2.002 Tutorial Presentation Problem 1-Atomic Force Microscopy Justin Lai.
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Transcript of 2.002 Tutorial Presentation Problem 1-Atomic Force Microscopy Justin Lai.
2.002 Tutorial PresentationProblem 1-Atomic Force
MicroscopyJustin Lai
1. Approximate the cantilever as a beam which interacts with the surface a force F. Give the expression for the deflection of the cantilever as a function of x, distance. What is the deflection at the end of the cantilever (x=L)? Where on the cantilever is the strain the highest?
FL
h
bL
y
x
External force and moment analysis:
F
AyR
AAzM
L xF
yF
zM
= 0
0: FR AyAyRF
0: AzMFL
FLM Az
F
F
AFLL
Internal force and moment analysis:
F
AFL
x
)(xFxx
)(xFxy
)(xM xz
Making a cut in the beam:
xF
yF
BzM
0)(: FxFxyFxFxy )(
0)(: xMFxFL xz
0)(: xFxx
B
FLFxxM xz )()()( xLFxM xz
From analysis of beam bending geometry:
y
E
yE
ydAM
dAyE
M 2
y
Distance from center to neutral axis
0
0
l
ll f
)( y
the moment from each elemental area
dAyE
M 2
dAyI zz2 = second moment of inertia
12
3bhI zz
12
3bhEM
1
2
2
dx
ud
2h
2h
bdyyI zz2
2
2
2
h
h
dyyb
|2/
2/
3
3
h
h
yb
12
3bh
112
3
Ebh
M
112
3
Ebh
M
2
2
3
12
dx
ud
Ebh
M
2
2
3))((
12
dx
udxLF
Ebh
)(12
32
2
xLFEbhdx
ud
FxEbh
FLEbhdx
ud332
2 1212
)()( xLFxM xz
0 0
FxEbh
FLEbhdx
ud332
2 1212
12
33
612cx
Ebh
Fx
Ebh
FL
dx
du
213
32
3
26)( cxcx
Ebh
Fx
Ebh
FLxu
3
3
3
3 26)(
Ebh
FL
Ebh
FLLxu
0dx
du
0)0( u
Boundary conditions for cantilever:
3
34)(Ebh
FLLu
33
23
26)( x
Ebh
Fx
Ebh
FLxu Where is the strain the highest?
We know that at the wall, the moment is the highest as there is the longest lever arm. Moment causes stress. And stress causes strain.
We can also look at the following equation for x = 0.
)()( xLFxM xz
3
3
4L
Ebhk
y
F
Silicon-Nitrogen cantilever with following specifications:
E = 140 GPa
L=100
h = 320nm
B = 15
m
m
36
3969
)10100(4
)10320)(1015)(10140(
m
mmPak
mNk 0172.
2. Derive a form for the spring constant k for a cantilever.
kxF kyF
3
34)(Ebh
FLLy
3. Variations in dimensions of E and of the cantilever sometimes on the order of a few percent or greater occur. Discuss possible sources of these variations. Calculate how much these variations can affect the cantilever k.
For example, say the height changes from 1 to 1.05, a 5% change:
3
3
)1(4
)05.01)(1)(1(
m
mmPak
157.1)05.01( 3 mTherefore, a 5% change in the height leads to a 16% change in the spring constant k.
By looking at the formula, we can see how each variable is directly and indirectly proportional to a given degree to the spring constant.
The main source of error is found in microfabrication. The very nature of creating instruments and tools on such a small scale lends itself easily to variations in dimensions.
3
3
4L
Ebhk
4. If you wanted to measure the mechanical properties of biomolecules (cell surfaces, or pulling on proteins), the forces involved are typically ~ 102pN. In order to measure forces of this magnitude, what restrictions does this put on the material properties and dimensions of the cantilever? Consider the interaction between the cantilever and the surface to be Hooke’s Law-like also.
cantileverk
specimenk
You want the spring constants of both the cantilever and specimen to be on the order of the same magnitude.
Imagine modeling this as two springs in series. Having spring constants of different order of magnitudes will create deformations that are also of different order of magnitudes. Also, the dissimilarity can cause damage in either component.
5. When AFM is utilized in a mode in which the cantilever is oscillated at a frequency above a surface, it is necessary to know what the resonant frequency f0 of a cantilever is. Write an expression for f0 first assuming one has a tip mass m that is much greater than the mass of the cantilever, thus mcantilever is negligible.
m
kf 02
20 L
Ectf
m
kf
21
0
How does the evaluation change if the mcantilever is not negligible?