testbanku.eu...Created Date 12/1/2008 11:14:54 AM
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Transcript of testbanku.eu...Created Date 12/1/2008 11:14:54 AM
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4 #7
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d = (18 x 2 x 1.27 + 21 x 4 x 1.27)/(6 x 1.27) = 20 in.
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The stress in the bottom layer of steel is determined using a distance from the neutral axis of 11.17 in. instead of 10.17 in as done above. This results in a value of steel stress, fs = 13,497 psi
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self-weight
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3
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