Wavelength ◦ The shortest distance between equivalent points on a continuous wave; either crest to...
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Transcript of Wavelength ◦ The shortest distance between equivalent points on a continuous wave; either crest to...
![Page 1: Wavelength ◦ The shortest distance between equivalent points on a continuous wave; either crest to crest or trough to trough ◦ Measured in m.](https://reader035.fdocuments.in/reader035/viewer/2022062313/56649cec5503460f949b89fa/html5/thumbnails/1.jpg)
![Page 2: Wavelength ◦ The shortest distance between equivalent points on a continuous wave; either crest to crest or trough to trough ◦ Measured in m.](https://reader035.fdocuments.in/reader035/viewer/2022062313/56649cec5503460f949b89fa/html5/thumbnails/2.jpg)
Wavelength◦The shortest distance between equivalent points on a continuous wave; either crest to crest or trough to trough
◦Measured in m
![Page 3: Wavelength ◦ The shortest distance between equivalent points on a continuous wave; either crest to crest or trough to trough ◦ Measured in m.](https://reader035.fdocuments.in/reader035/viewer/2022062313/56649cec5503460f949b89fa/html5/thumbnails/3.jpg)
Frequency◦the number of waves that pass a given point per second; one hertz (Hz) equals one wave per second
![Page 4: Wavelength ◦ The shortest distance between equivalent points on a continuous wave; either crest to crest or trough to trough ◦ Measured in m.](https://reader035.fdocuments.in/reader035/viewer/2022062313/56649cec5503460f949b89fa/html5/thumbnails/4.jpg)
Amplitude◦The wave's height from the origin to crest or origin to trough
◦Measured in m
![Page 5: Wavelength ◦ The shortest distance between equivalent points on a continuous wave; either crest to crest or trough to trough ◦ Measured in m.](https://reader035.fdocuments.in/reader035/viewer/2022062313/56649cec5503460f949b89fa/html5/thumbnails/5.jpg)
![Page 6: Wavelength ◦ The shortest distance between equivalent points on a continuous wave; either crest to crest or trough to trough ◦ Measured in m.](https://reader035.fdocuments.in/reader035/viewer/2022062313/56649cec5503460f949b89fa/html5/thumbnails/6.jpg)
As shown in the formula, if wavelength increases, frequency decreases. As wavelength decreases, frequency increases.
![Page 7: Wavelength ◦ The shortest distance between equivalent points on a continuous wave; either crest to crest or trough to trough ◦ Measured in m.](https://reader035.fdocuments.in/reader035/viewer/2022062313/56649cec5503460f949b89fa/html5/thumbnails/7.jpg)
speed = λ υ
c = speed of light = 3.00 x 108 m/s
![Page 8: Wavelength ◦ The shortest distance between equivalent points on a continuous wave; either crest to crest or trough to trough ◦ Measured in m.](https://reader035.fdocuments.in/reader035/viewer/2022062313/56649cec5503460f949b89fa/html5/thumbnails/8.jpg)
If a gamma ray traveling at the speed of light has a frequency of 2.88 x 1021Hz, what is its wavelength?
speed = λ υ 3.00 x 108 m/s = λ (2.88 x 1021 Hz)
Answer: λ = 1.04 x 10-13 m
![Page 9: Wavelength ◦ The shortest distance between equivalent points on a continuous wave; either crest to crest or trough to trough ◦ Measured in m.](https://reader035.fdocuments.in/reader035/viewer/2022062313/56649cec5503460f949b89fa/html5/thumbnails/9.jpg)
Energy will increase as frequency increases
E = h υ◦h is a constant = 6.626 x 10-34 Js
![Page 10: Wavelength ◦ The shortest distance between equivalent points on a continuous wave; either crest to crest or trough to trough ◦ Measured in m.](https://reader035.fdocuments.in/reader035/viewer/2022062313/56649cec5503460f949b89fa/html5/thumbnails/10.jpg)
A photon has an energy of 2.93 x 10 -25J. What is its frequency?
E = h υ 2.93 x 10-25 J = (6.626x10-34 Js) υ
Answer: υ = 4.42 x 105 Hz or 442,000 Hz
![Page 11: Wavelength ◦ The shortest distance between equivalent points on a continuous wave; either crest to crest or trough to trough ◦ Measured in m.](https://reader035.fdocuments.in/reader035/viewer/2022062313/56649cec5503460f949b89fa/html5/thumbnails/11.jpg)
What is the energy of an ultraviolet photon that has a wavelength of 1.18 x 10-8m?◦ E = h υ
But wait? Do we have frequency? No? So…Find it!
◦ Speed = c = λ υ 3.00 x 108m/s = (1.18 x 10-8m) υ υ = 2.54 x 1016
◦ Now solve for the energy E = (6.626 x 10-34 Js) (2.54 x 1016) E = 1.68 x 10-17 J