© T Madas. Experience on using the Pythagoras Theorem tells us that: There are a few integer...
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Transcript of © T Madas. Experience on using the Pythagoras Theorem tells us that: There are a few integer...
![Page 1: © T Madas. Experience on using the Pythagoras Theorem tells us that: There are a few integer lengths for a triangle which satisfy the Pythagorean law.](https://reader036.fdocuments.in/reader036/viewer/2022082610/56649da85503460f94a9546e/html5/thumbnails/1.jpg)
© T Madas
![Page 2: © T Madas. Experience on using the Pythagoras Theorem tells us that: There are a few integer lengths for a triangle which satisfy the Pythagorean law.](https://reader036.fdocuments.in/reader036/viewer/2022082610/56649da85503460f94a9546e/html5/thumbnails/2.jpg)
© T Madas
Experience on using the Pythagoras Theorem tells us that:
There are a few integer lengths for a triangle which satisfy the Pythagorean law.
• We all know the famous “three” numbers 3,4,5• Some of us are aware of 5,12,13• Even fewer of us know the 8,15,17 and the 7,24,25• What about 20,21,29?• How many of us know the 12,35,37?• or 9,40,41?• Does 2000, 999999, 1000001 also work?
Is there an infinite number of Pythagorean Triples?Is there a way to generate such numbers?
![Page 3: © T Madas. Experience on using the Pythagoras Theorem tells us that: There are a few integer lengths for a triangle which satisfy the Pythagorean law.](https://reader036.fdocuments.in/reader036/viewer/2022082610/56649da85503460f94a9546e/html5/thumbnails/3.jpg)
© T Madas
2 222 2 2 22m n mn m né ù é ùé ù- + º +ê ú ê úë ûë û ë û
where , and 1m n m nÎ > ³¥
We can generate such triples using the identity:
a b c
2 222 2 2 22m n mn m né ù é ùé ù- + º +ê ú ê úë ûë û ë û 1m n> ³
a b c ,m n Î ¥
![Page 4: © T Madas. Experience on using the Pythagoras Theorem tells us that: There are a few integer lengths for a triangle which satisfy the Pythagorean law.](https://reader036.fdocuments.in/reader036/viewer/2022082610/56649da85503460f94a9546e/html5/thumbnails/4.jpg)
© T Madas
2 222 2 2 22m n mn m né ù é ùé ù- + º +ê ú ê úë ûë û ë û 1m n> ³
a b c ,m n Î ¥
1
a = 9
b = 40
c = 41
4
a = 16
b = 30
c = 34
a = 21
b = 20
c = 29
a = 24
b = 10
c = 265
a = 7
b = 24
c = 25
a = 12
b = 16
c = 20
a = 15
b = 8
c = 174
a = 5
b = 12
c = 13
a = 8
b = 6
c = 103
a = 3
b = 4
c = 52
5321m nNotes
The condition m > n ≥ 1 is placed so that a > 0
It should be obvious that we can extend this table producing an infinite number of Pythagorean triples
This “formula” does not produce unique triples for different values of m and n
![Page 5: © T Madas. Experience on using the Pythagoras Theorem tells us that: There are a few integer lengths for a triangle which satisfy the Pythagorean law.](https://reader036.fdocuments.in/reader036/viewer/2022082610/56649da85503460f94a9546e/html5/thumbnails/5.jpg)
© T Madas
![Page 6: © T Madas. Experience on using the Pythagoras Theorem tells us that: There are a few integer lengths for a triangle which satisfy the Pythagorean law.](https://reader036.fdocuments.in/reader036/viewer/2022082610/56649da85503460f94a9546e/html5/thumbnails/6.jpg)
© T Madas
An unexpected way of generating Pythagorean triples is by adding unit fractions whose denominators are consecutive odd or even integers.
The numerator and denominator of the resulting fraction will always give the two shorter sides of a Pythagorean triple.11
13
+ 43
= Squaring and adding gives the 3, 4, 5 triple
13
15
+ 815
= Squaring and adding gives the 8, 15, 17 triple
15
17
+ 1235
= Squaring and adding gives the 12, 35, 37 triple
17
19
+ 1663
= Squaring and adding gives the 16, 63, 65 triple
![Page 7: © T Madas. Experience on using the Pythagoras Theorem tells us that: There are a few integer lengths for a triangle which satisfy the Pythagorean law.](https://reader036.fdocuments.in/reader036/viewer/2022082610/56649da85503460f94a9546e/html5/thumbnails/7.jpg)
© T Madas
12
14
+ 34
= Squaring and adding gives the 3, 4, 5 triple
14
16
+ 512
= Squaring and adding gives the 5, 12, 13 triple
16
18
+ 724
= Squaring and adding gives the 7, 24, 25 triple
18
110
+ 940
= Squaring and adding gives the 9, 40, 41 triple
An unexpected way of generating Pythagorean triples is by adding unit fractions whose denominators are consecutive odd or even integers.
The numerator and denominator of the resulting fraction will always give the two shorter sides of a Pythagorean triple.
![Page 8: © T Madas. Experience on using the Pythagoras Theorem tells us that: There are a few integer lengths for a triangle which satisfy the Pythagorean law.](https://reader036.fdocuments.in/reader036/viewer/2022082610/56649da85503460f94a9546e/html5/thumbnails/8.jpg)
© T Madas
2( )
Why does this method generates Pythagorean triples?1n
12n
++
1n= ( )
( )22
nn
´ +´ + ( )
12n
++
nn
´´ = 2n n+ +
( )2n n + 22 2
2n
n n+=
+
Squaring and adding these quantities should produce a perfect square, if this method is to work
2 2n + 2 22( )n n++ = 24n 8n+ 4+ 4n+ 34n+ 24n+
= 4n 34n+ 28n+ 8n+ 4+
2( )= 2n 2n+ 2+
![Page 9: © T Madas. Experience on using the Pythagoras Theorem tells us that: There are a few integer lengths for a triangle which satisfy the Pythagorean law.](https://reader036.fdocuments.in/reader036/viewer/2022082610/56649da85503460f94a9546e/html5/thumbnails/9.jpg)
© T Madas