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Transcript of © Boardworks Ltd 2005 1 of 49 A8 Linear and real-life graphs 3 ESO Mathematics.
![Page 1: © Boardworks Ltd 2005 1 of 49 A8 Linear and real-life graphs 3 ESO Mathematics.](https://reader035.fdocuments.in/reader035/viewer/2022062308/56649edf5503460f94bef55f/html5/thumbnails/1.jpg)
© Boardworks Ltd 2005 1 of 49
A8 Linear and real-life graphs
3 ESO Mathematics
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A8.1 Linear graphs
Contents
A8 Linear and real-life graphs
A8.2 Gradients and intercepts
A8.3 Parallel and perpendicular lines
A8.4 Interpreting real-life graphs
A8.5 Distance-time graphs
A8.6 Speed-time graphs
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Coordinate pairs
When we write a coordinate, for example,
Together, the x-coordinate and the y-coordinate are called a coordinate pair.
the first number is called the x-coordinate and the second number is called the y-coordinate.
(3, 5)
x-coordinate
(3, 5)
y-coordinate
(3, 5)
the first number is the x-coordinate and the second number is the y-coordinate.
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Graphs parallel to the y-axis
What do these coordinate pairs have in common?
(2, 3), (2, 1), (2, –2), (2, 4), (2, 0) and (2, –3)?
The x-coordinate in each pair is equal to 2.
Look what happens when these points are plotted on a graph.
x
y All of the points lie on a straight line parallel to the y-axis.
Name five other points that will lie on this line.
This line is called x = 2.x = 2
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Graphs parallel to the y-axis
All graphs of the form x = c,
where c is any number, will be parallel to the y-axis and will cut the x-axis at the point (c, 0).
All graphs of the form x = c,
where c is any number, will be parallel to the y-axis and will cut the x-axis at the point (c, 0).
x
y
x = –3x = –10 x = 4 x = 9
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Graphs parallel to the x-axis
What do these coordinate pairs have in common?
(0, 1), (4, 1), (–2, 1), (2, 1), (1, 1) and (–3, 1)?
The y-coordinate in each pair is equal to 1.
Look what happens when these points are plotted on a graph.
x
y All of the points lie on a straight line parallel to the x-axis.
This line is called y = 1.
y = 1Name five other points that will lie on this line.
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Graphs parallel to the x-axis
All graphs of the form y = c,
where c is any number, will be parallel to the x-axis and will cut the y-axis at the point (0, c).
All graphs of the form y = c,
where c is any number, will be parallel to the x-axis and will cut the y-axis at the point (0, c).
x
y
y = –2
y = 5
y = –5
y = 3
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Plotting graphs of linear functions
The x-coordinate and the y-coordinate in a coordinate pair can be linked by a function.
What do these coordinate pairs have in common?
(1, –1), (4, 2), (–2, –4), (0, –2), (–1, –3) and (3.5, 1.5)?
In each pair, the y-coordinate is 2 less than the x-coordinate.
These coordinates are linked by the function:
y = x – 2
We can draw a graph of the function y = x – 2 by plotting points that obey this function.
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Plotting graphs of linear functions
Given a function, we can find coordinate points that obey the function by constructing a table of values.
Suppose we want to plot points that obey the function
y = 2x + 5
We can use a table as follows:
x
y = 2x + 5
–3 –2 –1 0 1 2 3
–1
(–3, –1)
1 3 5 7 9 11
(–2, 1) (–1, 3) (0, 5) (1, 7) (2, 9) (3, 11)
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Plotting graphs of linear functions
to draw a graph of y = 2x + 5:
1) Complete a table of values:
2) Plot the points on a coordinate grid.
3) Draw a line through the points.
4) Label the line.
5) Check that other points on the line fit the rule.
xy = 2x + 5
–3 –2 –1 0 1 2 3
For example,
y = 2x + 5
y
x
–1 1 3 5 7 9 11
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Plotting graphs of linear functions
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A8.2 Gradients and intercepts
Contents
A8.3 Parallel and perpendicular lines
A8 Linear and real-life graphs
A8.1 Linear graphs
A8.4 Interpreting real-life graphs
A8.5 Distance-time graphs
A8.6 Speed-time graphs
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Gradients of straight-line graphs
The gradient of a line is a measure of how steep the line is.
y
x
a horizontal line
Zero gradient
y
x
a downwards slope
Negative gradient
y
x
an upwards slope
Positive gradient
The gradient of a line can be positive, negative or zero if, moving from left to right, we have
If a line is vertical its gradient cannot by specified.
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Calculating gradients
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Finding the gradient from two given points
If we are given any two points (x1, y1) and (x2, y2) on a line we can calculate the gradient of the line as follows,
the gradient =change in ychange in x
the gradient =y2 – y1
x2 – x1
x
y
x2 – x1
(x1, y1)
(x2, y2)
y2 – y1
Draw a right-angled triangle between the two points on the line as follows,
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Investigating linear graphs
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The general equation of a straight line
The general equation of a straight line can be written as:
y = mx + c
The value of m tells us the gradient of the line.
The value of c tells us where the line crosses the y-axis.
This is called the y-intercept and it has the coordinate (0, c).
For example, the line y = 3x + 4 has a gradient of 3 and crosses the y-axis at the point (0, 4).
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The gradient and the y-intercept
Complete this table:
equation gradient y-intercept
y = 3x + 4
y = – 5
y = 2 – 3x
1
–2
3 (0, 4)
(0, –5)
–3 (0, 2)
y = x
y = –2x – 7
x2
12
(0, 0)
(0, –7)
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Rearranging equations into the form y = mx + c
Sometimes the equation of a straight line graph is not given in the form y = mx + c.
The equation of a straight line is 2y + x = 4.Find the gradient and the y-intercept of the line.
Rearrange the equation by performing the same operations on both sides,
2y + x = 4
y = – x + 212
2y = –x + 4subtract x from both sides:
y =–x + 4
2divide both sides by 2:
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Rearranging equations into the form y = mx + c
Sometimes the equation of a straight line graph is not given in the form y = mx + c.
The equation of a straight line is 2y + x = 4.Find the gradient and the y-intercept of the line.
Once the equation is in the form y = mx + c we can determine the value of the gradient and the y-intercept.
So the gradient of the line is 12
– and the y-intercept is 2.
y = – x + 212
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Substituting values into equations
A line with the equation y = mx + 5 passes through the point (3, 11).
What is the value of m?
To solve this problem we can substitute x = 3 and y = 11 into the equation y = mx + 5.
This gives us, 11 = 3m + 5
6 = 3msubtract 5 from both sides:
2 = mdivide both sides by 3:
m = 2
The equation of the line is therefore y = 2x + 5.
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What is the equation of the line?
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Match the equations to the graphs
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A8.3 Parallel and perpendicular lines
Contents
A8.2 Gradients and intercepts
A8 Linear and real-life graphs
A8.1 Linear graphs
A8.4 Interpreting real-life graphs
A8.5 Distance-time graphs
A8.6 Speed-time graphs
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Investigating parallel lines
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Parallel lines
If two lines have the same gradient they are parallel.If two lines have the same gradient they are parallel.
Show that the lines 2y + 6x = 1 and y = –3x + 4 are parallel.
We can show this by rearranging the first equation so that it is in the form y = mx + c.
2y = –6x + 1subtract 6x from both sides:
y =–6x + 1
2divide both sides by 2:
2y + 6x = 1
y = –3x + ½
The gradient m is –3 for both lines and so they are parallel.
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Matching parallel lines
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Investigating perpendicular lines
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Perpendicular lines
If if the gradients of two lines have a product of –1 then they are perpendicular.
If if the gradients of two lines have a product of –1 then they are perpendicular.
In general, if the gradient of a line is m, then the gradient of
the line perpendicular to it is .–1m
Write down the equation of the line that is perpendicular to y = –4x + 3 and passes through the point (0, –5).
The gradient of the line y = –4x + 3 is
The gradient of the line perpendicular to it is therefore 14
The equation of the line with gradient and y-intercept –5 is,
y = x – 5 14
–4.14
.
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Matching perpendicular lines
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A8.4 Interpreting real-life graphs
Contents
A8.3 Parallel and perpendicular lines
A8.2 Gradients and intercepts
A8.1 Linear graphs
A8 Linear and real-life graphs
A8.5 Distance-time graphs
A8.6 Speed-time graphs
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Real-life graphs
The resulting graph shows the rate that one quantity changes with another. For example,
When we use graphs to illustrate real-life situations, instead of plotting y-values against x-values, we plot plot one physical quantity against another physical quantity.
British pounds
Am
eri
can
do
llars
This graph shows the exchange rate from British pounds to American dollars.
It is a straight line graph through the origin and so the equation of the line would be of the form y = mx.
What would the value of m represent?The value of m would be equal to the number of dollars in each pound.
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Real-life graphs
This graph show the value of an investment as it gains interest cumulatively over time.
time
inve
stm
en
t va
lue
The graph increases by increasing amounts.
Each time interest is added it is calculated on an ever greater amount.
This makes a small difference at first but as time goes on it makes a much greater difference.
This is an example of an exponential increase.
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Real-life graphs
This graph show the mass of a newborn baby over the first month from birth.
The baby’s mass decreases slightly during the first week.
Its mass then increases in decreasing amounts over the rest of the month.
time
ma
ss
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Rates of change
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Filling flasks
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A8.5 Distance-time graphs
Contents
A8.3 Parallel and perpendicular lines
A8.2 Gradients and intercepts
A8.1 Linear graphs
A8 Linear and real-life graphs
A8.6 Speed-time graphs
A8.4 Interpreting real-life graphs
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Formulae relating distance, time and speed
It is important to remember how distance, time and speed are related.
Using a formula triangle can help,
distance = speed × timedistance = speed × time
DISTANCE
SPEED TIME
time =distance
speed
speed =distance
time
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Distance-time graphs
In a distance-time graph the horizontal axis shows time and the vertical axis shows distance.
For example, John takes his car to visit a friend. There are three parts to the journey:
John drives at constant speed for 30 minutes until he reaches his friend’s house 20 miles away.
He stays at his friend’s house for 45 minutes.
He then drives home at a constant speed and arrives 45 minutes later.
0
time (mins)
dist
ance
(m
iles)
15 30 45 60 75 90 105 120
5
10
15
20
0
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Finding speed from distance-time graphs
How do we calculate speed?
Speed is calculated by dividing distance by time.
The steeper the line, the faster the object is moving.
time
dis
tan
ce
In a distance-time graph this is given by the gradient of the graph.
change in distance
change in time
gradient =change in distance
change in time
= speed
A zero gradient means that the object is not moving.
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Interpreting distance-time graphs
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Distance-time graphs
When a distance-time graph is linear the objects involved are moving at a constant speed.
Most real-life objects do not always move at constant speed, however. It is more likely that they will speed up and slow down during the journey.
Increase in speed over time is called acceleration.
acceleration =change in speed
time
It is measured in metres per second per second or m/s2.
When speed decreases over time is often is called deceleration.
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Distance-time graphs
Distance-time graphs that show acceleration or deceleration are curved. For example,
This distance-time graph shows an object decelerating from constant speed before coming to rest.
time
dis
tan
ce
This distance-time graph shows an object accelerating from rest before continuing at a constant speed.
time
dis
tan
ce
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A8.6 Speed-time graphs
Contents
A8.3 Parallel and perpendicular lines
A8.2 Gradients and intercepts
A8.1 Linear graphs
A8 Linear and real-life graphs
A8.5 Distance-time graphs
A8.4 Interpreting real-life graphs
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Speed-time graphs
Travel graphs can also be used to show change in speed over time.
For example, this graph shows a car accelerating steadily from rest to a speed of 20 m/s.
0
time (s)
spee
d (m
/s)
5 10 15 20 25 30 35 40
5
10
15
20
0
It then continues at a constant speed for 15 seconds.
The brakes are then applied and it decelerates steadily to a stop.
The car is moving in the same direction throughout.
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Finding acceleration from speed-time graphs
Acceleration is calculated by dividing speed by time.
The steeper the line, the greater the acceleration.
time
spe
ed
In a speed-time graph this is given by the gradient of the graph.
gradient =change in speedchange in time
= acceleration
A zero gradient means that the object is moving at a constant speed.
change in speed
change in time
A negative gradient means that the object is decelerating.
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Finding distance from speed-time graphs
The following speed-time graph shows a car driving at a constant speed of 30 m/s for 2 minutes.
What is the area under the graph?
0
time (s)
spee
d (m
/s)
15 30 45 60 75 90 105 120
5
10
15
20
0
The area under the graph is rectangular and so we can find its area by multiplying its length by its height.
Area under graph = 20 × 120 = 240
What does this amount correspond to?
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The area under a speed-time graph
This area under a speed-time graph corresponds to the distance travelled.This area under a speed-time graph
corresponds to the distance travelled.
0
time (s)
spee
d (m
/s)
5 10 15 20 25 30 35 40
5
10
15
20
0
For example, to find the distance travelled for the journey shown in this graph we find the area under it.
The shape under the graph is a trapezium so,
Area = ½(15 + 40) × 20= ½ × 55 × 20= 550
So, distance travelled= 550 m
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Interpreting speed-time graphs