· Web viewFinal #3 Solution Determining drainage area Fill Pits Flow Direction Flow Accumulation...

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Final #3 Solution 1. Determining drainage area a. Fill Pits b. Flow Direction c. Flow Accumulation (fac) d. Load the Outlets Shapefile and identify the flow accumulation value at the outlet 620523 grid cells x 30 x 30 m = 558.4 x 10 6 m 2 . This is the drainage area. 2. Delineating stream network a. Watershed upstream of outlet b. Reclassify to have a value of 1 c. Raster calculator (fac>1000)*wshed d. Stream link e. Stream to Feature making sure output is a feature class in a geodatabase so that the shapes have a shape length attribute f. Evaluate statistics on the Shape Length The total length of streams is 404064 m = 404 km. 3. Preparing layout a. Add snotel.xls b. Display XY data using NAD 1983.prj c. Export to Shapefile d. Label e. See layout next page

Transcript of  · Web viewFinal #3 Solution Determining drainage area Fill Pits Flow Direction Flow Accumulation...

Page 1:  · Web viewFinal #3 Solution Determining drainage area Fill Pits Flow Direction Flow Accumulation (fac) Load the Outlets Shapefile and identify the flow accumulation value at the

Final #3 Solution

1. Determining drainage areaa. Fill Pitsb. Flow Directionc. Flow Accumulation (fac)d. Load the Outlets Shapefile and identify the flow accumulation value at the outlet

620523 grid cells x 30 x 30 m = 558.4 x 106 m2. This is the drainage area.

2. Delineating stream networka. Watershed upstream of outletb. Reclassify to have a value of 1c. Raster calculator (fac>1000)*wshedd. Stream linke. Stream to Feature making sure output is a feature class in a geodatabase so that the shapes

have a shape length attributef. Evaluate statistics on the Shape Length

The total length of streams is 404064 m = 404 km.

3. Preparing layouta. Add snotel.xlsb. Display XY data using NAD 1983.prjc. Export to Shapefiled. Labele. See layout next page

Page 2:  · Web viewFinal #3 Solution Determining drainage area Fill Pits Flow Direction Flow Accumulation (fac) Load the Outlets Shapefile and identify the flow accumulation value at the

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Temple Fork

Tony Grove RS

Franklin Basin

USU Doc DanielTony Grove Lake

Klondike Narrows

Garden City Summit

Logan River Watershed

®0 4 82 Kilometers

ElevationHigh : 3100

Low : 1300

4. Finding snotel elevationsa. Zonal Statistics as Table

Page 3:  · Web viewFinal #3 Solution Determining drainage area Fill Pits Flow Direction Flow Accumulation (fac) Load the Outlets Shapefile and identify the flow accumulation value at the

b. Join to Shapefile attribute tablec. Export table to DBF and use Excel to prepare for presentation

Name Lat Long SWE_inchesElevation (m)Tony Grove Lake 41.900000 -111.633333 10.8 2603Klondike Narrows 41.968333 -111.596667 6.1 2217Garden City Summit 41.921667 -111.468056 6.8 2347Temple Fork 41.800000 -111.550000 4.8 2222Tony Grove RS 41.884444 -111.568889 2.7 1928USU Doc Daniel 41.900000 -111.516667 8.8 2576Franklin Basin 42.049444 -111.599444 8.0 2501

5. The following figure was generated using Excel

1500 1700 1900 2100 2300 2500 27000.0

2.0

4.0

6.0

8.0

10.0

12.0

f(x) = 0.0106648289755408 x − 18.1198713681037R² = 0.930966918047676

SWE_inchesLinear (SWE_inches)

Elevation m

Snow

Wat

er E

quiv

alen

t in

6. Use Raster calculator to apply the formula 0.0107 elevation -18.12 to estimate SWE("logan.tif" * 0.0107 - 18.12) * "wshed1". Isolate on the watershed by multiplying by wshed1.(SWE > 0)*SWE to get only positive valuesSee layout following

Page 4:  · Web viewFinal #3 Solution Determining drainage area Fill Pits Flow Direction Flow Accumulation (fac) Load the Outlets Shapefile and identify the flow accumulation value at the
Page 5:  · Web viewFinal #3 Solution Determining drainage area Fill Pits Flow Direction Flow Accumulation (fac) Load the Outlets Shapefile and identify the flow accumulation value at the

7. The mean of the SWE layer depicted above is 6.53 inches from the Source tab in layer properties. This is equivalent to 6.53 x 0.0254 = 0.166 m. The area is 558.4 x 106 m2. The volume of water present in the form of snow is therefore 0.166 x 558.4 x 106 = 92.62 x 106 m3.