1 Liquids, solids, & intermolecular forces Chapter 11.
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Transcript of 1 Liquids, solids, & intermolecular forces Chapter 11.
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KMT meets liquidsKMT meets liquids
Ideal gas is a gas even at absolute zeroReal gas condenses to liquid at low T/high P
Attractive forces exist between real gas molecules
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Intermolecular attractionsIntermolecular attractions
Attractive forces exist between all atoms/molecules
Relative strength of attractions indicated byBoiling point (higher b.p. = stronger attractions)Vapor pressure (high v.p. = weaker attractions)∆Hvaporization (large ∆Hvap = stronger attractions)
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Instantaneous or momentary dipolesInstantaneous or momentary dipoles
e– distribution is asymmetric –– just for a momentAtom/molecule is polar –– just for a moment
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Induced dipolesInduced dipoles
Momentary dipole in one atom induces a dipole in a neighboring atom . . . which induces a dipole in another neighboring atom, and so on, causing a little ripple of dipoles
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Dispersion forceDispersion force
Taken together, instantaneous & induced dipoles create an attractive force between molecules, called the dispersion force
Each dipole is tiny, but the constant ripple of countless dipoles throughout the substance makes this the primary attractive force between molecules
Even noble gas atoms show dispersion force between atoms
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PolarizabilityPolarizability
Magnitude of dispersion force depends on polarizability
Larger e– cloud = more polarizable Dispersion force increases with increasing molar massMelting and boiling points of molecular substances
generally increase as molar mass increases
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Molar mass & boiling pointMolar mass & boiling point
For compounds of similar structure, boiling point increases as molar mass increases
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PolarizabilityPolarizability
Polarizability is greater in elongated molecules than in compact ones of similar mass
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Permanent dipolesPermanent dipoles
Polar molecules tend to arrange themselves +/– to maximize attractions
Extra ordering increases tendency to stick together in liquid state
Boiling point of a polar substance is higher than that of a nonpolar substance of similar mass.
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The van der Waals forcesThe van der Waals forces
Together, dispersion and pemanent dipole forces are known as the van der Waals forcesWhen comparing substances of comparable mass
(±10%), the presence of a permanent dipole increases boiling point significantly
When comparing substances of different molar masses, the dispersion force (related to mass) is more important than the permanent dipole
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ExamplesExamples
Which would you expect to have the highest boiling point, and why: C3H8, CO2, CH3CN
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ExamplesExamples
Which would you expect to have the highest boiling point, and why: C3H8, CO2, CH3CNmasses similar (C3H8 = 44, CO2 = 44, CH3CN = 41)
CH3CN polar = highest bp
Actual values: C3H8 = 231K, CO2 = 195K, CH3CN =
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ExamplesExamples
Arrange these in order of increasing boiling point: Ne, He, Cl2, (CH3)2CO, O2, O3
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ExamplesExamples
Arrange these in order of increasing boiling point: Ne, He, Cl2, (CH3)2CO, O2, O3
masses: Ne = 20, He = 4, Cl2 = 71, (CH3)2CO = 58, O2 = 32, O3 = 48
Ordered by mass: He, Ne, O2, O3, (CH3)2CO, Cl2
(CH3)2CO is polar & has large surface area = higher bp
Predict He, Ne, O2, O3, Cl2, (CH3)2CO
Actual values: He = 4K, Ne = 27K, O2 = 90K, O3 = 161K, Cl2 = 238K, (CH3)2CO = 329K
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Weak bond to neighboring O is a hydrogen bond
O–H bond is very polar, and atoms are very small
Dipoles are close together, so their attraction is very strong
H atom is covalently bonded to its own O and weakly bonded (dotted line) to the neighboring O
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Hydrogen bondingHydrogen bonding
Hydrogen bonding occurs only between molecules containing N–H, O–H, and F–H bonds
Hydrogen bonding is much stronger than ordinary dispersion/dipole → much higher boiling points than expected for their mass
Hydrogen bonds are not as strong as covalent bonds (15-40 kJ/mol, vs >150 kJ/mol)
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Substances that are not molecularSubstances that are not molecularIonic substances
Held together by lattice energyGenerally high mp & bp
Metallic substancesMetal cations in sea of electronsGenerally high mp & bp
Network covalent solids (e.g. diamond)Melting = disrupt covalent bondsVERY high mp & bp
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VaporizationVaporization
At liquid surface, faster molecules have enough kinetic energy to escape (vaporize or evaporate)
As higher-energy molecules leave the liquid, average kinetic energy of the liquid decreases
Temperature of liquid decreases (evaporative cooling)
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VaporizationVaporization
For liquid temperature to remain constant during evaporation, liquid must absorb energy from surroundings
Amount of energy liquid must absorb to keep temperature constant during evaporation = enthalpy (heat) of vaporization (∆Hvaporization)
Vaporization is endothermic, so ∆Hvap is positive
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ExampleExample
How much energy is required to vaporize 2.35 g of diethyl ether, (C2H5)2O, at 298 K? ∆Hvap for diethyl ether at 298 K is 29.1 kJ/mol.
2.35g ×1mol
74.123g=0.0317mol ×
29.1kJ1mol
=0.923kJ
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Liquid-vapor equilibriumLiquid-vapor equilibrium
When rate of vaporization = rate of condensation in a closed sysem, system has reached equilibrium
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Vapor PressureVapor Pressure
Pressure exerted by vapor in dynamic equilibrium w its liquid = vapor pressure of that liquid
Vapor pressure depends only on type of liquid & temperature
As long as both phases are present, amount of liquid in container does not affect vapor pressure
Liquids with high vapor pressure at room temperature are volatile (evaporate easily)
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Vapor Vapor pressure pressure curvescurves
Vapor Vapor pressure pressure always always
increases as increases as temperature temperature
increasesincreases
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Vapor pressure and boilingVapor pressure and boiling In open container, evaporation occurs only at surface As temperature increases, evaporation increases
At some point, evaporation begins to occur throughout the liquid instead of just at the surface: boiling!
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Vapor pressureVapor pressure & boiling & boiling
Vapor bubbles form throughout liquid
Bubbles rise to surface, burst, release vapor
All energy is used to convert liquid to vapor, so temperature remains constant while liquid boils
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Boiling pointBoiling point
Boiling begins when the liquid’s vapor pressure matches the external pressure of the atmosphere
The temperature at which this occurs is the boiling point
When the external atmospheric pressure = 1 atm, the boiling point is called the normal boiling point
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The critical pointThe critical point
Liquid heated in a rigid sealed container does not boil Vapor pressure and vapor density increase Liquid density decreases Vapor & liquid densities become equal & meniscus disappears
This point is called the critical point
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Vapor pressure and temperatureVapor pressure and temperature
Clausius-Clapeyron equation shows relationship between vapor pressure and temperature
lnP2
P1
=∆Hvaporization
R1T1
−1T2
⎛
⎝⎜⎞
⎠⎟
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Clausius-Clapeyron Clausius-Clapeyron equationequation
P (vapor pressure) can be in any unitR must be 8.3145 J/mol K∆Hvaporization is usually given in kJ/mol but must be
converted to J/mol to agree with RT is in Kelvins (duh)
lnP2
P1
=∆Hvaporization
R1T1
−1T2
⎛
⎝⎜⎞
⎠⎟
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ExampleExample
The vapor pressure of methanol is 100 mm Hg at 21.2 °C. What is its vapor pressure at 25.0 °C? ∆Hvap for methanol is 38.0 kJ/mol.
lnP2
100mmHg=
38.0 ×103 Jmol
8.3145 JmolK
1294.35K
−1
298.15K⎛⎝⎜
⎞⎠⎟
lnP2
100mmHg=0.19789
P2
100mmHg=e0.19789 =1.22
P2 =122mmHg
lnP2
P1
=∆Hvaporization
R1T1
−1T2
⎛
⎝⎜⎞
⎠⎟
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ExampleExample
The normal boiling point of isooctane is 99.2 °C and its ∆Hvap is 35.76 kJ/mol. What is the vapor pressure of isooctane at 25.0 °C?
lnP2
P1
=∆Hvaporization
R1T1
−1T2
⎛
⎝⎜⎞
⎠⎟
lnP2
760mmHg=
35.76 ×103 Jmol
8.3145 JmolK
1372.35K
−1
298.15K⎛⎝⎜
⎞⎠⎟
lnP2
760mmHg=−2.8746
P2
760mmHg=e−2.8746 =0.056438
P2 =42.9mmHg
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Clausius-Clapeyron Clausius-Clapeyron equationequation
Plot of ln P vs 1/T gives straight line w slope –∆Hvap/R
lnP2
P1
=∆Hvaporization
R1T1
−1T2
⎛
⎝⎜⎞
⎠⎟
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Changes of stateChanges of stateLiquid ↔ gas
Vaporization/boiling and condensation
Solid ↔ liquidMelting (fusion) and freezing
Solid ↔ gasSublimation and deposition
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Heating curveHeating curve
Add energy
Temperature
(s)
meltingfreezing
boilingcondensing
(l)
(g)
melting/freezing point
boiling point
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Part of a cooling curve for waterPart of a cooling curve for water The dotted line shows
supercooling The water remains liquid
below 0 °C At the bottom of the dotted
line, crystallization begins Crystallization releases
energy; temperature returns to freezing temperature
Temperature remains constant until freezing is completed
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Phase diagramPhase diagram
A graphical representation of the conditions of temperature & pressure under which various phases of a substance exist
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Molecular substancesMolecular substances
Molecular solids held together by Dispersion Dipole Hydrogen bonding
Relatively low mp & bp For molecules of similar structure,
boiling point increases as molar mass increases
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Ionic substancesIonic substances
Ions held together by lattice forces Coulomb’s law:
Attraction of oppositely charged ions increases with increased charge and/or decreased ion size
Which has a higher mp, NaF or MgO? NaF mp 993 °C, MgO mp 2852 °C
NaCl or KI? NaCl mp 801 °C, KI mp 681 °C
F =kq1q2
r2
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Atomic substancesAtomic substances
Noble gas atoms held together only by dispersion forces
Metals atoms held together by metal cations in sea of electrons