MAT 1221 Survey of Calculus Section 6.4 Area and the Fundamental Theorem of Calculus .

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MAT 1221Survey of Calculus

Section 6.4

Area and the Fundamental Theorem of Calculus

http://myhome.spu.edu/lauw

Quiz

8 minutes

Major Themes in Calculus

Abstract World

The Tangent Problem

h

afhafh

)()(lim

0

( )y f x

x a

Real World

The Velocity Problem2t

( )y f t

t a

h

afhafh

)()(lim

0

Major Themes in Calculus

Abstract World

The Tangent Problem

h

afhafh

)()(lim

0

( )y f x

x a

We do not like to use the definition

Develop techniques to deal with different functions

Major Themes in Calculus

The Area Problem

( )

( ) 0 on [ , ]

y f x

f x a b

Abstract World

1

lim ( )n

ini

A f x x

The Energy Problem

( )y f x

( )f x

Real World

Major Themes in Calculus

We do not like to use the definition

Develop techniques to deal with different functions

1

lim ( )n

ini

A f x x

The Area Problem

( )

( ) 0 on [ , ]

y f x

f x a b

Abstract World

Preview

Look at the definition of the definite integral on

Look at its relationship with the area between the graph and the -axis on

Properties of Definite Integrals The Substitution Rule for Definite

Integrals

Key

Pay attention to the overall ideas Pay less attention to the details – We are

going to use a formula to compute the definite integrals, not limits.

Example 0

]5,1[on )( 2xxf

Example 0 ]5,1[on )( 2xxf

)1(f

)5.1(f

)4(f

)5.4(f

)2(f

Use left hand end points to get an estimation

Example 0 ]5,1[on )( 2xxf

)5.2(f

)5.1(f

)5(f

)5.4(f

)2(f

Use right hand end points to get an estimation

Example 0 Observation:

What happen to the estimation if we increase the number of subintervals?

In General

ith subinterval

ix

sample point

)( ixf

In General

Suppose is a continuous function defined on , we divide the interval into n subintervals of equal width

nabx /)(

The area of the rectangle is

xxf i )(

In General

subinterval sample point

xxf i )(

In General

Sum of the area of the rectangles is

n

ii

n

xxf

xxfxxfxxfxxf

1

321

)(

)()()()(

Riemann Sum

n

ii

n

xxf

xxfxxfxxfxxf

1

321

)(

)()()()(

In General

Sum of the area of the rectangles is

Sigma Notation for summation

n

ii

n

xxf

xxfxxfxxfxxf

1

321

)(

)()()()(

In General

Sum of the area of the rectangles is

IndexInitial value (lower limit)

Final value (upper limit)

In General

Sum of the area of the rectangles is

As we increase , we get better and better estimations.

n

ii

n

xxf

xxfxxfxxfxxf

1

321

)(

)()()()(

Definition

The Definite Integral of from to

n

ii

n

b

axxfdxxf

1

)(lim)(

Definition

n

ii

n

b

axxfdxxf

1

)(lim)(

upper limit

lower limit

integrand

The Definite Integral of from to

Definition

n

ii

n

b

axxfdxxf

1

)(lim)(

Integration : Process of computing integrals

The Definite Integral of from to

Remarks

We are not going to use this limit definition to compute definite integrals.

We are going to use antiderivative (indefinite integral) to compute definite integrals.

Area and Indefinite Integrals

If on , then

from to . under"" Area )( fdxxf

b

a

b

adxxf )(

Area and Indefinite Integrals

Otherwise, the definite integral may not have obvious geometric meaning.

b

adxxf )(

Example 1

Compute by interpreting it in terms of area.

2

1)1( dxx

21

1xy1

2

1( 1)x dx

Example 1

We are going to use this example to verify our next formula.

21

1xy1

2

1( 1)x dx

Fundamental Theorem of Calculus

Suppose is continuous on and

is any antiderivative of . Then

( ) ( ) ( )b

af x dx F b F a

Remarks

To simplify the computations, we always use the antiderivative with C=0.

( ) ( ) ( )b

af x dx F b F a

Remarks

To simplify the computations, we always use the antiderivative with C=0.

We will use the following notation to stand for F(b)-F(a):

( ) ( ) ( )b

aF x F b F a

FTC

( ) ( )b b

aaf x dx F x

Suppose is continuous on and

is any antiderivative of . Then

Example 2

2

1)1( dxx

21

1xy

1

bab

axFdxxf )()(

Example 3

bab

axFdxxf )()(

2

21

2dx

x

Example 4

12 3

0

(6 8 )x x dx

bab

axFdxxf )()(

The Substitution Rule for Definite Integrals

For complicated integrands, we use a version of the substitution rule.

The Substitution Rule for Definite Integrals

The procedures for indefinite and definite integrals are similar but different.

We need to change the upper and lower limits when using a substitution.

Do not change back to the original variable.

The Substitution Rule for Definite Integrals

)(

)()()())((

bg

ag

b

aduufdxxgxgf

The Substitution Rule for Definite Integrals

)(

)()()())((

bg

ag

b

aduufdxxgxgf

Let ( ).

, ( )

, ( )

u g x

x a u g a

x b u g b

xfor range ufor range ingcorrespond

Example 51

2 4

0

10 ( 3)x x dx2Let 3

2

2

limits:

1

0

u x

dux

dxdu xdx

x u

x u

781

Example 6

22

1

1x x dx

Physical Meanings of Definite Integrals

We will not have time to discuss the exact physical meanings.

Basic Idea: The definite integral of rate of change is the net change.

Example 7 (HW 18)

A company purchases a new machine for which the rate of depreciation can be modeled by the equation below, where  is the value of the machine after  years.

Find the total loss of value of the machine over the first 4 years.

17000 6 , 0 5dV

t tdt