11 3 arcs and chords lesson
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Transcript of 11 3 arcs and chords lesson
Arcs and Chords Arcs and Chords
You will learn to identify and use the relationships amongarcs, chords, and diameters.
Nothing New!
Arcs and Chords Arcs and Chords
BD
S
C
P
A
In circle P, each chord joins two points on a circle.
Between the two points, an arc forms along the circle.
vertical angles
By Theorem 11-3, AD and BC are congruentbecause their corresponding central angles are_____________, and therefore congruent.
By the SAS Theorem, it could be shown thatΔAPD ΔCPB.
Therefore, AD and BC are _________.congruent
The following theorem describes the relationship between two congruentminor arcs and their corresponding chords.
Arcs and Chords Arcs and Chords
Theorem11-4
In a circle or in congruent circles, two minor arcs are congruentif and only if (iff) their corresponding ______ are congruent.
B
D
C
A
chords
AD BCiff
AD BC
Arcs and Chords Arcs and Chords
A
BC
The vertices of isosceles triangle ABC are located on R.
R
If BA AC, identify all congruent arcs.
BA AC
Arcs and Chords Arcs and Chords
Step 1) Use a compass to draw circle on a piece of patty paper. Label the center P. Draw a chord that is not a diameter. Label it EF.
Step 2) Fold the paper through P so that E and F coincide. Label this fold as diameter GH.
E
F
P
G
H
Q1: When the paper is folded, how do the lengths of EG and FG compare?
Q2: When the paper is folded, how do the lengths of EH and FH compare?
Q3: What is the relationship between diameter GH and chord EF?
EG FG
EG FG
They appear to be perpendicular.
Arcs and Chords Arcs and Chords
Theorem11-5
In a circle, a diameter bisects a chord and its arc if and only if(iff) it is perpendicular to the chord.
PR
D
C
B
AAR BR and AD BD
iff
CD AB
Like an angle, an arc can be bisected.
Arcs and Chords Arcs and Chords
B
C
A
K
D
7
Find the measure of AB in K.
AB=2 ( DB ) Theorem 11-5
AB=2 (7 )AB= 14
Substitution
Arcs and Chords Arcs and Chords
M
K
L
K
N6
Find the measure of KM in K if ML = 16.
( K M )2= ( KN )2+ ( MN ) 2Pythagorean Theorem
( K M )2= (6 )2+ (8 )2 Given; Theorem 11-5
( KM )2=36+ 64
( K M )2= 100
√ ( KM )2=√100K M = 10