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    MATH14

    Plane and Solid Analytic Geometry

    Fundamental Concepts

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    SPECIFIC OBJECTIVES:

    At the end of the lesson, the student is expected to beable to:

    Familiarize with the use of Cartesian Coordinate

    System.

    Determine the distance between two points.

    Define and determine the angle of inclinations and

    slopes of a single line, parallel lines, perpendicular

    lines and intersecting lines. Determine the coordinates of a point of division of a

    line segment.

    Define the median of the triangle.

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    FUNDAMENTAL CONCEPTS

    Analytic Geometry is the branch of

    mathematics, which deals with the properties,

    behaviours, and solution of points, lines,

    curves, angles, surfaces and solids by means of

    algebraic methods in relation to a coordinatesystem.

    DEFINITION:

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    Two Parts of Analytic Geometry

    1. Plane Analytic Geometrydeals with figures

    on a plane surface.2. Solid Analytic Geometrydeals with solid

    figures.

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    Directed Linea line in which one direction is chosenas positive and the opposite direction as negative.

    Directed Line Segmentconsisting of any twopoints and the part between them.

    Directed Distancethe distance between two pointseither positive or negative depending upon the

    direction of the line.

    DEFINITION:

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    RECTANGULAR COORDINATES

    A pair of number (x, y) in which x is the first and y

    being the second number is called an ordered

    pair.

    A vertical line and a horizontal line meeting at an

    origin, O, are drawn which determines the

    coordinate axes.

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    Coordinate Planeis a plane determined by thecoordinate axes.

    o

    y

    x

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    x

    axisis usually drawn horizontally and is calledas the horizontal axis.

    y axisis drawn vertically and is called as the

    vertical axis.othe origin

    coordinatea number corresponds to a point in

    the axis, which is defined in terms of the

    perpendicular distance from the axes to the point.

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    DISTANCE BETWEEN TWO POINTS

    The length of a horizontal line segment is

    the abscissa (x coordinate) of the point on

    the right minus the abscissa (x coordinate)

    of the point on the left.

    1. Horizontal

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    2. Vertical

    The length of a vertical line segment

    is the ordinate (y coordinate) of the

    upper point minus the ordinate (y

    coordinate) of the lower point.

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    3. Slant

    To determine the distance between

    two points of a slant line segment

    add the square of the difference of

    the abscissa to the square of the

    difference of the ordinates and take

    the positive square root of the sum.

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    SAMPLE PROBLEMS

    1. Determine the distance betweena. (-2, 3) and (5, 1)

    b. (6, -1) and (-4, -3)

    2. Show that points A (3, 8), B (-11, 3) and C (-8, -2) are

    vertices of an isosceles triangle.

    3. Show that the triangle A (1, 4), B (10, 6) and C (2, 2) is a

    right triangle.

    4. Find the point on the y-axis which is equidistant fromA(-5, -2) and B(3,2).

    5. 5. By addition of line segments show whether the points

    A(-3, 0), B(-1, -1) and C(5, -4) lie on a straight line.

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    6. The vertices of the base of an isosceles triangle are(1, 2) and (4, -1). Find the ordinate of the third vertexif its abscissa is 6.

    7. Find the radius of a circle with center at (4, 1), if achord of length 4 is bisected at (7, 4).

    8. Show that the points A(-2, 6), B(5, 3), C(-1, -11) andD(-8, -8) are the vertices of a rectangle.

    9. The ordinate of a point P is twice the abscissa. This

    point is equidistant from (-3, 1) and (8, -2). Find thecoordinates of P.

    10. Find the point on the y-axis that is equidistant from(6, 1) and (-2, -3).

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    AREA OF A POLYGON BY COORDINATES

    Consider the triangle whose vertices are P1(x1, y1),

    P2(x2, y2) and P3(x3, y3) as shown below.

    o

    y

    x

    111 y,xP

    222 y,xP

    333 y,xP

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    Then the area of the triangle is determined by: [in

    counterclockwise rotation]

    1yx

    1yx1yx

    2

    1A

    33

    22

    11

    Generalized formula for the area of polygon by

    coordinates:

    1n54321

    1n54321

    yy..yyyyy

    xx..xxxxx

    21A

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    SAMPLE PROBLEMS

    1. Find the area of the triangle whosevertices are (-6, -4), (-1, 3) and (5, -3).

    2. Find the area of a polygon whose vertices

    are (6, -3), (3, 4), (-6, -2), (0, 5) and (-8, 1).

    3. Find the area of a polygon whose vertices

    are (2, -3), (6, -5), (-4, -2) and (4, 0).