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Transcript of -Nice neat notes that are legible and use indentations when appropriate.
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Part II
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-Nice neat notes that are legible and use indentations when appropriate.
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-Nice neat notes that are legible and use indentations when appropriate.
-Example of indent.
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-Nice neat notes that are legible and use indentations when appropriate.
-Example of indent.
-Skip a line between topics
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-Nice neat notes that are legible and use indentations when appropriate.
-Example of indent.
-Skip a line between topics
-Make visuals clear and well drawn.
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-Nice neat notes that are legible and use indentations when appropriate.
-Example of indent.
-Skip a line between topics
-Make visuals clear and well drawn. Please label.
Effort ArmResistance
Arm
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Speed: A measure of motion, = distance divided by time. D/T
Copyright © 2010 Ryan P. Murphy
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Speed: A measure of motion, = distance divided by time. D/T
Copyright © 2010 Ryan P. Murphy
ScalarsNo Direction
Speed is the rate of motion, or the rate of change of position.
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Speed: A measure of motion, = distance divided by time. D/T
Copyright © 2010 Ryan P. Murphy
ScalarsNo Direction
Speed is the rate of motion, or the rate of change of position.
Can only be zero or positive.
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Distance = Speed ● Time
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Distance = Speed ● Time
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D
S T
Distance = Speed ● Time
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D
S T
Distance = Speed ● Time
X
÷÷
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• How far did Joe walk if he walked a steady 4 km/h for three straight hours?
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• How far did Joe walk if he walked a steady 4 km/h for three straight hours?
Distance = Speed ● Time
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• How far did Joe walk if he walked a steady 4 km/h for three straight hours?
Distance = Speed ● Time
Distance = 4 km/h ● 3 h
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• How far did Joe walk if he walked a steady 4 km/h for three straight hours?
Distance = Speed ● Time
Distance = 4 km/h ● 3 hDistance =
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• How far did Joe walk if he walked a steady 4 km/h for three straight hours?
Distance = Speed ● Time
Distance = 4 km/h ● 3 hDistance = 12 km
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D
S T
DistanceSpeed = --------------- Time
X
÷÷
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• What is Joes speed if he walked a steady 5 km in one hour?
Rate / Speed R =
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• What is Joes speed if he walked a steady 5 km in one hour?
Rate / Speed R = 5 km1 hour
or 5 km/hr
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• What is Joes speed if he walked 5 km in one hour?
Rate / Speed R = 5 km1 hour
or 5 km/hr
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• Juan travels 300km in 6hrs. Find his average speed in km/h.
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• Juan travels 300km in 6hrs. Find his average speed in km/h.
• Speed = Distance / Time
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• Juan travels 300km in 6hrs. Find his average speed in km/h.
• Speed = Distance / Time
300km• Speed = ------------ = 50 km/h
6h
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• Juan travels 300km in 6hrs. Find his average speed in km/h.
• Speed = Distance / Time
300km 50km• Speed = ------------ = ---------
6h h
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D
S T
DistanceTime = --------------- Speed
X
÷÷
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• Marlene drove 500 km at an average speed of 50 km/h? How long did she drive?
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• Marlene drove 500 km at an average speed of 50 km/h? How long did she drive?
• Time = Distance / Speed
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• Marlene drove 500 km at an average speed of 50 km/h? How long did she drive?
• Time = Distance / Speed
500km • Time = ------------ = _____h
50km/h
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• Marlene drove 500 km at an average speed of 50 km/h? How long did she drive?
• Time = Distance / Speed
500km • Time = ------------ = _____h
50km/h
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• Marlene drove 500 km at an average speed of 50 km/h? How long did she drive?
• Time = Distance / Speed
500km • Time = ------------ = 10h
50km/h
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Velocity = (distance / time) and direction.
Copyright © 2010 Ryan P. Murphy
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• Velocity =–S is replaced with V because velocity is
speed and direction.
Copyright © 2010 Ryan P. Murphy
DV = ------
T
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• What’s Joes velocity if he walked 4 kilometers East in one hour?
4 km East 4 km
• V = ----------- = 4 km/hr/east 1 hour
Copyright © 2010 Ryan P. Murphy
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• What’s Joes velocity if he walked 4 kilometers East in one hour?
4 km East 4km km
• V = ----------- = 4 hr/east 1 hour
Copyright © 2010 Ryan P. Murphy
4kmhr
East
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• Velocity deals with displacement.– Displacement measures where you end up
relative to where you started.
Copyright © 2010 Ryan P. Murphy
Start
Finish
4m
8m
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• Velocity deals with displacement.– Displacement measures where you end up
relative to where you started.
Copyright © 2010 Ryan P. Murphy
Start
Now you try
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• Velocity deals with displacement.– Displacement measures where you end up
relative to where you started.
Copyright © 2010 Ryan P. Murphy
Start
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• Velocity deals with displacement.– Displacement measures where you end up
relative to where you started.
Copyright © 2010 Ryan P. Murphy
Start
Finish
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• Velocity deals with displacement.– Displacement measures where you end up
relative to where you started.
Copyright © 2010 Ryan P. Murphy
Start
Finish
50m
60m
30m
100m
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• Velocity deals with displacement.– Displacement measures where you end up
relative to where you started.
Copyright © 2010 Ryan P. Murphy
Start
Finish
50m
60m
30m
100m
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• Velocity deals with displacement.– Displacement measures where you end up
relative to where you started.
Copyright © 2010 Ryan P. Murphy
Start
Finish
50m
60m
30m
100m
178.88m
80m
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• Find the displacement.
Copyright © 2010 Ryan P. Murphy
Start/Finish
Don’t try this one(It’s a trick)
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• Find the displacement.
Copyright © 2010 Ryan P. Murphy
Start/Finish
Try this one
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• Find the displacement.
Copyright © 2010 Ryan P. Murphy
Start/Finish
50m
50m 10m
10m
20m
100m
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• The speed of the car is 80 km / hr .
Copyright © 2010 Ryan P. Murphy
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• The velocity of the car is 80 km / hr / West.
Copyright © 2010 Ryan P. Murphy
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• The velocity of the plane is 300 km / hr / West.
Copyright © 2010 Ryan P. Murphy
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• The velocity of the plane is 300 km / hr / West.
Copyright © 2010 Ryan P. Murphy
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• The velocity of the plane is 300 km / hr / West.
Copyright © 2010 Ryan P. Murphy
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Copyright © 2010 Ryan P. Murphy
The speed of the plane is 300 km / hr
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Copyright © 2010 Ryan P. Murphy
The speed of the plane is 300 km / hr
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Copyright © 2010 Ryan P. Murphy
The speed of the plane is 300 km / hr
Speed and Velocity Calculations and problems. Learn more at…. http://www2.franciscan.edu/academic/mathsci/mathscienceintegation/MathScienceIntegation-827.htm
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• It took Lightning McGreen 2.5 hours to travel 600 kilometers.–How fast was he going in Kilometers an
hour?
Copyright © 2010 Ryan P. Murphy
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• Forces in Motion, Speed, Velocity, Acceleration and more available sheet.
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• It took Lightning McGreen 2.5 hours to travel 600 kilometers.–How fast was he going in Kilometers an
hour?
Copyright © 2010 Ryan P. Murphy
![Page 58: -Nice neat notes that are legible and use indentations when appropriate.](https://reader030.fdocuments.in/reader030/viewer/2022013012/5697c0111a28abf838ccba7b/html5/thumbnails/58.jpg)
• It took Lightning McGreen 2.5 hours to travel 600 kilometers.–How fast was he going in Kilometers an
hour?
Copyright © 2010 Ryan P. Murphy
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• It took Lightning McGreen 2.5 hours to travel 600 kilometers.–How fast was he going in Kilometers an
hour?
Copyright © 2010 Ryan P. Murphy
Speed = Distance / Time
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• It took Lightning McGreen 2.5 hours to travel 600 kilometers.–How fast was he going in Kilometers an
hour?
Copyright © 2010 Ryan P. Murphy
Speed = Distance / Time
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• It took Lightning McGreen 2.5 hours to travel 600 kilometers.–How fast was he going in Kilometers an
hour?
Copyright © 2010 Ryan P. Murphy
Speed = Distance / TimeSpeed = 600 km / 2.5 h
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• It took Lightning McGreen 2.5 hours to travel 600 kilometers.–How fast was he going in Kilometers an
hour?
Copyright © 2010 Ryan P. Murphy
Speed = Distance / TimeSpeed = 600 km / 2.5 hSpeed = 240 km/h
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• Answer: 240 km/h –Speed is distance over time.
Copyright © 2010 Ryan P. Murphy
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• Forces in Motion, Speed, Velocity, Acceleration and more available sheet.
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• It took Ms. Rally 4 hours to travel 165 kilometers due North.–What was the velocity of her car in
Kilometers an hour?
Copyright © 2010 Ryan P. Murphy
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• It took Ms. Rally 4 hours to travel 165 kilometers due North.–What was the velocity of her car in
Kilometers an hour?
Copyright © 2010 Ryan P. Murphy
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• It took Ms. Rally 4 hours to travel 165 kilometers due North.–What was the velocity of her car in
Kilometers an hour?
Copyright © 2010 Ryan P. Murphy
V
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• It took Ms. Rally 4 hours to travel 165 kilometers due North.–What was the velocity of her car in
Kilometers an hour?
Copyright © 2010 Ryan P. Murphy
V
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• It took Ms. Rally 4 hours to travel 165 kilometers due North.–What was the velocity of her car in
Kilometers an hour?
Copyright © 2010 Ryan P. Murphy
VVelocity = Distance / Time
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• It took Ms. Rally 4 hours to travel 165 kilometers due North.–What was the velocity of her car in
Kilometers an hour?
Copyright © 2010 Ryan P. Murphy
VVelocity = Distance / TimeVelocity = 165km / 4 h
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• It took Ms. Rally 4 hours to travel 165 kilometers due North.–What was the velocity of her car in
Kilometers an hour?
Copyright © 2010 Ryan P. Murphy
VVelocity = Distance / TimeVelocity = 165km / 4 hVelocity = 41.25 km/h/North
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• Answer: 41.25 km / h / North –Velocity is distance over time and
direction.
Copyright © 2010 Ryan P. Murphy
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• Forces in Motion, Speed, Velocity, Acceleration and more available sheet.
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• What is the speed if the distance was 340 km and the time was 3 hours?–Was Jater speeding?
Copyright © 2010 Ryan P. Murphy
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• What is the speed if the distance was 340 km and the time was 3 hours?–Was Jater speeding?
Copyright © 2010 Ryan P. Murphy
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• What is the speed if the distance was 340 km and the time was 3 hours?–Was Jater speeding?
Copyright © 2010 Ryan P. Murphy
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• What is the speed if the distance was 340 km and the time was 3 hours?–Was Jater speeding?
Copyright © 2010 Ryan P. Murphy
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• What is the speed if the distance was 340 km and the time was 3 hours?–Was Jater speeding?
Copyright © 2010 Ryan P. Murphy
Speed = Distance / Time
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• What is the speed if the distance was 340 km and the time was 3 hours?–Was Jater speeding?
Copyright © 2010 Ryan P. Murphy
Speed = Distance / TimeSpeed = 340km / 3 h
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• What is the speed if the distance was 340 km and the time was 3 hours?–Was Jater speeding?
Copyright © 2010 Ryan P. Murphy
Speed = Distance / TimeSpeed = 340km / 3 hSpeed = 113km/h
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• 340 km / 3 hours = 113km/h–Jater was speeding.
Copyright © 2010 Ryan P. Murphy
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• Forces in Motion, Speed, Velocity, Acceleration and more available sheet.
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• How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours?
Copyright © 2010 Ryan P. Murphy
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• How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours?
Copyright © 2010 Ryan P. Murphy
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• How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours?
Copyright © 2010 Ryan P. Murphy
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• How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours?
Copyright © 2010 Ryan P. Murphy
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• How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours?
Copyright © 2010 Ryan P. Murphy
Distance = Speed ● Time
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• How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours?
Copyright © 2010 Ryan P. Murphy
Distance = Speed ● TimeDistance = 60km/h ● 4 h
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• How far did Doc Budson travel if he was going 60 kilometers an hour for 4 straight hours?
Copyright © 2010 Ryan P. Murphy
Distance = Speed ● TimeDistance = 60km/h ● 4 h
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• In this case, we just multiply the distance traveled by the time. 60 km/h times 4 hours.
Copyright © 2010 Ryan P. Murphy
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• 60 km times 4 hours = 240 km–Check your work, 240/4 should be 60.
Copyright © 2010 Ryan P. Murphy
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• Forces in Motion, Speed, Velocity, Acceleration and more available sheet.
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• What is the speed if a runner runs a distance of 400 meters in 43 seconds.
Copyright © 2010 Ryan P. Murphy
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• What is the speed if a runner runs a distance of 400 meters in 43 seconds.
Copyright © 2010 Ryan P. Murphy
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• What is the speed if a runner runs a distance of 400 meters in 43 seconds.
Copyright © 2010 Ryan P. Murphy
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• What is the speed if a runner runs a distance of 400 meters in 43 seconds.
Copyright © 2010 Ryan P. Murphy
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• What is the speed if a runner runs a distance of 400 meters in 43 seconds.
Copyright © 2010 Ryan P. Murphy
Speed = Distance / Time
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• What is the speed if a runner runs a distance of 400 meters in 43 seconds.
Copyright © 2010 Ryan P. Murphy
Speed = Distance / TimeSpeed = 400m / 43s
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• What is the speed if a runner runs a distance of 400 meters in 43 seconds.
Copyright © 2010 Ryan P. Murphy
Speed = Distance / TimeSpeed = 400m / 43sSpeed = 9.30 m/s
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• 400m / 43s = 9.30 m/s
Copyright © 2010 Ryan P. Murphy
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• Forces in Motion, Speed, Velocity, Acceleration and more available sheet.
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• Activity! Looking for the Violators.
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• Activity! Looking for the Violators.
Safety is a big concern here. Students need to be far from road. Outside behavior must be excellent.
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• Activity! Looking for the Violators.
Safety is a big concern here. Students need to be far from road. Outside behavior must be excellent.
We also must try to conceal ourselves at all time. We do not want anyone to see us / slow down.
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• Activity! Optional– Teacher measures out 300 feet along road and
puts a cone at the start and finish a short distance from the roads edge.
– From a distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone.
– Speed = Distance (300 ft) divided by time (ft/sec.) – Multiply by .681 (ft/sec to mph conversion) = mph– Over 30 mph is speeding in the village.– Create list of all the speeds and then average.– Does the village have a speeding problem?
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• Activity! Optional– Teacher measures out 300 feet along road and
puts a cone at the start and finish a short distance from the roads edge.
– From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone.
– Speed = Distance (300 ft) divided by time (ft/sec.) – Multiply by .681 (ft/sec to mph conversion) = mph– Over 30 mph is speeding in the village.– Create list of all the speeds and then average.– Does the village have a speeding problem?
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• Activity! Optional– Teacher measures out 300 feet along road and
puts a cone at the start and finish a short distance from the roads edge.
– From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone.
– Speed = Distance (300 ft) divided by time (ft/s.) – Multiply by .681 (ft/sec to mph conversion) = mph– Over 30 mph is speeding in the village.– Create list of all the speeds and then average.– Does the village have a speeding problem?
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• Activity! Optional– Teacher measures out 300 feet along road and
puts a cone at the start and finish a short distance from the roads edge.
– From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone.
– Speed = Distance (300 ft) divided by time (ft/s.) – Multiply by .681 (ft/sec to mph conversion) = mph– Over 30 mph is speeding in the village.– Create list of all the speeds and then average.– Does the village have a speeding problem?
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• Activity! Optional– Teacher measures out 300 feet along road and
puts a cone at the start and finish a short distance from the roads edge.
– From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone.
– Speed = Distance (300 ft) divided by time (ft/s.) – Multiply by .681 (ft/sec to mph conversion) = mph– Over 30 mph is speeding in the village.– Create list of all the speeds and then average.– Does the village have a speeding problem?
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• Activity! Optional– Teacher measures out 300 feet along road and
puts a cone at the start and finish a short distance from the roads edge.
– From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone.
– Speed = Distance (300 ft) divided by time (ft/s.) – Multiply by .681 (ft/sec to mph conversion) = mph– Over 30 mph is speeding in the village.– Create list of all the speeds and then average.– Does the village have a speeding problem?
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• Activity! Optional– Teacher measures out 300 feet along road and
puts a cone at the start and finish a short distance from the roads edge.
– From a hidden distance, students use a stopwatch to time the speed of cars from the start cone to the finish cone.
– Speed = Distance (300 ft) divided by time (ft/s.) – Multiply by .681 (ft/sec to mph conversion) = mph– Over 30 mph is speeding in the village.– Create list of all the speeds and then average.– Does the town have a speeding problem?
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Trains start off slow…
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Example of Instantaneous velocity
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• Note: This is nice to know.• Average vs. Instantaneous Velocity
– Instantaneous Velocity: When an object starts and then speeds up (not moving at one steady speed).
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• Note: This is nice to know.• Average vs. Instantaneous Velocity
– Instantaneous Velocity: When an object starts and then speeds up (not moving at one steady speed).
Instantaneous Velocity Definition: The velocity of an object at any given instant (especially that of an accelerating object); the limit of the change in position per unit time as the unit of time approaches zero; expressed mathematically
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• Note: This is nice to know.• Average vs. Instantaneous Velocity
– Instantaneous Velocity: When an object starts and then speeds up (not moving at one steady speed).
Instantaneous Velocity Definition: The velocity of an object at any given instant (especially that of an accelerating object); the limit of the change in position per unit time as the unit of time approaches zero; expressed mathematically
Note: Instantaneous Velocity of the shot
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• Average: The result obtained by adding several quantities together and then dividing this total by the number of quantities; the mean
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• Average: The result obtained by adding several quantities together and then dividing this total by the number of quantities; the mean.
Adding all the instantaneous velocities and then dividing this total by number of quantities
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Acceleration = The rate of change in velocity. (m/s)
Copyright © 2010 Ryan P. Murphy
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A = ----------------Velocity
Time
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A = ----------------Velocity
Time
Delta (Means Change)
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A = ----------------Velocity
Time
Delta (Means Change)
Or… a = (v2 − v1)/(t2 − t1)
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A = ----------------Velocity
Time
Delta (Means Change)
Or… a = (v2 − v1)/(t2 − t1)
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• Acceleration is measured by taking the change in velocity of an object divided by the time to change that velocity:
A = ----------------Velocity
Time
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• Acceleration is measured by taking the change in velocity of an object divided by the time to change that velocity:
A = ----------------Velocity
Time
Delta (Means Change)
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• Acceleration is measured by taking the change in velocity of an object divided by the time to change that velocity:
A = ----------------Velocity
Time
Delta (Means Change)
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• Acceleration is measured by taking the change in velocity of an object divided by the time to change that velocity:
A = ----------------Velocity
Time
Delta (Means Change)
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• Video Link! Speed, Velocity, Acceleration– Be proactive, sketch problems in journal as
completed in video.– http://www.youtube.com/watch_popup?v=rZo
8-ihCA9E
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Acceleration = The final velocity – the starting velocity, divided by time.
Copyright © 2010 Ryan P. Murphy
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Acceleration = The final velocity – the starting velocity, divided by time.
Copyright © 2010 Ryan P. Murphy
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Acceleration = The final velocity – the starting velocity, divided by time.
Copyright © 2010 Ryan P. Murphy
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Acceleration = The final velocity – the starting velocity, divided by time.
Copyright © 2010 Ryan P. Murphy
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• Video Link (Optional) 100 meter final London Summer Games (Note Bolt’s acceleration)– http://www.youtube.com/watch?v=2O7K-8G2nwU
(Skip ahead to 4:15 for race)
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• Forces in Motion, Speed, Velocity, Acceleration and more available sheet.
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• Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. – What’s the rat mobiles acceleration?
Copyright © 2010 Ryan P. Murphy
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• Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. – What’s the rat mobiles acceleration?
Copyright © 2010 Ryan P. Murphy
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• Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. – What’s the rat mobiles acceleration?
Copyright © 2010 Ryan P. Murphy
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• Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. – What’s the rat mobiles acceleration?
Copyright © 2010 Ryan P. Murphy
200 m/s 80 m/s
4 s
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• Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. – What’s the rat mobiles acceleration?
Copyright © 2010 Ryan P. Murphy
120 m/s
4 s
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• Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. – What’s the rat mobiles acceleration?
Copyright © 2010 Ryan P. Murphy
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• Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. – What’s the rat mobiles acceleration?
• The formula for acceleration is:• a = (Final velocity – starting velocity) / time.
Copyright © 2010 Ryan P. Murphy
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• Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. – What’s the rat mobiles acceleration?
• The formula for acceleration is:• a = (Final velocity – starting velocity) / time.• a = 200m/s -80m/s / 4 s =
Copyright © 2010 Ryan P. Murphy
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• Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. – What’s the rat mobiles acceleration?
• The formula for acceleration is:• a = (Final velocity – starting velocity) / time.• a = 200m/s -80m/s / 4 s =• a = 120 m/s / 4 s =
Copyright © 2010 Ryan P. Murphy
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• Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. – What’s the rat mobiles acceleration?
• The formula for acceleration is:• a = (Final velocity – starting velocity) / time.• a = 200m/s -80m/s / 4 s =• a = 120 m/s / 4 s = 30 m/s
Copyright © 2010 Ryan P. Murphy
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• Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters accelerating the rat mobile to 200 m/s in 4 seconds. – What’s the rat mobiles acceleration?
• The formula for acceleration is:• a = (Final velocity – starting velocity) / time.• a = 200m/s -80m/s / 4 s =• a = 120 m/s / 4 s = 30 m/s North
Copyright © 2010 Ryan P. Murphy
Vector
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• A car traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds. – What is its acceleration / deceleration?
Copyright © 2010 Ryan P. Murphy
a = (v2 − v1) t
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• A car traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds. – What is its acceleration / deceleration?
Copyright © 2010 Ryan P. Murphy
a = (v2 − v1) t
0 m/s 10 m/s
20 s
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• A car traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds. – What is its acceleration / deceleration?
Copyright © 2010 Ryan P. Murphy
a = (v2 − v1) t
10 m/s
20 s
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• A car traveling at 10 m/s starts to decelerate steadily. It comes to a complete stop in 20 seconds. – What is its acceleration / deceleration?
Copyright © 2010 Ryan P. Murphy
a = (v2 − v1) t
10 m/s
20 s
- .5 m/s
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• Forces in Motion, Speed, Velocity, Acceleration and more available sheet.
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• A unicyclist was traveling at 2 m/s South and speed up to 6 m/s in 3 seconds. – What was the acceleration?
Copyright © 2010 Ryan P. Murphy
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• A unicyclist was traveling at 2 m/s South and speed up to 6 m/s in 3 seconds. – What was the acceleration?
Copyright © 2010 Ryan P. Murphy
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• A unicyclist was traveling at 2 m/s South and speed up to 6 m/s in 3 seconds. – What was the acceleration?
Copyright © 2010 Ryan P. Murphy
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• The final velocity (6 m/s) minus the starting velocity (2 m/s) South divided by the time (3 seconds) = acceleration.
Copyright © 2010 Ryan P. Murphy
6 m/s – 2m/s
3s – 0s
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• The final velocity (6 m/s) minus the starting velocity (2 m/s) South divided by the time (3 seconds) = acceleration.
Copyright © 2010 Ryan P. Murphy
4 m/s
3s
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• The final velocity (6 m/s) minus the starting velocity (2 m/s) South divided by the time (3 seconds) = acceleration.
Copyright © 2010 Ryan P. Murphy
4 m/s
3s
= 1.333 m/s South
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Copyright © 2010 Ryan P. Murphy
Acceleration: Learn more at… http://www.physicsclassroom.com/class/1dkin/u1l1e.cfm
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• Video Link! Khan Academy. Acceleration.• (Optional) complete problems as he does.
– Be active in your learning not passive.– http://www.khanacademy.org/science/physics/
mechanics/v/acceleration
Copyright © 2010 Ryan P. Murphy
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Deceleration: To slow velocity.-
Copyright © 2010 Ryan P. Murphy
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Deceleration: To slow velocity.Formula is the same as acceleration but
will be a negative value.
Copyright © 2010 Ryan P. Murphy
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Deceleration: To slow velocity.Formula is the same as acceleration but
will be a negative value.
Copyright © 2010 Ryan P. Murphy
Note: There is no "deceleration", only negative acceleration
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• The formula is the same, but the value will be a negative.–Deceleration = (final velocity – starting
velocity) divided by time.
Copyright © 2010 Ryan P. Murphy
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• Forces in Motion, Speed, Velocity, Acceleration and more available sheet.
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• Lightning McGreen was traveling 200 m/s West when he slowed to 50 m/s in 10 seconds. –What was his deceleration?
Copyright © 2010 Ryan P. Murphy
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• Lightning McGreen was traveling 200 m/s West when he slowed to 50 m/s in 10 seconds. –What was his deceleration?
Copyright © 2010 Ryan P. Murphy
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• The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds.
Copyright © 2010 Ryan P. Murphy
50 m/s - 200 m/s
10s – 0s
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• The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds.
Copyright © 2010 Ryan P. Murphy
150 m/s
10s
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• The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds.
Copyright © 2010 Ryan P. Murphy
150 m/s
10s
Deceleration = -15 m/s
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• The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds.
Copyright © 2010 Ryan P. Murphy
150 m/s
10s
Deceleration = -15 m/s West
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• The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds.
Copyright © 2010 Ryan P. Murphy
150 m/s
10s
Deceleration = -15 m/s West
Vector or Scalar?
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• The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds.
Copyright © 2010 Ryan P. Murphy
150 m/s
10s
Deceleration = -15 m/s West
Vector
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• The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds.
Copyright © 2010 Ryan P. Murphy
150 m/s
10s
Deceleration = -15 m/s West
Vector
M_______and d______
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• The final velocity (50 m/s) minus the starting velocity (200 m/s) divided by 10 seconds.
Copyright © 2010 Ryan P. Murphy
150 m/s
10s
Deceleration = -15 m/s West
Vector
Magnitudeand direction
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Momentum: A measure of the motion of a body equal to the product of its mass and velocity.
Copyright © 2010 Ryan P. Murphy
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Momentum = Mass * Velocity.
Copyright © 2010 Ryan P. Murphy
p = m v
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Momentum = Mass * Velocity.
Copyright © 2010 Ryan P. Murphy
p = m vMomentu
mMass kg
Velocity m/s
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• Momentum = ?
Copyright © 2010 Ryan P. Murphy
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• Video Link! Momentum (Optional)– http://www.youtube.com/watch?v=edcpZoM5xmo
Copyright © 2010 Ryan P. Murphy
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• Forces in Motion, Speed, Velocity, Acceleration and more available sheet.
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• What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West?
Copyright © 2010 Ryan P. Murphy
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• What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West?
Copyright © 2010 Ryan P. Murphy
p = m v
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• What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West?
Copyright © 2010 Ryan P. Murphy
p = m vMomentum = 3000 kg 20/m/s/ West
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• What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West?
Copyright © 2010 Ryan P. Murphy
p = m vMomentum = 3000 kg 20/m/s/ WestMomentum =
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• What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West?
Copyright © 2010 Ryan P. Murphy
p = m vMomentum = 3000 kg 20/m/s/ WestMomentum = 60,000 kg/m/s West
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• What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West?
Copyright © 2010 Ryan P. Murphy
p = m vMomentum = 3000 kg 20/m/s/ WestMomentum = 60,000 kg/m/s West
Can you put it into SI?
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• What is the momentum of Fred if he weighs 3000 kg and is traveling with a velocity of 20 m/s / West?
Copyright © 2010 Ryan P. Murphy
p = m vMomentum = 3000 kg 20/m/s/ WestMomentum = 60,000 kg/m/s WestMomentum = 6 x 104 kg/m/s West
Can you put it into SI?
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• Momentum = 60,000 kg/m/s
Copyright © 2010 Ryan P. Murphy
Momentum. Learn more at… http://www.physicsclassroom.com/class/momentum/u4l1a.cfm
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• Forces in Motion, Speed, Velocity, Acceleration and more available sheet.
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• Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum?
Copyright © 2010 Ryan P. Murphy
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• Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum?
Copyright © 2010 Ryan P. Murphy
p = m v
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• Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum?
Copyright © 2010 Ryan P. Murphy
p = m vMomentum = 1000 kg 20/m/s/ North
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• Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum?
Copyright © 2010 Ryan P. Murphy
p = m vMomentum = 1000 kg 20/m/s/ NorthMomentum = 20,000 kg/m/s North
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• Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum?
Copyright © 2010 Ryan P. Murphy
p = m vMomentum = 1000 kg 20/m/s/ NorthMomentum = 20,000 kg/m/s North
Can you put it into SI?
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• Chick Licks weighs 1000 kg and had a velocity of 20 m/s North. –What was his momentum?
Copyright © 2010 Ryan P. Murphy
p = m vMomentum = 1000 kg 20/m/s/ NorthMomentum = 20,000 kg/m/s NorthMomentum = 2 x 104 kg/m/s North
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• Momentum for car = 20,000 kg/m/s North
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Copyright © 2010 Ryan P. Murphy
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• Momentum for car = 20,000 kg/m/s North–The truck has more momentum so the
car gets pushed back.
Copyright © 2010 Ryan P. Murphy
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• Momentum for car = 20,000 kg/m/s North–The truck has more momentum so the
car gets pushed back.
Copyright © 2010 Ryan P. Murphy