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These are the notes of class 12th notes.

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  • Ways of Expressing Concentrations of Solutions

  • Mass PercentageMass % of A = 100

  • Parts per Million andParts per Billionppm = 106Parts per Million (ppm)Parts per Billion (ppb)ppb = 109

  • Mole Fraction (X)In some applications, one needs the mole fraction of solvent, not solutemake sure you find the quantity you need!

  • Molarity (M)Because volume is temperature dependent, molarity can change with temperature.

  • Molality (m)Because neither moles nor mass change with temperature, molality (unlike molarity) is not temperature dependent.

  • Changing Molarity to MolalityIf we know the density of the solution, we can calculate the molality from the molarity, and vice versa.

  • PRACTICE EXERCISE(a) Calculate the mass percentage of NaCl in a solution containing 1.50 g of NaCl in 50.0 g of water. (b) A commercial bleaching solution contains 3.62 mass % sodium hypochlorite, NaOCl. What is the mass of NaOCl in a bottle containing 2500 g of bleaching solution?PRACTICE EXERCISEA commercial bleach solution contains 3.62 mass % NaOCl in water. Calculate (a) the molality and (b) the mole fraction of NaOCl in the solution.

  • Ideal solutionsNon-ideal solutionsPositive deviation from Raoults lawNegative deviation from Raoults law1.Obey Raoults law at every range of concentration. 2.Hmix= 0; neither is evolved nor absorbed during dissolution.

    3.Vmix= 0; total volume of solution is equal to sum of volumes of the components.

    4.P = pA + pB = pA0XA+ pB0XB i.e., pA= 1.Do not obey Raoults law.

    2.Hmix>0. Endothermic dissolution; heat is absorbed.

    3.Vmix> 0. Volume is increased after dissolution.

    4.pA> pA0XA; pB> pB0XB pA+ pB> pA0XA+ pB0XB1.Do not obey Raoults law.

    2.Hmix

  • Ideal solutionsNon-ideal solutionsPositive deviation from Raoults lawNegative deviation from Raoults law

    5.AA, AB, BB interactions should be same, i.e., A and B are identical in shape, size and character.

    6. Escaping tendency of A and B should be same in pure liquids and in the solution. Examples: dilute solutions; benzene + toluence: n-hexane + n-heptane; chlorobenzene + bromobenzene; n-butyl chloride + n-butyl bromide. 5.AB attractive force should be weaker than AA and BB attractive forces. A and B have different shape, size and character.

    6. A and B escape easily showing higher vapour pressure than the expected value. Examples: acetone + ethanol acetone + CS2; water + methanol; water + ethanol; CCl4+ toluene; CCl4+ CHCl3; acetone + benzene; CCl4+ CH3OH; Cyclohexane + ethanol 5. AB attractive force should be greater than AA and BB attractive forces. A and B have different shape, size and character.

    6. Escaping tendency of both components A and B is lowered showing lower vapour pressure than expected ideally. Examples: acetone + aniline; acetone + chloroform; CH3OH + CH3COOH; H2O + HNO3; Choloroform + diethyl ether, water + HCl; acetic acid + pyridine; chloroform + benzene.

  • PRACTICE EXERCISE(a) Calculate the mass percentage of NaCl in a solution containing 1.50 g of NaCl in 50.0 g of water. (b) A commercial bleaching solution contains 3.62 mass % sodium hypochlorite, NaOCl. What is the mass of NaOCl in a bottle containing 2500 g of bleaching solution?Answers:(a) 2.91%, (b) 90.5 g of NaOClAnswers: (a) 0.505 m, (b) 9.00 103

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