1 Chapter 13 Carboxylic Acids, Esters, Amines, and Amides 13.1 Carboxylic Acids Copyright © 2005 by...
-
Upload
basil-mosley -
Category
Documents
-
view
217 -
download
1
Transcript of 1 Chapter 13 Carboxylic Acids, Esters, Amines, and Amides 13.1 Carboxylic Acids Copyright © 2005 by...
1
Chapter 13 Carboxylic Acids, Esters, Amines, and Amides
13.1 Carboxylic Acids
Copyright © 2005 by Pearson Education, Inc.Publishing as Benjamin Cummings
2
A carboxylic acid contains a carboxyl group, which• is a carbonyl group (C=O) attached to a hydroxyl
group (—OH).• is found on carbon 1 in carboxylic acids.
O
CH3 — C—OH hydroxyl group or CH3COOH
carbonyl group
Carboxylic Acids
3
Models of Carboxylic Acids
The three-dimensional models show the geometry of atoms in carboxylic acid molecules.
4
The IUPAC names of carboxylic acids:
• Replace the -e in the alkane name with -oic acid.
CH4 methane HCOOH methanoic acid
CH3—CH3 ethane CH3—COOH ethanoic acid
• Number substituents from the carboxyl carbon 1.
CH3 O | ║
CH3—CH—CH2—C—OH 4 3 2 1
3-methylbutanoic acid
IUPAC Names
5
Names and Sources of Some Carboxylic Acids
6
Common Carboxylic Acids
Methanoic acid (formic acid)
O
║
H─C─OH
ethanoic acid (acetic acid)
O
║
CH3─C─OH
7
Aromatic Carboxylic Acids
Benzoic acid• is the aromatic
carboxylic acid.
• locates substituents by numbering the ring from carbon 1 in the carboxyl group.
OHC
O
OHC
O
OHC
O
ClNH2
3-chlorobenzoic acid 4-aminobenzoic acid
benzoic acid
8
Learning Check
Give the IUPAC names of each compound. A. CH3─CH2─COOH
CH3
|
B. CH3─CH─CH2─COOHC.
OHC
O
Br
9
Solution
A. CH3─CH2─COOH propanoic acid
CH3
|
B. CH3─CH─CH2─COOH 3-methylbutanoic acid
C. 3-bromobenzoic acid OHC
O
Br
10
13.2 Properties of Carboxylic Acids
Chapter 13 Carboxylic Acids, Esters, Amines and Amides
Copyright © 2005 by Pearson Education, Inc.Publishing as Benjamin Cummings
11
Polarity of Carboxylic Acids
Carboxylic acids
• are strongly polar.
• have two polar groups: hydroxyl (−OH) and carbonyl (C=O).
12
Polarity of Carboxylic Acids
Carboxylic acids• form dimers in which hydrogen bonds form between two carboxyl
groups.
O H—O || |
CH3—C C—CH3
| ||
O—H O A dimer of acetic acid
• have higher boiling points than alcohols, ketones, and aldehydes of similar mass.
13
Comparison of Boiling Points
Compound Molar Mass Boiling Point
O
║
CH3−CH2−C−H 58 49°C
CH3−CH2−CH2−OH 60 97°C
O
║
CH3−C−OH 60 118°C
14
Solubility in Water
Carboxylic acids: • form hydrogen bonds
with many water molecules.
• with 1-4 carbon atoms are very soluble in water.
Water molecules
15
Boiling Points and Solubility
16
Acidity of Carboxylic Acids
Carboxylic acids • are weak acids.• ionize in water to produce carboxylate ions
and hydronium ions.
O O ║ ║
CH3−C−OH + H2O CH3−C−O– + H3O+
17
Neutralization of Carboxylic Acids
Carboxylic acid salts • are a product of the neutralization of a carboxylic acid
with a strong base. CH3—COOH + NaOH CH3—COO– Na+ + H2O
acetic acid sodium acetate (carboxylic acid salt)
• are used as preservatives and flavor enhancers.
18
Learning Check
Write the equation for the reaction of propanoic acid with
A. water
B. KOH
19
Solution
Write the equation for the reaction of propanoic acid with
A. waterCH3—CH2—COOH + H2O CH3—CH2—COO– + H3O+
B. KOH CH3—CH2—COOH + KOH CH3—CH2—COO– K+ + H2O
20
Chapter 13 Carboxylic Acids, Esters, Amines, and Amides
13.3 Esters
Copyright © 2005 by Pearson Education, Inc.Publishing as Benjamin Cummings
21
Esters
In an ester, the H in the carboxyl group is replacedwith an alkyl group.
O
CH3 — C—O —CH3
ester group
22
Esterification is the reaction of a carboxylic acid and alcohol in the presence of an acid catalyst to produce an ester.
O H+
CH3—C—OH + H—O—CH2—CH3
O
CH3—C—O—CH2—CH3 + H2O ethyl acetate (an ester)
Esterification
23
Write the equation for the reaction of propanoic acid and methanol in the presence of an acid catalyst.
Learning Check
24
Write the equation for the reaction of propanoic acid and methanol in the presence of an acid catalyst.
O H+
CH3—CH2—C—OH + H—O—CH3
propanoic acid methanol O
CH3—CH2—C—O—CH3 + H2O
Solution
25
Ester Products
Aspirin• is used to relieve pain and
reduce inflammation.• is an ester of salicylic acid
and acetic acid.
Oil of wintergreen• is used to soothe sore
muscles. • is an ester of salicylic acid
and methanol.
CH3
O
CO
OH
O
C
OH
CH3O
O
C
26
Naming Esters
The name of an ester contains the names of• the alkyl group from the alcohol.• the carbon chain from the acid with –ate ending.
methyl ethanoate (acetate)
O
CH3— O—C —CH3
IUPAC: methyl ethanoate
common: methyl acetate
27
Esters in Plants
Esters give flowers and fruits their pleasant fragrances and flavors.
Copyright © 2005 by Pearson Education, Inc.Publishing as Benjamin Cummings
28
Learning Check
Give the IUPAC and common names of the following compound, which is responsible for the flavor and odor of pears.
O
CH3 — C—O—CH2—CH2—CH3
29
Give the IUPAC and common names of the following compound, which is responsible for the flavor and odor of pears.
from 1-propanol O CH3—C—O—CH2—CH2—CH3
Propyl ethanoate (IUPAC)Propyl acetate (common)
Solution
30
Draw the structure of the following compounds.
A. 3-bromobutanoic acid
B. ethyl propionoate
Learning Check
31
Solution
A. 3-bromobutanoic acid
Br
|
CH3—CH—CH2—COOH
B. ethyl propionoate O CH3—CH2 —C—O—CH2—CH3
32
In acid hydrolysis • an ester reacts with water to produce a carboxylic acid
and an alcohol.• an acid catalyst is required.
O H+
H—C—O—CH2—CH3 + H2O
O H—C—OH + H—O—CH2—CH3
Acid Hydrolysis of Esters
33
Base hydrolysis or saponification, • is the reaction of an ester with a strong base. • produces the salt of the carboxylic acid and an
alcohol. O
|| CH3—C—O—CH2—CH3 + NaOH
O CH3—C—O– Na+ + HO—CH2—CH3
salt of carboxylic acid alcohol
Base Hydrolysis (Saponification)
34
Base Hydrolysis of Fatty Acids Produces Soaps
35
Cleaning Action of Soap
A soap• contains a nonpolar end
that dissolves in nonpolar fats and oils, and a polar end that dissolves in water.
• forms groups of soap molecules called micelles that dissolve in water and are washed away.
36
Write the organic products when methyl acetate reacts withA. water and an acid catalyst.
B. KOH.
Learning Check
37
Write the organic products when methyl acetate reacts withA. water and an acid catalyst.
O CH3—C—OH + HO—CH3
B. KOH. O
CH3—C—O– K+ + HO—CH3
Solution
38
Chapter 13 Carboxylic Acids, Ester, Amines, and Amides
13.4 Amines
39
Amines
Amines
• are derivatives of ammonia, NH3.
• contain N attached to one or more alkyl or aromatic groups.
CH3 CH3
CH3—NH2 CH3—NH CH3—N—CH3
NH2
40
Classification of Amines
Amines are classified as primary, secondary, or tertiary.• In a primary (1°) amine, one carbon group is bonded to the nitrogen
atom.• A secondary (2°) amine has two carbon groups bonded to the
nitrogen atom.• A tertiary (3°) amine has three carbon groups bonded to the
nitrogen atom.
H CH3 CH3 | | | CH3—N—H CH3—N—H CH3—N—CH3
1° 2° 3°
41
Models of Amines
The three-dimensional models show the shapes of amine molecules with one or more alkyl groups bonded to the nitrogen atom.
Copyright © 2005 by Pearson Education, Inc.Publishing as Benjamin Cummings
42
Naming Amines
Simple amines • are named as alkylamines.• List the names of the alkyl groups bonded to the N atom
in alphabetical order in front of amine.
CH3—CH2—NH2 ethylamine
CH3—NH—CH3 dimethylamine
CH3
|CH3—N—CH2—CH3 ethyldimethylamine
43
Give the common name and classify asprimary, secondary, or tertiary.
A. CH3—CH2—CH2—NH2
CH3
|B. CH3—CH2—N—CH3
Learning Check
44
A. CH3—CH2—CH2—NH2
propylamine, 1°
CH3 |B. CH3—CH2—N—CH3
ethyldimethylamine, 3°
Solution
45
Aromatic Amines
• The amine of benzene is named aniline.• Alkyl groups on the N use the prefix N- with alkyl name.
aniline 3-chloroaniline N-methylaniline
NH2
Cl
NH2 CH3NH
46
Learning Check
Give the common name of each compound.
A. CH3—NH—CH2—CH3
CH3
|
B. CH3—CH2—N—CH2—CH3
C.NH2
47
Solution
A. CH3—NH—CH2—CH3 ethylmethylamine
CH3
|B. CH3—CH2—N—CH2—CH3
diethylmethylamine
C.
aniline
NH2
48
Hydrogen Bonding for Amines
The N−H bond• provides hydrogen bonding in 1°and 2° amines, but
not in 3° amines.• is not as polar as the O-H bonds in alcohols.
49
Solubility in Water
Amines• with 1-5 carbon atoms are soluble in water.• form hydrogen bonds with the polar O-H bond in water.
50
Learning Check
Consider the following compounds.
1) CH3—CH2—CH2—NH2
2) CH3—CH2—NH—CH3
3) CH3—CH2—CH2—CH3
A. Which compound has the highest boiling point?
B. Which compound is soluble in water?
51
Solution
Consider the following compounds.1) CH3—CH2—CH2—NH2
2) CH3—CH2—NH—CH3
3) CH3—CH2—CH2—CH3
A. Which compound has the highest boiling point?1) CH3—CH2—CH2—NH2
B. Which compound is soluble in water?1) CH3—CH2—CH2—NH2
2) CH3—CH2—NH—CH3
52
Like ammonia, amines are weak bases in water.
NH3 + H2O NH4+ + OH–
ammonium hydroxide
CH3—NH2 + H2O CH3—NH3+ + OH–
methylammonium hydroxide
Amines React as Bases
53
An amine salt • forms when an amine is neutralized
by acid. • is named by replacing the amine
part of the name with ammonium followed by the name of the negative ion.
CH3—NH2 + HCl CH3—NH3+ Cl–
methylamine methylammonium chloride
Neutralization forms Amine Salts
54
Properties of Amine Salts
Amine salts are• solids at room temperature.• soluble in water and body fluids.• the form used for drugs.
55
Alkaloids
Alkaloids are• physiologically active
nitrogen-containing compounds.
• obtained from plants.• used as anesthetics,
antidepressants, and in stimulants such as caffeine.
• often addictive.
56
Cocaine
Cocaine is• sold illegally as the amine salt.• reacted with NaOH to produce the free amine form
known as “crack.”
57
Caffeine• is a stimulant of the
central nervous system. • is found in coffee beans,
tea, chocolate, and soft drinks.
Caffeine
58
Nicotine
Nicotine• increases the adrenaline level in the blood.• causes addiction to tobacco.
N
CH3
59
Morphine and Codeine
Morphine and codeine are• alkaloids.• obtained from the
oriental poppy plant.• used as painkillers. • modified to make heroin.
60
Learning Check
Write the structural formula for
A methylpropylamine
B. 2-chloroaniline
61
Solution
A. methylpropylamine CH3–CH2–CH2–NH–CH3
B. 2-chloroaniline
NH2
Cl
62
13.5 Amides
Chapter 13 Carboxylic Acids, Esters, Amines, and Amides
Copyright © 2005 by Pearson Education, Inc.Publishing as Benjamin Cummings
63
In amides,• an amino group(–NH2) replaces the –OH group of
carboxylic acids. O O || ||
CH3—C—OH CH3—C—NH2
Amides
Copyright © 2005 by Pearson Education, Inc.Publishing as Benjamin Cummings
64
Aromatic Amide
The aromatic amine is benzamide.
benzamide
O
CNH2
65
Preparation of Amides
Amides are produced• by reacting a carboxylic acid with ammonia
or an amine (1° or 2°).• using heat. O O Heat CH3—C—OH + NH3 CH3—C—NH2 + H2O
O O Heat CH3—C—OH + CH3—NH2 CH3—C—NH—CH3 + H2O
66
Amides are named as alkanamides.• IUPAC replaces –oic acid ending with –amide.• Common names replace -ic acid ending with –amide. O Methanamide (IUPAC) H—C—NH2 Formamide (common)
O Propanamide (IUPAC) CH3—CH2—C—NH2 Propionamide (common)
Naming Amides
67
An alkyl group bonded to the N atom is named as N-alkyl in front of the amide name. O H │ CH3 —C—N—CH3 N-methylethanamide (IUPAC)
N-methylacetamide (common) O H │ CH3—CH2 —C—N—CH2—CH3
N-ethylpropanamide (IUPAC)N-ethylpropionamide (common)
Naming Amides with N Groups
68
Learning Check
Give the IUPAC and common names for the following.
O A. CH3–CH2–CH2–C–NH2
O H │B. CH3–C–N–CH2–CH3
69
Solution
O A. CH3–CH2–CH2–C–NH2
butanamide; butryamide
O H │B. CH3–C–N–CH2–CH3
N-ethylethanamide; N-ethylacetamide
70
Learning Check
Draw the structures of
A. pentanamide.
B. N-methylbutyramide.
71
Solution
A. pentanamide O
CH3–CH2–CH2–CH2–C–NH2
B. N-methylbutyramide O
CH3–CH2–CH2–C–NH–CH3
72
Some Amides in Health and Medicine
• Urea is the end product of protein metabolism.
• Saccharin is an artificial sweetener.
• Some amides such as phenobarbital, Nembutal and Seconal are barbiturates.
• Acetaminophen is used to reduce fever and pain.
73
Some Amides in Health and Medicine
74
Physical Properties of Amides
Amides• that are primary (−NH2) or secondary (−NH−) form
hydrogen bonds.• that are primary have higher melting points than
secondary.• that are tertiary (no H on N) do not form hydrogen bonds
and have lower melting points.• all form hydrogen bonds with water.• with 1-5 carbon atoms are soluble in water.
75
Hydrogen Bonding of Amides
O || CH3—C—N—H | H Hydrogen bonding occurs
between primary amides. O ||
CH3—C—N—H |
H
76
Amides undergo• Acid hydrolysis to produce a carboxylic acid and
an ammonium salt.
• Base hydrolysis to produce the salt of a carboxylic acid and an amine or ammonia.
Hydrolysis of Amides
77
acid hydrolysis O
|| O CH3—C—OH + NH4
+Cl–
|| HCl + H2O CH3—C—NH2
NaOH O ||
CH3—C—O– Na+ + NH3
base hydrolysis
Hydrolysis Reactions
78
Write the products of the hydrolysis of
N-ethylpropanamide with NaOH.
Learning Check
79
Write the products of the hydrolysis of
N-ethylpropanamide with NaOH.
O CH3—CH2—C—O– Na+ + CH3—CH2—NH2
Solution