1© Manhattan Press (H.K.) Ltd. 10.6 Resonance tube – Measurement of speed of sound in air.
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Transcript of 1© Manhattan Press (H.K.) Ltd. 10.6 Resonance tube – Measurement of speed of sound in air.
© Manhattan Press (H.K.) Ltd. 1
10.6 Resonance tube – 10.6 Resonance tube – Measurement of speed Measurement of speed
of sound in airof sound in air
© Manhattan Press (H.K.) Ltd. 2
10.6 Resonance tube – Measurement of speed of sound in air (SB p. 148)
Resonance tube
Vibrate tuning fork over open end of tube- air column in tube is vibrated
fv
fvc
fvc
2
43
43
44
21
2
1
Speed of sound in air v = 2f (2 – 1)
© Manhattan Press (H.K.) Ltd. 3
10.6 Resonance tube – Measurement of speed of sound in air (SB p. 149)
Resonance tube
c,f
vv
cvf
fvc
1
1
1
01When
graph ofGradient 4air in sound of Speed
4Gradient
41
4
Go to
Example 8Example 8
Go to
Example 9Example 9
© Manhattan Press (H.K.) Ltd. 4
End
© Manhattan Press (H.K.) Ltd. 5
10.6 Resonance tube – Measurement of speed of sound in air (SB p. 150)
Q:Q: A tuning fork of frequency 250 Hz is used with
a resonance tube, closed at one end, to measure the speed of sound in air. The resonant lengths are found to be 0.30 m and 0.96 m. Calculate(a) the speed of sound, and(b) the end correction of the tube.
Solution
© Manhattan Press (H.K.) Ltd. 6
10.6 Resonance tube – Measurement of speed of sound in air (SB p. 150)
Solution:Solution:
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TextText
m 030300
4321300
4 correction end
1equation Using(b)s m 330321250 sound of Speed
m 321 210.66 12
2430.96
m, 0.96 islength resonant the When
14
0.30
m, 0.30 oflength resonant first For the (a)
1
....c
,.fv
.
................c
..................c
© Manhattan Press (H.K.) Ltd. 7
10.6 Resonance tube – Measurement of speed of sound in air (SB p. 151)
Q:Q:
A vibrating tuning fork is held near the end A of a tube AB. The piston P is moved slowly from A to B. A loud sound is first heard when AP is 0.15 m, and the next when AP is 0.47 m (see figure above). (a) For the second resonant length, draw a graph showing how the amplitude a of vibration of the air particles in the tube varies with the distance x from P.(b) Explain why the relationship between the two resonant lengths is not a simple ratio.
Solution
© Manhattan Press (H.K.) Ltd. 8
10.6 Resonance tube – Measurement of speed of sound in air (SB p. 151)
Solution:Solution:
(a)
© Manhattan Press (H.K.) Ltd. 9
10.6 Resonance tube – Measurement of speed of sound in air (SB p. 151)
Solution (cont’d) :Solution (cont’d) :
m 0.01 150
4640 1 from and
m 0.64,211500.47 12
ratio. simplenot iswhich
41
43
0.150.47
12
243 ,0.47
430.47 length,resonant second For the
14
0.15 ,4
0.15 length,resonant first For the
.correction end thebe Let tube. theof endopen thebeyond extend particlesair theof s vibration thebecause ratio simple anot is lengthsresonant two theof ratio The (b)
..c
.
c
c
........cc
..............cc
c
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