1 Chapter 7 Chemical Quantities The Mole Basic Chemistry Copyright © 2011 Pearson Education, Inc....

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1 Chapter 7 Chemical Quantities The Mole Basic Chemistry Copyright © 2011 Pearson Education, Inc. Collections of items include dozen, gross, and mole.

Transcript of 1 Chapter 7 Chemical Quantities The Mole Basic Chemistry Copyright © 2011 Pearson Education, Inc....

Page 1: 1 Chapter 7 Chemical Quantities The Mole Basic Chemistry Copyright © 2011 Pearson Education, Inc. Collections of items include dozen, gross, and mole.

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Chapter 7 Chemical Quantities

The Mole

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Collections of items include dozen, gross, and mole.

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Collection Terms

A collection term states a specific number of items.

• 1 dozen donuts = 12 donuts

• 1 ream of paper = 500 sheets

• 1 case = 24 cans

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Collections of items include dozen, gross, and mole.

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A mole (mol) is a collection that contains

• the same number of particles as there are carbon atoms in 12.01 g of carbon.

• 6.022 x 1023 atoms of an element (Avogadro’s number).

1 mol of Element Number of Atoms

1 mol C = 6.022 x 1023 C atoms

1 mol Na = 6.022 x 1023 Na atoms

1 mol Au = 6.022 x 1023 Au atoms

A Mole of Atoms

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A mole

• of a covalent compound has Avogadro’s number of molecules

1 mol CO2 = 6.022 x 1023 CO2 molecules

1 mol H2O = 6.022 x 1023 H2O molecules

• of an ionic compound contains Avogadro’s number of formula units

1 mol NaCl = 6.022 x 1023 NaCl formula units

1 mol K2SO4 = 6.022 x 1023 K2SO4 formula units

A Mole of A Compound

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Samples of One Mole Quantities

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Avogadro’s number (6.022 x 1023) can be written as an equality and two conversion factors.

Equality:

1 mol = 6.022 x 1023 particles

Conversion Factors:

6.022 x 1023 particles and 1 mol 1 mol 6.022 x 1023

particles

Avogadro’s Number

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Using Avogadro’s Number

Avogadro’s number converts moles of a substance to the number of particles.

How many Cu atoms are in 0.50 mol of Cu?

0.50 mol Cu x 6.022 x 1023 Cu atoms

1 mol Cu

= 3.0 x 1023 Cu atoms

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Using Avogadro’s Number

Avogadro’s number is used to convert the number of particles of a substance to moles.

How many moles of CO2 are in 2.50 x 1024 molecules of CO2?

2.50 x 1024 molecules CO2

x 1 mol CO2

6.022 x 1023 molecules CO2

= 4.15 mol of CO2

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1. The number of atoms in 2.0 mol of Al is

A. 2.0 Al atoms

B. 3.0 x 1023 Al atoms

C. 1.2 x 1024 Al atoms

2. The number of moles of S in 1.8 x 1024 atoms of S is

A. 1.0 mol of S atoms

B. 3.0 mol of S atoms

C. 1.1 x 1048 mol of S atoms

Learning Check

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1. 2.0 mol Al x 6.022 x 1023 Al atoms

1 mol Al

= 1.2 x 1024 Al atoms (C)

2. 1.8 x 1024 S atoms x 1 mol S

6.022 x 1023 S atoms = 3.0 mol of S atoms (B)

Solution

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Subscripts and Moles

The subscripts in a formula state• the relationship of atoms in the formula• the moles of each element in 1 mol of compound

Glucose

C6H12O6

1 molecule: 6 atoms of C 12 atoms of H 6 atoms of O

1 mol: 6 mol of C 12 mol of H 6 mol of O

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Subscripts State Atoms and Moles

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Factors from Subscripts

Subscripts used for conversion factors• relate moles of each element in 1 mol of compound • for aspirin C9H8O4 can be written as

9 mol C 8 mol H 4 mol O

1 mol C9H8O4 1 mol C9H8O4 1 mol C9H8O4

and

1 mol C9H8O4 1 mol C9H8O4 1 mol C9H8O4

9 mol C 8 mol H 4 mol O

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Calculating Atoms or Molecules

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Learning Check

How many O atoms are in 0.150 mol of aspirin, C9H8O4?

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Solution

How many O atoms are in 0.150 mol of aspirin, C9H8O4?

STEP 1 Given 0.150 mol of C9H8O4

Need molecules of C9H8O4

STEP 2 Plan

moles of aspirin moles of O atoms of O

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Solution (continued)STEP 3 Equalities/Conversion Factors

1 mol of C9H8O4 = 4 mol of O

1 mol C9H8O4 and 4 mol O

4 mol O 1 mol C9H8O4

1 mol of O = 6.022 x 1023 atoms of O

1 mole O and 6.022 x 1023 atoms O

6.022 x 1023 atoms O 1 mol O

STEP 4 Set Up Problem

0.150 mol C9H8O4 x 4 mol O x 6.022 x 1023 O atoms

1 mol C9H8O4 1 mol O

= 3.61 x 1023 O atoms

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Molar Mass

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Lithium carbonate produces a red color in fireworks.

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Molar Mass

The molar mass • is the mass of one mol of an

element or compound• is the atomic mass expressed in

grams

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Molar Mass from the Periodic Table

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Give the molar mass for

A. 1 mol of K atoms = ________

B. 1 mol of Sn atoms = ________

Learning Check

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Give the molar mass for

A. 1 mol of K atoms = 39.10 g

B. 1 mol of Sn atoms = 118.7 g

Solution

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Guide to Calculating Molar mass

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Molar Mass of a Compound

For a compound, the molar mass is the sum of the molar masses of the elements in the formula.

Example: Calculate the molar mass of CaCl2.

Element Number of Moles

Atomic Mass Total Mass

Ca 1 40.08 g/mol 40.08 g

Cl 2 35.45 g/mol 70.90 g

CaCl2 110.98 g

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Molar Mass of K3PO4

Determine the molar mass of K3PO4.

Element Number of Moles

Atomic Mass Total Mass in K3PO4

K 3 39.10 g/mol 117.3 g

P 1 30.97 g/mol 30.97 g

O 4 16.00 g/mol 64.00 g

K3PO4 212.3 g

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Some One-Mol Quantities

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Calculate the molar mass for Al(OH)3 with four

significant figures.

1) 44.00 g/mol

2) 75.00 g/mol

3) 78.00 g/mol

Learning Check

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STEP 1 Obtain the molar mass of each element. Al 26.98 g/mol O 16.00 g/mol H 1.008 g/molSTEP 2 Multiply each by the subscript.

1 mol Al x 26.98 g Al = 26.98 g 1 mol Al

3 mol O x 16.00 g O = 48.00 g 1 mol O

3 mol H x 1.008 g H = 3.024 g

1 mol H STEP 3 Calculate the molar mass by adding the

masses of the elements. 1 mol of Al(OH)3 = 78.00 g (3)

Solution

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Prozac, C17H18F3NO, is an antidepressant that inhibits the uptake of serotonin by the brain. What is the molar mass of Prozac?1) 40.06 g/mol2) 262.0 g/mol 3) 309.4 g/mol

Learning Check

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Prozac, C17H18F3NO, is an antidepressant that inhibits the uptake of serotonin by the brain. What is the molar mass of Prozac?

STEP 1 Obtain the molar mass of each element. C 12.01 g/mol H 1.008 g/mol F 19.00 g/mol N 14.01 g/mol O 16.00 g/mol

STEP 2 Multiply each by the subscript in the formula. 17 mol C x 12.01 g C = 204.2 g

1 mol C 18 mol H x 1.008 g H = 18.14 g

1 mol H

Solution

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Solution (continued)

STEP 2 3 mol F x 19.00 g F = 57.00 g

1 mol F 1 mol N x 14.01 g N = 14.01 g 1 mol N

1 mol O x 16.00 g O = 16.00 g

1 mol O

STEP 3 1 mol of C17H18F3NO = 309.4 g

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Calculations Using Molar Mass

Calculations Using Molar Mass

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Table salt is NaCl.

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Molar mass conversion factors • are written from molar mass• relate grams and moles of an element or

compound

Example: Write molar mass factors for methane CH4

used in gas cook tops and gas heaters.

Molar mass:

1 mol CH4 = 16.04 g

Conversion factors:

16.04 g CH4 and 1 mol CH4

1 mol CH4 16.04 g CH4

Molar Mass Factors

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Acetic acid HC2H3O2 gives the sour taste to vinegar. Write an equality and two molar mass conversion factors for acetic acid.

Learning Check

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Acetic acid HC2H3O2 gives the sour taste to vinegar.Write an equality and two molar mass conversion

factors for acetic acid.

Equality:

1 mol of acetic acid = 60.05 g of acetic acid

Molar mass conversion factors:

1 mol acetic acid and 60.05 g acetic acid 60.05 g acetic acid 1 mol acetic acid

Solution

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Guide to Calculation Using Molar Mass

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Aluminum is used to build lightweight bicycleframes. How many grams of Al are in 3.00 mol of Al?

Moles to Grams

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STEP 1 Given 3.00 mol of Al Need grams of Al

STEP 2 Plan moles of Al grams of Al

STEP 3 Equalities/Conversion Factors

1 mol of Al = 26.98 g of Al 1 mol Al and 26.98 g Al

26.98 g Al 1 mol Al

Solution

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STEP 4 Set Up ProblemSet up with molar mass as a factor:

3.00 mol Al x 26.98 g Al = 80.9 g of Al 1 mol Al molar mass factor for Al

Solution (continued)

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The artificial sweetener aspartame (NutraSweet), C14H18N2O5, is used to sweeten diet foods, coffee, and soft drinks. How many moles of aspartame are present in 225 g of aspartame?

Learning Check

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STEP 1 Given 225 g of C14H18N2O5 Need molesSTEP 2 Plan g of aspartame moles of aspartameSTEP 3 Equalities/Conversion Factors

1 mol aspartame = 294.3 g 1 mol aspartame and 294.3 g aspartame 294.3 g aspartame 1 mol aspartameSTEP 4 Set Up Problem

225 g aspartame x 1 mol aspartame 294.3 g aspartame

mole factor (inverted)

= 0.765 mol of aspartame

Solution

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Learning CheckAllyl sulfide, C6H10S, is a compound that has the odor of garlic. How many moles of C6H10S are in 225 g of C6H10S?

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STEP 1 Given 225 g of C6H10S Need moles of C6H10S

STEP 2 Plan g of C6H10S moles of C6H10S

STEP 3 Equalities/Conversion Factors

1 mol of C6H10S = 114.21 g of C6H10S

1 mol C6H10S and 114.21 g C6H10S

114.21 g C6H10S 1 mol C6H10S

STEP 3 Set Up Problem 225 g C6H10S x 1 mol C6H10S

114.21 g C6H10S

= 1.97 mol C6H10S

Solution

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Guide to Converting Grams to Particles

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Learning Check

How many molecules of H2O are in 24.0 g of H2O?

1) 4.52 x 1023

2) 1.44 x 1025

3) 8.02 x 1023

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Solution

STEP 1 Given 24.0 g of H2O

Need molecules of H2O

STEP 2 Plan

g of H2O moles of H2O molecules of H2O

STEP 3 Equalities/Conversion Factors

1 mol of H2O = 18.02 g of H2O

1 mol H2O and 18.02 g H2O

18.02 g H2O 1 mol H2O

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Solution (continued)

STEP 3 Equalities/Conversion Factors (continued)

1 mol of H2O = 6.022 molecules of H2O

1 mol H2O and 6.022 x 1023 H2O molecules

6.022 H2O molecules 1 mol H2O

STEP 4 Set Up Problem

24.0 g H2O x 1 mol H2O

18.02 g H2O

x 6.022 x 1023 H2O molecules

1 mol H2O

= 8.02 x 1023 H2O molecules (3)

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