03 Lecture Lam freedman physics 13ed
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Transcript of 03 Lecture Lam freedman physics 13ed
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
PowerPoint Lectures forUniversity Physics, Twelfth Edition
Hugh D. Young and Roger A. Freedman
Lectures by James Pazun
Chapter 3
Motion in Two orThree Dimensions
Modified by Pui Lam 5_29_2013
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
Goals for Chapter 3 To recognize that in 2 or 3-dimensions that the
velocity vector and the acceleration vector need notbe parallel.
Examples
projectile motion uniform and non-uniform circular motion general curve motion Distinguish constant speed vs constant velocity Use dot product between v and a vectors to
determine whether an object is speeding up orslowing down
To investigate relative velocity
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
Position relative to the originFigure 3.1 For general motion in 3-dimension, the position vector
relative to the origin can have components in x , y , and z directions. The path of a particle is generally a curve.
!
r (t ) = x(t ) i + y(t ) j + z(t ) k
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
Average velocity and Instantaneous velocityFigure 3.2 The average velocity between two points will have the
same direction as the displacement
** Instantaneous velocity=!
v !d
!
rdt
=dxdt
i +dydt
j +dzdt
k
** Instantaneous velocity is a vector tangent to the path
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
Example - Projectile motion A projectile is any body given an initial velocity that follows a
path determined by the effects of gravity and air resistance. If air resistance is negligible, then projectile motion = motion
under constant acceleration, a x =0 and a y= -g
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
Equations for Projectile Motion (neglect air-resistance)
Find x(t) and y(t) for a projectile motion given its initial positionand initial velocity.
Calculate the subsequent velocity as a function of time.
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
Projectile motion - numerical example IQ . Given : v o = 10 m / s , ! o = 30
o , and
g ~ 10 m/s 2 . (Assume no air resistance)
(1) Find the time it reaches the top.
(2) Find the velocity vector at the top
(3) Find the range.
(4) Find the velocity vector when it returns to the ground
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
Effect of air resistance
Q . Sketch the path if there is air - resistance.
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
Projectile motion - numerical example II
Q . A basket player is shooting a baskeball from a height of 2m.The basket ball rim is 5 m away (horizontal distance) and 3 m high.
He must make the basket in 1 sceond.
At what angle ( ! ) from the horizontal and at what initial speed
must he throw the ball to make the basket in 1 second?
(Assume no air resistance and g=10m/s 2 )
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
The instantaneous acceleration vectorFigure 3.6 The acceleration vector is non-zero as long as there is a change in
the velocity vector. The change can be either the magnitude OR the direction of the
velocity, OR both.
In 2- and 3-dimension, acceleration vector needs not be in the
same direction of velocity vector. Example: Car going around acurve.
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
Uniform circular motion and centripetal acceleration For circular motion:
x(t)=rcos!
(t), y(t)=rsin!
(t)For uniform circular motion:! increases uniformly " ! (t)= # t" x(t)=rcos # t, y(t)=rsin # t
(e.g. 10 rpm " # = 10(2 $ rad . ) /60 s )
From these, one can calc;!
v(t) and!
a(t)
(You fill in the details)
Result:
!
a c =
!
v2
r ; !
v =
magnitude of velocity=speed
Note: In uniform circular motion, the
speed
is unchanged,but the velocity vector changes => there is an acceleration.
The acceleration is called centripetal acceleration pointing to the center.
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
Example of non-uniform circular motion
Circular motion
doesn t mean a completecircle, could be part of acircle or any curve.
In non-uniform circularmotion, the speed is NOTconstant, hence there isalso a tangential
acceleration , in additionto the centripetalacceleration.
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
In daily language, acceleration means speeding up and deceleration meansslowing down.
In Physics, acceleration (vector) = change of velocity (vector) wrt time.
An object has a non-zero acceleration (vector) whenever there is a change invelocity (vector); the object can be speeding up, slowing down, or keeping thesame speed.
!
v !
a > 0 ! speedingup !
v !
a < 0 ! slowing down !
v !
a = 0 ! constant speed
Acceleration daily usage vs. physics usage
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
Relative velocity on a straight road
What is the velocity vector of the Truck with respect to you?Let
!
VT/E = ! 20 j;!
VY/E = + 30 j!
VT/Y =!
VT/E +!
VE/Y"
!
VT/Y =!
VT/E !!
VY/E= ! 20 ! 30 = ! 50 j
Same formula applies for2- or 3-dimensiosn.
Example :!
VT/E = ! 20 j ,!
VY/E = 30 j
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Copyright 2008 Pearson Education Inc., publishing as Pearson Addison-Wesley
Question: The compass of an airplane indicates that it is
headed north and the plane is moving at 240km/hr throughthe air. If there is wind of 100km/hr from west to east, whatis the velocity of the plane relative to the ground?