1 Let g(t) be periodic; period = T o. Fundamental frequency = f o = 1/ T o Hz or o = 2 / T o...
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Transcript of 1 Let g(t) be periodic; period = T o. Fundamental frequency = f o = 1/ T o Hz or o = 2 / T o...
1
Let g(t) be periodic; period = To . Fundamental frequency = fo = 1/ To Hz or o = 2/ To rad/sec.
Harmonics =n fo , n =2,3 4, . . .
Trigonometric forms
Communication Systems : Prof. Ravi Warrier
dt)tnsin()t(gT2
b,dt)tncos()t(gT2
a0nFor
,componentdcdt)t(gT1
a
)tnsin(b)tncos(aa)t(g
o1
1
o1
1
o1
1
Tt
t
oo
n
Tt
t
oo
n
Tt
too
1nonono
)ab
(tanbaC0nFor
Ca
)tncos(CC)t(g
:formCompact
n
n1n
2n
2nn
oo
1nnono
EXAMPLE :g(t)
0.2-0.2 0.6 1-0.6-1 0t
)t(g
dt)nt5.2sin(28.02
dt)tnsin()t(gT2
b
dt)nt5.2cos(28.02
dt)tncos()t(gT2
a0nFor
,dt28.01
dt)t(gT1
a
.sec/rad5.2sec,8.0T;)tnsin(b)tncos(aa)t(g
2.0
2.0
Tt
t
oo
n
2.0
2.0
Tt
t
oo
n
2.0
2.0
Tt
too
oo1n
onono
o1
1
o1
1
o1
1
R
C
+
g(t)
-
+
g o(t)
-
a) For R = 1 M and C=1 µF , what is go(t) ?
b) For R = 1 M and C=0.1 µF , what is go(t) ?
2
FOURIER SERIES
2
Communication Systems : Prof. Ravi Warrier
EXERCISE :g(t)
3 5-5 0t (sec)
-1 1-3
2
What is go(t) if the frequency response of the filter is as shown ?
FilterH()
g(t) go(t)
EXERCISE : a)Find the Fourier series in trigonometric compact form.
g(t)
2 4-4 0
t (sec)
-1 1-2
2
-2
-2
0 10 200
0.2
0.4
0.6
0.8
1
1.2
1.4MAGNITUDE
Freq. in rad/s
|H(jw
)|
0 10 20-350
-300
-250
-200
-150
-100
-50
0PHASE
Freq. in rad/s
| H(jw
)
3
Communication Systems : Prof. Ravi Warrier
o1
1
oo
Tt
t
tjn
on
n
tjnn dte)t(g
T1
DeD)t(g
:formlExponentiaComplex
EXAMPLE :g(t)
0t
5.0 5.0 5.15.1
2
21
Tdte221
dte)t(gT1
D o
5.0
5.0
jntTt
t
tjn
o
n
oo1
1
o
Sketch the Fourier spectra.
Suppose that g(t) is passed through a filter of frequency response as shown. What is the output signal ?
(Both positive and negative frequencies are shown here)
H(j)g(t) go(t)
|H(j)|1
0 3.2-3.2
H(j)
4
Communication Systems : Prof. Ravi Warrier
ENERGY AND POWER
Energy of g(t): g(t) is an energy signal if Eg < .
Power of g(t) :
dt)t(gE 2g
.ldt)t(gT1
P2
T
2
T
2
Tlim intervatimearbitraryanisTwhere
g(t) is a power signal if 0< P < .
EXAMPLES : Let g(t) be as shown . The energy of g(t) is : Eg=54 J.
Let g(t) be a unit step function: g(t) = u(t). Is this a power or an energy signal ?
-1 4 5
-3
3g(t)
t
1
g(t)
t
0
2g (t)dtgE dt Not an energy signal.
w2
1dt
T
1lim
T(t)dtg
T
1lim
TP
2
T
2
T
2
T
2
0
A power signal.
Average Power of sinewaves
2
2A2o
T
2o
Tt)]dtocos(2[1
2
2A
T
12o
T
2o
Tt)dto(cos2A
T
12T
2T
(t)dt2gT
1lim
TP
t)Acos(g(t)Let
o
2
o
o
.Then)tcos(nCCg(t)Let1n
nono
1n 2
2nC2
oCP
2nC
|nD,|oDoC
.TheneDg(t)Let-n
tjnn
o
why?
1n
2nD22
oD-n
2nDP
POWER OF ANY PERIODIC FUNCTION IN TERMS OF FOURIER COEFFICIENTS :
EXAMPLE :
g(t)
0.2-0.2 0
2
t-0.6-1 -0.60.6
W2
...00901.0081206.01
)n5.0sin(n4
21
1PThen
)tn5.2cos()n5.0sin(n4
1)t(gthatfoundWe
2
1n
1n
5
Communication Systems : Prof. Ravi Warrier
Signal Comparison : CORRELATION
Let g1(t) and g2(t) be two signals. Their correlation is defined as
.dt)t(g)t(g)( 21gg 21
If g1(t) = g2(t) = g(t), this becomes autocorrelation function, given by
.dt)t(g)t(g)(g
We see that g(0)=Eg we ge the signal energy. That is, the signal energy =autocorrelation at = 0.
FOURIER TRANSFORMSFOURIER TRANSFORMS
Definition : F{g(t)} = G() F-1{G()} =g(t)
d)eG(
2
1g(t)dt g(t)e)G( tjtj-
TRANSFORM EXAMPLES :
)t()t(g t,1)(Gg(t)
t0 0
)(G 1
t,A)t(g).(A2)(G
t0
Ag(t)
t0
Ag(t)
2
t
rectA)t(g
0
)(G
).(A2
)(G
A
2
csinA)(G
2
Wtsincg(t)
2W
rectW
)G(
2
2
)(Ag(t) tg(t)
A
2
2 0 t
2
4csin
2A)(G
)(G
x)xsin()x(csin
6
Communication Systems : Prof. Ravi Warrier
0a),t(ue)t(g at g(t)
ja
1)(G
g(t)
0a,eg(t) |t|a 22a
2a)G(
0
0
tj oeg(t) )2)G(
)(G
o0
)tcos(g(t) o )))G(
)(G
o0o
t
t
t
)tsin(g(t) o ))j)G(
)tsgn(g(t) 1
-10 t
)t(ug(t)
j2)G(
j1)()G(
7
PROPERTIES F{g(t)} = G()
1. Symmetry :
2. Scaling :
3. Time-shifting :
4. Frequency shifting :
)(g2)t(G
)(G)at(gaa
1
)(Ge)tt(g otjo
)(G)t(g
FOR PROOF READ TEXT.
(The term represents a linear phase ; in time domain it is delay).
otje
)(Ge)t(g;)(Ge)t(g otj
otj oo
)(G)(G
)t(g
?)tcos()t(g
oo21
2ee
otojtoj
F
FWhat is
Here g(t) is modulating the sinusoid amplitude - AMPLITUDE MODULATION.
g(t) is the modulating signal, cos(ot) is called the carrier.
EXAMPLE : .trect)t(gLet We will find the Fourier transform of g(t)cos(10t).
1
0
trect)t(g cos(10t)
21
21
t t 0
21
21
t
g(t)cos(10t)
=
TIME
domain
)(G
1
2 2
)t10cos()t(gF
21
10-10
Note : Multiplication in time-domain doesn’t transform to multiplication in frequency domain. 0
?)t10cos()t(gF
Math:
2
10csin
2
10csin)t10cos()t(rect
2csin)t(rect
21FF
EXERCISE : 1. What is
2. Find the spectrum of a)
b)
).t20cos()t2(g(t)
).t20sin()t2(g(t)
Sketch the time functions and the spectra.
Communication Systems : Prof. Ravi Warrier
FREQUENCY
domain
8
Communication Systems : Prof. Ravi Warrier
5. Differentiation ).(G)j()(Gj n
dt
)t(gddt
)t(dgn
n
FF
EXAMPLE : We find the Fourier transform of the triangular function shown using this property.
)(Ag(t) t
g(t)A
2
2 0 t 2
2
0
t
A2
dt)t(dg
2
20 t
A2
2
2
dt
)t(gd
A2
A4
)(csin2
A
)(
)(sin
2
A)(sin)(G
1)(sin212)cos(2e2e)(G
:functionsimpulsetheoftransformFouriertheTaking
)(G)(G)j(
42
24
42
24
2A84
2A42
A2jjA22
22
dt
)t(gd
22
2
2
F
6. Integration : )()0(Gd)(gj
)(Gt
F
7. Convolution :
)(G)(Gdx)x(G)x(G)t(g)t(g 2121
2121
21
F
CONVOLUTION IN TIME DOMAIN ( )
MULTIPLICATION IN FREQUENCY DOMAIN
)(G)(Gd)t(g)(g)t(g)t(g
d)t(g)(g)t(g)t(g
212121
2121
FF
CONVOLUTION IN FREQUENCY DOMAIN
MULTIPLICATION IN TIME DOMAIN
9
Communication Systems : Prof. Ravi Warrier
EXAMPLE: )t(g)t(gFind);t(rect)t(gLet
).()}t(g)t(g{
)(csin)}({tabletransformFourierFrom
)(csin)(G)}t(g)t(g{).(csin)(GhaveWe
2t
22
2t
2222
2
1-F
F
F
0 t
g(t)
0 t2
1
2
Note : g(t) has a pulse width of /2 sec but has pulse width of sec. Convolution increases the width of the function.
EXERCISE : Let g(t) = sinc(50t). What is the spectral width (bandwidth) of g(t) ?
What is the bandwidth of g2(t) ?
EXAMPLE : What is the Fourier transform of a periodic function ?
Periodic functions can be expressed in time domain as sum of a dc term and sinusoids of fundamental frequency and harmonics. Fourier transform of a sinusoid is a pair of impulse functions. Therefore, the Fourier transform of a periodic function is a sum of impulse functions centered at zero frequency, fundamental frequency and harmonics.
non
n
tjnn
n
tjnn
)n(D2eD)}t(g{
eD
o
o
FF
g(t)
EXAMPLE : We find the Fourier transform of the periodic function shown.
1
0
)t(g)t(g )t(g)t(g
2
2 2 2
g(t)
t
The Fourier series of g(t) is given (in page 51, text) by
The Fourier transform of g(t) is
)7()7(
5()5()3()3()1()1(2)()(G
71
51
31
)t7cos(
)t5cos()t3cos()tcos()t(g
142
102
622
21
-5 -4 -3 -2 -1 0 1 2 3 4 5
-5 -4 -3 -2 -1 0 1 2 3 4 5
|G()|
G()
)))}t{cos( o FWe have
10
Communication Systems : Prof. Ravi Warrier
-4To -3To -2To -To 0 To 2To 3To 4To t
g(t)
EXAMPLE : Consider the periodic function g(t) consisting of impulse functions at equal spaces of To sec.
We find the Fourier transform of g(t). We can express g(t) as
noo
noT
2
n
tjnT1
n
tjnT1
no
)n()n(e)}t(g{
.seriesFouriere
)nTt(
oo
o
oo
FF
g(t)
-4o -3o -2o - o 0 o 2o 3o 4o
G()
o
SIGNAL ENERGY AND ENEGY SPECTRAL DENSITY
We define signal energy as .
If g(t) is complex we can express energy as
(t)dtgE 2g
(t)dtg(t)gdtg(t)E *2g
Parseval’s theorem : Signal energy is
d)G()d()GG(dtg(t)E2
21*
212
g
Energy Spectral Density (ESD): is called the energy spectral density of g(t). The signal energy is the integral of the energy spectral density ( multiplied by 2).
2g )G()(
)d(E g21
g
ESD provides a way of computing energy from the Fourier transform of g(t).
.J1
)(tand)d(E
)(G)()(G
.J1dtedtedtg(t)E
5.0x21
5.01
5.0x21
25.01
21
g21
g
25.012
g5.0j1
0
t-
0
20.5t-2g
2
2
EXAMPLE : Consider g(t)=e-0.5t u(t). Find the energy and the ESD of g(t).
25.0
2)G(
0
11
Communication Systems : Prof. Ravi Warrier
ENERGY OF MODULATED SIGNAL
Let g(t) be a baseband energy signal bandlimited to B Hz.
Let .B2where,signalulatedmodamplitudean)tcos()t(g)t( oo
.EEthatfindweThen
)()(
)(G)(G)(
,B2Since
.)(G)(G)(is)t(ofESD
.)(G)(G)(
g21
ogog41
2o
2o4
1o
2oo4
1
oo21
.)(G)(G)( oo21
Suppose that G() is as shown. ThenG()
B2B2 0
()
oB4
o
The signal energy is reduced by 1/2 when it is multiplied by a sinewave of unit amplitude.
ESD OF A SYSTEM INPUT AND OUTPUT
H()G() Y()
d)()(Hd)(E)()(H)(
)(G)(H)(Y)(G)(H)(Y
G2
21
Y21
yG2
Y
222
EXAMPLE : Find the input and output energies. R=200 and C=0.01 F. g(t)=sinc(t).
R
C
+
g(t)
-
+
g o(t)
-
J87.0)2(tan2
ddd)(E
)()(H)(
)(rectx)(G)(H)(Y
)(G)(H)(Y)(H
JdE)(rect )(G
1
11
8
1
1
1
1
181
1421
Y21
y
G2
Y
22
141222
12j1
1jRC1
1
1
221
g2
2
212
2
22
2
s/rad 1for124
2
Otherwise0
EXERCISE : Redo the Example problem for R=200 and C=0.001 F.
12
Communication Systems : Prof. Ravi Warrier
Autocorrelation Function and ESD : For g(t) a real function
.)G()()GG()(
)(G)G(-de)g(de)g()}F{g(-)G()}F{g(
)}.)}F{g(-F{g()(
)()dxg(xg(x)x))dx(g(g(x))g(-)g(
x)dxg(g(x))g()g( : of functionaasnConvolutio
case).thisin(lagtimetheoffunctionaisnatioautocorrelTime
operation.timeaisnConvolutio.operationsdifferentrepresenttheybut
? nconvolutio to related this isHow
function.evenan)()(Thus
TEXT)READtlettingbythisshowcan(We)dtg(tg(t))dtg(tg(t))(
2*g
*jj
g
g
gg
g
Energy Spectral Density is the Fourier Transform of the autocorrelation function.
SIGNAL POWER AND POWER SPECTRAL DENSITY(PSD)
Energy and energy spectral density are useful for energy signals. For power signals we define power and power spectral density as follows :
de)(S)}({S)( Or)(S})({
P)0( )()(
)dtg(tg(t)lim)(
as defined is signal power real aoffunctionaisnatioautocorrelTime
d)(SP THEN .lim)(Sdensity spectral power The
d)(GlimE lim dt(t)glimP )t(g Defining
dt(t)glimP
jg2
1gggg
gggg
T1
Tg
g21
gT
)(G
Tg
2T2
1T1
TgT
1
T
2T1
Tg2
T t 2T- for )t(g
otherwise 0
2T1
Tg
2T
2T
2T
2T
2T
TTT
1-FRRF
RRR
R
13
Communication Systems : Prof. Ravi Warrier
Input signal power , output signal power Let g(t) be a power signal applied to a system.
H() Y()
d)(SP)(S)(H)(S
)(G)(H)(Y)(G)(H)(Y
Y21
yG2
Y
222
G()
EXAMPLE : Let g(t)=A cos(ot) , a power signal.
)0( P Also
d)-()-( d)(SP THEN
)-()-( )}( )(Sdensity spectral power The
)cos(
dt)])t2(cos(dt)cos(
dt)])t2(cos()[cos(
dt))t(cos()tcos(A)dtg(tg(t))dtg(tg(t)lim)(
isfunctionaisnatioautocorrelTime
periodT dt(t)gP
gg
2A
oo2A
21
g21
g
oo2A
gg
o2A
o2A
T1
o2A
T1
oo2A
T1
oo2
T1
T1
T1
Tg
o2A2
T1
g
22
2
2
2oT
2oT
2
o
2oT
2oT
2
o
2oT
2oT
2
o
2oT
2oT
o
2oT
2oT
o
2T
2T
22oT
2oT
o
R
RF{
R
oo
22A
)(gS
EXAMPLE : Consider a noise signal n(t) with PSD is the input to a differentiator.
What is the output noise power ? bb- ,K)(nS
bb- 2)H( K)(nS 2)H()(Sy
22)H( ,j)(H
H()=j y(t)n(t)
)(nS K
bb - 0 bb - 0
2)(H
bb - 0
)(Sy
3
3bK
d)(SP Y21
y
0
14
Communication Systems : Prof. Ravi Warrier
EXERCISE : 1 Consider a noise signal n(t) with PSD applied to a RC filter with
RC=1 sec. Determine the input noise power and output noise power. (Input power = 2W, Output power=0.25 W)
1010- ,1.0)(nS
R
C
+
n(t)
-
+
n o(t)
-
2. Suppose that the input to RC filter is g(t)=2cos(0.5t), what is the input and out put signal powers ? (Ans: power in=2W, power out=1.79W)
3. Next consider the input filter to be g(t)+n(t). Find the (signal power)/(noise power) at the input and output. This is called the signal-to-noise ratio.
REVIEW : 1) Fourier transform inverse Fourier transform definitions 2) Properties : Important ones :- Symmetry, time-delay /phase shift, Modulation 3) Results : Fourier transform of periodic functions, Energy, ESD, autocorrelation, power, PSD, autocorrelation, input energy-output energy, input power-output power.
What is the autocorrelation function of a sinewave ? What is the PSD of a sinewave ? What is the average power of a sinewave ? Does phase shift affect the power and autocorrelation ? What is the autocorrelation function of g(t) =cos(20t) ? What is the autocorrelation function of g(t) =sin(20t) ?
READ TEXT BOOK A LOT.
Distortionless Transmission : The ideal goal of a communication system is to make sure the received and transmitted signals are the same. That is, the received signal is not distorted. This means the communication system transfer function should have a constant magnitude and linear phase characteristics, in the frequency region of interest.
H() Y()G()
dt-je K)(H
)(H
K
0
)(H
0
dt
EXERCISE : Find the Fourier transform and sketch the spectra of : i)g(t) = sinc(20t)cos(100t)
ii) g(t) = sinc(20t)cos2(100t).
15
t
2bT
2bT
bT For
t
2bT
t
)t(g
)t(g
g(t)=1 for binary 1, g(t) = -1 for binary 0
2bT
is )-g(t)g(t under area the 2bT
writecan weSo
2bT
is )-g(t)g(t under area the 02bT
for that,show can weSimilarly
2bT
0 For
2bT
region shaded the of Area
1)-g(t)g(t product the region shaded the In
2bT
Communication Systems : Prof. Ravi Warrier