1. Introduction How to solve the problems? Four types of interactions
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Transcript of 1. Introduction How to solve the problems? Four types of interactions
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Electricity, Magnetism and Light PHYSICS 208, Instructor: Olga Kocharovskaya
Lectures 1,2 (Ch.21)Electric Charge and Electric Field
1. Introduction• How to solve the problems? • Four types of interactions
2. Electric Properties of the matter Two types of electric charge Conductors and Insulators Coulomb’s Law
3. Electric field
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How to solve problems?• Solve many before this one• Solve it yourself• Ask for hints but not for solution• Discuss it with your friends• Think about it before you go to sleep (you may find a solution in your
dream)
• Use symmetry of the problem• Use superposition principle• Do not surrender!• Forget it (not for exam!), then try again• Enjoy the solution!!!
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How to make sure your answer is correct?• Get a general (algebraic) solution• Check the units of the answer, make sure you have
units consistency• Check limiting cases • Check an order of magnitude, is it REASONABLE?
(the speed should not be greater then than that of the light in vacuum, a charge should not be smaller than that of electron, a distance is unlikely to be smaller than 10-15 m in our course, etc.)
• Check the answer in the textbook
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Four types of interactions
1.Gravity (between massive bodies)
F
g
Gm1m
2
r 2
Planetary systems, Galaxies,Space trajectories
Earth
Weight:F=mg
gF
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2. Electromagnetic Interactions ( ELECTRICALLY CHARGED BODIES) Structure of ATOMS
e
e
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Positive and negative Ions
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Structure of the Molecules
e e
H2 Na+Cl-
ee
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Chemical reactions and biological processes
Water is an excellent solvent due to the dipole character of its molecule
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Modern Technologies: internet, telecommunications, nanotechnolgies, CD, DVD,
lasers, cell phones,…
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Large Hadron Collider (LHC) Counter propagating proton beams accelerated to 7x1012 eVIn search for a dark matter
27 km ring
4.Weak InteractionsHadrons (proton, neutron,…),
colour charge
3.Strong InteractionsLeptons (electron, muon, tau-
lepton, neitrinos)
lepton charge Interactions between elementary particles, using modern EM technologies
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Electric Properties of the matter1. Two types of charges: + and – (Ben Franklin,1740)
glass
plastic
silk
fur
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2. Quatization of chargeQ=ne, n=1,2,3,…
e is the minimum value of charge
Particle mass charge electron 9.11×10-31kg -1.60×10-19 C (-e)proton 1.672×10-27kg +1.60×10-19C (+e)neutron 1.674×10-27kg 0
SI : [Q]=1C
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3. Conservation of Charge:
e e
Na Cl Na+Cl-
ee
N
ii constq
1
Na+ q1=e Cl- q2=-e
q1=0 q2=0 q1+q2=0
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4. Three types of materials1. Conductors (free electrons)Metalls, alloys, plasmas
Induction2. Insulators=Dielectrics (bounded electrons)Glass, plastic, paper
Polarization3. Semiconductors (number of free electrons stronglydepends on external conditions such as temperature, electric
field , pressure; under the usual conditions number of electrons is small)
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5. Amber effect: Charged and neutral object always attract each other
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6. Charging of neutral objects1.By friction: q1=0, q2=0 q1=Q q2=-Q
2. By contactq1=Q q2=0 q1+q2=Q q1=Q/2 q2=Q/2
3. By induction
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Coulomb’s Law, 1786
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Coulomb’s Law
For an ensemble of charges use a Superposition Principle:
oe rr
kQqF
2
r
rr testsource
0
2
29
0
100.94
1
C
Nmk
2
212
0 10854.8Nm
C
qr
rkQF
N
i i
iitotal
1
0
0r
0r
0r
0r
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kgm
kgm
Ce
mGm
ke
F
F
p
e
epg
e
27
31
19
362
1067.1
109
106.1
!10
oe rr
kQqF
2
Example1. Compare the electric and gravity forcesbetween an electron and a proton.
02r
r
GMmFg
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Electric Field,
“That one body may act upon another at a distance … is to me so great an absurdity…” I. Newton
Michael Faraday (1791-1867) Two steps:1.Q creates electric field,
2. produces the force on q
oe rr
kQqF
2
02
rr
GMmFg
Coulomb’s Law Newton’s Law
r r
)(rE
)(rEQ
q
FE Qq
Q
orq
FE Qonq
Q
lim
)(rEQ
QQq EqF
QE
0r
0r
Q Mq m
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Two steps in more details: the source and test charges
QSource
Q produces electric field at point P indepententely on the presence of charge q at this point:
0202r
r
kQr
r
kQq
q
FE Qq
)(rEQ
produces a force on a test charge q:
1.
2.
02r
r
kqQEqF QQq
SI units of E:[E]=[F]/[q]=N/C
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of a point charge)(rE
0202r
r
kQr
r
kQq
q
FE qQ
For charged bodies of finite size atr
02r
r
kQE
∞
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E of a dipole: along x axis
-q +q
x0-a
p
22222222 )(
2
)(
4]
)(
1
)(
1[
ax
kpx
ax
axkq
axaxkqEEEtotal
x-aa
x+a
3
2
x
kpE
ax
aqp 2E
E
tE
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E of a dipole: along y axis
q -q
-a a
y E
E
tE
3
2/3222/322 )()(
22
y
kpE
ay
ya
kp
ya
kqaEE
total
xtotal
22
22 )(
ya
aCos
CosEE
ya
kQE
x
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• Field of a line of charge (along the line)
2)( rz
kdqdE
dza
Qdq
)(]
11[
)(02 arr
kQ
arra
kQ
rz
dz
a
kQE
a
dq
z
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x
k
ax
kQE
xa
2222/322
1
)( yx
y
xyx
dy
2x
kQE
ax
22
)( 22
yx
xCos
dECosdE
dE
x
yx
kdQ
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E of a half of the ring of charge
dq
dE
2
2/
02
22
22
a
kQdSin
a
kQE
dESindE
Qd
a
k
a
kdqdE
Qd
a
Qaddl
a
Qdq
total
y
Etot
dEy dE
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Rx
x
kQ
x
R
x
RE
Rx
x
220
2
0 4])(
2
111[
2
2
(near the disc it looks like an infinite plane)
2
2
R
Q
rdrQ
EdE
ring
ringx
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Two infinite planes
0
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Electric field lines 1.Tangent is in direction of E
2.Density of lines is proportional to |E|3. Originate on “+” and terminate on “-” charges4. Crossing of E lines is impossible5. Closed lines are impossible in ES
NB: in the general case (i)|E| is not const along E lines(ii)Not the trajectories of the charged particles
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2
2
1~|~|
rS
NE
rS
constN
02r
r
kQE
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E
E
A positive vs. negative point charge
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of a dipoleE
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Infinite line of charge
rrl
N
S
NE
1~
2~
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Two infinite planes
0
Uniform E : the same direction and magnitude at each pointN=const, S=const, E=const
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Motion in a uniform E
-
+v0
e E
Data: electron, , L,v0
Find: 1.trajectory; 2.vf
02
0
20
2
0
20
22
0
0
00tan
,
,
22.2
.1
m
q
v
L
vvv
m
q
m
qEaaTv
v
axaty
TvL
tvx
vaT
v
v
fyf
fy
fy
Fvf
parabola
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Electric dipole in a uniform E
EpU
Ep
pESinqdESin
Sind
qE
Fr
tot
tot
2
1.Stable equilibrium
2.Unstable equilibrium
pEU 0
pEU 0