Lectures posted online after lecture.

Textbook sections and/or pages posted a few days prior to each lecture.

In many instances there is a unique pattern of inheritance.

Traits disappear and reappear in new ratios.

CB 14.3

Genotype PhenotypeCB 14.6

Human blood types

AA orAO

AB

BB orBO

OO

CB tbl 14.2

Looking at the past:

If Frank has B blood type,

his Dad has A blood type,

And his Mom has B blood type…

Should Frank be worried?

Mom=B blood

BB or BO

Dad=A blood

AA or AO

Gametes all B / 50% B and50% O

all A / 50% A and50% O

possible

genotypes

Frank can be BO= B blood …no worries

We can also predict the future

Fig 2.12

Mom = AB Dad = AB

Inheritance of blood types

Mom = AB Dad = AB

Gametes: A or B A or B

Inheritance of blood types

Mom = AB Dad = AB

Gametes: A or B A or B

A or B

A or B

AA

AB BB

AB

Chance of each phenotype for each offspring25% AA50% AB25% BB

Mom

Dad

Inheritance of blood types

CB14.7Testcross:

determining dominant/ recessive and zygosity

CB5.21

Sickle-cell anemia is caused by a point mutation

Sickled and normal red blood cells

Mom = HS Dad = HS

H or S

H or S

HH

HS SS

HS possible offspring75% Normal25% Sickle-cell

Mom

Dad

S=sickle-cell

H=normal

Sickle-Cell Anemia:A dominant or recessive allele?

Coincidence of malaria and sickle-cell anemia

CB 23.13

Mom = HS Dad = HS

H or S

H or S

HH

HS SS

HS

possible offspringOxygen transport:75% Normal25% Sickle-cell

Malaria resistance:75% resistant25% susceptible

Mom

Dad

Sickle-Cell Anemia:A dominant or recessive allele?

S=sickle-cell

H=normal

Variation in Peas

Phenotype

Genotype

CB 14.8

CB 14.8The inheritance of genes on different chromo-somes is independent.

Y y

r R

Gene for seed color

Gene for seed shape

Approximate position of seed color and shape genes in peas

Chrom. 1/7 Chrom. 7/7

CB 15.2The inheritance of genes on different chromosomes is independent:independent assortment

CB 15.2

meiosis I

meiosis II

CB 15.2The inheritance of genes on different chromosomes is independent:independent assortment

CB 14.8

Inheritance can be predicted by probability

CB 14.9

Probability of a 4= 1/6

Probability of two 4’s in a row=1/6x1/6=1/36

Probability of 3 or 4 = 1/6+1/6= 1/3

“and” multiply

“or” add

Huntington’s Disease

D=disease

d=normal

Neurological disease, symptoms begin around 40 years old.

Mom = dd Dad = Dd

d or d

D or d

Dd

Dd dd

ddpossible offspring50% Huntington’s50% Normal

Mom

Dad

Huntington’s Disease D=disease

d=normal

Two different people:One with Huntington’s disease = Dd HhOne without Huntington’s disease = dd Hhmate. What is the probability that their offspring will have Huntington’s disease and sickle cell anemia?(Dd hh)

Two people:One with Huntington’s disease = Dd HhOne without Huntington’s disease = dd Hhmate. What is the probability that their offspring will have

Huntington’s disease and sickle cell anemia? Dd hh

Probability of each outcome:

Probability of Dd (Ddxdd) = .5

Probability of hh (HhxHh) = .25

Two people:One with Huntington’s disease = Dd HhOne without Huntington’s disease = dd Hhmate. What is the probability that their offspring will have

Huntington’s disease and sickle cell anemia? Dd hh

Probability of each outcome:

Probability of Dd (Ddxdd) = .5Probability of hh (HhxHh) = .25Multiply both probabilities .25 X.5 = 12.5%

chance Dd hh offspring

CB 14.11Many traits are coded for by more than one gene.

Eye color: One trait controlled by multiple genes

Lectures posted online after lecture.

Textbook sections and/or pages posted a few days prior to each lecture.