008 Complex Numbers
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Transcript of 008 Complex Numbers
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Complex NumbersComplex Numbers
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Consider the quadratic equation x 2 + 1= 0.
Solving for x , gives x 2 = 112 ! x
1! x
Complex Numbers
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Since there is not real number whoseSince there is not real number whosesquare issquare is - -1 , the equation has no1 , the equation has noreal solution. French mathematicianreal solution. French mathematician
Rene Descartes (1596Rene Descartes (1596 - -1650)1650)proposed thatproposed that i i be defined suchbe defined suchthat ,that ,
1!i
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1!i
Complex Numbers
12 !i Note that squaring both sides yields:therefore
and
so
and
iiiii !!! *1* 132
1)1(*)1(* 224 !!! iii
iiiii !!! *1*45
1*1* 2246 !!! iiii
A nd so on
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Finding Powers of Finding Powers of i i
T he successive powers of i rotate through the four values of i , -1, - i , and 1.
i n = i if
n = 1, 5 , 9 ,
i n = - 1 if
n = 2, 6 , 10,
i n = - i if
n = 3 , 7 , 11,
i n = 1 if n
= 4 , 8 , 12,
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then,1-I !i
12 !i
ii !3
14 !i
ii !5
16
!i
ii !7
18 !i
* For larger exponents , divide the exponent by
4 , then use theremainder as your
exponent instead.
Example: ?23 !i
3oremainder aith5423
!
.etcii -hichuseSo, 3 !
ii !23
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R eal NumbersImaginary Numbers
Real numbers and imaginarynumbers are subsets of the set of complex numbers.
Complex Numbers
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Imaginary UnitImaginary UnitUntil now , you have always been toldthat you cant take the square root of
a negative number.If you useimaginary units , you can!
The imaginary unit is .=I t is used to write the square root of a negative number.
1
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Property of the square rootProperty of the square rootof negative numbersof negative numbers
I f r is a positive real number , then
r ir ! r i
Examples:
!3 3i !4 !4i i2
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ExamplesExamples2
)3( 1. i22 )3(i!
)3*3(1!
)3(1!3!
26103 olve 2.2
! x363 2 ! x
122 ! x
122 ! x12i x s!
32i x s!
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Complex NumbersComplex NumbersA complex number has a real part & an imaginary part.
Standard form is: b ia
Real part Imaginary part
Example: 5+4iExample: 5+4i
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Adding and SubtractingAdding and Subtracting
To Add or Subt rac t C omplex Nu m b ers
1. Change all imaginary numbers to b i form .
2. A dd (or subtract ) the real parts of the complexnumbers .
3. A dd (or subtract ) the imaginary parts of the
complex numbers .4. Write the answer in the form a + b i .
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Adding and SubtractingAdding and Subtracting(add or subtract the real parts , then(add or subtract the real parts , thenadd or subtract the imaginary parts)add or subtract the imaginary parts)
Ex: )33()21( ii)32()31( ii!
i52!
Ex: )73()32( ii)73()32( ii!
i41!
Ex: )32()3(2 iii)32()23( iii!
i21!
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MultiplyingMultiplying
To Mu lti ply C omplex Nu m b ers
1. Change all imaginary numbers to b i form .
2. Multiply the complex numbers as you wouldmultiply polynomials .
3. Substitute 1 for each i 2.
4. Combine the real parts and the imaginary parts . Write the answer in a + b i form .
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MultiplyingMultiplyingTreat the is like variables , thenTreat the is like variables , then
change any that are not to thechange any that are not to thefirst powerfirst power
Ex: )3( ii2
3 ii!)1(3! i
i31!
Ex: )26)(32( ii2618412 iii!
)1(62212! i
62212! ii226!
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CAUTIO N!CAUTIO N!
?24 !
!! 2424 ii
!22 2i 22
824 {
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DividingDividing
To Divid e C omplex Nu m b ers
1. Change all imaginary numbers to b i form .
2. R ationalize the denominator by multiplying boththe numerator and the denominator by theconjugate of the denominator .
3. Substitute 1 for each i 2.
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DividingDividing
E xamples:
!i
i
3434
!i
i
i
i
3434
3434
!2316
3434i
ii
!916
924162
ii25
247 i
!
53
5!
53
5i
!
53
53
53
5i
i
i
!259
)53(5i
i!
59)5515 i
14)5515 i
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i
i
i
i E x
2121
*21
113 :
)21)(21()21)(113(
ii
ii!
2
2
4221221163iii
iii!
)1(41
)1(2253!
i
412253
!i
5
525 i!
55
525 i
!
i! 5
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EVALUATE theFOLLOWING
8
15
27
52
12
1.
2.
3. 2
4.5.
i
i
i
i
i
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C hange to biform 1. 36
2. 120
3. 48
4. 6005. 4 64
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1 . ( 2 8 ) (3 5 )
2 . (5 8 ) ( 4 2 ) (3 )
3 . 3 ( 2 5 )
4 . ( 4 3 )(2 5 )
45 .
23
6 .
i i
i i i
i i
i i
i
ii
i
P erform the followingoperations