!""""""""# $t+ W Tl+% $Oo+ OoVo% $ Mo+ Mo+% $+ Q + + % $ + PpBv+% $+ N +n+ % $pP + PpP% $+ +rKb+r%
1 1 . . 0 0 n oo n i i t t c c e SS e s s n oo n i i t t u ......1 1 . . 0 0 n oo n i i t t c c e SS...
Transcript of 1 1 . . 0 0 n oo n i i t t c c e SS e s s n oo n i i t t u ......1 1 . . 0 0 n oo n i i t t c c e SS...
SSoolluuttiioonnss SSeeccttiioonn 00..11SSeeccttiioonn 00..11
1. 2(4 + (−1))(2 · − 4) = 2(3)(−8) = (6)(−8) = −48 2. 3 + ([4 − 2] · 9)
= 3 + (2 × 9) = 3 + 18 = 213. 20/(3*4) − 1 = 2012 − 1 = 53 − 1 = 23
4. 2 − (3*4)/10 = 2 − 1210 = 2 − 65 = 45
5. 3 + ([3 + (−5)])3 − 2 × 2
= 3 + (−2)3 − 4 = 1−1 = −16.
12 − (1 − 4)2(5 − 1) · 2 − 1 = 12 − (−3)16 − 1 = 1515 = 1
7. (2 − 5*(−1))/1 − 2*(−1) = 2 − 5 · (−1)1 − 2 · (−1) = 2 + 51 + 2 = 7 + 2 = 9
8. 2 − 5*(−1)/(1 − 2*(−1)) = 2 − 5 · (−1)1 − 2 · (−1) = 2 − −51 + 2 + 2 = 2 + 53 = 115
9. 2 · (−1)2/2 = 2 × (−1)22 = 2 × 12 = 22 = 1 10. 2 + 4 · 32 = 2 + 4 × 9 = 2 + 36 = 38
11. 2 · 42 + 1 = 2 × 16 + 1 = 32 + 1 = 33 12. 1 − 3 · (−2)2 × 2
= 1 − 3 × 4 × 2 = 1 − 24 = −2313. 3^2+2^2+1 = 32 + 22 + 1 = 9 + 4 + 1 = 14 14. 2^(2^2-2)
= 2(22−2) = 24−2 = 22 = 415.
3 − 2(−3)2−6(4 − 1)2
= 3 − 2 × 9−6(3)2 = 3 − 18−6 × 9 = −15−54 = 518
16. 1 − 2(1 − 4)22(5 − 1)2 · 2
= 1 − 2(−3)22(4)2 · 2 = 1 − 2 × 92 × 16 × 2
= 1 − 1864 = − 176417. 10*(1+1/10)^3
= 10(1 + 110)3 = 10(1.1)3 = 10 × 1.331 = 13.31
18. 121/(1+1/10)^2
= 121!1 + 110"2 = 1211.12
= 1211.21 = 100
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SSoolluuttiioonnss SSeeccttiioonn 00..11
19. 3[ −2 · 32−(4 − 1)2]
= 3[−2 × 9−32 ] = 3[−18−9 ] = 3 × 2 = 6
20. −[ 8(1 − 4)2−9(5 − 1)2]
= −[ 8 × 9−9 × 16] = −( 72−144) = −(− 12) = 12
21. 3[1 − (− 12)2]2 + 1 = 3[1 − 14]2 + 1 = 3[34]2 + 1 = 3[ 916] + 1 = 2716 + 1 = 4316
22. 3[19 − (23)2]2 + 1 = 3[19 − 49]2 + 1 = 3[−39 ]2 + 1 = 3[−13 ]2 + 1 = 3 19 + 1 = 39 + 1 = 43
23. (1/2)^2-1/2^2
= [12]2 − 122 = 14 − 14 = 024. 2/(1^2)-(2/1)^2
= 212 − [21]2 = 21 − 41 = −225. 3 × (2 − 5) = 3*(2-5) 26. 4 + 59 = 4+5/9 or 4+(5/9)
27. 32 − 5 = 3/(2-5)
Note 3/2-5 is wrong, as it corresponds to 32 − 5.28. 4 − 13 = (4-1)/3
29. 3 − 18 + 6 = (3-1)/(8+6)
Note 3-1/8-6 is wrong, as it corresponds to
3 − 18 − 6.30. 3 + 32 − 9 = 3+3/(2-9)
31. 3 − 4 + 78 = 3-(4+7)/8 32. 4 × 2!23"
= 4*2/(2/3) or (4*2)/(2/3)
33. 23 + + − +,2 = 2/(3+x)-x*y^2 34. 3 + 3 + ++, = 3+(3+x)/(x*y)
35. 3.1+3 − 4+−2 − 60+2 − 1 = 3.1x^3-4x^(-2)-60/(x^2-1)
36. 2.1+−3 − +−1 + +2 − 32 = 2.1x^(-3)-x^(-1)+(x^2-3)/2
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SSoolluuttiioonnss SSeeccttiioonn 00..11
37. !23"5
= (2/3)/5
38. 2!35"
= 2/(3/5)
39. 34−5 × 6 = 3^(4-5)*6Note that the entire exponent is in parentheses.
40. 23 + 57−9 = 2/(3+5^(7-9))Note that the entire exponent is in parentheses.
41. 3(1 + 4100)−3 = 3*(1+4/100)^(-3)
42. 3(1 + 4100 )−3 = 3((1+4)/100)^(-3)
43. 32+−1 + 4+ − 1 = 3^(2*x-1)+4^x-1
44. 2+2 − (22+)2 = 2^(x^2)-(2^(2*x))^2
45. 22+2−++1 = 2^(2x^2-x+1)Note that the entire exponent is in parentheses.
46. 22+2−+ + 1 = 2^(2x^2-x)+1Note that the entire exponent is in parentheses.
47. 4/−2+2 − 3/−2+
= 4*e^(-2*x)/(2-3e^(-2*x)) or 4(*e^(-2*x))/(2-3e^(-2*x)) or (4*e^(-2*x))/(2-3e^(-2*x))
48. /2+ + /−2+/2+ − /−2+
= (e^(2*x)+e^(-2*x))/(e^(2*x)-e^(-2*x))
49. 3(1 − (− 12)2)2 + 1 = 3(1-(-1/2)^2)^2+1
50. 3(19 − (23)2)2 + 1 = 3(1/9-(2/3)^2)^2+1
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SSoolluuttiioonnss SSeeccttiioonn 00..22SSeeccttiioonn 00..22
1. 33 = 27 2. (−2)3 = −83. −(2 · 3)2 = −(22 · 32) = −(4 · 9) = −36or−(2 · 3)2 = −62 = −36
4. (4 · 2)2 = 42 · 22 = 16 · 4 = 64 or
(4 · 2)2 = 82 = 64
5. (−23 )2 = (−2)232 = 49 6. (32)3 = 33
23 = 2787. (−2)−3 = 1(−2)3 = 1−8 = − 18 8. −2−3 = − 123 = − 189. (14)−2 = 1(1/4)2 = 11/16 = 16 10. (−23 )−2 = 1(−2/3)2 = 14/9 = 9411. 2 · 30 = 2 · 1 = 2 12. 3 · (−2)0 = 3 · 1 = 313. 2322 = 23+2 = 25 = 32or2322 = 8 · 4 = 32
14. 323 = 3231 = 32+1 = 33 = 27or
323 = 9 · 3 = 2715. 222−1242−4 = 22−1+4−4 = 21 = 2 16. 525−3525−2 = 52−3+2−2 = 5−1 = 1517. +3+2 = +3+2 = +5 18. +4+−1 = +4−1 = +3
19. −+2+−3, = −+2−3, = −+−1, = − ,+ 20. −+,−1+−1 = −+1−1,−1 = −+0,−1 = − 1,21. +3
+4 = +3−4 = +−1 = 1+ 22. ,5,3 = ,5−3 = ,2
23. +2,2+−1, = +2− (−1),2−1 = +3, 24. +−1,+2,2 = +−1−2,1−2 = +−3,−1 = 1+3,
25. (+,−103)2
+2,02 = +2(,−1)2(03)2+2,02
= +2,−206+2,02 = +2−2,−2−106−2
26. +2,02(+,0−1)−1 = +2,02
+−1,−1(0−1)−1 = +2,02
+−1,−10 = +2− (−1),1− (−1)02−1 = +3,204
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SSoolluuttiioonnss SSeeccttiioonn 00..22
= +0,−304 = 04,3
27. (+,−20+−10 )3 = (+,−20)3
(+−10)3 = +3,−603
+−303 = +3− (−3),−603−3 = +6,−600 = +6
,6
28. (+2,−100+,0 )
2 = (+2,−100)2(+,0)2
= +4,−2+2,202 = +4−2,−2−20−2
= +2,−40−2 = +2,402
29. (+−1,−202+, )
−2 = (+−1−1,−2−102)−2 = (+−2,−302)−2 = +4,60−4 = +4,6
04
30. ( +,−2+2,−10)
−3 = (+1−2,−2+10−1)−3 = (+−1,−10−1)−3 = +3,303
31. 3+−4 = 3+4 32. 12 +−4 = 12+4
33. 34 +−2/3 = 34+2/3 34. 45 ,−3/4 = 45,3/4
35. 1 − 0.3+−2 − 65 +−1 = 1 − 0.3+2 − 65+ 36. 13+−4 + 0.1+−23 = +43 + 0.13+2
37. 4√ = 2 38. 5√ ≈ 2.23639. 14√ = 1√4√ = 12 40. 19√ = 1√9√ = 1341. 169√ = 16√ 9√ = 43 42. 94√ = 9√4√ = 3243. 4√5 = 25 44. 625√ = 6545. 9√ + 16√ = 3 + 4 = 7 46. 25√ − 16√ = 5 − 4 = 147. 9 + 16√ = 25√ = 5 48. 25 − 16√ = 9√ = 3
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SSoolluuttiioonnss SSeeccttiioonn 00..22
49. 8 − 273√ = −193√ ≈ − 2.668 50. 81 − 164√ = 654√ ≈ 2.839
51. 27/83√ = 273√83√ = 32 52. 8 × 643√ = 83√ · 643√ = 2 · 4 = 8
53. (−2)2√ = 4√ = 2 54. (−1)2√ = 1√ = 1
55. 14 (1 + 15)√ = 164√ = 16√ 4√ = 42 = 2 56. 19 (3 + 33)√ = 369√ = 36√ 9√ = 63 = 2
57. 5262√ = 52√ 62√ = 56 58. 5262√ = 52√62√ = 56
59. (+ + 9)2√ = + + 9(+ + 9 > 0 because + is positive.)
60. ! + + 9√ "2 = + + 9
61. +3(53 + 63)3√ = +33√ (53 + 63)3√ = + (53 + 63)3√ (Not +(5 + 6))
62. +454644
√ = +44√544√ 644√ = +56
63. 4+,3+2,√ = 4,2+√ = 4√ ,2√+√ = 2,+√ 64. 4(+2 + ,2)82√ = 4√ +2 + ,2√
82√ = 2 +2 + ,2√ 8
(Not 2(+ + ,)/8)
65. 3√ = 31/2 66. 8√ = 81/2
67. +3√ = +3/268. +23√ = +2/3
69. +,23√ = (+,2)1/3 70. +2,√ = (+2,)1/2
71. +2+√ = +2
+1/2 = +2−1/2 = +3/2 72. ++√ = ++1/2 = +1−1/2 = +1/2
73. 35+2 = 35 +−2 74. 25+−3 = 25 +3
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SSoolluuttiioonnss SSeeccttiioonn 00..22
75. 3+−1.22 − 13+2.1 = 32 +−1.2 − 13 +−2.1 76. 23+−1.2 − +2.13 = 23 +1.2 − 13 +2.1
77. 2+3 − +0.12 + 43+1.1 = 23 + − 12 +0.1 + 43 +−1.1 78. 4+23 + +3/26 − 23+2 = 43 +2 + 16 +3/2 − 23 +−2
79. 3 +√4 − 53 +√ + 43+ +√ = 3+1/24 − 53+1/2 + 43+ · +1/2 = 34 +1/2 − 53 +−1/2 + 43 +−3/2
80. 35 +√ − 5 +√8 + 72 +3√
= 35+1/2 − 5+1/28 + 72+1/3 = 35 +−1/2 − 58 +1/2 + 72 +−1/3
81. 3 +25√4 − 72 +3√ = 3+2/54 − 72+3/2 = 34 +2/5 − 72 +−3/2
82. 18+ +√ − 23 +35√ = 18+3/2 − 23+3/5
= 18 +−3/2 − 23 +−3/5
83. 1(+2+1)3 − 34 +2 + 13√
= 1(+2+1)3 − 3(+2+1)1/3 = (+2+1)−3 − 34 (+2+1)−1/3
84. 23(+2+1)−3 − 3 (+2+1)73√ 4 = 23 (+2+1)3 − 34 (+2+1)7/3
85. 22/3 = 223√ 86. 34/5 = 345√
87. +4/3 = +43√ 88. ,7/4 = ,74√
89. (+1/2,1/3)1/5 = +√ ,3√5√ 90. +−1/3,3/2 = ,3/2
+1/3 = ,3√+3√
91. − 32 +−1/4 = − 32+1/4 = − 32 +4√ 92. 45 +3/2 = 4 +3√5
93. 0.2+−2/3 + 37+−1/2 = 0.2+2/3 + 3+1/27 = 0.2
+23√ + 3 +√794. 3.1+−4/3 − 117 +−1/7 = 3.1+4/3 − 117+1/7 = 3.1 +43√ − 11
7 +7√
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SSoolluuttiioonnss SSeeccttiioonn 00..22
95. 34(1 − +)5/2 = 34 (1 − +)5√ 96. 94(1 − +)−7/3 = 9(1 − +)7/3
4 = 9 (1 − +)73√ 497. 4−1/247/2 = 4−1/2+7/2 = 46/2 = 43 = 64 98. 21/5
22/5 = 21/5−2/5 = 2−1/5 = 121/5
99. 32/33−1/6 = 32/3−1/6 = 31/2 = 3√ 100. 21/32−122/32−1/3 = 21/3−1+2/3−1/3 = 2−1/3 = 121/3
101. +3/2+5/2 = +3/2−5/2 = +−1 = 1+ 102. ,5/4
,3/4 = ,5/4−3/4 = ,1/2 = ,√
103. +1/2,2+−1/2, = +1/2− (−1/2),2−1 = +, 104. +−1/2,+2,3/2 = +−1/2−2,1−3/2 = +−5/2,−1/2
105. (+,)1/3(,+)2/3 = +1/3,1/3 · ,2/3
+2/3 = +1/3−2/3,−1/3+2/3 = +−1/3,1/3 or (,+)1/3
106. (+,)−1/3(,+)1/3 = +−1/3,−1/3 · ,1/3
+1/3 +−1/3−1/3,1/3+1/3 = +−2/3,2/3 or (,+)2/3
107. +2 − 16 = 0 ⇒ +2 = 16 ⇒ + = ± 16√ ⇒ + = ± 4
108. +2 − 1 = 0 ⇒ +2 = 1 ⇒ + = ± 1√ ⇒ + = ± 1
109. +2 − 49 = 0 ⇒ +2 = 49 ⇒ + = ± 49√ ⇒ + = ± 23
110. +2 − 110 = 0 ⇒ +2 = 110 ⇒ + = ± 110√ ⇒ + = ± 110√
111. +2 − (1 + 2+)2 = 0 ⇒ +2 = (1 + 2+)2 ⇒ + = ± 1 + 2+If + = 1 + 2+, then −+ = 1 ⇒ + = −1.
If + = −(1 + 2+), then 3+ = −1 ⇒ + = − 13 .
So, + = 1 or − 13 .
112. +2 − (2 − 3+)2 = 0 ⇒ +2 = (2 − 3+)2 ⇒ + = ± 2 − 3+If + = 2 − 3+, then 4+ = 2 ⇒ + = 12 .
If + = −(2 − 3+), then −2+ = −2 ⇒ + = 1.
So, + = 1 or 12 .
113. +5 + 32 = 0 ⇒ +5 = −32 ⇒ + = −325√ = −2
114. +4 − 81 = 0 ⇒ +4 = 81 ⇒ + = ± 814√ = ± 3
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SSoolluuttiioonnss SSeeccttiioonn 00..22
115. +1/2 − 4 = 0 ⇒ +1/2 = 4 ⇒ + = 42 = 16
116. +1/3 − 2 = 0 ⇒ +1/3 = 2 ⇒ + = 23 = 8
117. 1 − 1+2 = 0 ⇒ 1 = 1+2 ⇒ +2 = 1 ⇒ + = ± 1√ = ± 1
118. 2+3 − 6+4 = 0 ⇒ 2+3 = 6+4 ⇒ 2+4 = 6+3 ⇒ 2+ = 6 ⇒ + = 3
119. (+ − 4)−1/3 = 2 ⇒ + − 4 = 2−3 = 18 ⇒ + = 4 + 18 = 338
120. (+ − 4)2/3 + 1 = 5 ⇒ (+ − 4)2/3 = 4 ⇒ + − 4 = ± 43/2 = ± 8 ⇒ + = 4 ± 8 = −4 or 12
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SSoolluuttiioonnss SSeeccttiioonn 00..33SSeeccttiioonn 00..33
19. (+2−2+ + 1)2 = (+2 − 2+ + 1)(+2 − 2+ + 1) = +2(+2 − 2+ + 1) − 2+(+2 − 2+ + 1) + 1(+2 − 2+ + 1) = +4 − 2+3 + +2 − 2+3 + 4+2 − 2+ + +2 − 2+ + 1 = +4 − 4+3 + 6+2 − 4+ + 120. (+ + , − +,)2 = (+ + , − +,)(+ + , − +,) = +(+ + , − +,) + ,(+ + , − +,) − +,(+ + , − +,) = +2 + +, − +2, + +, + ,2 − +,2 − +2, − +,2 + +2,2 = +2 + 2+, + ,2 − 2+2, − 2+,2 + +2,2
21. (,3 + 2,2 + ,)(,2 + 2, − 1) = ,3(,2 + 2, − 1) + 2,2(,2 + 2, − 1) + ,(,2 + 2, − 1) = ,5 + 2,4 − ,3 + 2,4 + 4,3 − 2,2 + ,3 + 2,2 − ,
1. +(4+ + 6) = 4+2 + 6+ 2. (4, − 2), = 4,2 − 2,3. (2+ − ,), = 2+, − ,2 4. +(3+ + ,) = 3+2 + +,5. (+ + 1)(+ − 3) = +2 + + − 3+ − 3 = +2 − 2+ − 3
6. (, + 3)(, + 4) = ,2 + 3, + 4, + 12 = ,2 + 7, + 12
7. (2, + 3)(, + 5) = 2,2 + 3, + 10, + 15 = 2,2 + 13, + 15
8. (2+ − 2)(3+ − 4) = 6+2 − 6+ − 8+ + 8 = 6+2 − 14+ + 8
9. (2+ − 3)2 = 4+2 − 12+ + 9 10. (3+ + 1)2 = 9+2 + 6+ + 111. (+ + 1+)2 = +2 + 2 + 1+2 12. (, − 1,)2 = ,2 − 2 + 1,2
13. (2+ − 3)(2+ + 3) = (2+)2 − 32 = 4+2 − 9 14. (4 + 2+)(4 − 2+) = 42 − (2+)2 = 16 − 4+2
15. (, − 1,)(, + 1,) = ,2 − (1,)2 = ,2 − 1,2 16. (+ − +2)(+ + +2) = +2 − (+2)2 = +2 − +4
17. (+2 + + − 1)(2+ + 4) = +2(2+ + 4) + +(2+ + 4) − 1(2+ + 4) = 2+3 + 4+2 + 2+2 + 4+ − 2+ − 4 = 2+3 + 6+2 + 2+ − 4
18. (3+ + 1)(2+2 − + + 1) = 3+(2+2 − + + 1) + 1(2+2 − + + 1) = 6+3 − 3+2 + 3+ + 2+2 − + + 1 = 6+3 − +2 + 2+ + 1
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SSoolluuttiioonnss SSeeccttiioonn 00..33
= ,5 + 4,4 + 4,3 − ,22. (+3 − 2+2 + 4)(3+2 − + + 2) = +3(3+2 − + + 2) − 2+2(3+2 − + + 2) + 4(3+2 − + + 2) = 3+5 − +4 + 2+3 − 6+4 + 2+3 − 4+2 + 12+2 − 4+ + 8 = 3+5 − 7+4 + 4+3 + 8+2 − 4+ + 823. (+ + 1)(+ + 2) + (+ + 1)(+ + 3) = (+ + 1)(+ + 2 + + + 3) = (+ + 1)(2+ + 5)
24. (+ + 1)(+ + 2)2 + (+ + 1)2(+ + 2) = (+ + 1)(+ + 2)(+ + 2 + + + 1) = (+ + 1)(+ + 2)(2+ + 3)
25. (+2+1)5(+ + 3)4 + (+2+1)6(+ + 3)3 = (+2+1)5(+ + 3)3(+ + 3 + +2 + 1) = (+2+1)5(+ + 3)3(+2 + + + 4)
26. 10+(+2+1)4(+3+1)5 + 15+2(+2+1)5(+3+1)4 = 5+(+2+1)4(+3+1)4[2(+3 + 1) + 3+(+2 + 1)] = 5+(+2+1)4(+3+1)4(5+3 + 3+ + 2)
27. (+3 + 1) + + 1√ − (+3+1)2 + + 1√ = (+3 + 1) + + 1√ · [1 − (+3 + 1)] = −+3(+3 + 1) + + 1√
28. (+2 + 1) + + 1√ − (+ + 1)3√ = + + 1√ · [+2 + 1 − (+ + 1)2√ ] = + + 1√ · [+2 + 1 − (+ + 1)] = (+2 − +) + + 1√ = +(+ − 1) + + 1√
29. (+ + 1)3√ + (+ + 1)5√ = (+ + 1)3√ · [1 + (+ + 1)2√ ] = (+ + 1)3√ · (1 + + + 1) = (+ + 2) (+ + 1)3√
30. (+2 + 1) (+ + 1)43√ − (+ + 1)73√ = (+ + 1)43√ · [+2 + 1 − (+ + 1)33√ ] = (+ + 1)43√ · [+2 + 1 − (+ + 1)] = (+2 − +) (+ + 1)43√ = +(+ − 1) (+ + 1)43√
31. a. 2+ + 3+2 = +(2 + 3+)b. +(2 + 3+) = 0 + = 0 or 2 + 3+ = 0 + = 0 or −2/3
32. a. ,2 − 4, = ,(, − 4)b. ,(, − 4) = 0 , = 0 or , − 4 = 0 , = 0 or 4
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SSoolluuttiioonnss SSeeccttiioonn 00..33
33. a. 6+3 − 2+2 = 2+2(3+ − 1)b. 2+2(3+ − 1) = 0 +2 = 0 or 3+ − 1 = 0 + = 0 or 1/3
34. a. 3,3 − 9,2 = 3,2(, − 3)b. 3,2(, − 3) = 0 ,2 = 0 or , − 3 = 0 , = 0 or 3
35. a. +2 − 8+ + 7 = (+ − 1)(+ − 7)b. (+ − 1)(+ − 7) = 0 + − 1 = 0 or + − 7 = 0 + = 1 or 7
36. a. ,2 + 6, + 8 = (, + 2)(, + 4)b. (, + 2)(, + 4) = 0 , + 2 = 0 or , + 4 = 0 , = −2 or −4
37. a. +2 + + − 12 = (+ − 3)(+ + 4)b. (+ − 3)(+ + 4) = 0 + − 3 = 0 or + + 4 = 0 + = 3 or −4
38. a. ,2 + , − 6 = (, − 2)(, + 3)b. (, − 2)(, + 3) = 0 , − 2 = 0 or , + 3 = 0 , = 2 or −3
39. a. 2+2 − 3+ − 2 = (2+ + 1)(+ − 2)b. (2+ + 1)(+ − 2) = 0 2+ + 1 = 0 or + − 2 = 0 + = −1/2 or 2
40. a. 3,2 − 8, − 3 = (3, + 1)(, − 3)b. (3, + 1)(, − 3) = 0 3, + 1 = 0 or , − 3 = 0 , = −1/3 or 3
41. a. 6+2 + 13+ + 6 = (2+ + 3)(3+ + 2)b. (2+ + 3)(3+ + 2) = 0 2+ + 3 = 0 or 3+ + 2 = 0 + = −3/2 or −2/3
42. a. 6,2 + 17, + 12 = (3, + 4)(2, + 3)b. (3, + 4)(2, + 3) = 0 3, + 4 = 0 or 2, + 3 = 0 , = −4/3 or −3/2
43. a. 12+2 + + − 6 = (3+ − 2)(4+ + 3)b. (3+ − 2)(4+ + 3) = 0 3+ − 2 = 0 or 4+ + 3 = 0 + = 2/3 or −3/4
44. a. 20,2 + 7, − 3 = (4, − 1)(5, + 3)b. (4, − 1)(5, + 3) = 0 4, − 1 = 0 or 5, + 3 = 0 , = 1/4 or −3/5
45. a. +2 + 4+, + 4,2 = (+ + 2,)2b. (+ + 2,)2 = 0 + + 2, = 0 + = −2,
46. a. 4,2 − 4+, + +2 = (2, − +)2b. (2, − +)2 = 0 2, − + = 0 , = +/2
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47. a. +4 − 5+2 + 4 = (+2 − 1)(+2 − 4) = (+ + 1)(+ − 1)(+ + 2)(+ − 2)b. (+ + 1)(+ − 1)(+ + 2)(+ − 2) = 0 + + 1 = 0 or + − 1 = 0 or
+ + 2 = 0 or + − 2 = 0 + = ± 1 or ±2
48. a. ,4 + 2,2 − 3 = (,2 − 1)(,2 + 3) = (, + 1)(, − 1)(,2 + 3)b. (, + 1)(, − 1)(,2 + 3) = 0 , + 1 = 0 or , − 1 = 0 or ,2 + 3 = 0 , = ± 1 (Notice that ,2 + 3 = 0 has no real solutions.)
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1. + − 4+ + 1 · 2+ + 1+ − 1 = (+ − 4)(2+ + 1)(+ + 1)(+ − 1) = 2+2 − 7+ − 4+2 − 1
2. 2+ − 3+ − 2 · + + 3+ + 1 = (2+ − 3)(+ + 3)(+ − 2)(+ + 1) = 2+2 + 3+ − 9+2 − + − 2
3. + − 4+ + 1 + 2+ + 1+ − 1 = (+ − 4)(+ − 1) + (+ + 1)(2+ + 1)(+ + 1)(+ − 1) = 3+2 − 2+ + 5+2 − 1
4. 2+ − 3+ − 2 + + + 3+ + 1 = (2+ − 3)(+ + 1) + (+ − 2)(+ + 3)(+ − 2)(+ + 1) = 3+2 − 9+2 − + − 2
5. +2+ + 1 − + − 1+ + 1 = +2 − (+ − 1)+ + 1 = +2 − + + 1+ + 1
6. +2 − 1+ − 2 − 1+ − 1 = (+2 − 1)(+ − 1) − (+ − 2)(+ − 2)(+ − 1) = +3 − +2 − 2+ + 3+2 − 3+ + 2
7. 1! ++−1"
+ + − 1 = + − 1+ + + − 1 = + − 1 + +(+ − 1)+ = +2 − 1+
8. 2(+−2+2 ) − 1+ − 2 = 2+2+ − 2 − 1+ − 2
= 2+2 − 1+ − 29. 1+[+ − 3+, + 1,] = 1+[+ − 3 + ++, ] = 2+ − 3+2,
10. ,2+ [2+ − 3, + +,] = ,2
+ [2+ − 3 + ++, ] = ,2(3+ − 3)+, = ,(3+ − 3)+ = 3+, − 3,+
11. (+ + 1)2(+ + 2)3 − (+ + 1)3(+ + 2)2
(+ + 2)6
= (+ + 1)2(+ + 2)2[(+ + 2) − (+ + 1)](+ + 2)6 = (+ + 1)2
(+ + 2)4
12. 6+(+2+1)2(+3+2)3 − 9+2(+2+1)3(+3+2)2
(+3+2)6 = 3+(+2+1)2(+3+2)2[2(+3 + 2) − 3+(+2 + 1)]
(+3+2)6 = 3+(+2+1)2(−+3 − 3+ + 4)
(+3+2)4
13. (+2 − 1) +2 + 1√ − +4
+2+1√+2 + 1 = (+2 − 1)(+2 + 1) − +4
(+2 + 1) +2 + 1√ = −1(+2+1)3√
14. + +3 − 1√ − 3+4
+3−1√+3 − 1 = +(+3 − 1) − 3+4(+3 − 1) +3 − 1√
= −2+4 − +(+3−1)3√ = −+(2+3 + 1)
(+3−1)3√
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15.
1(++,)2 − 1+2, = +2 − (+ + ,)2,+2(+ + ,)2
= +2 − +2 − 2+, − ,2,+2(+ + ,)2 = −,(2+ + ,)
,+2(+ + ,)2 = −(2+ + ,)+2(+ + ,)2
16.
1(++,)3 − 1+3, = +2 − (+ + ,)2,+2(+ + ,)2
= +3 − +3 − 3+2, − 3+,2 − ,3,+3(+ + ,)3
= −,(3+2 + 3+, + ,2),+3(+ + ,)3 = −(3+2 + 3+, + ,2)
+3(+ + ,)3
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1. + + 1 = 0 ⇒ + = 0 − 1 ⇒ + = −1 2. + − 3 = 1 ⇒ + = 1 + 3 ⇒ + = 43. −+ + 5 = 0 ⇒ − + = −5 ⇒ + = 5 4. 2+ + 4 = 1 ⇒ 2+ = −3 ⇒ + = − 325. 4+ − 5 = 8 ⇒ 4+ = 13 ⇒ + = 134 6. 34 + + 1 = 0 ⇒ 34 + = −1 ⇒ + = − 437. 7+ + 55 = 98 ⇒ 7+ = 43 ⇒ + = − 437 8. 3+ + 1 = + ⇒ 2+ = −1 ⇒ + = − 129. + + 1 = 2+ + 2 ⇒ − + = 1 ⇒ + = −1 10. + + 1 = 3+ + 1 ⇒ − 2+ = 0 ⇒ + = 011. 5+ + 6 = 8 ⇒ 5+ = 8 − 6 ⇒ + = 8 − 65 12. + − 1 = 8+ + < ⇒ (1 − 8)+ = < + 1 ⇒ + = < + 11 − 813. 2+2 + 7+ − 4 = 0 ⇒ (2+ − 1)(+ + 4) = 0 ⇒ + = −4, 12
14. +2 + + + 1 = 0 ⇒ Δ = 62 − 458 = −3 < 0,so this equation has no real solutions.
15. +2 − + + 1 = 0 ⇒ Δ = 62 − 458 = −3 < 0,so this equation has no real solutions.
16. 2+2 − 4+ + 3 ⇒ Δ = 62 − 458 = −8 < 0,so this equation has no real solutions.
17. 2+2 − 5 = 0 ⇒ +2 = 52 ⇒ + = ± 52√ 18. 3+2 − 1 = 0 ⇒ +2 = 13 ⇒ + = ± 13√
19. −+2 − 2+ − 1 = 0 ⇒ − (+ + 1)2 = 0 ⇒ + = −1
20. 2+2 − + − 3 = 0 ⇒ (2+ − 3)(+ + 1) = 0 ⇒ + = 32, −1
21. 12 +2 − + − 32 = 0 ⇒ +2 − 2+ − 3 = 0 ⇒ (+ + 1)(+ − 3) = 0 ⇒ + = −1, 3
22. − 12 +2 − 12 + + 1 = 0 ⇒ +2 + + − 2 = 0 ⇒ (+ + 2)(+ − 1) = 0 ⇒ + = −2, 1
23. +2 − + = 1 ⇒ +2 − + − 1 = 0 ⇒ + = −6 ± 62 − 458√25 = 1 ± 5√2
24. 16+2 = −24+ − 9 ⇒ 16+2 + 24+ + 9 = 0 (4+ + 3)2 = 0 ⇒ + = − 34
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25. + = 2 − 1+ ⇒ +2 = 2+ − 1 ⇒ +2 − 2+ + 1 = 0 ⇒ (+ − 1)2 = 0 ⇒ + = 1
26. + + 4 = 1+ − 2 ⇒ (+ + 4)(+ − 2) = 1 ⇒ +2 + 2+ − 8 = 1 ⇒ +2 + 2+ − 9 − 0 ⇒ + = −6 ± 62 − 458√25 = −2 ± 40√2 = −1 ± 10√
27. +4 − 10+2 + 9 = 0 ⇒ (+2 − 1)(+2 − 9) = 0 ⇒ +2 = 1 or +2 = 0 ⇒ + = ± 1, ± 3 28. +4 − 2+2 + 1 = 0 ⇒ (+2−1)2 = 0
⇒ + = ± 129. +4 + +2 − 1 = 0 ⇒ +2 = −6 ± 62 − 458√25 ⇒ +2 = −1 ± 5√2 ⇒ + = ± −1 ± 5√2√
30. +3 + 2+2 + + = 0 ⇒ +(+2 + 2+ + 1) = 0 ⇒ +(+ + 1)2 = 0 ⇒ + = 0, −1
31. +3 + 16+2 + 11+ + 6 = 0 ⇒ (+ + 1)(+ + 2)(+ + 3) = 0 ⇒ + = −1, −2, −3 32. +3 − 6+2 + 12+ − 8 = 0
⇒ (+ − 2)3 = 0 ⇒ + = 233. +3 + 4+2 + 4+ + 3 = 0 ⇒ (+ + 3)(+2 + + + 1) = 0 ⇒ + = −3(For +2 + + + 1 = 0, Δ = 62 − 458 = −3 < 0, sothere are no real solutions to this quadratic equation.)
34. ,3 + 64 = 0 ⇒ ,3 = −64 ⇒ , = −643√ = −4
35. +3 − 1 = 0 ⇒ +3 = 1 ⇒ + = 13√ = 1
36. +3 − 27 = 0 ⇒ +3 = 27 ⇒ + = 273√ = 3
37. ,3 + 3,2 + 3, + 2 = 0 ⇒ (, + 2)(,2 + , + 1) = 0 ⇒ , = −2(For ,2 + , + 1 = 0, Δ = 62 − 458 = −3 < 0, sothere are no real solutions to this quadratic equation.)
38. ,3 − 2,2 − 2, − 3 = 0 ⇒ (, − 3)(,2 + , + 1) = 0 ⇒ , = 3(For ,2 + , + 1 = 0, Δ = 62 − 458 = −3 < 0, so thereare no real solutions to this quadratic equation.)
39. +3 − +2 − 5+ + 5 = 0 ⇒ (+ − 1)(+2 − 5) = 0 ⇒ + = 1, ± 5√
40. +3 − +2 − 3+ + 3 = 0 ⇒ (+ − 1)(+2 − 3) = 0 ⇒ + = 1, ± 3√
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41. 2+6 − +4 − 2+2 + 1 = 0 ⇒ (2+2 − 1)(+4 − 1) = 0 ⇒ (2+2 − 1)(+2 − 1)(+2 + 1) = 0(Think of the cubic you get by substituting , for +2)
⇒ + = ± 1, ± 12√
42. 3+6 − +4 − 12+2 + 4 = 0 ⇒ (3+2 − 1)(+4 − 4) = 0 ⇒ (3+2 − 1)(+2 − 2)(+2 + 2) = 0(Think of the cubic you get by substituting , for +2)
⇒ + = ± 2√ , ± 13√
43. (+2 + 3+ + 2)(+2 − 5+ + 6) = 0 ⇒ (+ + 2)(+ + 1)(+ − 2)(+ − 3) = 0 ⇒ + = −2, −1, 2, 3
44. (+2−4+ + 4)2(+2+6+ + 5)3 = 0 ⇒ (+ − 2)4(+ + 1)3(+ + 5)3 = 0 ⇒ + = −5, −1, 2
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1. +4 − 3+3 = 0, +3(+ − 3) = 0, + = 0, 3 2. +6 − 9+4 = 0, +4(+2 − 9) = 0, + = 0, ±33. +4 − 4+2 = −4, +4 − 4+2 + 4 = 0,
(+2−2)2 = 0, + = ± 2√4. +4 − +2 = 6, +4 − +2 − 6 = 0,
(+2 − 3)(+2 + 2) = 0, + = ± 3√
5. (+ + 1)(+ + 2) + (+ + 1)(+ + 3) = 0, (+ + 1)(+ + 2 + + + 3) = 0,
(+ + 1)(2+ + 5) = 0, + = −1, −5/26. (+ + 1)(+ + 2)2 + (+ + 1)2(+ + 2) = 0, (+ + 1)(+ + 2)(+ + 2 + + + 1) = 0, (+ + 1)(+ + 2)(2+ + 3) = 0, + = −1, −2, −3/2
7. (+2+1)5(+ + 3)4 + (+2+1)6(+ + 3)3 = 0, (+2+1)5(+ + 3)3(+ + 3 + +2 + 1) = 0, (+2+1)5(+ + 3)3(+2 + + + 4) = 0, + = −3(Neither +2 + 1 = 0 nor +2 + + + 4 = 0 has a realsolution.)
8. 10+(+2+1)4(+3+1)5 − 10+2(+2+1)5(+3+1)4 = 0, 10+(+2+1)4(+3+1)4[+3 + 1 − +(+2 + 1)] = 0, 10+(+2+1)4(+3+1)4(1 − +) = 0, + = −1, 0, 1
9. (+3 + 1) + + 1√ − (+3+1)2 + + 1√ = 0, (+3 + 1) + + 1√ [1 − (+3 + 1)] = 0, −+3(+3 + 1) + + 1√ = 0, + = 0, −1
10. (+2 + 1) + + 1√ − (+ + 1)3√ = 0, + + 1√ [+2 + 1 − (+ + 1)] = 0, (+2 − +) + + 1√ = 0, +(+ − 1) + + 1√ = 0, + = −1, 0, 1
11. (+ + 1)3√ + (+ + 1)5√ = 0, (+ + 1)3√ (1 + + + 1) = 0, (+ + 2) (+ + 1)3√ = 0, + = −1(+ = −2 is not a solution because (+ + 1)3√ is not
defined for + = −2.)
12. (+2 + 1) (+ + 1)43√ − (+ + 1)73√ = 0, (+ + 1)43√ [+2 + 1 − (+ + 1)] = 0, (+2 − +) (+ + 1)43√ = 0, +(+ − 1) (+ + 1)43√ = 0, + = −1, 0, 1
13. (+ + 1)2(2+ + 3) − (+ + 1)(2+ + 3)2 = 0, (+ + 1)(2+ + 3)(+ + 1 − 2+ − 3) = 0, (+ + 1)(2+ + 3)(−+ − 2) = 0, + = −2, −3/2, −1
14. (+2−1)2(+ + 2)3 − (+2−1)3(+ + 2)2 = 0, (+2−1)2(+ + 2)2(+ + 2 − +2 + 1) = 0, −(+2−1)2(+ + 2)2(+2 − + − 3) = 0, + = −2, −1, 1, (1 ± 13√ )/2
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15. (+ + 1)2(+ + 2)3 − (+ + 1)3(+ + 2)2
(+ + 2)6 = 0,
(+ + 1)2(+ + 2)2[(+ + 2) − (+ + 1)](+ + 2)6 = 0,
(+ + 1)2(+ + 2)4 = 0, (+ + 1)2 = 0,
+ = −1
16. 6+(+2+1)2(+2+2)4 − 8+(+2+1)3(+2+2)3
(+2+2)8 = 0,
2+(+2+1)2(+2+2)3[3(+2 + 2) − 4(+2 + 1)](+2+2)8 = 0,
−2+(+2+1)2(+2 − 2)
(+2+2)5 = 0, −2+(+2+1)2(+2 − 2) = 0, + = 0, ± 2√
17. 2(+2 − 1) +2 + 1√ − +4
+2+1√+2 + 1 = 0,
2(+2 − 1)(+2 + 1) − +4(+2 + 1) +2 + 1√ = 0,
+4 − 2(+2 + 1) +2 + 1√ = 0, +4 − 2 = 0, + = ± 24√
18. 4+ +3 − 1√ − 3+4
+3−1√+3 − 1 = 0,
4+(+3 − 1) − 3+4(+3 − 1) +3 − 1√ = 0,
+4 − 4+(+3 − 1) +3 − 1√ = 0, +4 − 4+ = 0, +(+3 − 4) = 0, + = 0, ± 43√
19. + − 1+ = 0, +2 − 1 = 0, + = ± 1 20. 1 − 4+2 = 0, +2 − 4 = 0, + = ± 2
21. 1+ − 9+3 = 0, +2 − 9 = 0, + = ± 3 22. 1+2 − 1+ + 1 = 0, + + 1 − +2 = 0, +2 − + − 1 = 0, + = (1 ± 5√ )/2
23. + − 4+ + 1 − ++ − 1 = 0,
(+ − 4)(+ − 1) − +(+ + 1)(+ + 1)(+ − 1) = 0, −6+ + 4(+ + 1)(+ − 1) = 0, −6+ + 4 = 0, + = 2/3
24. 2+ − 3+ − 1 − 2+ + 3+ + 1 = 0,
(2+ − 3)(+ + 1) − (2+ + 3)(+ − 1)(+ − 1)(+ + 1) = 0, −2+(+ − 1)(+ + 1) = 0, −2+ = 0, + = 0
25. + + 4+ + 1 + + + 43+ = 0,
3+(+ + 4) + (+ + 1)(+ + 4)3+(+ + 1) = 0,
(+ + 4)(3+ + + + 1)3+(+ + 1) = 0,
(+ + 4)(4+ + 1)3+(+ + 1) = 0,
26. 2+ − 3+ − 2+ − 3+ + 1 = 0,
(2+ − 3)(+ + 1) − +(2+ − 3)+(+ + 1) = 0,
(2+ − 3)(+ + 1 − +)+(+ + 1) = 0,
(2+ − 3)+(+ + 1) = 0, 2+ − 3 = 0, + = 3/2
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(+ + 4)(4+ + 1) = 0, + = −4, −1/4
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SSoolluuttiioonnss SSeeccttiioonn 00..77SSeeccttiioonn 00..77
1. ? (0, 2), @(4, −2), A(−2, 3), B(−3.5, −1.5), C (−2.5, 0), D(2, 2.5)2. ? (−2, 2), @(3.5, 2), A(0, −3), B(−3.5, −1.5), C (2.5, 0), D(−2, 2.5)
5. Solve the equation + + , = 1 for , to get , = 1 − +. Then plot some points:
Graph:
3. 4.
+ −2 −1 0 1 2, = 1− + 3 2 1 0 −1
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SSoolluuttiioonnss SSeeccttiioonn 00..77
6. Solve the equation , − + = −1 for , to get , = −1 + +. Then plot some points:
Graph:
7. Solve the equation 2, − +2 = 1 for , to get , = 1 + +22 . Then plot some points:
Graph:
+ −2 −1 0 1 2, = −1 + + −3 −2 −1 0 1
+ −2 −1 0 1 2, = 1 + +2
2 2.5 1 0.5 1 2.5
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SSoolluuttiioonnss SSeeccttiioonn 00..77
8. Solve the equation 2, + +√ = 1 for , to get , = 1 − +√2 . Then plot some points:
Graph:
9. Solve the equation +, = 4 for , to get , = 4+ . Then plot some points:
Graph:
+ 0 1 4 9 16, = 1− +√2 0.5 0 −0.5 −1 −1.5
+ −3 −2 −1 1 2 3, = 4+ − 43 −2 −4 4 2 43
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SSoolluuttiioonnss SSeeccttiioonn 00..77
10. Solve the equation +2, = −1 for , to get , = − 1+2 . Then plot some points:
Graph:
11. Solve the equation +, = +2 + 1 for , to get , = + + 1+ . Then plot some points:
Graph:
+ −3 −2 −1 1 2 3, = − 1+2 − 19 − 14 −1 −1 − 14 − 19
+ −2 −1 − 12 12 1 2, = + + 1+ − 52 −2 − 52 52 2 52
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SSoolluuttiioonnss SSeeccttiioonn 00..77
12. Solve the equation +, = 2+3 + 1 for , to get , = 2+2 + 1+ . Then plot some points:
Graph:
+ −2 −1 − 12 12 1 2, = 2+2 + 1+ 152 1 − 32 52 3 172
13. (2 − 1)2 + (−2 + 1)2√ = 2√ 14. (6 − 1)2 + (1 − 0)2√ = 26√
15. (0 − 5)2 + (6 − 0)2√ = 52 + 62√ 16. (6 − 5)2 + (6 − 0)2√ = 2(6 − 5)2√ or 2√ |6 − 5|17. Set the two distances equal and solve:
(1 − 0)*2 + (E − 0)2√ = (1 − 2)2 + (E − 1)2√ ⇒ 1 + E2√ = 2 − 2E + E2√ ⇒ 1 + E2 = 2 − 2E + E2 ⇒ 2E = 1 ⇒ E = 12
18. Set the two distances equal and solve:
(E + 1)*2 + (E − 0)2√ = (E − 0)2 + (E − 2)2√ ⇒ 2E2 + 2E + 1√ = 2E2 − 4E + 4√ ⇒ 2E2 + 2E + 1 = 2E2 − 4E + 4 ⇒ 6E = 3 ⇒ E = 12
19. Circle with center (0, 0) and radius 3. 20. The single point (0, 0).
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SSoolluuttiioonnss SSeeccttiioonn 00..88SSeeccttiioonn 00..88
1.
2.
3.
4.
5. log416 = the power to which we need to raise 4 in order to get 16. Because 4 2 = 16, this power is 2, so log416 = 2.6. log5125 = the power to which we need to raise 5 in order to get 125. Because 5 3 = 125, this power is 3, so
log5125 = 3.
7. log5 125 = the power to which we need to raise 5 in order to get 125 . Because 5 −2 = 125 , this power is −2, so
log5 125 = −2.
ExponentialForm 102 = 100 43 = 64 44 = 256 0.450 = 1 81/2 = 2 2√ 4−3 = 164
LogarithmicForm log10100 = 2 log464 = 3 log4256 = 4 log0.451 = 0 log82 2√ = 12 log4( 164) = −3
ExponentialForm 101 = 10 55 = 3,125 63 = 216
LogarithmicForm log1010 = 1 log53,125 = 5 log6216 = 3
ExponentialForm 0.53 = 0.125 41/4 = 2√ 3−4 = 181
LogarithmicForm log0.50.125 = 3 log4 2√ = 14 log3( 181) = −4
ExponentialForm 0.32 = 0.09 (12)0 = 1 10−3 = 0.001
LogarithmicForm log0.30.09 = 2 log1/21 = 0 log100.001 = −3
ExponentialForm 9−2 = 181 210 = 1,024 64−1/3 = 14
LogarithmicForm log9 181 = −2 log21,024 = 10 log64 14 = − 13
ExponentialForm 2−1 = 12 105 = 100,000 10−5 = 0.00001
LogarithmicForm log2 12 = −1 log10100,000 = 5 log100.00001 = −5
ExponentialForm 211 = 2,048 16−1/4 = 12 0.252 = 0.0625
LogarithmicForm log22,048 = 11 log16 12 = − 14 log0.250.0625 = 2
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8. log4 164 = the power to which we need to raise 4 in order to get 164 . Because 4 −3 = 164 , this power is −3, so
log4 164 = −3.
9. log 100,000 = log10100,000 = the power to which we need to raise 10 in order to get 100,000. Because
10 5 = 100,000, this power is 5, so log 100,000 = 5.
10. log 1,000 = log101,000 = the power to which we need to raise 10 in order to get 1,000. Because 10 3 = 1,000, this
power is 3, so log 1,000 = 3.
11. log1616 = the power to which we need to raise 16 in order to get 16. Because 16 1 = 16, this power is 1, so
log1616 = 1.
12. log1/2 12 = the power to which we need to raise 12 in order to get 12 . Because (12) 1 = 12, this power is 1, so
log1/2 12 = 1.
13. log4 116 = the power to which we need to raise 4 in order to get 116 . Because 4 −2 = 116 , this power is −2, so
log4 116 = −2.
14. log2 18 = the power to which we need to raise 2 in order to get 18 . Because 2 −3 = 18 , this power is −3, so
log2 18 = −3.
15. log2 2√ = the power to which we need to raise 2 in order to get 2√ . Because 2 1/2 = 2√ , this power is 12, so
log2 2√ = 12 .
16. log4 2√ = the power to which we need to raise 4 in order to get 2√ . Because 4 1/4 = 2√ , this power is 14, so
log4 2√ = 14 .
17. By Identity (1), log63 + log64 = log6(3 × 4) = log6 12.18. By Identity (2), log63 − log64 = log6 34 .19. log62 − log65 − log64 = log62 − (log65 + log64) = log62 − (log6(5 × 4)) (Identity 1)
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SSoolluuttiioonnss SSeeccttiioonn 00..88
= log6( 25 × 4) (Identity 2) = log6 11020. log63 + log62 − log67 = log6(3 × 2) − log67 (Identity 1) = log6(3 × 27 ) (Identity 2) = log6 6721. log63 − 3log62 = log63 − log623 (Identity 3) = log6( 323) (Identity 2) = log6 3822. 3log62 + 2log63 = log623 + log632 (Identity 3) = log6(23 × 32) (Identity 1) = log6 7223. 4log6 + + 5log6 , = log6 +4 + log6 ,5 (Identity 3) = log6 +4,5 (Identity 1)
24. 3log6 G − 2log6 H = log6 G3 − log6 H2 (Identity 3) = log6 G3H2 (Identity 2)
25. 2log6 + + 3log6 , − 4log6 0 = log6 +2 + log6 ,3 − log6 04 (Identity 3)
= log6(+2,3) − log6 04 (Identity 1) = log6 +2,304 (Identity 2)
26. 4log6 G − 3log6 H − 2log6 I = log6 G4 − log6 H3 − log6 I2 (Identity 3)
= log6 G4 − (log6 H3 + log6 I2) = log6 G4 − log6(H3I2) (Identity 1) = log6 G4H3I2 (Identity 2)
27. + log62 − 2log6 + = log62+ − log6 +2 (Identity 3) = log6 2++2 (Identity 2)
28. G log6 H + H log6 G = log6 HG + log6 GH (Identity 3) = log6 HGGH (Identity 1)
29. log 21 = log(3 × 7) = log 3 + log 7 = 6 + 8 (Identity 1)
30. log 14 = log(2 × 7) = log 2 + log 7 = 5 + 8 (Identity 1)
31. log 42 = log(2 × 3 × 7) = log 2 + log 3 + log 7 = 5 + 6 + 8 (Identity 1)
32. log 28 = log(2 × 2 × 7) = log 2 + log 2 + log 7 = 25 + 8 (Identity 1)
33. log(17) = − log 7 = −8 (Identity 5)
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34. log(13) = − log 3 = −6 (Identity 5)
35. log(23) = log 2 − log 3 = 5 − 6 (Identity 2)
36. log(72) = log 7 − log 2 = 8 − 5 (Identity 2)
37. log(47) = log 4 − log 7 (Identity 2) = log 2 + log 2 − log 7 (Identity 1) = 25 − 8
38. log(29) = log 2 − log 9 (Identity 2) = log 2 − (log 3 + log 3) (Identity 1) = 5 − 2639. log 16 = log24 = 4log 2 = 45 (Identity 3)
40. log 81 = log34 = 4log 3 = 46 (Identity 3)
41. log 0.03 = log( 3102) = log 3 − log 102 = log 3 − 2log 10 = 6 − 242. log 7,000 = log(7 × 103) = log 7 + log 103 = log 7 + 3log 10 = 8 + 343. log 5 = log(102 ) = log 10 − log 2 = 1 − 5 (Identity 2)
44. log 25 = log(1004 ) = log 100 − log 4 = log 102 − log22 = 2log 10 − 2log 2 = 2 − 25
45. log 7√ = log(71/2) = 12 log 7 = 8246. log( 23√ ) = log(2) − log 3√ = log(2) − log(31/2) = log 2 − 12 log 3 = 5 − 6247. 4 = 2+ is exactly the equation we solve in order to calculate log24; answer: 2. alternatively, write the equation
4 = 2+ in logarithmic form to get + = log24 = 2.48. 81 = 3+ is exactly the equation we solve in order to calculate log381; answer: 4. alternatively, write the equation
81 = 3+ in logarithmic form to get + = log381 = 4.
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49. Take the base 3 logarithm of both sides of the given equation 27 = 32+−1 to get
log327 = log332+−13 = (2+ − 1)log33 By Identity 3
3 = 2+ − 1 By Identity 4
+ = 3 + 12 = 2 Solve for +.
50. Take the base 4 logarithm of both sides of the given equation 42−3+ = 256 to get
log442−3+ = log4256(2 − 3+)log44 = 4 By Identity 3
2 − 3+ = 4 By Identity 4
+ = 2 − 43 = − 23 Solve for +.
51. Take the base 5 logarithm of both sides of the given equation 5−++1 = 1125 to get
log55−++1 = log5( 1125)(−+ + 1)log55 = − log5125 By Identities 3 and 5
−+ + 1 = −3 By Identity 4
+ = 1 + 3 = 4 Solve for +.
52. Take the base 3 logarithm of both sides of the given equation 3+2−12 = 127 to get
log33+2−12 = log3( 127)(+2 − 12)log33 = − log327 By Identities 3 and 5
+2 − 12 = −3 By Identity 4
+ = ± 9√ = ±3 Solve for +.
53. First divide both sides of the given equation by 50 to get 2.4 = 23J. Take the common logarithm of both sides:
log 2.4 = log(23J)log 2.4 = 3J log 2 By Identity 3
3J = log 2.4log 2 Divide.
J = log 2.43log 2 ≈ 0.4210 Solve for J.If instead you take the base-2 logarithm, the answer is represented as
log2(2.4)3 .54. First divide both sides of the given equation by 500 to get 2 = 1.12J. Take the common logarithm of both sides:
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log 2 = log(1.12J)log 2 = 2J log 1.1 By Identity 3
2J = log 2log 1.1 Divide.
J = log 22log 1.1 ≈ 3.6363 Solve for J.
55. First divide both sides of the given equation by 300 to get 103 = 1.34J−1. Take the common logarithm of both
sides: log(103 ) = log(1.34J−1)log 10 − log 3 = (4J − 1)log 1.3 By Identities 2 and 3
4J − 1 = log 10 − log 3log 1.3 Divide.
J = 14(log 10 − log 3log 1.3 + 1) ≈ 1.3972 Solve for J.
56. First divide both sides of the given equation by 700 to get 1007 = 1.043J+1. Take the common logarithm of both
sides: log(1007 ) = log(1.043J+1)log 100 − log 7 = (3J + 1)log 1.04 By Identities 2 and 3
3J + 1 = log 100 − log 7log 1.04 Divide.
J = 13(log 100 − log 7log 1.04 − 1) ≈ 22.2675 Solve for J.
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