantilever beam
under concentrated tip load
In plane loadBOTTOM
Results at the root
Fixed
p
TOPFixed
L3L4
L5L6L7
L8 TOPIn plane strain
BOTTOM
(Global coordinate)ZL1
L2
L8
L9
L10Z
TOP
TOP
BOTTOM
YL10
L11
L12
L20Y
XL12
L13L14
L15 L16 L17L18
L19
BOTTOM
- In plane load & strain are same for- In plane load & strain are same for case(1),(2) and (3).
32
Effect of fiber angles on stress distribution: Circular Beam
At root
L2
L3L4
L5L6L7
L8
FixedTOP
(Global coordinate)
Y
ZL1
L2L9
L10Y
Z
X
YL11
L12 L19
L20
BOTTOM XL13
L14L15 L16 L17
L18 Laminate #BOTTOM
TensionCompression
Small fiber angle reduces strength ratios
θFiber
33
Effect of ply angles on natural frequencies : Circular Beam
Natural frequencies & modal shapes
1st Mode shape1st Mode shape
2nd Mode shape
3rd Mode shape
Case(1): 30°
Case(2): 45°
Case(3): 60°
34
Application : PI joint
PI-Joint : One of most critical joints in aerospace structures
shaped Joint
35
p
Modeling of PI joint using 3D-BEAM
•No. of Laminates: 12
L12
•A section consists of several laminatesL1, L2, L7, L8, L11, L12 [0/45/-45/0]2s
L L L L [0/45/ 45/0]
•No. of Section Groups : 1•No of Nodes: 11L9
L10
L11 L2 ~ L6 , L9, L10 [0/45/-45/0]4s
•No. of Nodes: 11•No. of Elements: 10L1 L2 L3 L4 L5 L6 L7 L8
E10
E1E2
E3
36
Results : PI joint using 3D-BEAM
•No. of Laminates: 12
L1 L2 L7 L8 L11 L12 [0/45/ 45/90]L120.025
Deflection along X‐axis
L1, L2, L7, L8, L11, L12 : [0/45/-45/90]2s
L2 ~ L6 , L9, L10 : [0/45/-45/90]4sL10
L11
L12
0 01
0.015
0.02
U₁
U₂
L1 L2 L3 L4 L5 L6 L7 L8
L9
0
0.005
0.01
0 0 2 0 4 0 6 0 8 1 1 2
U₂
U₃
‐0.0050 0.2 0.4 0.6 0.8 1 1.2
0 50.6
1
212
Failure Index (1/R)Failure Index (1/R)
0.10.20.30.40.5
311
0 4
59
10
Laminate #3D contour plot tool for the 3D BEAM II
37
6
7
8for the 3D BEAM II
Parametric Study: PI-joint
L11
L12
Cross section
(Local coordinate)
Task : Minimize ply thickness for a layup sequence.
Restriction : Strength ratio(1/R) > 1
• No. of Section group : 1
• No. of Laminates: 12
N f N d 21
L9
L10 0.1mX₂
X₃
( )
• Load : 100kN
• Material : T300/N520
100kN
• No. of Nodes : 21
• No. of Elements : 20L1 L2 L3 L4 L5 L6 L7 L8 (: Laminate #)
0.2m
• Laminate sequence : [0/(±θ) /0]ns
Element #20
Node #21
1mY
θ x
Fixed
Angle of ply
N d #2
X
Y Case (1) 30°1/R > 1Case (2) 45°
C (3) 60°
38
Node #1Node #2
Element #1Element #2
Z(Global coordinate)
Case (3) 60°
Application: PI-joint (Stress & strength ratio).
Displacement at the end
L11
L12
Strength ratio
L9
L10
Strength ratio
L1 L2 L3 L4 L5 L6 L7 L8
39
Application: PI-joint ( Mode shape )
Natural frequencies
1st Mode shape
Mode shape
2nd Mode shape
3rd Mode shape
° C (2) θ 45° Case(3) : θ = 60°
40
Case(1) : θ = 30° Case(2) : θ = 45° Case(3) : θ = 60
Twisted PI joint
Twisted
How to twist sections (3D BEAM “Section DB” sheet) θ = 0° θ = 45°
PliesX₃
X₃
x₃ x₂45°
Laminates
X₂X₂
x₂ x₃
41
Application : Wing in aircraft Regional jet
Modeling in 3D BEAM
42
Problem statement : Wing in aircraft Task : Apply different fiber angle to reduce strength ratio and adjust natural frequency.
L4L5L6L7L8L9• No. of Section group : 19
• No. of Laminates: 20L1L2
L3L4L9L10L11
L12
L13
L25L26
L27
L28L29
L30
• No. of Nodes : 20
• No. of Elements : 19
• Airfoil : NACA 64A204Fixed
N d #14.4mZ
L13L14 L15 L16 L17 L18 L19 L20 L21 L22 L23 L24
• Airfoil : NACA 64A204
• Wing load : Fz (5kN : distributed )
• Material : T300/N520
Node #1…
Element #1Node #2
Y
• Laminate sequence [05/(±θ)5/905]
θ Element #20
X
Case (1) 30°
Case (2) 45°
Case (3) 60°
Node #21
1m
43
Case (3) 60
Wing in aircraft : Stress analysis results.
Strength ratio
3L1L2
L3L4L5L6L7L8L9L10L11
L12L25
L26 L28L29
1
23 L12
L13L14 L15 L16 L17 L18 L19 L20 L21 L22 L23 L24
L27L29
L30
1 2 3
To decrease strength ratio, make the fiber direction smaller.
Wing in aircraft : Modal analysis results
1st Mode shape
Natural frequency (Hz) Mode shape
2nd Mode shape
3rd Mode shape
As increase fiber direction, decrease natural frequency.
Case(1): 30°
Case(2): 45°
Case(3): 60°
45
, q y
Swung PI joint
3D contour plot tool for the 3D BEAM II
Helix twistHalf circle
46
Application : Fuselage with stringers and spars Fuselage with stringers and spar in aircraft structure
M d li i 3D BEAMModeling in 3D BEAM
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Problem statement : Structure of aircraft Task : Minimize maximum displacement in structure changing fiber direction.
• No. of Section group : 8 • Load : 3.45kN θ
• No. of Laminates: 12
• No. of Nodes : 80
f l
• Material : AS/H3501
• Laminate sequence : [02/(±θ)2/02]s
Case (1) 30°Case (2) 45°Case (3) 60°• No. of Elements : 88 Case (3) 60
2 m
0.5m
L11
L12
2 m
L1 L2 L3 L4 L5 L6 L7 L8L9
L100.05 m
3 45kN
L1 L2 L3 L4 L5 L6 L7 L8
Fixed 0.1 m
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3.45kN
Structure of aircraft : Problem statement
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Structure of aircraft : Stress results Maximum displacement comparison Original shape
Case(1) : θ = 30°
Maximum displacement Deformed shapeCase(2) : θ = 45°
UyCase(2) : θ 45
Case(3) : θ = 60°
As smaller degree of fiber direction , less displacement
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less displacement.
Structure of aircraft : Mode results Natural frequencies Mode shapes
1st Mode shape 2nd Mode shape
3rd Mode shape 4th Mode shape
As increase fiber direction decrease natural frequency
Case(1) : θ = 30° Case(2) : θ = 45° Case(3) : θ = 60°
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As increase fiber direction, decrease natural frequency.
WindWind Turbine BladesTurbine BladesWind Wind Turbine BladesTurbine Blades
HSC
L Tu
rbin
e
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Application: 5 kW Wind turbine blades
• Rated Power: 5 kW• Rated wind speed: 10 m/s• Hub height: 10 m
• Blades = 3• Orientation = Upwind• Rotation = Clockwise
D
• Rotor diameters: 2.5 m• Cut in wind speed: 4 m/s• Cut out wind speed: 25 m/s• Annual mean wind speed: 5 m/s
• Speed = Variable• Control = Pitch regulated
Hub height• Annual mean wind speed: 5 m/s• Average Reynolds # : 1.5 x 106
• Vertical Wind Shear: α = 0.2• Weibull Distribution: k = 2
*Reference: Finite element analysis with an improved failure criterionfor composite wind turbine blades, Forsch Ingenieurwes (2008) 72: 193–207
Hub height
Airfoil NACA 4412Rotor Radius = 2.5 m
Hub
Sections = 12Twist = 18o
Material:
0º
Neck
Sh llHub Metal and Composite*Neck Composite*Shell Composite*
18ºFig: Model of a wind turbine blade
Shell
* E-glass LY556 epoxy resin lamina Twistangle 0º
Application: Wind turbine blades
Distributed loads : Fz/length= 350N/ (2.5 m)
2.5mLayup sequence[ 0 / (±45) ][ 0 / (±45) ][ Al(4mm)/0 / (±45) ]
Material : E-glass LY556
Layup sequence[ 0 6/ (±45)2][ 0 8/ (±45)4][ Al(4mm)/0 8/ (±45)4]
Wing sections
0.04
0.06
0.08
Airfoil NACA 4412Twist = 18o
‐0.08
‐0.06
‐0.04
‐0.02
0
0.02
‐0.02 0 0.02 0.04 0.06 0.08 0.1 0.12 0.14 0.16
Application : Wind turbine blade
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Application : Wind turbine blade
0.01
0.02
0.03
In Plane stress at Element # 1
N1
N2
N6 0.00002
0.00004
0.00006
0.00008
In Plane strain at Element # 1
e1
e2
e6
0.005
0.01
0.0151
23
4
517
18
1920
Failure Index (1/R)Element #1
‐0.03
‐0.02
‐0.01
0
0 5 10 15 20 25
‐0.00008
‐0.00006
‐0.00004
‐0.00002
0
0 5 10 15 20 25
e60 6
7
8
91012
13
14
15
16
Laminate # Laminate # 11Laminat #
0.02
0.03
0.04
In Plane stress at Element # 4
N1
N2
N6 0 0002
0.0004
0.0006
In Plane strain at Element # 4
e1
e2 0.040.060.080.1
12
3
4
517
18
1920
Failure Index (1/R)
(4)
(8)Element #4
‐0.03
‐0.02
‐0.01
0
0.01
0 5 10 15 20 25
N6
0 0006
‐0.0004
‐0.0002
0
0.0002
0 5 10 15 20 25
e60
0.025
6
7
8
913
14
15
16
17
(1)
‐0.04Laminate #
‐0.0006
Laminate #
910
1112
13
Laminat #
0.04
0.06
In Plane stress at Element # 8
N1
N2 0 001
0.0015
In Plane strain at Element # 8
e10 1
0.15
0.21
23
418
1920
Failure Index (1/R)Element #8
0 04
‐0.02
0
0.02
0 5 10 15 20 25
N2
N6
‐0.0005
0
0.0005
0.001
0 5 10 15 20 25
e2
e60
0.05
0.15
6
7
814
15
16
17
56
‐0.06
‐0.04
Laminate #
‐0.001
Laminate #
910
1112
13
Laminat #
Application :3.5kW Wind turbine 3.5kW Wind turbine with blades and tower
Blade
Modeling in 3D BEAM
Tower
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3.5kW wind turbine blades and tower Task : Analyze 3.5kW wind turbine for gravitational and aerodynamic load
• Rated power : 3.5kW • No. of Nodes : 57 • No. of Section group : 16
• Rated wind speed : 12m/s
• Load : gravitational and aerodynamic
• No. of Elements : 56
• Materials : Tower ( Steel ), Blade ( Steel, E-glass, IM6/epoxy)
• No. of Laminates: 30
8.3m
Wind turbine geometry Blade loads
12m
1m
0.6m
Airfoils : DU45 Gravitational load Aerodynamic load
58
3.5kW wind turbine : stress resultantsMaximum displacement
0.15m
Maximum strength ratioStrength ratio at blade
Strength ratio at root
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3.5kW wind turbine : mode results
Natural frequencies and mode shapes
2nd Mode shape : 1 28Hz 3rd Mode shape : 2 71Hz1st Mode shape : 1.02 Hz 2nd Mode shape : 1.28Hz 3rd Mode shape : 2.71Hz
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Effects of stiffeners thickness on wind turbine bladesT300/N5208Stiffener T300/N5208
E glass/LY556 Epoxy
Leading edge
Trailing edge
E-glass/LY556 Epoxy
[0/+45/0] 60 [0/+45/0]40 [0/+45/0]40 [0/+45/0]10
Trailing edge
Upper Spar Cap
Lower Spar Cap
Shear web [0/+45/0] 8 [0/+45/0] 8 [0/+45/0] 8 [0/+45/0] 8
Case (1) : n = 0;Case(2) : n = 10;Case(3) : n = 20.
[0n]Stiffener T300/N5208
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( )
Blade deflection : Ultimate load
Ultimate load at the tip4,000 N/m
Deflection
: No Stiffener
: Stiffener =[010] T300/N5208
: Stiffener =[020] T300/N5208
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Strength ratio : Ultimate load
(1) (2) (3)
(1) (2) (3)Strength ratio (Tsai-Wu)
L3L4L5L6L7L8L9L10
Laminate #
L1L2L3L4L9L10
L11L12
L13 L23 L24
L25L26
L27
L28L29
L30
L14 L15 L16 L17 L18 L19 L20 L21 L22 L23 L24
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Vibration mode
: No Stiffener
Stiff [0 ] G hit1st mode shape
: Stiffener =[010] Graphite
: Stiffener =[020] Graphite
1st 2nd 3rd 4th
Vibration modesVibration modes
2nd mode shape 3rd mode shape 4th mode shape
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Summary and Conclusion
• The 3D beam can be used as a preliminary design tool• The 3D-beam can be used as a preliminary design tool.• Accurate, yet easy-to-use Tool for structural analysis of composite structures.• Calculate displacements, strains, stresses, failure index and natural vibration modes.p• It is based on a new composite beam theory, as accurate as 3D shell• Various applications, many structures can be treated as beams.
• A 3D-beam II- basic is available to the audience.• A smooth link from the 3D-beam to the SMM+ is under development• A smooth link from the 3D-beam to the SMM+ is under development.• Reliablity analysis tool will be linked.
Thank you for your attention !!!
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