Insert using Linear Hashing

h001

4

H level (n) = level+1 bits of n Level = 0, next =

7

Insert 2, h0(2) = 0

initial

4 = 100, so h0(4) = 07 = 111, so h0(7) = 1

Insert using Linear Hashing

h001

4 2

H level (n) = level+1 bits of n Level = 0, next =

7

Insert 8, h0(8) = 0

Insert using Linear Hashing

h001

4 2

H level (n) = level+1 bits of n Level = 0, next =

7

8

No room, so insert into an overflow block, which triggers the splitting process.

Insert using Linear Hashing

h001

4 2

H level (n) = level+1 bits of n Level = 0, next =

7

8

No room, so insert into an overflow block, which triggers the splitting process.

H1(4) = 00H1(2) = 10H1(8) = 00

h100011011

Insert using Linear Hashing

h001

4 8

H level (n) = level+1 bits of n Level = 0, next =

7

h100

10 2

Denotes split bucket

No room, so insert into an overflow block, which triggers the splitting process.

H1(4) = 00H1(2) = 10H1(8) = 00

Insert using Linear Hashing

h001

4 8

H level (n) = level+1 bits of n Level = 0, next =

7

Insert 5, h0(5) = 1

Advance NEXT by one.

h100

10 2

Insert using Linear Hashing

h001

4 8

H level (n) = level+1 bits of n Level = 0, next =

7 5

Insert 3, h0(3) = 1

h100

10 2

Insert using Linear Hashing

h001

4 8

H level (n) = level+1 bits of n Level = 0, next =

7 5No room, insert into overflow and trigger a split.

h100

10 2

3

Insert using Linear Hashing

h001

4 8

H level (n) = level+1 bits of n Level = 0, next =

5Redistribute 3, 5, 7 using H1

H1(3) = 11H1(5) = 01H1(7) = 11

h100011011 2

3 7

Insert using Linear Hashing

h001

4 8

H level (n) = level+1 bits of n Level = 0, next =

5Advance Next, but it is at the bottom of the current Level.

h100011011 2

3 7

Insert using Linear Hashing

h001

4 8

H level (n) = level+1 bits of n Level = 1, next =

5So reset it to the top and increment Level to 1.

h100011011 2

3 7

Insert using Linear Hashing

4 8

H level (n) = level+1 bits of n Level = 1, next =

5Remove split indicators and only use H1

h100011011 2

3 7

Insert using Linear Hashing

4 8

H level (n) = level+1 bits of n Level = 1, next =

5

Insert 15, h1(15) = 11

h100011011 2

3 7

Insert using Linear Hashing

4 8

H level (n) = level+1 bits of n Level = 1, next =

5

h100011011 2

3 7 15No room, so insert into an overflow block, which triggers the splitting process.

Insert using Linear Hashing

4 8

H level (n) = level+1 bits of n Level = 1, next =

5

h100011011 2

3 7 15

Split Next using level+1 H functionH2(4) = 100H2(8) = 000

Insert using Linear Hashing

8

H level (n) = level+1 bits of n Level = 1, next =

5

h100011011 2

3 7 15

Split Next using level+1 H functionH2(4) = 100H2(8) = 000

h2100 4

h2000

Insert using Linear Hashing

8

H level (n) = level+1 bits of n Level = 1, next =

5

h100011011 2

3 7 15

Mark bucket as splitAdvance Next.

h2100 4

Insert using Linear Hashing

8

H level (n) = level+1 bits of n Level = 1, next =

5

h100011011 2

3 7 15

Mark bucket as splitAdvance Next.

h2100 4

And Insert and Insert and Insert ….