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Grade 12 Mathematical Literacy

LO3 Revision of Grade 10 and 11

1. The figures below show the axis of symmetry and across section of a cylinder:

Calculate the following:

1.1 The volume of a right cylinder with diameter 5 cm and height 8cm.

1.2 The surface area of a right cylinder with diameter 5 cm andheight 8 cm.

2. A swimming pool is 12 m long, 9 m wide and 1,5 m deep.

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2.1 Calculate the area of material neededfor a cover for the pool, if the cover overlaps the sides by 30 cm. Giveyour answer in metres (m).

2.2 Calculate the volume of the pool.Give your answer in litres (ℓ).

2.3 Liquid algaecide must be added at a rate of 1 ℓ of algaecide per 10 000 ℓ of water. Calculate how much algaecide you must addto the pool.

3. For each of the following shapes determine the following:

3.1 Design a formula to determine the area of each shape.

3.2 Use your formula to determine the area of each shape.

3.3 Determine the perimeter of each shape.

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Grade 12 Mathematical Literacy

4. Manto has the storage container as shown below (not drawn toscale):

20 cm

12 cm

40 cm26 cm

4.1 Determine the surface area of the container.

4.2 Calculate the volume of the container.

5. The drawing below is of Mr Zuma’s house that is to be wired for electricity. Eskom will install a prepaid meter, a light and a socketoutlet. Study the drawing carefully and answer the questions thatfollow:

5.1 What view has been provided of the house?

5.2 Use the scale to work out the length and breadth of the house.

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20cm

Bedroom 1

Bedroom 2

Kitchen

Lounge

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Grade 12 Mathematical Literacy

5.3 Using the scale, work out the dimensions of bedroom 1.

5.4 In which room has the meter been installed?

6. Look at the drawing of a kite below;

6.1 Calculate, to the first decimal, the length of AC and BC.

6.2 Calculate the perimeter of the kite.

7. A ladder rests against a wall. The top of the ladder reaches aheight of 6 m above the ground and the bottom of the ladder is 2 m

away from the wall. Determine the following:

7.1 The length of the ladder.

7.2 The value of cos L.

7.3 The value of tan N.

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Grade 12 Mathematical Literacy

ANSWERS

1.1 Volume = hr 2

π   = 8522×× ,π  

= 157 cm³

1.2 Surface area = rhr  π  π   222+ = 8522522

2×××+×× ,(),( π π 

= 164,85 cm²

2.1 2.1 A = lb = (12 + 0,3 + 0,3) x (9 + 0,3 + 0,3)= 114,156 m²

2.2 V = lbh = 12 x 9 x 1,5= 163 m³= 162 x 1 000 = 162 000 ℓ

2.3 162 000 ÷ 10 000 = 16,2 ℓ

3.1A = (q x 9,2)+ ((p – q) x (½(9,2))

B = (½bh) + (½bh)

3.2 A = (9,2 x (9,2 ÷ 2)) + ((9,2 ÷ 2) x (9,2 ÷ 2))

= 42,32 + 21,16= 63,48 m²

B = (½(9) x ( 22915 − )) + (½( )( 222

91513 −− ) x( 22915 − )

= (4,5 x 12) + (2,5 x 12)

= 54 + 30= 84 m²

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3.3 A = 9,2 + (½(9,2) + (½(9,2) + (½(9,2) + (½(9,2) + 9,2A = 36,8 m

B = 15 + 5 + 13 + 9B = 42 m

4.1

Note: Divide up the container to make the calculations easier.

4.1 (26 x 12 x 2) + (20 x 8 x 2) + (6 x 8) + (( 2268 + ) x 40) + (20 x

40) + (40 x 26) + (40 x 12) + (20 x 40)

= 624 + 320 + 48 + 400 + 800 + 1040 + 480 + 800

= 4 512 cm²

4.2 (26 x 40 x 12) + (20 x 40 x 8) + (½(8 x 6 x 40))

= 12480 + 6 400 + 960= 19 840 cm³

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5.1 Plan view

5.2 (71,5 x 1 500) x (54 x 1 500)107,25 m x 81 m

5.3 31,5 x 29= 47 250 x 43 500 mm= 47,25 m x 43,5 m

5.4 Kitchen

6.1

AC =15

516

cos. = 17,08 cm

BC = 17,08 x sin15º = 4,42 cm

6.2 (16,5 x 2) + (4,42 x 2) = 41,84 cm

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Grade 12 Mathematical Literacy

7.1 Use Pythagoras:

2262 +

= 6,32455532= 6,32 m

7.2Hypotenuse

 Adjacent Cos =θ 

326

2

,=θ  Cos

°=∴ 5571,θ  

7.3 Adjacent 

OppositeTan =θ 

6

2=θ Tan

°=∴ 4318,θ Tan

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