1 Revision - JB Publishing House · nine (b) Six lakh, ninty-nine thousand and four (c) Three lakh...

1. Write the following in words :Ans.

2. Write the following in figures :Ans.

60309

699004

303033

10055091

3. Fill in the blanks :Ans. 3 8

0 08 59 8

9 45

4. Write in expanded form :Ans.

5. Write 900000 + 300000 + 20000 +7000 + 600 + 20 + 7 in short form.

Ans.

6. Write the greatest and the smallest 6digit numbers that can be formedwith the digits 5, 4, 3, 7 and 9.

Ans.

7. Write the place value of :Ans.

8. Look at the pattern carefully andthen fill in the blanks :

Ans. 4801 49015001

5921059510 59810

2030 20402050

9.9999999

100000000

53288987999

10. Add the following :Ans.

11. Subtract the following :Ans.

12. Find the value of :Ans. 68690000

210701543210011286972989740183705588

13. Find the quotient and remainder :Ans.

(a) Forty thousand and four.(b) Eight lakh eighty thousand seven

hundred and fifty- five.(c) Seven lakh fifty thousand.(d) Three lakh thirty-one thousand

forty-three.

(a) Sixty thousand, three hundrednine

(b) Six lakh, ninty-nine thousand andfour

(c) Three lakh three thousand andthirty-three

(d) One crore fifty-five thousandninety-one

(a) 380085 = lakhs + tenthousands + thousands +hundreds + tens + ones

(b) 98945 = ten thousands +thousands + hundreds + tens+ ones

(a) 48947= 40000 + 8000 + 900 + 40 + 7

(b) 38971= 30000 + 8000 + 900 + 70 + 1

(c) 438000= 400000 + 30000 + 8000

900000 + 300000 + 20000 + 7000 +600 + 20 + 7 = 1227627

Greatest 6 digit number = 997543Smallest 6 digit number = 334579

(a) 7000 (b) 8000

(a) 4501, 4601, 4701, , ,

(b) 58310, 58610, 58910, ,,

(c) 2000, 2010, 2020, , ,

(a) The greatest 7 digit number=

(b) The smallest 9 digit number=

(c) 532888 comes just before=

(d) 88000 comes just after =

(a) (b)

(a) (b)

(a) 68690 × 1000 =(b) 4483 × 47 =(c) 54321 × 100 =(d) 91764 × 123 =(e) 98974 × 10 =(f) 84346 × 2178 =

(a) 607548 ÷ 38

Quotient = 15988Remainder = 4

(b) 507642 ÷ 32


Revision1

1 2 3 4 5 63 4 5 6 7

2 3 4 51 2 3

1 2+ 1

1 6 0 5 0 4

6 0 5 0 06 0 0 0

6 0 06 0+ 6

6 7 1 6 6

7 7 7 7 7 7+ 7 7 7 7 77 0 0 0 0 0

1 0 0 0 0 0– 1 0 0 0 0

9 0 0 0 0

38 607548 15988–38227

–190375

–342334

–304308

–30404

0000 00000000 00000000 0000000 0000000 000000 000000 00000

000000000000000

32 507642 15863–32187

–160276

–256204

–192122–9626

0000 00000000 00000000 0000000 0000000 000000 000000 00000

000000000000000

Mathematics–5102

Paramount Mathematics-5

50 608000 12160–50108

–10080

–50300

–3000

– 0×

0000 00000000 00000000 0000000 0000000 000000 000000 00000

000000000000000

60 706050 11767–60106–60460

–420405

–360450

–42030

0000 00000000 00000000 0000000 0000000 000000 000000 00000

000000000000000

78 389718 4996–312

777–702

751–702

498–468

30

000 000000 000000 00000 00000 0000

000000000000

72 488728 6787–432

567–504

632–576

568–504

64

000 000000 000000 00000 00000 0000

000000000000

Mathematics–5 103

(c) 608000 ÷ 50


(d) 706050 ÷ 60


(e) 389718 ÷ 78


(f) 488728 ÷ 72


(a) 536 and 212Factors (Divisors) of 535 and 212536 = 2 × 2 × 2 × 67212 = 2 × 2 × 53

Common factors = 2 × 2 =4

Greatest common divisor = 4

(b) 432 and 216Factors (Diviors) of 432 and 216432 = 2 × 2 × 2 × 2 × 3 × 3 × 3216 = 2 × 2 × 2 × 3 × 3 × 3

Common factors (Divisors)= 2 × 2 × 2 × 3 × 3 × 3= 216


(c) 308, 244, 510Factors (Divisors) of 308, 244,510

308 = 2 × 2 × 7 × 11244 = 2 × 2 × 61510 = 2 × 5 × 51


(d) 3041, 232 and 536Facotrs of 3041, 232 and 5363041 = 3041× 1232 = 2 × 2 × 2 × 29536 = 2 × 5 × 51

There is no common factor


(a) 21, 27, 189

3 × 7 × 9 = 189

14. Write the greatest common divisiorof the following :

Ans. 15. Write L.C.M. of :

∴

∴

∴

∴

⇒

∴

2 5362 2682 134

67

2 5362 268

53

2 4322 2162 1082 543 273 93 3

1

2 2162 1082 543 273 93 3

1

2 3082 1547 77

11

2 2442 122

61

2 5105 255

51

2 2322 1162 58

29

2 5362 2682 134

67

3041 30411

3 21, 27, 1897 7, 9, 639 1, 9, 9

1, 1, 1

(b) 360, 320 and 240

2 × 2 × 2 × 2 × 3 × 5 × 4 = 960

(a) 27 ÷ 9 ÷ 3 + 8 × 2 ÷ 4= 3 ÷ 3 + 8 × 2 ÷ 4= 1 + 16 ÷ 4= 1 + 4 = 5

(b) 6 × 4 + 8 ÷ 2 – 3 × 2= 6 × 4 + 4 – 3 × 2= 24 + 4 – 6= 28 – 6 = 22

(a) —,—,— and —

LCM of

2 × 2 × 3 × 3 × 3 × 2 ×= 216

Putting it,

——–, ———, ——–, ——–

——, ——, —–, —–

Increasing order

= —– < —— < —– < —–

or — < —– < —– < —–

(b) — , — , — , — and —

Taking LCM

3 × 3 × 2 × 2 × 2 × l = 72

Putting it,

——–, ——, ——–, ——–, ——

—, —, —, —, —

Increasing order

= — < — < — < — < —

or — < — < — < — < —

(a) — + — + —

Taking LCM5 × 5 × 3 × 4 = 300

——— + ——— + ———

—– + —– + —–

——— = —–

(b) — + — + — + —

Taking LCM

2 × 2 × 2 × 3 × 13 = 312

——— + ——– + ——– + ——–

—— + —— + —— + ——

= ——— = ——

(a) — – — = —

(b) 3 — – — = — – —

= ——– – ——–

= —– – —– = —

= —— = —

⇒

⇒

⇒

⇒

⇒

⇒

⇒

⇒

⇒

⇒

⇒

16. Simplify :Ans.

17. Arrange the following fractions inascending order :

Ans.

18. Add the following :

19. Subtract the following :

Ans.

20. Three bells are rung at intervals of 5,9 and 15 minutes. They are rungsimultaneously at 9 o'clock in themorning. When will they ringtogether again?

2 360, 320, 2402 180, 160, 1202 90, 80, 60

3, 4, 1

0 00 0 00 0 00 0 0000 00 00

02 45, 40, 303 45, 20, 155 15, 20, 5

43

612

254

18

4 × 723 × 72

6 × 1812 × 18

2 × 454 × 4

1 × 278 × 27

288216

108216

8216

27216

8216

27216

108216

288216

18

254

612

43

13

29

512

1124

718

2 3, 9, 12, 242 3, 9, 6, 12, 93 3, 9, 3, 6, 93

, 18

1, 3, 1, 2, 31, 1, 1, 2, 1

0 00 0 00 0 00 0 0

1 × 243 × 24

2472

2 × 89 × 8

5 × 612 × 6

11 × 324 × 3

7 × 418 × 4

1672

3072

3372

2872

1672

2472

2872

3072

3372

29

13

718

512

1124

825

215

1020

5 25, 15, 205, 3, 40 0 0

8 × 1225 × 12

2 × 2025 × 20

10 × 1520 × 15

96300

40300

150300

286300

143

150

143150

2 3, 8, 26, 242 3, 4, 13, 122 3, 2, 13, 63 3, 1, 13, 3

1, 1, 13, 1

000

23

58

1326

724

2× 1043× 104

5× 398× 39

13 × 1226 × 12

7× 1324 × 13

208312

195312

156312

91312

650312

325

156

325156

725

325

425

26

215

206

215

20 × 56× 5

2 ×215 × 2

10030

430

9630

4815

16

5

165

2 3, 12, 542 3, 6, 27, 43 3, 3, 27, 23

, 8

1, 1, 9, 23 1, 1, 3, 22 1, 1, 1, 2

1, 1, 1, 1

000 00 00 00 0

Mathematics–5104

Mathematics–5 105

Ans.

21. If 6 litres of petrol costs 90, what

will be the cost of 9 litres of petrol?Ans.

22. A bundle contains 252 five rupeesnotes. How much money is there inthe bundle?

Ans.

23. 17 – kg of oil costs 498.75 paise.

Find the cost of 1 kg of oil.

Ans.

24. Add :Ans.

25. A plane take off from Delhi at 1610hours. It is to land at Kolkata after 3hours 45 minutes. At what time doesit land at Kolkata?

Ans.

26. Write the Roman numerals for thefollowing :

Ans.

27. Fill in the blanks :Ans. sides

euqitateral

right

isosceles

28. Draw any rectangle. Measure itsangle. Find the sum of the fourangles of the rectangle.

Ans.

29. Using protracter, draw an angle of120°.

Ans.

Taking LCM

The bells will ring, together after, 45minutes i.e. at 9 : 45 a.m.

Cost of 1 litre of petrol= (the cost of litres of pertrol) ÷ 6

= 90 ÷ 6

= 15

Cost of 9 litres of petrol

= (Cost of 1 litre of petrol) × 9

= 15 × 9

= 135

The cost of 9 litres of petrol is 135

Total money = 232 × 5 = 1160

Cost of 1 kg of oil = 498.75 ÷ 17.5

= 28.5(a)

15 hr and (60 + 30 min) and 60

second

(15 hr + 1 hr), 30 min + 1 min and 0

second

16 hr, 31 min and 0 second

(b) 45 min 25 second – 25 min 45second

(c) 5 hours 15 minutes × 6

= 30 hrs 90 min= 30 hrs and (60 +30 min)= 31hrs 30 min

(d) 26 hours 35 minutes 10 sec. ÷ 5

19 hrs 55 minutes = 1955 hrsConverting into 12 hour clock1955 hrs = 7: 55 p.m.

The plane will land at Kolkata on 7:55

p.m.

(a) XXVI (b) XLV(c) XXIX (d) XL

(a) A rectangle having all itsequal is called a square.

(b) Atriangle having three equal sidesis called triangle.

(c) If an angle has the measure 90°then the triangle is a angledtriangle.

(d) If two sides of a triangle are equalit will be an triangle.

Sum = 90° + 90° + 90 ° + 90° = 360°

`

`

`

`

`

`

` `

`

`

`

∴

∴

⇒

⇒

⇒

∴

5 5, 9, 153 1, 9, 3

1, 3, 100

9 hrs. 40 min. 30 second

+6 hrs. 50 min. 30 second

15 hrs. 90 min. 60 second

45 min. 25 sec.

–25 min. 45 sec.

19 min. 40 sec.

8544

5 hrs. 15 min.

× 6

30 hrs. 90 min.

0

16 hrs. 10 min.

+3 hrs. 45 min.

19 hrs. 55 min.

120°

90° 90°

90°90°

A B

CD

12

5 26 hrs. 35 min. 10 sec.25

35+60 min.

1 hrs.

95–545

– 45×

5 hrs 19 min. 2 sec.

10

–10

×

10

30. What is the relation between thesides of a square? What is therelation between the angles of asquare?

Ans.

31. Write the complementary angle ofeach of the following angles :

Ans.

32. Write the supplementary angle ofeach of the following angles :

Ans.

33. Find the difference between the

supplementary angle and thecomplementary angle of 80°.

Ans.

34. Find the perimeters of the giventriangles :

Ans.

35. Find the perimeters of the givenfigures :

All the sides and angles of a square arealways equal

(a) 60° [ 90° – 30°]

(b) 2° [ 90° – 88°]

(c) 35° [ 90° – 55°]

(d) 30° [ 90° – 60°]

(a) 135° [ 180° – 45°]

(b) 45° [ 180° – 135°]

(c) 60° [ 180° – 120°]

(d) 105° [ 180° – 75°]

Supplementary angle = 180° – 80°= 100°

Complementary angle = 90° – 80°= 10°

Difference = 100° – 10° = 90°

(i) P= Sum of all sides= 9 cm + 5cm + 10cm = 24 cm

(ii) Sum of all sides= 1cm + 8 cm + 12 cm = 12 cm

(i) P= sum of all sides= 6 cm + 4 cm + 5 cm + 6 cm + 9cm= 30 cm

(ii) P= sum of all sides= 2cm + 3 cm + 2 cm + 4 cm + 1 cm+ 3 cm + 1 cm + 4 cm = 20 cm

∴

∴

∴

∴

∴

∴

∴

∴

∴

Number and Numeration2

1. Write the following numbers :

Ans.

2. Rewrite the following numbersusing space to separate the periodsaccording to the Indian Place ValueChart :

Ans.

3. Write the numbers between :

Ans.

4. Write the number names for each ofthe following numbers using theIndian System of Numeration :

Ans.

5. Write the numbers in figures :Ans.

6. Write the period and place value ofthe underlined digits in thefollowing:

Ans.

(a) 999999999 (b) 99999999(c) 100000000

(a) 86 42 15 309(b) 83 20 00 260(c) 90 80 00 203(d) 2 56 10 34 790

(a) 754321891, 754321892

(b) 654219801, 654219802

(c) 532701626, 532701627,532701628

(d) 428785643, 428785644

(a) Eight crore, thirty-two lakh, fifty-four thousand, one hundred andthirty-two.

(b) Nine crore, sixty-seven lakh, fourhundred and thirty-five.

(c) Seven crore, eighty-six lakh, twothousand, one hundred and thirty.

(d) Nineteen crore, three lakh, fourthousand and five.

(e) Eleven crore, twenty-two lakhforty-four thousand, threehundred and thirty-three

(f) One hundred and thirty crore,twelve lakh, twenty thousand fivehundred and six

(g) Thirty-two crore, sixty-twothousand and seven

(h) Ninety crore, ten lakh, forty-fivethousand and four

(a) 785202407 (b) 820000088(c) 40205008 (d) 900600006(e) 890000100 (f) 568070005(g) 50602006 (h) 128506704(i) 300500000

(a) Period – crore;Place value – 70000000

(b) Period – ten crore;Place value – 600000000

(c) Period – 7-lakh;Place value – 700000Period 4-ten thousand ;Place value – 4000

Mathematics–5106

(d) Period 3- ten thousand;Place value – 30000Period 4-ten thousand ;Place value – 4000

(a) 231 456 789 (b) 456 281 897(c) 798 456 281 (d) 8456 798 812(e) 900 900 900 (f) 2003 100 200(g) 432 455 167 (h) 9796 543 218

(a) 90070060 (b) 70000086(c) 506000912 (d) 116007063(e) 2059000339 (f) 901034005(g) 485000000

(a) Two hundred and thirty-fivemillion, eight hundred and ninety-seven thousand, two hundred andsixty-four.

(b) Four hundred million, sevenhundred thousand, eight hundred.

(c) Three hundred fifteen million,seven hundred and five thousand,nine hundred and ninety-five.

(d) One billion five hundred twomillion four thousand fourhundred and five.

(e) Two hundred and eighty-ninemillion, sixty-nine thousand andforty-eight.

(f) One Million four hundred andsixty-five thousand, two hundredand forty-six.

(g) Four million, three hundred andfifty thousand, five hundred.

(h) Fifty-two million, four hundredand seventy-eight thousand, twohundred and thirteen.

(a) 8 million (b) 800 million(c) 9 million (d) 8 billion

(a) 49216968 (b) 52354701

(c) 88888998 (d) 909090910

(a) 295035206

2× 100000000 + 9 × 10000000 +

5 × 100000 + 0 × 10 + 3 × 10000 +5 × 100000 + 2 × 100 + 6 × 1

(b) 153495604

1 × 100000000 + 5 × 10000000 +

3 × 1000000 + 4 × 100000 + 9 ×10000 + 5 × 1000 + 6 × 100 + 0 ×10 + 4 × 1

(c) 422120130

4 × 100000000 + 2 × 10000000 + 2

× 1000000 + 1 × 100000 + 2 ×10000 + 0 × 1000 + 1 × 100 + 3 ×10 + 0 × 1

(d) 234909005

2 × 100000000 + 3 × 10000000 + 4

× 1000000 + 9 × 100000 + 4 ×10000 + 9 × 1000 + 0 × 100 + 0 ×10 + 5× 1

(a) 53 43 67 209 (b) 400 63 309(c) 80 00 04 007 (d) 75 02 00 451(e) 10 34 03 217

(a) 1 lakh = thousand

(b) 1 crore = lakh

(c) 1 million = thousand

(d) 1 million = lakh

(e) 1 crore = million

(f) 1 billion = million

(a) 555555558; 696969598;879000001; 899987899

(b) 123456789; 153565879;223456879; 233456879

(c) 109898908; 182000919;182212919; 191900009

(d) 208888888; 252789787;400000000; 443322446

(a) 959595965, 789000202,787878878, 565567888

(b) 999899802, 900000000,887799232, 886699232

(c) 919000092, 909999201,900000092, 700009119

7. Rewrite each of the followingnumbers using space to separate theperiods according to theInternational Place Value Chart :

Ans.

8. Write the numbers for each of thefollowing according to theInternational Place Value Chart :

Ans.

9. Write the following numbers inwords : (International system)

Ans.

10. Write the place value of the encircleddigits in the following by using theInternational System of Numeration

Ans.

11. Fill in the blanks :Ans.

12. Write the following numbers inexpanded form :

Ans.

13. Write the following in short form :Ans.

14. Fill in the blanks :

Ans. one hundred

one hundred

ten hundred

ten

ten

one thousand15. Arrange the following numbers in

ascending order :Ans.

16. Arrange the following numbers indescending order :

Ans.

⇒

⇒

⇒

⇒

Mathematics–5 107

Roman Numerals3

Exercise - 2

Worksheet

1. Write in Roman Numerals for thefollowing :

Ans.

2. Write in Hindu Arabic Numerals forthe following :

Ans.

3. Write Roman Numerals :Ans.

4. Write correct numeral from thefollowing numerals given in pairs :

Ans.

5. Fill in the blanks with >, = or < :Ans. <

<=>=<><=<

6. Arrange the following in ascendingorder :

Ans.

7. Arrange the following in descendingorder :

Ans.

8. State ‘True’ or ‘False’ for thefollowing statements given inRoman Numeral System :

Ans.False

TrueFalseTrue

True

9. Fill in the blanks using Romannumerals :

Ans. ––

MMXIV

MCMXLVII

MCMXLVIII

Complete the following :

Ans.

(a) XXI, XI, XXXI, LXII, LXXV,LXXXV, XCV

(b) LXIV, XCI, LI, LXXI, LXXI, LV,LXXXVIII

(c) X, XX, XXX, XL, L, LX, LXX,LXXX, XC, C

(a) 64, 67, 200, 47, 49(b) 55, 77, 88, 66, 46(c) 97, 40, 99, 93, 69

(a) X, XI, XII, XIII, XIV, XV, XVI,XVII, XVIII, XIX, XX

(b) XL, XLI, XLII, XLIII, XLIV, XLV,XLVI, XLVII, XLVIII, XLIX,L

(c) LXXX, LXXXI, LXXXII ,LXXXIII, LXXXIV, LXXXV,LXXXVI, LXXXVII,LXXXVIII,LXXXIX, XC

(a) XV (b) XXIV(c) CL (d) LV(e) IV (f) LXIV

(a) L LX(b) XC C(c) 99 XCIX(d) LX XL(e) 25 XXV(f) LVIII LXVIII(g) 83 XXXVIII(h) 100 L(i) XX + XXX L(j) LXX LX XI

(a) V, X, XVIII, XX, XXX, XC(b) XLVII I , LXXVII , LXXX,

XCVIII, C(c) XXXVI, XLIV, LXVIII, LXXI,

LXXV

(a) LXXVI, LXV, LIV, XXV, XVI(b) XCIII, LXXXII, XLIII, XIX, IX(c) LIX, LVII, LV, LIII, XLI

(a) V subtracted from C gives VC.

(b) VII added to XX gives XXVII.

(c) Ladded to Lgives LL.(d) II added to XX gives XXII.(e) I subtracted from XV gives XIV.

(a) I was born in the year .(b) The year in progress is .(c) The next commonwealth Games

will be held in the year .(d) India got Independence in the year

.(e) Mahatma Gandhi died in the year

.

1. 15 XV

2. 19 XIX

3. CC

15

19

17. Write in expanded notationaccording to the given system :

Ans. (b) 30,00,00,000 +1,00,00,000+ 10,00,000 + 1,00,000 + 20,000+ 8,000 + 900 + 40 + 6

(c) 8,00,00,000 + 70,00,000+ 4,00,000 + 30,000 + 4

(d) 10,00,00,000 + 6,00,00,000+ 20,00,000 + 800 + 8

(e) 30,00,00,000 + 9,00,00,000+ 10,00,000 + 5,00,000 + 60,000+ 8,000 + 100 + 90 + 2

(g) 900,000,000,000 + 4,000,000,000+ 200,000,000 + 300,000 + 8,000+ 200 + 10 + 8

(h) 80,000,000,000 + 5,000,000,000+ 600,000,000 + 20,000,000+ 5,000,000 + 400,000

Mathematics–5108

Mathematics–5 109

Addition and Subtraction4

Exercise - 3Add the following :

1. 1089451, 6836129 and 8510312Ans.

2. 31108213, 153214 and 81334401Ans.

3. 912828, 568549 and 775355Ans.

4. 79643219, 3824312, 634960 and50304090

Ans.

5. 1768471, 1204987, 2760035 and3987689

Ans.

6. 34581021, 63510210, 87354121 and27367898

Ans.

7. 1089451 + 8510312Ans.

8. 4488997 + 3322115 + 5544332Ans.

9. 432509506 + 7987095 + 987Ans.

10. 2887098, 3703895 and 903Ans.

Sum = 16435892

Sum = 112595828

Sum = 2256732

Sum = 134406581

Sum = 9721172

Sum = 212813250

Sum = 9599763

Sum = 13355444

Sum = 440497588

Sum = 16435892

∴

∴

∴

∴

∴

∴

∴

∴

∴

∴

1 0 8 9 4 5 16 8 3 6 1 2 9

+8 5 1 0 3 1 21 6 4 3 5 8 9 2

Th H T O

1 1 1

T-L L T-Th

1

3 1 1 0 8 2 1 31 5 3 2 1 4

+8 1 3 3 4 4 0 11 1 2 5 9 5 8 2 8

Th H T O

1

T-L L T-ThC

9 1 2 8 2 85 6 8 5 4 9

+ 7 7 5 3 5 52 2 5 6 7 3 2

Th H T O

1 1

L T-Th

21 1

7 9 6 4 3 2 1 93 8 2 4 3 1 2

6 3 4 9 6 0+5 0 3 0 4 0 9 0

1 3 4 4 0 6 5 8 1

Th H T O

2 1 1

T-L L T-Th

1111

C

1 7 6 8 4 7 11 2 0 4 9 8 72 7 6 0 0 3 5

+3 9 8 7 6 8 99 7 2 1 1 8 2

Th H T OT-L L T-Th

2 2 22 2 2

3 4 5 8 1 0 2 16 3 5 1 0 2 1 08 7 3 5 4 1 2 1

+2 7 3 6 7 8 9 82 1 2 8 1 3 2 5 0

Th H T O

2 1 2

T-L L T-ThC

1 1 1 1

1 0 8 9 4 5 1+8 5 1 0 3 1 2

9 5 9 9 7 6 3

Th H T OT-L L T-Th

4 4 8 8 9 9 73 3 2 2 1 1 5

+5 5 4 4 3 3 21 3 3 5 5 4 4 4

Th H T O

1 1 1

T-L L T-Th

1 1 1

4 3 2 5 0 9 5 0 67 9 8 7 0 9 5

+9 8 74 4 0 4 9 7 5 8 8

Th H T O

1 1

T-L L T-ThC

1 111

2 8 8 7 0 9 83 7 0 3 8 9 5

+9 0 36 5 9 1 8 9 6

Th H T OT-L L T-Th

1 1 1 1 1

7 7 7 8 8 84 4 4 3 3 3

+ 5 5 6 6 0 61 7 7 8 8 2 7

Th H T O

1 1

L T-Th

11 1

9 3 1 2 5 6 8 18 1 3 5 4 1 2 7

+3 8 9 1 2 3 5 12 1 3 3 9 2 1 5 9

Th H T O

1 1

T-L L T-ThC

1 11

4 8 8 4 4 8 82 8 4 8 4 4 8 42 3 2 1 1 7 8 9

+9 0 1 2 3 5 44 5 5 9 3 1 1 5

Th H T O

1 1 1

T-L L T-Th

2322

C

9 1 2 8 2 8

5 6 8 5 4 9

+ 7 7 5 3 5 5

2 2 5 6 7 3 2

dc 7 3 2 4 2

7 8 7 5 9

6 2 6 7

+ 2 2 6 6 4 1

3 8 4 9 0 9

a 3 2 8 7 8

2 3 5 2 4

+ 1 1 3 5 9

6 7 7 6 1

1 4 2 3 2 1

6 7 4 8 6 5

+ 1 5 0 3 7 7

9 6 7 5 6 5

b

3 9 5 7 6 4 2

4 8 3 1 7 5

+ 3 7 1 8 7 4

4 8 1 2 6 9 1

1 0 8 7 9 4 5

+ 7 8 4 3 2 1 5 4

7 9 5 2 0 0 9 9

8 0 9 5 2 8 7

9 0 8 7 8 4 3

+ 9 1 8 7 9 4 3 2

1 0 9 0 6 2 5 6 2

9 9 9 9 9 9 9 9

+ 9 9 9 9 9 9 9 9 9

1 0 9 9 9 9 9 9 9 8

4 8 1 2 6 9 1

– 8 7 6 4

4 8 0 3 9 2 7

Mathematics–5110

11. 777888 + 444333 + 556606Ans.

12. 93125681 + 81354127 + 38912351Ans.

13. 4884488 + 8484484 + 23211789 +9012354

Ans.

14. Replace the missing digits in each ofthe following :

Ans.

1. There are three candidates in anelection. They received 3957642,4 8 3 1 7 5 a n d 3 7 1 8 7 4 v o t e srespectively. The number of invalidvotes was 8764. How many voteswere registered there?

Sol.

2. Arun bought a plot of land for

1087945 to build a hotel. He spent

78432154 on the construction of the

hotel. How much money did hespend in all?

Sol.

3. In 2009, hand pumps were dug indrought areas. In three differentstates the Government spent

8095287, 9087843 and 91879432

respectively. How much money wasspent in these states?

Sol.

4. Add the greatest 8 digit number tothe greatest 9 digit number.

Sol.

5. The number of persons who visitedVaisnav Devi in the year 2008, 2009,and 2010 were 8432467, 9432878 and7483456 respectively. How manypersons visited Vaisnav Devi in thesethree consecutive years?

Sum = 1778827

Sum = 213392159

Sum = 45593115

Total votes registered= 3957642 + 483175 + 371874 – 8764

Total votes registered = 4803927

Cost of the land = 1087945

Cost of the construction = 78432154Total money spent

= 1087945 + 78432154

Total money spent = 79520099

Total money spent = 8095287

+ 9087843 + 91879432

Total money spent by the Government

was 109062562

Greatest 8 digit number = 99999999Greatest 9 digit number = 99999999Sum = 99999999 + 999999999

Sum = 1099999998

∴

∴

∴

Exercise - 4

⇒

∴

∴

∴

∴

`

`

`

`

` `

`

` ` `

`

` `

`

Sol.

6. A cloth mill produced 989997965 mcloth in 2008, 797877765 m cloth in2009 and 696867664 m cloth in 2010.How much cloth did it produced inthese three years?

Sol.

7. A survey conducted on an Indianstate shows that 1623540 peoplehave only primary education,9768678 people have secondaryeducation, 6437945 people havehigher education and 2682635people are illiterate. If the number ofchildren below the age of schooladmission be 698781, find thepopulation of the state.

Sol.

8. A number exceeds 85384655 by9463184. What is that number?

Sol.

9. In a certain year an industryproduced 6736265 bicycles. Nextyear the number of bicyclesproduced was 1374589 more thanthose produced in the precedingyear. How many bicycles wereproduced during these two years?

Sol.

10. The difference between twonumbers is 8974568. If the smallernumber is 6468457, find the greaternumber.

Sol.


Total persons visited= (persons visited in the year 2008)+ (persons visited int heyear 2009)

+ (person visited in the year 2010)= 8432467 + 9432878 + 7483456

Total person visited in three years

= 25348801

Cloth produced= (cloth produced in 2008)

+ (cloth produced in 2009)+ (cloth produced in 2010)

= 989997965 m + 797877765 m+ 696867664

Total cloth produced in three years

= 2484743394 m

Population of the state = 1623540

+ 9768678 + 6437945 + 2682635

+ 698781

Total population = 21211579

Number = 85384655 + 9463184

Required number = 94847839

Total bicycles produced= (bicycles produced in Ist year)

+ (bicycles produced in 2nd year)= 6736265 + (1374589 + 6736265)

Total bicycles produced during two

years = 14847119

Greater number= difference + small number= 8974568 + 6468457

Greater number is 15443025

(a) (b)

(c)

∴

∴

∴

∴

∴

∴

Exercise - 5

Mathematics–5 111

8 4 3 2 4 6 7

9 4 3 2 8 7 8

+ 7 4 8 3 4 5 6

2 5 3 4 8 8 0 1

9 8 9 9 9 7 9 6 5

7 9 7 8 7 7 7 6 5

+ 6 9 6 8 6 7 6 6 4

2 4 8 4 7 4 3 3 9 4

1 6 2 3 5 4 0

9 7 6 8 6 7 8

6 4 3 7 9 4 5

2 6 8 2 6 3 5

+ 6 9 8 7 8 1

2 1 2 1 1 5 7 9

8 5 3 8 4 6 5 5

+ 9 4 6 3 1 8 4

9 4 8 4 7 8 3 9

6 7 3 6 2 6 5

1 3 7 4 5 8 9

+ 6 7 3 6 2 6 5

1 4 8 4 7 1 1 9

8 9 7 4 5 6 8

+ 6 4 6 8 4 5 7

1 5 4 4 3 0 2 5

7 9 1 4 3 2

– 2 8 7 0 1 6

5 0 4 4 1 6

48 123

6 6 5 5 4 4 3

– 4 4 7 7 8 8 9

2 1 7 7 5 5 4

44314

333141313

8 2 8 2 7 2 2 6

– 4 9 1 4 8 3 3 8

3 3 6 7 8 8 8 8

167 1 6 1 17 12

11161111

(d)

(e) (f)

(g) (h)

(i) (j)

(k) (l)

(a)

Difference = 948084

(b)

Difference = 19145930

(c) 7890342 – (1234567 + 1230321)


(a)

1827615 + 240428 + 1275560

– 22942 = 3320661(b)

57614 + 2318493 + 1880000

– 9474 = 4246633

(c)

32545875 + 4369525 + 7265863

– 70503303 = 13004060(d)

22516400 + 34450675

+ 60060500 – 31821799 = 85205776(e)

85800 + 3742450 + 4241158

– 6840 = 8062568

Savings= (Total income – total expenses)

= 56227662 – 22747788

Money saved by the company was

33479874

Money borrowed fromthe bank= (Total cost of theaeroplane – Money with Mr.Anil)

= 429855 – 349800

Money borrowed from the bank

= 80055


3. Simplify :Ans.

Solve the following word problems :

1. A company earned 56227662 in a

year. If its expenses were 22747788,

how much money was saved by thecompany?

Sol.

2. Mr. Anil wanted to buy an aeroplane

which cost 429855. He had

349800 and borrowed the rest from

a bank. How much money did heborrow from the bank?

Sol.

3. The difference between, twonumbers is 6457058. If the greater

∴

∴

⇒

∴

⇒

∴

⇒

∴

⇒

∴

⇒

∴

⇒

∴

∴

∴

Exercise - 6

`

`

` `

`

`

`

` `

`

65 65 656 5

– 16 76 868 7

48 88 787 8

54 632 478

– 25 678 324

28 954 154

482013520

– 294024638

187988882

342115678

– 156783272

185332406

382042086

– 222948148

159093938

540265876

– 321454286

218811590

954381568

– 421562258

532819310

584321786

– 342767832

241553954

35 005 00

– 25 524 16

9 480 84

200 000 00

– 8 540 70

191 459 30

2 000 000 0

– 85 407 2

1 914 592 8

7 890 342

– 2 464 888

5 425 454

3 343 603

– 22 942

3 320 661

182 761 5

+ 2 4 042 8

+ 127 556 0

334 360 3

4 256 107

– 9 474

4 246 633

5 761 4

+ 2 31 849 3

+ 188 000 0

425 610 7

8 360 736 3

– 7 050 330 3

1 300 406 0

325 458 75

436 956 25

+ 72 658 63

835 073 63

11 702 757 5

–3 182 179 9

8 520 577 6

225 164 00

344 506 75

+ 600 605 00

1170 275 75

806 940 8

– 684 0

806 256 8

858 00

37 424 50

+ 424 11 58

80 694 08

562 276 62

– 337 477 88

334 798 74

42 985 5

– 34 980 0

8 005 5

6 5 3 2 1 4 2 8

– 3 2 4 5 6 7 3 9

3 2 8 6 4 6 8 9

181 0 3 14

11101311

2

12

Mathematics–5112

number is 10452760, find the smallnumber.

Sol.

4. From a given sum of 2580327, the

sum of 875200, 275579 and

557203 are spent on different

occasion. Find the balance of moneyin hand.

Ans.

5. A publisher published 52837222books in one year, Out of these175500 books were on English,4128900 books on Mathematics,3837500 books were on Hindi andremaining books were on othersubjects. How many books werepublished on other subjects?

Sol.

6. A cloth mill produced 301520928 min 2009 and 353715905 m in 2010. Inwhich year did it produced morecloth and how much?

Sol.

7. In an examination 7080500 studentspassed. Out of these 2580905 got firstdivision, 4285803 got second divisionand the remaining got third division.How many got third division?

Sol.

8. What must be added to the leastnumber formed by the digits 1, 2, 3,4, 5, 6 to get the sum as the greatestnumber formed by the digits 2, 5, 7,8, 9, 0?

Ans.

9. In 2009, there were 354155 wagonsin a country. In 2010, the countryhad 361240 wagons. How manywagons were added from 2009 to2010.

Sol.

10. India exported readymade garments

of 659823509 in two years. If one

year the export of readymade

garments was for 424768925, find

the amount received from export inthe second year?

Smaller number= (Greater number

– difference)= 10452760 – 6457058

The smaller number is 3995702

Balance= (Total money – Total expenditure)

= 2580327 – ( 875200 + 275579

+ 557203)

Balance of money in hand is 872345

Books published on other subjects

= Total books published

– (Books published on English

+ Books published on Mathematics

+ Books published on Hindi)= 52837222 – (175500 + 4128900

+ 3837500)

Books published on other subjects

were 44695322

Cloth produced more= (cloth produced in 2010

– cloth produced in 2009)= 353715905 m – 301520928 m

In 2010 more cloth were produced, by

52194977 m.

Students who got third division

= Total students passed – (Studentswho got first division + students whogot second division)= 7080500 – (2580905 + 4285803)

The number of students who got third

division is 213792

Number of be added =( G r e a t e s t n u m b e rformed by the digits– Least number formed by the digits)

= 987520 – 123456

The number to be added to make the

sum equal is 864064

Wagons added = (Wagonsin 2010 – Wagons in 2009)= 361240 – 354155

Wagons added from 2009 to 2010 were

7085

∴

⇒

∴

⇒

∴

∴

⇒

∴

∴

∴

`

` `

`

` ` `

`

`

`

`

Mathematics–5 113

2 580 327

– 1 707 982

872 345

87 520 0

27 557 9

+ 55 720 3

170 798 2

52 837 222

– 8 141 900

44 695 322

17 550 0

412 890 0

+ 383 750 0

814 190 0

353 715 905

– 301 520 928

52 194 977

98 752 0

– 12 345 6

86 406 4

70 805 00

– 68 667 08

2 137 92

2 580 905

+ 4 285 803

6 866 708

36 124 0

–35 415 5

708 5

10 452 760

– 6 457 058

3 995 702

Sol.

11. Kaki bought a farmhouse for190000500 and spent 847400 on

its repairing. What was the totalmoney that Kaki spent?

Sol.

12. A person won an election by getting1224985 votes against his nearestrival who got 368872 votes. By howmuch margin did the person win?

Sol.

13. The money collected by sellingtickets in a theatre on Sunday and

Saturday was 22445600 and

8134672 respectively. What was thetotal collection in both daystogether?

Sol.

14. What is the difference between thegreatest 9-digit number and thegreatest 8-digit number?

Sol.

15. Find the population of the states ofMaharastra and Tamil Nadutogether, if the population ofMaharstra is 23123000 and that ofTamil Nadu is 31725000?

Sol.

16. The money collected by selling ticketsin a theater on Monday and Tuesday

was 2565690 and 1316472

respectively. Which day’s collectionwas moreand by how much?

Sol.

17. What is the difference between thegreatest 8-digit number and thegreatest 7-digit number?

Sol.

Amount received in the second year

= (Total amount received – Amountreceived in the first year)

= 659823509 – 424768925Amount received in the second year

was 235054584

Total money spent = (Money spent onpurchasing + Money spent onrepairing)

= 90000500 + 847400

Total money spent by Kaki was

19087900

Margin of the win = (Votes got by thewinner – votes got by the loser)

= 1224985votes – 368872 votes

The person won by the margin of

356113 votes

Total collection= (Money collected on Sunday

+ Money collected on Saturday)

= 22445600 + 8134672

Total collection was 30580272

Greates 9 – digit number = 999999999Greates 8 – digit number = 99999999

Difference = (Greates 9 – digit number

– Greates 8 digit number)= 9999999999 – 999999999


Total population = (Population ofMaharashtra + Population of TamilNadu)= 23123000 + 31725000

Total population

= 54848000

Money collected on Monday= 2565690

Money collected on Tuesday= 1316472

Money collected onMonday was morethan money collectedon Tuesday

Monday’s collection was more than

Tuesday’s collection by 1249218.

Greatest 8- digit number = 99999999Greatest 7 - digit number = 9999999

Difference = (Greatest 8-digit number

– greatest 7-digit number)= 99999999 – 9999999


` `

`

` `

` `

` `

` `

`

` `

`

`

`

∴

∴

∴

∴

∴

∴

∴

∴

∴

190 000 500

+ 8 47 400

190 847 900

12 24 985

– 3 68 872

8 56113

224 456 00

– 81 346 72

305 802 72

99 999 999 9

– 9 999 999 9

90 000 000 0

23123000

+31725000

54848000

256 569 0

– 131 647 2

124 921 8

99 99 999 9

– 9 99 999 9

90 00 000 0

6 598 235 09

– 4 247 689 25

2 350 545 84

Mathematics–5114

Mathematics–5 115

Exercise - 7

Exercise - 8

Exercise - 9

Solve the following :

15000 2000

14000 13000

18000 11000

12000 3000

5000 31000

25000 21000

9000 23000

19000 8000

700 6000

600 4000

1. Using suitable grouping, find theproducts of the following :

Ans.

2. Find the products of the following :Ans.

3. Fill in the blanks :Ans. 1050

10

47175

4. Solve the following :Ans. 72190

6532081675007256300837500034560009999885200

Solve the following :

1. 2.

3. 4.

5. 6.

1. 15 × 1000 = 2. 2 × 1000 =

3. 14 × 1000 = 4. 13 × 1000 =

5. 18 × 1000 = 6. 11 × 1000 =

7. 12 × 1000 = 8. 3 × 1000 =

9. 5 × 1000 = 10. 31 × 1000 =

11. 25 × 1000 = 12. 21 × 1000 =

13. 9 × 1000 = 14. 23 × 1000 =

15. 19 × 1000 = 16. 8 × 1000 =

17. 7 × 100 = 18. 6 × 1000 =

19. 6 × 100 = 20. 4 × 1000 =

(a) 4 × 237 × 25= (40 × 25) × 237= 100 × 237 = 23700

(b) 8 × 1047 × 125= (8 × 125) × 1047= 1000 × 1047 = 1047000

(c) 12 × 525 × 25= (12 × 25) × 525= 300 × 525 = 157500

(d) 500 × 1236 × 2= (500 × 2) × 1236= 1000 × 1236 = 1236000

(e) 5 × 479 × 20= (5 × 20) × 479= 100 × 479 = 47900

(f) 250 × 756 × 4= (250 × 4) × 756= 1000 × 756 = 756000

(a) 4065 × 50 (b) 8497 × 60

(c) 18245 × 70 (d) 9278 × 300

(e) 8689 × 900 (f) 30526 × 800

(a) 2346 × = 2346 × 1050(b) 7227 × = 7227(c) 5843 × = 0(d) 25 × (100 + 47)

= (25 × 100) + (25 × )(e) × (3010 × 175)

= (115 × 3010) × 175

(a) 7219 × 10 =(b) 6532 × 10 =(c) 81675 × 100 =(d) 72563 × 100 =(e) 8375 × 1000 =(f) 3456 × 1000 =(g) 9999 × 1 =(h) 8852 × 1 =(i) 100000 × 0 =(j) 35600 × 0 =

5937 × 36 4850 × 75

8125 × 85 7237 × 456

5038 × 808 3497 × 337

Multiplication5

4 065× 50

0 000203 250203 250

849 7×6 0

000 050 982 050 982 0

1 824 5×7 0

0 000 0127 715 0127 715 0

927 8× 30 0000 0

0 000 0278 340 0278 340 0

30 526× 800

00 000000 000

24 420 80024 420 800

868 9× 90 0000 0

0 000 07 82 010 07 82 010 0

5 937× 36

35 6221 78 110213 732

4 85 0× 7 5

24 25 0339 50 0363 75 0

8 125× 85

40 625650 000690 625

7 23 7× 45 6

43 42 2361 80 0

3 300 07 2

5 038× 808

40 30400 000

4 030 4004 070 704

3 49 7× 33 7

24 47 9104 91 0

1 049 10 01178 48 9

2 808 3× 632 5

14 041 556 166 0

8 42 490 0168 49 800 0177 62 497 5

2 508×5 032

5 01675 240

000 00012 540 00012 620 256

28 063×4 026

168 378561 260

0 000 000112 252 000112 981 638

2 500 0× 9 9

22 500 02 25 000 02 47 500 0

80 000×1 587

560 0006 400 000

40 000 00080 000 000

126 960 000

503 0× 123 42 012 0

15 090 0100 600 0503 000 0620 702 0

400 325× 209

3 602 9250 000 000

80 065 00083 667 925

728 090× 222

1 456 18014 561 800

1 45 618 0001 61 635 980

3 215 23×3 24

12 860 9264 304 60

964 569 001 041 734 52

354 286× 234

1 417 14410 628 58070 857 20082 902 924

456 783× 576

2 740 69831 974 810

228 391 500263 107 008

4 567 82×3 25

22 839 1091 356 40

1 370 346 001 484 541 50

24 826 7× 45 6

1 48 960 212 41 335 099 30 680 0

113 20 975 2

3 256 78×4 32

6 513 5697 703 40

132 712 001 406 928 96

34 287 6× 54 6

2 05 725 613 71 504 0

171 43 800 0187 21 029 6

6 532 15×7 65

32 660 75391 929 00

4 572 505 004 997 094 75

84 567 8× 64 5

4 22 839 033 82 712 0

507 40 680 0545 46 231 0

7 876 53×6 57

55 135 71393 826 50

4 725 918 005 174 880 21

34 567 8× 34 5

1 72 839 013 82 712 0

103 70 340 0119 25 891 0

9 897 8× 785 00 000 0

494 890 07 918 240 0

69 284 600 077 697 730 0

625 308× 152

1 250 61631 265 40062 530 80095 046 816

Mathematics–5116

2508 × 5032 28083 × 6325

28063 × 4026 99 × 25000

1587 × 80000 5030 × 1234

400325 × 209 728090 × 222

321523 × 324 625308 × 152

354286 × 234 456783 × 576

456782 × 325 248267 × 456

325678 × 432 342876 × 546

653215 × 765 845678 × 645

787653 × 657 345678 × 345

Number of apples in 7850 boxes= (Number of apples in one box) × 7850= 98978 × 7850

Total number of apples

= 776977300 apples

7. 8.

9. 10.

11. 12.

13. 14.

15. 16.

17. 18.

19. 20.

21. 22.

23. 24.

25. 26.


1. There are 98978 apples in one box.How many apples are there in 7850such boxes?

Sol.

2. The cost of a car is 895470. How

much do 977 cars cost?

Exercise - 10

∴

`

Sol.

3. The weight of a box containing booksis 5 kg 250 gm. How much will be theweight of 139 such boxes?

Sol.

4. How many seconds are there in aday?

Sol.

5. The cost of a T.V. set is 18525. Find

the cost of such 8350 T.V. set.Sol.

6. A factory produces 2985 bulbs in aday. How many bulbs did it producein the year 2010 if there were 60holidays in a year?

Sol.

7. Multiply the largest 5-digit numberby the largest 3-digit number.

Sol.

8. Diksha can type 80 words in aminute, How many words will shetype in 15 days, if she type daily 5hours 30 minutes?

Sol.

9. If the monthly fee for per student is

535, what is the total fee for 3476

students?Sol.

10. An engine pumps out 25500 litres ofwater in an hour. The engine is usedfor 10 hours daily. How many litresof water will it pump out in 10 days?

Sol.

Cost of 977 cars= (Cost of one car) × 977

= 895470 × 977

Total cost of the cars = 874874190

Weight of 139 boxes

= (weight of 1 box) × 139

= 5 kg 250 gm × 139

Weight of boxes

= 729 kg 750 gm

Number of seconds in a day= (Number of seconds in a minutes

× Number of minutes in an hour× Number of hours in a day)

= 60 × 60 × 24

Number of seconds in a day

= 86400 seconds

Cost of 8350 T.V. sets= (The cost of a T.V. set) × 8350

= 18525 × 8350

Cost of T.V. sets = 154683750

Number of bulbsproduced in 2010

= (Number of bulbsproduced in oneday) × (365 – 60)= 2985 × 305

Number of bulbs produced in 2010

= 910425 bulbs

Largest 5- digit number= 99999

Largest 3- digit number= 999

Product = 99999 × 999

Product = 99899001

Number of words typed in a day

= (Number of words typed

in a minute)

× 5 hrs 30 minutes= 80 × (60 × 5 + 30) minutes= 80 × 330 minutes= 26400 wordsNumber of words typed

in 15 days= (Number of words typed

in one day) × 15= 26400 × 15

Words typed in 15days =396000words

Total fee for 3476students

= (Fee for a student)× 34476

= 535 × 3476

Total fee = 1859660

Water pumped out in a day= (Water pumped in an hour ) × 10= 25500 litres × 10= 25500 litres

`

`

`

`

`

`

`

∴

∴

⇒

∴

∴

∴

∴

∴

∴

Mathematics–5 117

89 547 0× 97 7

626 829 06 268 090 0

80 592 300 087 487 419 0

5 . 2 50×1 39

472 501 575 005 250 00

72 9 . 7 50

36 00× 24

1 44 007 20 008 64 00

6 0× 6 0

0 036 0

3 60 0

185 25× 83 50000 00

9 262 5055 575 00

1 482 000 001 546 837 50

298 5× 30 5

1 492 50 000 0

89 550 091 042 5

99 999× 999

899 9918 999 910

89 999 10099 899 001

3 30× 800 00

264 00264 00

2 640 0×1 5

13 200 026 400 039 600 0

347 6× 53 5

1 738 010 428 0

173 800 0185 966 0

Water pumped in 10 days= (Water pumped in one day) × 10= 255000 litres × 10= 2550000 litres

The engine will pump out 2550000

litres of water in 10 days.

Weight of 425 bags

of sugar

= (Weight of one bag

of sugar ) × 425

= 125 kg 850 g × 425

Total weight = 53486 kg 250g

Total number of tiles required= (Number of flats)× (Number of rooms)× (Number of floor tiles in each room)

= 24 × 5 × 135 tiles

Total number of tiles required for the

housing complex = 16320 tiles

Money earned by MrAnil in 4 years= (Money earned in onemonth)× (Number of months in

a year) × 4

= 14788 × 12 × 4

= 14788 × 48

Anil will earn 709824 in 4 years

Number of nails to be produced inMarch = (Number of nails produced in

a day) × (Number of days in the monthof March)

= 264137 nails × 31

In the month of the March the factory

will produce 8188247 nails

Money required to buy44 Maruti cars

= (Cost of 1 Maruti car )× 44

= 334840 × 44

Money required to buy 44 Maruti cars

is 14732960

Total nuts in 385 boxes

= (Number of nuts in one

box) × 385

= 20340 nuts × 385

Total number of nuts

= 7830900 nuts

Cost of 204 ghee packs= (The cost of one ghee

pack) × 204

= 234 × 204

The cost of 204 ghee

packs = 47736

Number of pages in 254notebooks

= (Number of pages inone notebook)

× 254= 510 × 254

Pages in notebooks = 129540 pages

∴

∴

⇒

∴

∴

∴

∴

∴

∴

∴

11. A bag of sugar weighs 125 kg 850 g.Find the total weight of sugar in 425such bags.

Sol.

12. A housing complex has 24 flats, eachflat has 5 rooms. Each room require136 floor tiles. How many tiles wouldbe required for the housingcomplex?

Sol.

13. Anil earns 14788 per month. How

much will he earn in 4 years?Sol.

14. A factory produce 264137 iron nailsevery day. How many iron nails willit produce in the month of March?

Sol.

15. A Maruti car costs 334840. How

much money is required to buy 44such Maruti cars?

Sol.

16. Abox contain 20340 nuts. How manynuts will be there in 385 such boxes?

Sol.

17. The costs of a pack of ghee is 234.

Find cost of 204 such ghee packs?Sol.

18. There are 510 pages in a notebook.How many pages are there in 254such notebooks.

Sol.

`

`

`

`

`

`

`

`

`

`

1 25 . 85 0× 42 5

62 925 02 51 700 0

50 34 000 0534 86 . 25 0

13 6× 12 0

00 02 72 0

13 60 016 32 0

2 4× 5

12 0

147 88× 48

1183 045 915 207 098 24

26 413 7× 3 1

26 413 77 924 11 0818 824 7

33 484 0× 4 4

1 33 936 013 39 360 014 73 296 0

2 034 0× 38 5

10 170 0162 720 0610 200 0783 090 0

2 34×2 04

9 3600 00

468 00477 36

51 0× 25 4204 0

2 550 010 200 012 954 0

Mathematics–5118

Mathematics–5 119

Division6

Exercise - 11Find the quotient and remainder :

1. 6990390 ÷ 7400Ans.

2. 912563 ÷ 4000Ans.

3. 98376800 ÷ 100000Ans.

4. 566532367 ÷ 1000Ans.

5. 920010025 ÷ 8253Ans.

6. 720050028 ÷ 9012Ans.

7. 82356529 ÷ 3405Ans.

8. 8697255 ÷ 1525Ans.

Quotient = 944, Remainder = 4760


Quotient = 983 Remainder = 76800


Quotient = 111475,Remainder = 6850




7400 6990390 944–66600

33039–29600

34390–29600

4790

00 0000 0000 000

000000000

4000 912563 228–8000

11256–800032563

–32000563

00 0000 0000 000

000000000

8253 920010025 111475–8253

9471–825312180–825339270

–3301262582

–5777148115

–412656850

00000 0000000000 0000000000 000000000 000000000 00000000 00000000 0000000 0000000 000000

000000000000000000

9012 720050028 79899–63084

89210–81108

81020–72096

89242–81108

81348–81108

240

0000 00000000 00000000 0000000 0000000 000000 000000 00000

000000000000000

3405 82356529 24186–681014256

–136206365

–340529602

–2724023629

–204303199

0000 00000000 00000000 0000000 0000000 000000 000000 00000

000000000000000

1525 8697255 5703–762510722

–106754755

–4575180

000 000000 000000 0000

000000000000

100000 98376800 983–900000

837680–800000

376800–300000

76800

00 0000 0000 000

000000000

1000 566532367 566532–5000

6653–6000

6532–6000

532350003236300023672000367

00000 0000000000 0000000000 000000000 000000000 00000000 00000000 0000000 0000000 000000

000000000000000000

9. 5820635 ÷ 2875Ans.

10. 308509 ÷ 2314Ans.

11. 61836704 ÷ 603Ans.

12. 6384615 ÷ 216Ans.

13. 4519460 ÷ 264Ans.

14. 36648067 ÷ 943Ans.

15. 6224378 ÷ 584Ans.

16. 99999 ÷ 315Ans.

17. 1523811 ÷ 37Ans.

18. 323465 ÷ 72Ans.











2875 5820635 2024–5750

7063–575013135

–115001635

000 00000 00000 0000

000000000000

2314 908509 392–694221430

–208266049

–46281421

00 0000 0000 000

000000000

603 61836704 102548–603

1536–1206

3307–3015

2920–2412

5084–4824

260

00000 000000000 000000000 00000000 00000000 0000000 0000000 000000

000000000000000000

216 6384615 29558–4322064

–19441206

–10801261

–10801815

–172887

0000 00000000 00000000 0000000 0000000 000000 000000 00000

000000000000000

264 4519460 17119–2641879

–1848314

–264

0000 00000000 00000000 0000000 0000000 00000

506–2642420

–237644

00

943 36648067 38863–2829

8358–7544

8140–7544

5966–5658

3087–2829

258

0000 00000000 00000000 0000000 0000000 000000 000000 00000

000000000000000

584 6224378 10658–584

3843–3504

3397–2920

4778–4672

106

0000 0000000 0000000 000000 000000 00000

000000000000000

315 99999 317–945

549–3152349

–2205144

00 0000 0000 000

000000000

37 1523811 41184–148

43–37

68–37

311–296

151–148

3

0000 00000000 00000000 0000000 0000000 000000 000000 00000

000000000000000

72 323465 4492–288

354–288

666–648

000 000000 000000 00000 00000 0000

185–144

41

00

Mathematics–5120

Mathematics–5 121

19. 12346026 ÷ 82Ans.

20. 149826 ÷ 68

Ans.

21. 18325 ÷ 43

Ans.

22. 537809 ÷ 35

Ans.


1. What least number should besubtracted from 7280603 so that theremainder is exactly divided by 928?

Sol.

2. A factory makes a machine whichhas 12 parts. Each part requires 20nuts. The nuts are supplied to thefactory in boxes which contains 120nuts each. If the factory wants tomake 1200 machines, how manyboxes of nuts would it require?

Sol.

3. A fruit-seller had 256000 mangoes.He packed them in boxes. Each boxcontained 175 mangoes. How manyboxes were used and how manymangoes were left over?

Sol.

Quotient = 150561,Remainder = 24


Quotient = 426 Remainder = 7


By dividing 7280603 by 828, we get

Here remainder is 443

So, the least number to be subtractedfrom 7280603 is 443.

Number of nuts required

for a machine

= 12 × 20 nuts

= 240 nuts

Number of nuts required

for 1200 machines

= (nuts required for 1 machine) × 1200

= 240 nuts × 1200 = 288000 nutsNumber of boxes required= (Total nuts) ÷ (number of nuts in a

box)= 288000 ÷ 120

Number of boxes required = 2400.

Exercise - 12

∴

68 149826 2203–136

138–136

226–204

22

000 000000 000000 0000

000000000000

82 12346026 150561–82414

–410460

–410502

–492106–8224

00000 0000000000 0000000000 000000

00 00000000 0000000 0000000 000000

000000000000000000

43 18325 426–172

112–86265

–2587

00 0000 0000 000

000000000

35 537809 15365–35187

–175128

–105230

–210209

–17534

0000 00000000 00000000 0000000 0000000 000000 000000 00000

000000000000000

928 7280603 7845–6496

7846–7424

4220–3712

5083–4640

443

000 000000 000000 00000 00000 0000

000000000000

12 00×2 4000 00

480 002 400 002 880 00

120 288000 2400–240

480– 480

0–0

0–00

000 000000 000000 00000 00000 0000

000000000000

175 256000 1462–175

810–700

1100–1050

500–350150

000 000000 000000 00000 00000 0000

000000000000

Here quotient = 1462and remainder = 150

Number of boxes used = 1462

Number of mangoes left over = 150.

Money each student will get = (Totalmoney) ÷ (Number of students)

= 3021850 ÷ 325

Each student will get 9298

Number of radio sets sold = (Totalmoney realized) ÷ (cost of a radio)

= 5977125 ÷ 945

The number of radio sets sold in that

year = 6325.

Quotient = Divident ÷ Divisor

Quotient = 31.

The other number= Product ÷ one number= 3698640 ÷ 144

The other number is 25685.

Number of flowers required to makeone garland= (number of rows)

× (number of flowers in a row)= 3 × 100 = 300 flowers

Number of flowersrequired to make 88garlands

= (number of flowers

in one garland) × 88= 300 × 88= 26400 flowers

Number of bunches required

= (Number of flowers in total)

÷ (Number of flowers in a bunch)= 26400 ÷ 120

Bunches of flowers required = 220.

Number of tables sold = (Total moneycollected) ÷ (the cost of one table)

∴

∴

∴

∴

∴

4. A man divides 3021850 equally

among 325 poor students. Howmuch money will each student get?

Sol.

5. The cost of a radio set is 945. A

company realized 5977125 by

selling radio sets in a year. Find thenumber of radio sets sold in thatyear.

Sol.

6. In a certain division sum, thedivident is 109876, the divisor is 3456and the remainder being 2740. Findthe quotient.

Sol.

7. The product of two numbers is3698640 one of them is 144. Find theother number.

Sol.

8. A garland has three rows of flowers.Each row has 100 flowers. Theflowers come in bunches, eachcontaining 120 flowers. How manybunches of flowers would berequired to make 88 such agarlands?

Sol.

9. The cost of one table is 1525. If a

shopkeeper collected 826550 by

selling the tables, how many tablesdid he sell?

Sol.

`

`

`

`

`

`

`

`

∴

325 3021850 9298–2925

968–6503185

–29252600

–2600×

000 000000 000000 00000 00000 0000

00000000

0 0000

945 5977125 6325–5760

3071–2835

2362–1890

4725–4725

×

000 000000 000000 00000 00000 0000

00000000

0 0000

3456 109876 31–10368

6196–34562740

0 00000000

144 3698640 25685–288

818–720

986–8641224

–1152720

–720×

0000 00000000 00000000 0000000 0000000 000000 000000 00000

0000000000

0 00000

3 00× 88

24 00240 00264 00

120 26400 220–240

240–240

0–0×

00 0000 0000 000

000000000

Mathematics–5122

= 826550 ÷ 1525

Total number of tables sold = 542

Greatest number of 9-digits= 999999999

Greatest number of 3 - digit = 999= 999999999 ÷ 999

Quotient = 1001001

Number of tourists visit each day= (Total number of tourists visited)

÷ (Number of days)= 2317756 ÷ 826

Tourists visited Delhi each day = 2806.

Number of years = (Total number ofdays) ÷ (Number of days in a year)= 228125 ÷ 365

.

There are 625 years in 228125 days.

The other number= Product ÷ the first number= 59616 ÷ 288

The other number is 207

Contribution of each house = (Totalmoney required) ÷ (Number of houses)

= 4912500 ÷ 786

Each house will contribute 6250.

Number of shirts sold = (Total moneycollected) ÷ (The rate of one shirt)

= 429938 ÷ 454

The number of shirts sold = 947.

Number of packets to be bought= (Total number of sheets required)

÷ (Number of sheets in a packet)= 288144 ÷ 144

Number of packets to be bought = 2001

∴

∴

∴

∴

∴

∴

∴

∴

10. Divide the greatest numberof 9 digitsby the greatestnumberof3-digits.

Sol.

11. 2317756 tourists visited Delhi in 826days. How many tourists visitedDelhi each day?

Sol.

12. How many years are there in 228125days.Assume that 1 year = 365 days.

Sol.

13. The product of two numbers is59616. If one of the numbers is 288,find the other.

Sol.

14. 4912500 are needed to dig aborewell. 786 houses contributesequally to dig this well. How muchwill each house contribute?

Sol.

15. A wholesaler collected 429938 byselling shirts at the rate of 454 pershirt. What is the number of shirt hesold?

Sol.

16. I need 288144 sheets of white paperfor a project. If a packet contains 144sheets, how many packets should Ibuy?

Sol.

`

`

`

`

`

Mathematics–5 123

1525 826550 542–7625

6405–6100

3050–3050

×

00 0000 0000 000

000000

0 000

999 999999999 1001001–999

999999

999999×

000000 0000000000 0000000000 0000000

00000000000000

0 0000000

826 2317756 2806–1652

6657–6608

4956–4956

×

000 000000 000000 0000

00000000

0 0000

288 59616 207–576

2016–2016

×

00 000000000

0 000

454 429938 947–4086

2133–1816

3178–3178

×

00 0000 0000 000

000000

0 000

144 288144 2001–288

144–144

×

000 000000000000

0 0000

365 228125 625–2190

912–7301825

–1825×

00 0000 0000 000

000000

0 000

786 4912500 6250– 4716

1965–1572

3930–3930

0–0×

000 000000 000000 00000 00000 0000

000000000000

1 Revision - JB Publishing House · nine (b) Six lakh, ninty-nine thousand and four (c) Three lakh...

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