1520 mm Hg = ____ atms. Use your notes to find the equivalence line. Day 4 11-7.
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Transcript of 1520 mm Hg = ____ atms. Use your notes to find the equivalence line. Day 4 11-7.
1520 mm Hg = ____ atms.
Use your notes to find the equivalence line.
Day 4 11-7
How does a cartesian diver work?
Day 4 11-7
1. Gases consist of large #s of tiny particles that are far apart relative to their size (each particle has mass)
Kinetic-molecular Theory - Gases
2. Collisions between gas particles and between particles and container walls are elastic3. Gas particles are in constant, rapid, random motion… they possess kinetic energy
Kinetic-molecular Theory - Gases
4. There are no forces of attraction or repulsion between gas particles
5. The average kinetic energy of gas particles depends on the temperature of the gas
cartesian divers
Day 4 11-7
33,600 mL of Helium = ____ atoms at STP
Day 5 11-9
The Gas LawsBoyle’s Law: – Pressure-volume relationship – the volume of a fixed mass of gas varies inversely with the pressure at constant temperature
Comparing conditions:
P1V1 = P2V2Boyle’s Law:
Constant n and TP and V change
The Gas LawsCharles’ Law: – Volume-temperature relationship – the volume of a fixed mass of gas varies directly with the Kelvin temperature at constant pressure
Comparing conditions:
V1/T1 = V2/T2
Temperature decreaseCharles’ Law: –
Constant n and PT and V change
The Gas LawsGay-Lussac’s Law: – Pressure-temperature relationship – the pressure of a fixed mass of gas varies directly with the Kelvin temperature at constant volume
Comparing conditions:
P1/T1 = P2/T2
Low T - Slow moving
High T - Fast moving
Temperature Increase
Gay-Lussac’s Law: – Constant n and VT and P change
http://mc2.cchem.berkeley.edu/Java/molecules/index.html
Increase pressure
Temperature __________
Volume __________
Increase temperature
Volume __________
Pressure __________
Increase volume Temperature __________
Pressure __________
increases decreases
increasesincreases
increases decreases
What happens if…?
Constant V Constant T
Constant VConstant P
Constant P Constant T
The pressure exerted on a 3 L sample of gas is 600 mm Hg, if the pressure is decreased to 300 mm Hg what is the new volume?
1.Highlight important info.2.Choose a law3. Identify conditions as
beginning (1) or ending (2)4.Solve
P1V1 = P2V2
DAY 6 11-101. What is Boyle’s law? _____________ 2. Write a Boyle’s law problem in your
notebook with the answer
3. Why are temperatures around zero kelvins bad for an ideal gas?
Review section 14.2 and complete #s 17-19, 22, 24, + 25 on page 463
Whose LawP1/T1 = P2/T2
P1V1 = P2V2
V1/T1 = V2/T2
Gay-Lussac’s
Boyle’s
Charles’
At 100 K a sample exerts a pressure of 2.026e5 Pa, if the pressure is decreased to 1.013e5 Pa what is the new temperature?
What law do you use? __________________
Solve:
Gay-Lussac’s: P1/T1 = P2/T2
1. At 100 K and 1 atm a sample has a volume of 2L, if the gas expands to 6L what is the new temperature?
Not in notes
Observe what happens.
How could we get the egg back out without breaking it?
EXPLAIN why the egg enters the flask.
Ideal gas law – mathematical relationship of pressure, volume, temperature, and the # of moles of a gas
PV = nRT
R = the ideal gas constant = 8.314
Page 454 table 13.2
L * kPamol * K
http://en.wikipedia.org/wiki/Gas_constant
What pressure in atms. is exerted by 0.325 mol of hydrogen gas in a 4.08 L container at 35°C?
1. Convert to Kelvins
2. Choose R
3. Solve
0.0821 atm-L/mol-K
8.314 J/mol-K
PV = nRT
DAY 1 11-11A sample of gas that contains 4.0 moles at 400K and 2 atms. takes up how much space?
1. If a balloon is in this room (about 1 atm. and 300 K) and its volume is 0.40 L, how many moles of gas does it contain?
On notes page 6
What mass of chlorine gas in grams is contained in a 10.0 L tank at 27°C and 3.50 atm of pressure?
101 gOn notes page 5
What is the volume occupied by 4.67 moles of H2 at 27.0 °C and 2.00 atm.?
On notes page 6
Boyle’s Law
Ideal Gas
Kinetic Energy
Mole
Standard Temperature and Pressure
Attract
Volume-temperature relationship
Absolute zero
Charles’ Law
Avogadro’s Law
Pascal
Precipitate
Synthesis reaction
Homework # 1 Unit 4
At 300 K a sample of gas occupies 5 L, if the volume is decreased to 2 L what is the new temperature?
V1/T1 = V2/T2
1. Explain what happens at very low temperatures in terms of kinetic molecular theory.
2. List one of the 5 assumptions of kinetic molecular theory.
5-6
Read Section 12.1 (Kinetic Molecular Theory) and
complete #s 8-11 + 13 on page 410
HomeworkPractice problems 1 + 2 on page 443
Practice Problems 4-6 on page 446
Practice Problems 8 + 9 on page 448
Periods 3 & 6 5-5
1. Highlight important info.
2. Choose a law
3. Identify conditions as beginning (1) or ending (2)
4. Solve
Boyle’s Law: Constant n and TP and V change